Are there theorems which relate the eigenvalues of matrices and sub matrices?
$begingroup$
I am looking for theorems which relate the eigenvalues square matrices and their submatrices such as https://math.stackexchange.com/a/1670001/374907 but for general matrices not just Hermitian matrices.
I do not know if there exists any theorems on this topic so that I why I am posting this question.
Notes
- Theorems that relate the eigenvalues of $A$, $B$ square matrices and the eigenvalues of $C$ (where $C=A+B$) would be appreciated as well.
- I am not looking for theorems on finding eigenvalues.
- References to books or papers would be appreciated.
- I am not looking for theorems that cover a general square matrices.
- If you need any clarification please feel free to ask.
matrices reference-request eigenvalues-eigenvectors
$endgroup$
add a comment |
$begingroup$
I am looking for theorems which relate the eigenvalues square matrices and their submatrices such as https://math.stackexchange.com/a/1670001/374907 but for general matrices not just Hermitian matrices.
I do not know if there exists any theorems on this topic so that I why I am posting this question.
Notes
- Theorems that relate the eigenvalues of $A$, $B$ square matrices and the eigenvalues of $C$ (where $C=A+B$) would be appreciated as well.
- I am not looking for theorems on finding eigenvalues.
- References to books or papers would be appreciated.
- I am not looking for theorems that cover a general square matrices.
- If you need any clarification please feel free to ask.
matrices reference-request eigenvalues-eigenvectors
$endgroup$
1
$begingroup$
you want Horn and Johnson, mentioned at the other question. It is not Hamiltonian matrices involved, it is Hermitian. It is always possible that someone has defined something called Hamiltonian matrix, but news to me.
$endgroup$
– Will Jagy
May 2 '18 at 20:34
$begingroup$
Sorry it's been a long day. Do you have an idea of which section I should look in? I found nothing non-obvious in the eigenvalue section of the text.
$endgroup$
– AzJ
May 2 '18 at 20:48
1
$begingroup$
I don't really know, and perhaps you should get some sleep. user1551 from the other question would know references, but i don't know whether he is awake, i.e. what time zone he is in.
$endgroup$
– Will Jagy
May 2 '18 at 20:57
add a comment |
$begingroup$
I am looking for theorems which relate the eigenvalues square matrices and their submatrices such as https://math.stackexchange.com/a/1670001/374907 but for general matrices not just Hermitian matrices.
I do not know if there exists any theorems on this topic so that I why I am posting this question.
Notes
- Theorems that relate the eigenvalues of $A$, $B$ square matrices and the eigenvalues of $C$ (where $C=A+B$) would be appreciated as well.
- I am not looking for theorems on finding eigenvalues.
- References to books or papers would be appreciated.
- I am not looking for theorems that cover a general square matrices.
- If you need any clarification please feel free to ask.
matrices reference-request eigenvalues-eigenvectors
$endgroup$
I am looking for theorems which relate the eigenvalues square matrices and their submatrices such as https://math.stackexchange.com/a/1670001/374907 but for general matrices not just Hermitian matrices.
I do not know if there exists any theorems on this topic so that I why I am posting this question.
Notes
- Theorems that relate the eigenvalues of $A$, $B$ square matrices and the eigenvalues of $C$ (where $C=A+B$) would be appreciated as well.
- I am not looking for theorems on finding eigenvalues.
- References to books or papers would be appreciated.
- I am not looking for theorems that cover a general square matrices.
- If you need any clarification please feel free to ask.
matrices reference-request eigenvalues-eigenvectors
matrices reference-request eigenvalues-eigenvectors
edited May 2 '18 at 20:42
AzJ
asked May 2 '18 at 20:26
AzJAzJ
295219
295219
1
$begingroup$
you want Horn and Johnson, mentioned at the other question. It is not Hamiltonian matrices involved, it is Hermitian. It is always possible that someone has defined something called Hamiltonian matrix, but news to me.
$endgroup$
– Will Jagy
May 2 '18 at 20:34
$begingroup$
Sorry it's been a long day. Do you have an idea of which section I should look in? I found nothing non-obvious in the eigenvalue section of the text.
$endgroup$
– AzJ
May 2 '18 at 20:48
1
$begingroup$
I don't really know, and perhaps you should get some sleep. user1551 from the other question would know references, but i don't know whether he is awake, i.e. what time zone he is in.
$endgroup$
– Will Jagy
May 2 '18 at 20:57
add a comment |
1
$begingroup$
you want Horn and Johnson, mentioned at the other question. It is not Hamiltonian matrices involved, it is Hermitian. It is always possible that someone has defined something called Hamiltonian matrix, but news to me.
$endgroup$
– Will Jagy
May 2 '18 at 20:34
$begingroup$
Sorry it's been a long day. Do you have an idea of which section I should look in? I found nothing non-obvious in the eigenvalue section of the text.
