SYNTAX ERROR “)” ON DATE RANGE
I'm trying to segregate records by month name for the first three months of the year. Everything with a date range of 1/1/19
through 1/31/19
, should return JAN
, for example.
I'm getting syntax errors of a missing parenthesis. Here's what I wrote:
IF(AND(Application__c.CreatedDate>=(2019,1,19),Application__c.CreatedDate<=(2019,1,31)),"JAN",IF(AND(Application__c.CreatedDate<=(2019,2,1),Application__c.CreatedDate<=(2019,2,18)),"FEB",IF(AND(Application__c.CreatedDate>=(2019,3,1),Application__c.CreatedDate<=(2019,3,31)),"MAR","")))
formula syntax
New contributor
add a comment |
I'm trying to segregate records by month name for the first three months of the year. Everything with a date range of 1/1/19
through 1/31/19
, should return JAN
, for example.
I'm getting syntax errors of a missing parenthesis. Here's what I wrote:
IF(AND(Application__c.CreatedDate>=(2019,1,19),Application__c.CreatedDate<=(2019,1,31)),"JAN",IF(AND(Application__c.CreatedDate<=(2019,2,1),Application__c.CreatedDate<=(2019,2,18)),"FEB",IF(AND(Application__c.CreatedDate>=(2019,3,1),Application__c.CreatedDate<=(2019,3,31)),"MAR","")))
formula syntax
New contributor
add a comment |
I'm trying to segregate records by month name for the first three months of the year. Everything with a date range of 1/1/19
through 1/31/19
, should return JAN
, for example.
I'm getting syntax errors of a missing parenthesis. Here's what I wrote:
IF(AND(Application__c.CreatedDate>=(2019,1,19),Application__c.CreatedDate<=(2019,1,31)),"JAN",IF(AND(Application__c.CreatedDate<=(2019,2,1),Application__c.CreatedDate<=(2019,2,18)),"FEB",IF(AND(Application__c.CreatedDate>=(2019,3,1),Application__c.CreatedDate<=(2019,3,31)),"MAR","")))
formula syntax
New contributor
I'm trying to segregate records by month name for the first three months of the year. Everything with a date range of 1/1/19
through 1/31/19
, should return JAN
, for example.
I'm getting syntax errors of a missing parenthesis. Here's what I wrote:
IF(AND(Application__c.CreatedDate>=(2019,1,19),Application__c.CreatedDate<=(2019,1,31)),"JAN",IF(AND(Application__c.CreatedDate<=(2019,2,1),Application__c.CreatedDate<=(2019,2,18)),"FEB",IF(AND(Application__c.CreatedDate>=(2019,3,1),Application__c.CreatedDate<=(2019,3,31)),"MAR","")))
formula syntax
formula syntax
New contributor
New contributor
edited yesterday
battery.cord
6,94851745
6,94851745
New contributor
asked yesterday
user65727user65727
61
61
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New contributor
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2 Answers
2
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oldest
votes
Use a CASE
function. Its much easier to write. Also, it will avoid issue in leap year.
CASE(MONTH(PO_Received_Date__c),
1, "January",
2, "February",
3, "March",
4, "April",
5, "May",
6, "June",
7, "July",
8, "August",
9, "September",
10, "October",
11, "November",
12, "December",
"None")
Thank you. These are helpful comments. Now I receive an incorrect parameter message: Warning Incorrect parameter type for function 'MONTH()'. Expected Date, received Object
– user65727
yesterday
1
the variable that you are using in Month Function is not a date
– m Peixoto
yesterday
add a comment |
Application__c.CreatedDate>=(2019,3,1)
(2019,3,1)
isn't a valid date format. In formulas, to create dates, you need to use the DATE(year,month,day)
. You can fix your code by adding DATE
to your date values.
Application__c.CreatedDate >= DATE(2019, 3 ,1)
Issues with your code aside, it makes much more sense to use CASE
on the MONTH
of the date field instead.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use a CASE
function. Its much easier to write. Also, it will avoid issue in leap year.
CASE(MONTH(PO_Received_Date__c),
1, "January",
2, "February",
3, "March",
4, "April",
5, "May",
6, "June",
7, "July",
8, "August",
9, "September",
10, "October",
11, "November",
12, "December",
"None")
Thank you. These are helpful comments. Now I receive an incorrect parameter message: Warning Incorrect parameter type for function 'MONTH()'. Expected Date, received Object
– user65727
yesterday
1
the variable that you are using in Month Function is not a date
– m Peixoto
yesterday
add a comment |
Use a CASE
function. Its much easier to write. Also, it will avoid issue in leap year.
