Changing directory in script doesn't change directory — why?
I've seen this answer since searching for this, but initially I wrote this script:
for i in `seq 1 $1`;
do cd ../;
done;
It doesn't change directory. Why is this, running as
./updir.sh 5
bash bash-scripting
add a comment |
I've seen this answer since searching for this, but initially I wrote this script:
for i in `seq 1 $1`;
do cd ../;
done;
It doesn't change directory. Why is this, running as
./updir.sh 5
bash bash-scripting
Thanks guys. I've gone with the function solution with:function updir() { a=""; for i in
seq 1 $1; do a=$a"../"; done; cd $a; }
. This allows use ofcd -
as expected.
– David Boshton
Dec 6 at 17:39
add a comment |
I've seen this answer since searching for this, but initially I wrote this script:
for i in `seq 1 $1`;
do cd ../;
done;
It doesn't change directory. Why is this, running as
./updir.sh 5
bash bash-scripting
I've seen this answer since searching for this, but initially I wrote this script:
for i in `seq 1 $1`;
do cd ../;
done;
It doesn't change directory. Why is this, running as
./updir.sh 5
bash bash-scripting
bash bash-scripting
edited Dec 6 at 16:34
asked Dec 6 at 16:15
David Boshton
1104
1104
Thanks guys. I've gone with the function solution with:function updir() { a=""; for i in
seq 1 $1; do a=$a"../"; done; cd $a; }
. This allows use ofcd -
as expected.
– David Boshton
Dec 6 at 17:39
add a comment |
Thanks guys. I've gone with the function solution with:function updir() { a=""; for i in
seq 1 $1; do a=$a"../"; done; cd $a; }
. This allows use ofcd -
as expected.
– David Boshton
Dec 6 at 17:39
Thanks guys. I've gone with the function solution with:
function updir() { a=""; for i in
seq 1 $1; do a=$a"../"; done; cd $a; }
. This allows use of cd -
as expected.– David Boshton
Dec 6 at 17:39
Thanks guys. I've gone with the function solution with:
function updir() { a=""; for i in
seq 1 $1; do a=$a"../"; done; cd $a; }
. This allows use of cd -
as expected.– David Boshton
Dec 6 at 17:39
add a comment |
2 Answers
2
active
oldest
votes
Running a script as you show creates a copied environment in a sub-shell, and any changes you make, such as setting directories or environment variables, affect only this sub-shell environment, not the calling shell.
In order to make changes to the current shell from a script, you must run the script within the current shell using the source
or .
command:
. ./updir.sh 5
You can make this automatic with an alias:
alias updir='. ./updir.sh'
Alternatively, you can use a function instead of a script:
updir()
{ for i in `seq 1 $1`;
do cd ../;
done
}
add a comment |
Because scripts are run in a subshell, which keeps track of the current working directory separately. The simplest solution is to use a function:
function updir() {
for i in $(seq 1 $1); do
cd ..
done
}
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 at 16:33
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "3"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fsuperuser.com%2fquestions%2f1381398%2fchanging-directory-in-script-doesnt-change-directory-why%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Running a script as you show creates a copied environment in a sub-shell, and any changes you make, such as setting directories or environment variables, affect only this sub-shell environment, not the calling shell.
In order to make changes to the current shell from a script, you must run the script within the current shell using the source
or .
command:
. ./updir.sh 5
You can make this automatic with an alias:
alias updir='. ./updir.sh'
Alternatively, you can use a function instead of a script:
updir()
{ for i in `seq 1 $1`;
do cd ../;
done
}
add a comment |
Running a script as you show creates a copied environment in a sub-shell, and any changes you make, such as setting directories or environment variables, affect only this sub-shell environment, not the calling shell.
In order to make changes to the current shell from a script, you must run the script within the current shell using the source
or .
command:
. ./updir.sh 5
You can make this automatic with an alias:
alias updir='. ./updir.sh'
Alternatively, you can use a function instead of a script:
updir()
{ for i in `seq 1 $1`;
do cd ../;
done
}
add a comment |
Running a script as you show creates a copied environment in a sub-shell, and any changes you make, such as setting directories or environment variables, affect only this sub-shell environment, not the calling shell.
In order to make changes to the current shell from a script, you must run the script within the current shell using the source
or .
command:
. ./updir.sh 5
You can make this automatic with an alias:
alias updir='. ./updir.sh'
Alternatively, you can use a function instead of a script:
updir()
{ for i in `seq 1 $1`;
do cd ../;
done
}
Running a script as you show creates a copied environment in a sub-shell, and any changes you make, such as setting directories or environment variables, affect only this sub-shell environment, not the calling shell.
In order to make changes to the current shell from a script, you must run the script within the current shell using the source
or .
command:
. ./updir.sh 5
You can make this automatic with an alias:
alias updir='. ./updir.sh'
Alternatively, you can use a function instead of a script:
updir()
{ for i in `seq 1 $1`;
do cd ../;
done
}
answered Dec 6 at 16:30
AFH
13.9k31938
13.9k31938
add a comment |
add a comment |
Because scripts are run in a subshell, which keeps track of the current working directory separately. The simplest solution is to use a function:
function updir() {
for i in $(seq 1 $1); do
cd ..
done
}
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 at 16:33
add a comment |
Because scripts are run in a subshell, which keeps track of the current working directory separately. The simplest solution is to use a function:
function updir() {
for i in $(seq 1 $1); do
cd ..
done
}
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 at 16:33
add a comment |
Because scripts are run in a subshell, which keeps track of the current working directory separately. The simplest solution is to use a function:
function updir() {
for i in $(seq 1 $1); do
cd ..
done
}
Because scripts are run in a subshell, which keeps track of the current working directory separately. The simplest solution is to use a function:
function updir() {
for i in $(seq 1 $1); do
cd ..
done
}
edited Dec 6 at 16:35
Kamil Maciorowski
24k155176
24k155176
answered Dec 6 at 16:27
Program man
1211
1211
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 at 16:33
add a comment |
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 at 16:33
1
1
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 at 16:33
Sorry, my answer crossed with yours, but I am leaving mine because I gave some extra details.
– AFH
Dec 6 at 16:33
add a comment |
Thanks for contributing an answer to Super User!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fsuperuser.com%2fquestions%2f1381398%2fchanging-directory-in-script-doesnt-change-directory-why%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Thanks guys. I've gone with the function solution with:
function updir() { a=""; for i in
seq 1 $1; do a=$a"../"; done; cd $a; }
. This allows use ofcd -
as expected.– David Boshton
Dec 6 at 17:39