$endgroup$
– AzJ
May 2 '18 at 20:48
1
$begingroup$
I don't really know, and perhaps you should get some sleep. user1551 from the other question would know references, but i don't know whether he is awake, i.e. what time zone he is in.
$endgroup$
– Will Jagy
May 2 '18 at 20:57
1
1
$begingroup$
you want Horn and Johnson, mentioned at the other question. It is not Hamiltonian matrices involved, it is Hermitian. It is always possible that someone has defined something called Hamiltonian matrix, but news to me.
$endgroup$
– Will Jagy
May 2 '18 at 20:34
$begingroup$
you want Horn and Johnson, mentioned at the other question. It is not Hamiltonian matrices involved, it is Hermitian. It is always possible that someone has defined something called Hamiltonian matrix, but news to me.
$endgroup$
– Will Jagy
May 2 '18 at 20:34
$begingroup$
Sorry it's been a long day. Do you have an idea of which section I should look in? I found nothing non-obvious in the eigenvalue section of the text.
$endgroup$
– AzJ
May 2 '18 at 20:48
$begingroup$
Sorry it's been a long day. Do you have an idea of which section I should look in? I found nothing non-obvious in the eigenvalue section of the text.
$endgroup$
– AzJ
May 2 '18 at 20:48
1
1
$begingroup$
I don't really know, and perhaps you should get some sleep. user1551 from the other question would know references, but i don't know whether he is awake, i.e. what time zone he is in.
$endgroup$
– Will Jagy
May 2 '18 at 20:57
$begingroup$
I don't really know, and perhaps you should get some sleep. user1551 from the other question would know references, but i don't know whether he is awake, i.e. what time zone he is in.
$endgroup$
– Will Jagy
May 2 '18 at 20:57
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Two results come to mind:
- If $A$ is a nonnegative matrix (i.e., $a_{ij} ge 0$, $1 le i,j le n$), then the Perron-Frobenius theorem asserts that the spectral radius $rho(A)$ is an eigenvalue of $A$. If $tilde{A}$ is a principal submatrix of $A$, then $rho(tilde{A}) le rho(A)$ (see, e.g., Corollary 8.1.20 of Matrix Analysis, $2^text{nd}$ edition, by Horn and Johnson).
- More recently, the following result was established: let $p$ be a monic polynomial of degree $n$ with roots $lambda_1,dots,lambda_n$ (including multiplicities) and critical points $mu_1,dots,mu_{n-1}$ (including multiplicities). Let $H$ be a complex Hadamard matrix (e.g., $H$ could be the discrete Fourier transform matrix), $D=text{diag}(lambda_1,dots,lambda_n)$, and $A=HDH^{-1}$. If $A_{(i)}$ denotes the $i$th principal submatrix of $A$, then the characteristic polynomial of $A_{(i)}$ is $p'(t)/n$. Consequently, the eigenvalues of $A_{(i)}$ are $mu_1,dots,mu_{n-1}$ (this result is implied by Theorem 5.12 in Hoover et al. [MR3834205; On the realizability of the critical points of a realizable list. Linear Algebra Appl. 555 (2018), 301–313]).
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2763941%2fare-there-theorems-which-relate-the-eigenvalues-of-matrices-and-sub-matrices%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Two results come to mind:
- If $A$ is a nonnegative matrix (i.e., $a_{ij} ge 0$, $1 le i,j le n$), then the Perron-Frobenius theorem asserts that the spectral radius $rho(A)$ is an eigenvalue of $A$. If $tilde{A}$ is a principal submatrix of $A$, then $rho(tilde{A}) le rho(A)$ (see, e.g., Corollary 8.1.20 of Matrix Analysis, $2^text{nd}$ edition, by Horn and Johnson).
- More recently, the following result was established: let $p$ be a monic polynomial of degree $n$ with roots $lambda_1,dots,lambda_n$ (including multiplicities) and critical points $mu_1,dots,mu_{n-1}$ (including multiplicities). Let $H$ be a complex Hadamard matrix (e.g., $H$ could be the discrete Fourier transform matrix), $D=text{diag}(lambda_1,dots,lambda_n)$, and $A=HDH^{-1}$. If $A_{(i)}$ denotes the $i$th principal submatrix of $A$, then the characteristic polynomial of $A_{(i)}$ is $p'(t)/n$. Consequently, the eigenvalues of $A_{(i)}$ are $mu_1,dots,mu_{n-1}$ (this result is implied by Theorem 5.12 in Hoover et al. [MR3834205; On the realizability of the critical points of a realizable list. Linear Algebra Appl. 555 (2018), 301–313]).
$endgroup$
add a comment |
$begingroup$
Two results come to mind:
- If $A$ is a nonnegative matrix (i.e., $a_{ij} ge 0$, $1 le i,j le n$), then the Perron-Frobenius theorem asserts that the spectral radius $rho(A)$ is an eigenvalue of $A$. If $tilde{A}$ is a principal submatrix of $A$, then $rho(tilde{A}) le rho(A)$ (see, e.g., Corollary 8.1.20 of Matrix Analysis, $2^text{nd}$ edition, by Horn and Johnson).
