Adding up numbers in Portuguese is strange












9












$begingroup$


My friend from Portugal said that 2 + 2 is 8 in Portuguese. And he could prove it. I did not understand it at first. But then he showed me the following equation:



  D O I S
D O I S
+ ________
O I T O


Ah, now it is clear. Two is "dois" and eight is "oito" in Portuguese. And the equation above makes perfect sense. Could you solve the single one solution that explain this?



Rules: D, O, I, S and T are a number between 0 - 9. Each one is unique.










share|improve this question









$endgroup$

















    9












    $begingroup$


    My friend from Portugal said that 2 + 2 is 8 in Portuguese. And he could prove it. I did not understand it at first. But then he showed me the following equation:



      D O I S
    D O I S
    + ________
    O I T O


    Ah, now it is clear. Two is "dois" and eight is "oito" in Portuguese. And the equation above makes perfect sense. Could you solve the single one solution that explain this?



    Rules: D, O, I, S and T are a number between 0 - 9. Each one is unique.










    share|improve this question









    $endgroup$















      9












      9








      9





      $begingroup$


      My friend from Portugal said that 2 + 2 is 8 in Portuguese. And he could prove it. I did not understand it at first. But then he showed me the following equation:



        D O I S
      D O I S
      + ________
      O I T O


      Ah, now it is clear. Two is "dois" and eight is "oito" in Portuguese. And the equation above makes perfect sense. Could you solve the single one solution that explain this?



      Rules: D, O, I, S and T are a number between 0 - 9. Each one is unique.










      share|improve this question









      $endgroup$




      My friend from Portugal said that 2 + 2 is 8 in Portuguese. And he could prove it. I did not understand it at first. But then he showed me the following equation:



        D O I S
      D O I S
      + ________
      O I T O


      Ah, now it is clear. Two is "dois" and eight is "oito" in Portuguese. And the equation above makes perfect sense. Could you solve the single one solution that explain this?



      Rules: D, O, I, S and T are a number between 0 - 9. Each one is unique.







      alphametic






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 20 at 4:09









      ChaoticChaotic

      621316




      621316






















          3 Answers
          3






          active

          oldest

          votes


















          10












          $begingroup$

          Could it be





             1246 

          + 1246

          ------

          2492



          Then




          D=1, O=2, I=4, S=6, T=9







          share|improve this answer











          $endgroup$













          • $begingroup$
            Perfect! Easy one?
            $endgroup$
            – Chaotic
            Mar 20 at 4:50






          • 1




            $begingroup$
            Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
            $endgroup$
            – El-Guest
            2 days ago



















          13












          $begingroup$


          From $S+S=O$ we know $O$ is even. From the $O+O$ part, we know $Ole4$ because $2O$ doesn't carry (otherwise $O$ would also have to be odd). Therefore $I$ is doubly even ($I=2O$), and because $2I$ doesn't carry, $I=4$ and $O=2$. $D=Spm5$ and $2D$ doesn't carry, so $S=6$ and $D=1$. $T=2I+1=9$.







          share|improve this answer











          $endgroup$













          • $begingroup$
            You haven't given a value for $T$.
            $endgroup$
            – ZanyG
            2 days ago



















          0












          $begingroup$

          Let's start as a basic Brute Force





          Consider D as 1

          Since D and S gives a Unit Place as O

          So,S is D+5 ;S is 6

          So, Here O is 2

          Given I = O + O; So,I=4

          Since T is I+I with a carry of 1 ;T is 9






          share|improve this answer










          New contributor




          NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.






          $endgroup$













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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            10












            $begingroup$

            Could it be





               1246 

            + 1246

            ------

            2492



            Then




            D=1, O=2, I=4, S=6, T=9







            share|improve this answer











            $endgroup$













            • $begingroup$
              Perfect! Easy one?
              $endgroup$
              – Chaotic
              Mar 20 at 4:50






            • 1




              $begingroup$
              Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
              $endgroup$
              – El-Guest
              2 days ago
















            10












            $begingroup$

            Could it be





               1246 

            + 1246

            ------

            2492



            Then




            D=1, O=2, I=4, S=6, T=9







            share|improve this answer











            $endgroup$













            • $begingroup$
              Perfect! Easy one?
              $endgroup$
              – Chaotic
              Mar 20 at 4:50






            • 1




              $begingroup$
              Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
              $endgroup$
              – El-Guest
              2 days ago














            10












            10








            10





            $begingroup$

            Could it be





               1246 

            + 1246

            ------

            2492



            Then




            D=1, O=2, I=4, S=6, T=9







            share|improve this answer











            $endgroup$



            Could it be





               1246 

            + 1246

            ------

            2492



            Then




            D=1, O=2, I=4, S=6, T=9








            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 2 days ago









            Omega Krypton

            4,8702444




            4,8702444










            answered Mar 20 at 4:42









            El-GuestEl-Guest

            20.8k24791




            20.8k24791












            • $begingroup$
              Perfect! Easy one?
              $endgroup$
              – Chaotic
              Mar 20 at 4:50






            • 1




              $begingroup$
              Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
              $endgroup$
              – El-Guest
              2 days ago


