CASE(MONTH(PO_Received_Date__c),
1, "January",
2, "February",
3, "March",
4, "April",
5, "May",
6, "June",
7, "July",
8, "August",
9, "September",
10, "October",
11, "November",
12, "December",
"None")
Thank you. These are helpful comments. Now I receive an incorrect parameter message: Warning Incorrect parameter type for function 'MONTH()'. Expected Date, received Object
– user65727
yesterday
1
the variable that you are using in Month Function is not a date
– m Peixoto
yesterday
add a comment |
Use a CASE
function. Its much easier to write. Also, it will avoid issue in leap year.
CASE(MONTH(PO_Received_Date__c),
1, "January",
2, "February",
3, "March",
4, "April",
5, "May",
6, "June",
7, "July",
8, "August",
9, "September",
10, "October",
11, "November",
12, "December",
"None")
Use a CASE
function. Its much easier to write. Also, it will avoid issue in leap year.
CASE(MONTH(PO_Received_Date__c),
1, "January",
2, "February",
3, "March",
4, "April",
5, "May",
6, "June",
7, "July",
8, "August",
9, "September",
10, "October",
11, "November",
12, "December",
"None")
edited yesterday
answered yesterday
m Peixotom Peixoto
578316
578316
Thank you. These are helpful comments. Now I receive an incorrect parameter message: Warning Incorrect parameter type for function 'MONTH()'. Expected Date, received Object
– user65727
yesterday
1
the variable that you are using in Month Function is not a date
– m Peixoto
yesterday
add a comment |
Thank you. These are helpful comments. Now I receive an incorrect parameter message: Warning Incorrect parameter type for function 'MONTH()'. Expected Date, received Object
– user65727
yesterday
1
the variable that you are using in Month Function is not a date
– m Peixoto
yesterday
Thank you. These are helpful comments. Now I receive an incorrect parameter message: Warning Incorrect parameter type for function 'MONTH()'. Expected Date, received Object
– user65727
yesterday
Thank you. These are helpful comments. Now I receive an incorrect parameter message: Warning Incorrect parameter type for function 'MONTH()'. Expected Date, received Object
– user65727
yesterday
1
1
the variable that you are using in Month Function is not a date
– m Peixoto
yesterday
the variable that you are using in Month Function is not a date
– m Peixoto
yesterday
add a comment |
Application__c.CreatedDate>=(2019,3,1)
(2019,3,1)
isn't a valid date format. In formulas, to create dates, you need to use the DATE(year,month,day)
. You can fix your code by adding DATE
to your date values.
Application__c.CreatedDate >= DATE(2019, 3 ,1)
Issues with your code aside, it makes much more sense to use CASE
on the MONTH
of the date field instead.
add a comment |
Application__c.CreatedDate>=(2019,3,1)
(2019,3,1)
isn't a valid date format. In formulas, to create dates, you need to use the DATE(year,month,day)
. You can fix your code by adding DATE
to your date values.
Application__c.CreatedDate >= DATE(2019, 3 ,1)
Issues with your code aside, it makes much more sense to use CASE
on the MONTH
of the date field instead.
add a comment |
Application__c.CreatedDate>=(2019,3,1)
(2019,3,1)
isn't a valid date format. In formulas, to create dates, you need to use the DATE(year,month,day)
. You can fix your code by adding DATE
to your date values.
Application__c.CreatedDate >= DATE(2019, 3 ,1)
Issues with your code aside, it makes much more sense to use CASE
on the MONTH
of the date field instead.
Application__c.CreatedDate>=(2019,3,1)
(2019,3,1)
isn't a valid date format. In formulas, to create dates, you need to use the DATE(year,month,day)
. You can fix your code by adding DATE
to your date values.
Application__c.CreatedDate >= DATE(2019, 3 ,1)
Issues with your code aside, it makes much more sense to use CASE
on the MONTH
of the date field instead.
answered yesterday
battery.cordbattery.cord
6,94851745
6,94851745
add a comment |
add a comment |
user65727 is a new contributor. Be nice, and check out our Code of Conduct.
user65727 is a new contributor. Be nice, and check out our Code of Conduct.
user65727 is a new contributor. Be nice, and check out our Code of Conduct.
user65727 is a new contributor. Be nice, and check out our Code of Conduct.
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