- More recently, the following result was established: let $p$ be a monic polynomial of degree $n$ with roots $lambda_1,dots,lambda_n$ (including multiplicities) and critical points $mu_1,dots,mu_{n-1}$ (including multiplicities). Let $H$ be a complex Hadamard matrix (e.g., $H$ could be the discrete Fourier transform matrix), $D=text{diag}(lambda_1,dots,lambda_n)$, and $A=HDH^{-1}$. If $A_{(i)}$ denotes the $i$th principal submatrix of $A$, then the characteristic polynomial of $A_{(i)}$ is $p'(t)/n$. Consequently, the eigenvalues of $A_{(i)}$ are $mu_1,dots,mu_{n-1}$ (this result is implied by Theorem 5.12 in Hoover et al. [MR3834205; On the realizability of the critical points of a realizable list. Linear Algebra Appl. 555 (2018), 301–313]).
$endgroup$
add a comment |
$begingroup$
Two results come to mind:
- If $A$ is a nonnegative matrix (i.e., $a_{ij} ge 0$, $1 le i,j le n$), then the Perron-Frobenius theorem asserts that the spectral radius $rho(A)$ is an eigenvalue of $A$. If $tilde{A}$ is a principal submatrix of $A$, then $rho(tilde{A}) le rho(A)$ (see, e.g., Corollary 8.1.20 of Matrix Analysis, $2^text{nd}$ edition, by Horn and Johnson).
- More recently, the following result was established: let $p$ be a monic polynomial of degree $n$ with roots $lambda_1,dots,lambda_n$ (including multiplicities) and critical points $mu_1,dots,mu_{n-1}$ (including multiplicities). Let $H$ be a complex Hadamard matrix (e.g., $H$ could be the discrete Fourier transform matrix), $D=text{diag}(lambda_1,dots,lambda_n)$, and $A=HDH^{-1}$. If $A_{(i)}$ denotes the $i$th principal submatrix of $A$, then the characteristic polynomial of $A_{(i)}$ is $p'(t)/n$. Consequently, the eigenvalues of $A_{(i)}$ are $mu_1,dots,mu_{n-1}$ (this result is implied by Theorem 5.12 in Hoover et al. [MR3834205; On the realizability of the critical points of a realizable list. Linear Algebra Appl. 555 (2018), 301–313]).
$endgroup$
Two results come to mind:
- If $A$ is a nonnegative matrix (i.e., $a_{ij} ge 0$, $1 le i,j le n$), then the Perron-Frobenius theorem asserts that the spectral radius $rho(A)$ is an eigenvalue of $A$. If $tilde{A}$ is a principal submatrix of $A$, then $rho(tilde{A}) le rho(A)$ (see, e.g., Corollary 8.1.20 of Matrix Analysis, $2^text{nd}$ edition, by Horn and Johnson).
- More recently, the following result was established: let $p$ be a monic polynomial of degree $n$ with roots $lambda_1,dots,lambda_n$ (including multiplicities) and critical points $mu_1,dots,mu_{n-1}$ (including multiplicities). Let $H$ be a complex Hadamard matrix (e.g., $H$ could be the discrete Fourier transform matrix), $D=text{diag}(lambda_1,dots,lambda_n)$, and $A=HDH^{-1}$. If $A_{(i)}$ denotes the $i$th principal submatrix of $A$, then the characteristic polynomial of $A_{(i)}$ is $p'(t)/n$. Consequently, the eigenvalues of $A_{(i)}$ are $mu_1,dots,mu_{n-1}$ (this result is implied by Theorem 5.12 in Hoover et al. [MR3834205; On the realizability of the critical points of a realizable list. Linear Algebra Appl. 555 (2018), 301–313]).
edited Dec 14 '18 at 23:08
answered Dec 14 '18 at 21:37
Pietro PaparellaPietro Paparella
1,494615
1,494615
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2763941%2fare-there-theorems-which-relate-the-eigenvalues-of-matrices-and-sub-matrices%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
you want Horn and Johnson, mentioned at the other question. It is not Hamiltonian matrices involved, it is Hermitian. It is always possible that someone has defined something called Hamiltonian matrix, but news to me.
$endgroup$
– Will Jagy
May 2 '18 at 20:34
$begingroup$
Sorry it's been a long day. Do you have an idea of which section I should look in? I found nothing non-obvious in the eigenvalue section of the text.
$endgroup$
– AzJ
May 2 '18 at 20:48
1
$begingroup$
I don't really know, and perhaps you should get some sleep. user1551 from the other question would know references, but i don't know whether he is awake, i.e. what time zone he is in.
$endgroup$
– Will Jagy
May 2 '18 at 20:57