            • $begingroup$
              Perfect! Easy one?
              $endgroup$
              – Chaotic
              Mar 20 at 4:50






            • 1




              $begingroup$
              Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
              $endgroup$
              – El-Guest
              2 days ago
















            $begingroup$
            Perfect! Easy one?
            $endgroup$
            – Chaotic
            Mar 20 at 4:50




            $begingroup$
            Perfect! Easy one?
            $endgroup$
            – Chaotic
            Mar 20 at 4:50




            1




            1




            $begingroup$
            Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
            $endgroup$
            – El-Guest
            2 days ago




            $begingroup$
            Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
            $endgroup$
            – El-Guest
            2 days ago











            13












            $begingroup$


            From $S+S=O$ we know $O$ is even. From the $O+O$ part, we know $Ole4$ because $2O$ doesn't carry (otherwise $O$ would also have to be odd). Therefore $I$ is doubly even ($I=2O$), and because $2I$ doesn't carry, $I=4$ and $O=2$. $D=Spm5$ and $2D$ doesn't carry, so $S=6$ and $D=1$. $T=2I+1=9$.







            share|improve this answer











            $endgroup$













            • $begingroup$
              You haven't given a value for $T$.
              $endgroup$
              – ZanyG
              2 days ago
















            13












            $begingroup$


            From $S+S=O$ we know $O$ is even. From the $O+O$ part, we know $Ole4$ because $2O$ doesn't carry (otherwise $O$ would also have to be odd). Therefore $I$ is doubly even ($I=2O$), and because $2I$ doesn't carry, $I=4$ and $O=2$. $D=Spm5$ and $2D$ doesn't carry, so $S=6$ and $D=1$. $T=2I+1=9$.







            share|improve this answer











            $endgroup$













            • $begingroup$
              You haven't given a value for $T$.
              $endgroup$
              – ZanyG
              2 days ago














            13












            13








            13





            $begingroup$


            From $S+S=O$ we know $O$ is even. From the $O+O$ part, we know $Ole4$ because $2O$ doesn't carry (otherwise $O$ would also have to be odd). Therefore $I$ is doubly even ($I=2O$), and because $2I$ doesn't carry, $I=4$ and $O=2$. $D=Spm5$ and $2D$ doesn't carry, so $S=6$ and $D=1$. $T=2I+1=9$.







            share|improve this answer











            $endgroup$




            From $S+S=O$ we know $O$ is even. From the $O+O$ part, we know $Ole4$ because $2O$ doesn't carry (otherwise $O$ would also have to be odd). Therefore $I$ is doubly even ($I=2O$), and because $2I$ doesn't carry, $I=4$ and $O=2$. $D=Spm5$ and $2D$ doesn't carry, so $S=6$ and $D=1$. $T=2I+1=9$.








            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 2 days ago

























            answered 2 days ago









            JonMark PerryJonMark Perry

            20.4k64099




            20.4k64099












            • $begingroup$
              You haven't given a value for $T$.
              $endgroup$
              – ZanyG
              2 days ago


















            • $begingroup$
              You haven't given a value for $T$.
              $endgroup$
              – ZanyG
              2 days ago
















            $begingroup$
            You haven't given a value for $T$.
            $endgroup$
            – ZanyG
            2 days ago




            $begingroup$
            You haven't given a value for $T$.
            $endgroup$
            – ZanyG
            2 days ago











            0












            $begingroup$

            Let's start as a basic Brute Force





            Consider D as 1

            Since D and S gives a Unit Place as O

            So,S is D+5 ;S is 6

            So, Here O is 2

            Given I = O + O; So,I=4

            Since T is I+I with a carry of 1 ;T is 9






            share|improve this answer










            New contributor




            NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$


















              0












              $begingroup$

              Let's start as a basic Brute Force





              Consider D as 1

              Since D and S gives a Unit Place as O

              So,S is D+5 ;S is 6

              So, Here O is 2

              Given I = O + O; So,I=4

              Since T is I+I with a carry of 1 ;T is 9






              share|improve this answer










              New contributor




              NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.






              $endgroup$
















                0












                0








                0





                $begingroup$

                Let's start as a basic Brute Force





                Consider D as 1

                Since D and S gives a Unit Place as O

                So,S is D+5 ;S is 6

                So, Here O is 2

                Given I = O + O; So,I=4

                Since T is I+I with a carry of 1 ;T is 9






                share|improve this answer










                New contributor




                NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                $endgroup$



                Let's start as a basic Brute Force





                Consider D as 1

                Since D and S gives a Unit Place as O

                So,S is D+5 ;S is 6

                So, Here O is 2

                Given I = O + O; So,I=4

                Since T is I+I with a carry of 1 ;T is 9







                share|improve this answer










                New contributor




                NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                share|improve this answer



                share|improve this answer








                edited 2 days ago









                JonMark Perry

                20.4k64099




                20.4k64099






                New contributor




                NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.









                answered 2 days ago









                NaveenGopal NolluNaveenGopal Nollu

                1




                1




                New contributor




                NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





                New contributor





                NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






























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