Replace all words that start with @ by another word
0
So, basicly, I need to edit something like this:
@john TEST TEST TEST
@andrew EXAMPLE EXAMPLE
@geady JK JK JK
and I need to replace all of them to get like this:
@replaced TEST TEST TEST
@replaced EXAMPLE EXAMPLE
@replaced JK JK JK
How can I achieve this with notepad++? Thanks in advance!
notepad++ regex
edited Dec 6 at 15:14
Hashim
3,01063056
asked Dec 6 at 13:46
pedroribeiro98
1
add a comment |
0
So, basicly, I need to edit something like this:
@john TEST TEST TEST
@andrew EXAMPLE EXAMPLE
@geady JK JK JK
and I need to replace all of them to get like this:
@replaced TEST TEST TEST
@replaced EXAMPLE EXAMPLE
@replaced JK JK JK
How can I achieve this with notepad++? Thanks in advance!
notepad++ regex
edited Dec 6 at 15:14
Hashim
3,01063056
asked Dec 6 at 13:46
pedroribeiro98
1
add a comment |
0
0
0
So, basicly, I need to edit something like this:
@john TEST TEST TEST
@andrew EXAMPLE EXAMPLE
@geady JK JK JK
and I need to replace all of them to get like this:
@replaced TEST TEST TEST
@replaced EXAMPLE EXAMPLE
@replaced JK JK JK
How can I achieve this with notepad++? Thanks in advance!
notepad++ regex
edited Dec 6 at 15:14
Hashim
3,01063056
asked Dec 6 at 13:46
pedroribeiro98
1
So, basicly, I need to edit something like this:
@john TEST TEST TEST
@andrew EXAMPLE EXAMPLE
@geady JK JK JK
and I need to replace all of them to get like this:
@replaced TEST TEST TEST
@replaced EXAMPLE EXAMPLE
@replaced JK JK JK
How can I achieve this with notepad++? Thanks in advance!
notepad++ regex
notepad++ regex
edited Dec 6 at 15:14
Hashim
3,01063056
asked Dec 6 at 13:46
pedroribeiro98
1
edited Dec 6 at 15:14
Hashim
3,01063056
asked Dec 6 at 13:46
pedroribeiro98
1
edited Dec 6 at 15:14
Hashim
3,01063056
edited Dec 6 at 15:14
Hashim
3,01063056
edited Dec 6 at 15:14
Hashim
3,01063056
3,01063056
asked Dec 6 at 13:46
pedroribeiro98
1
asked Dec 6 at 13:46
pedroribeiro98
1
asked Dec 6 at 13:46
pedroribeiro98
1
1
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
0
Ctrl+H
- Find what:
@w+
- Replace with:
@replaced
- check Wrap around
- check Regular expression
- Replace all
Explanation:
@ # literally
w+ # 1 or more word character (i.e. [a-zA-Z0-9_])
You may use S+ if you want to match any character that is not a space
Result for given example:
@replaced TEST TEST TEST
@replaced EXAMPLE EXAMPLE
@replaced JK JK JK
answered Dec 6 at 14:04
Toto
3,47091226
Thanks for your answer, although it didn't worked 100% for me... I'm using: Find what: @S+ Replace with: @replacedL$0 And I get: @replaced@john TEST TEST TEST
– pedroribeiro98
Dec 6 at 14:27
@pedroribeiro98: Could you show some cases that don't work?
– Toto
Dec 6 at 14:28
I just edit my comment above @Toto. Thanks for the help
– pedroribeiro98
Dec 6 at 14:29
@pedroribeiro98: Please, edit your question and add some test cases with expected result.
– Toto
Dec 6 at 14:39
I think it's clear, I want to replace the word that starts with @, so instead of getting [@john] , I get [@replaced] , but with your solution, I'm getting [@replaced@john]
– pedroribeiro98
Dec 6 at 14:43
|
show 2 more comments
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1 Answer
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oldest
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
0
Ctrl+H
- Find what:
@w+
- Replace with:
@replaced
- check Wrap around
- check Regular expression
- Replace all
Explanation:
@ # literally
w+ # 1 or more word character (i.e. [a-zA-Z0-9_])
You may use S+ if you want to match any character that is not a space
Result for given example:
@replaced TEST TEST TEST
@replaced EXAMPLE EXAMPLE
@replaced JK JK JK
answered Dec 6 at 14:04
Toto
3,47091226
Thanks for your answer, although it didn't worked 100% for me... I'm using: Find what: @S+ Replace with: @replacedL$0 And I get: @replaced@john TEST TEST TEST
– pedroribeiro98
Dec 6 at 14:27
@pedroribeiro98: Could you show some cases that don't work?
– Toto
Dec 6 at 14:28
I just edit my comment above @Toto. Thanks for the help
– pedroribeiro98
Dec 6 at 14:29
@pedroribeiro98: Please, edit your question and add some test cases with expected result.
– Toto
Dec 6 at 14:39
I think it's clear, I want to replace the word that starts with @, so instead of getting [@john] , I get [@replaced] , but with your solution, I'm getting [@replaced@john]
– pedroribeiro98
Dec 6 at 14:43
|
show 2 more comments
0
Ctrl+H
- Find what:
@w+
- Replace with:
@replaced
- check Wrap around
- check Regular expression
- Replace all
Explanation:
@ # literally
w+ # 1 or more word character (i.e. [a-zA-Z0-9_])
You may use S+ if you want to match any character that is not a space
Result for given example:
@replaced TEST TEST TEST
@replaced EXAMPLE EXAMPLE
@replaced JK JK JK
answered Dec 6 at 14:04
Toto
3,47091226
Thanks for your answer, although it didn't worked 100% for me... I'm using: Find what: @S+ Replace with: @replacedL$0 And I get: @replaced@john TEST TEST TEST
– pedroribeiro98
Dec 6 at 14:27
@pedroribeiro98: Could you show some cases that don't work?
– Toto
Dec 6 at 14:28
I just edit my comment above @Toto. Thanks for the help
– pedroribeiro98
Dec 6 at 14:29
@pedroribeiro98: Please, edit your question and add some test cases with expected result.
– Toto
Dec 6 at 14:39
I think it's clear, I want to replace the word that starts with @, so instead of getting [@john] , I get [@replaced] , but with your solution, I'm getting [@replaced@john]
– pedroribeiro98
Dec 6 at 14:43
|
show 2 more comments
0
0
0
Ctrl+H
- Find what:
@w+
- Replace with:
@replaced
- check Wrap around
- check Regular expression
- Replace all
Explanation:
@ # literally
w+ # 1 or more word character (i.e. [a-zA-Z0-9_])
You may use S+ if you want to match any character that is not a space
Result for given example:
@replaced TEST TEST TEST
@replaced EXAMPLE EXAMPLE
@replaced JK JK JK
answered Dec 6 at 14:04
Toto
3,47091226
Ctrl+H
- