How do I use the three given answers to find the other 2 answers they are asking for?
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I haven't seen a problem like this ever and I have no idea how to even go about solving it.
calculus
edited Nov 14 at 21:40
Bernard
115k637107
asked Nov 14 at 21:35
CodeGuy7153
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I haven't seen a problem like this ever and I have no idea how to even go about solving it.
calculus
edited Nov 14 at 21:40
Bernard
115k637107
asked Nov 14 at 21:35
CodeGuy7153
11
If you integrate from $a$ to $c$ isn't that the same as adding the integrals from $a$ to $b$ and from $b$ to $c$
– M. Nestor
Nov 14 at 21:37
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up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
Image of the problem
I haven't seen a problem like this ever and I have no idea how to even go about solving it.
calculus
edited Nov 14 at 21:40
Bernard
115k637107
asked Nov 14 at 21:35
CodeGuy7153
11
Image of the problem
I haven't seen a problem like this ever and I have no idea how to even go about solving it.
calculus
calculus
edited Nov 14 at 21:40
Bernard
115k637107
asked Nov 14 at 21:35
CodeGuy7153
11
edited Nov 14 at 21:40
Bernard
115k637107
asked Nov 14 at 21:35
CodeGuy7153
11
edited Nov 14 at 21:40
Bernard
115k637107
edited Nov 14 at 21:40
Bernard
115k637107
edited Nov 14 at 21:40
Bernard
115k637107
115k637107
asked Nov 14 at 21:35
CodeGuy7153
11
asked Nov 14 at 21:35
CodeGuy7153
11
asked Nov 14 at 21:35
CodeGuy7153
11
11
If you integrate from $a$ to $c$ isn't that the same as adding the integrals from $a$ to $b$ and from $b$ to $c$
– M. Nestor
Nov 14 at 21:37
add a comment |
If you integrate from $a$ to $c$ isn't that the same as adding the integrals from $a$ to $b$ and from $b$ to $c$
– M. Nestor
Nov 14 at 21:37
If you integrate from $a$ to $c$ isn't that the same as adding the integrals from $a$ to $b$ and from $b$ to $c$
– M. Nestor
Nov 14 at 21:37
If you integrate from $a$ to $c$ isn't that the same as adding the integrals from $a$ to $b$ and from $b$ to $c$
– M. Nestor
Nov 14 at 21:37
add a comment |
2 Answers
2
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You're given three integrals:
begin{align}
int_4^{10} f(x) dx &= 8 \
int_4^6 f(x) dx &= 18 \
int_8^{10} f(x) dx &= 3 \
end{align}
The first integral that is asked, asks for the domain $[6, 8]$. Notice that the second and third domain are over the domains $[4, 6]$ and $[8, 10]$. Comparing this with the domain the first integral is over, we see that the first integral covers the domains of the second and third as well. We can write:
$$ int_4^{10} f(x)dx = int_4^6 f(x)dx + int_6^8 f(x)dx + int_8^{10} f(x)dx $$
Filling in the known values:
$$ 8 = 18 + int_6^8 f(x)dx + 3 $$
Solving we find $int_6^8 f(x)dx = -13$. Using a similar method you should be able to solve the second question yourself.
answered Nov 14 at 21:45
Wavy
235
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up vote
0
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The key is the formula $$int _a^b = int _a^c + int _c ^b$$
You have enough information to find the answer.
You may sketch a graph to help you and do not worry if some integrals have negative values.
answered Nov 14 at 21:54
Mohammad Riazi-Kermani
40.2k41958
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
You're given three integrals:
begin{align}
int_4^{10} f(x) dx &= 8 \
int_4^6 f(x) dx &= 18 \
int_8^{10} f(x) dx &= 3 \
end{align}
The first integral that is asked, asks for the domain $[6, 8]$. Notice that the second and third domain are over the domains $[4, 6]$ and $[8, 10]$. Comparing this with the domain the first integral is over, we see that the first integral covers the domains of the second and third as well. We can write:
$$ int_4^{10} f(x)dx = int_4^6 f(x)dx + int_6^8 f(x)dx + int_8^{10} f(x)dx $$
Filling in the known values:
$$ 8 = 18 + int_6^8 f(x)dx + 3 $$
Solving we find $int_6^8 f(x)dx = -13$. Using a similar method you should be able to solve the second question yourself.
answered Nov 14 at 21:45
Wavy
235
add a comment |
up vote
0
down vote
accepted
You're given three integrals:
begin{align}
int_4^{10} f(x) dx &= 8 \
int_4^6 f(x) dx &= 18 \
int_8^{10} f(x) dx &= 3 \
end{align}
The first integral that is asked, asks for the domain $[6, 8]$. Notice that the second and third domain are over the domains $[4, 6]$ and $[8, 10]$. Comparing this with the domain the first integral is over, we see that the first integral covers the domains of the second and third as well. We can write:
$$ int_4^{10} f(x)dx = int_4^6 f(x)dx + int_6^8 f(x)dx + int_8^{10} f(x)dx $$
Filling in the known values:
$$ 8 = 18 + int_6^8 f(x)dx + 3 $$
Solving we find $int_6^8 f(x)dx = -13$. Using a similar method you should be able to solve the second question yourself.
answered Nov 14 at 21:45
Wavy
235
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
You're given three integrals:
begin{align}
int_4^{10} f(x) dx &= 8 \
int_4^6 f(x) dx &= 18 \
int_8^{10} f(x) dx &= 3 \
end{align}
The first integral that is asked, asks for the domain $[6, 8]$. Notice that the second and third domain are over the domains $[4, 6]$ and $[8, 10]$. Comparing this with the domain the first integral is over, we see that the first integral covers the domains of the second and third as well. We can write:
$$ int_4^{10} f(x)dx = int_4^6 f(x)dx + int_6^8 f(x)dx + int_8^{10} f(x)dx $$
Filling in the known values:
$$ 8 = 18 + int_6^8 f(x)dx + 3 $$
Solving we find $int_6^8 f(x)dx = -13$. Using a similar method you should be able to solve the second question yourself.
answered Nov 14 at 21:45
Wavy
235
You're given three integrals:
begin{align}
int_4^{10} f(x) dx &= 8 \
int_4^6 f(x) dx &= 18 \
int_8^{10} f(x) dx &= 3 \
end{align}
The first integral that is asked, asks for the domain $[6, 8]$. Notice that the second and third domain are over the domains $[4, 6]$ and $[8, 10]$. Comparing this with the domain the first integral is over, we see that the first integral covers the domains of the second and third as well. We can write:
$$ int_4^{10} f(x)dx = int_4^6 f(x)dx + int_6^8 f(x)dx + int_8^{10} f(x)dx $$
Filling in the known values:
$$ 8 = 18 + int_6^8 f(x)dx + 3 $$
Solving we find $int_6^8 f(x)dx = -13$. Using a similar method you should be able to solve the second question yourself.
answered Nov 14 at 21:45
Wavy
235
answered Nov 14 at 21:45
Wavy
235
answered Nov 14 at 21:45
Wavy
235
answered Nov 14 at 21:45
Wavy
235
235
add a comment |
add a comment |
up vote
0
down vote
The key is the formula $$int _a^b = int _a^c + int _c ^b$$
You have enough information to find the answer.
You may sketch a graph to help you and do not worry if some integrals have negative values.
answered Nov 14 at 21:54
Mohammad Riazi-Kermani
40.2k41958
add a comment |
up vote
0
down vote
The key is the formula $$int _a^b = int _a^c + int _c ^b$$
You have enough information to find the answer.
You may sketch a graph to help you and do not worry if some integrals have negative values.
answered Nov 14 at 21:54
Mohammad Riazi-Kermani
40.2k41958
add a comment |
up vote
0
down vote
up vote
0
down vote
The key is the formula $$int _a^b = int _a^c + int _c ^b$$
You have enough information to find the answer.
You may sketch a graph to help you and do not worry if some integrals have negative values.
answered Nov 14 at 21:54
Mohammad Riazi-Kermani
40.2k41958
The key is the formula $$int _a^b = int _a^c + int _c ^b$$
You have enough information to find the answer.
You may sketch a graph to help you and do not worry if some integrals have negative values.
answered Nov 14 at 21:54
Mohammad Riazi-Kermani
40.2k41958
answered Nov 14 at 21:54
Mohammad Riazi-Kermani
40.2k41958
answered Nov 14 at 21:54
Mohammad Riazi-Kermani
40.2k41958
answered Nov 14 at 21:54
Mohammad Riazi-Kermani
40.2k41958
40.2k41958
add a comment |
add a comment |
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If you integrate from $a$ to $c$ isn't that the same as adding the integrals from $a$ to $b$ and from $b$ to $c$
– M. Nestor
Nov 14 at 21:37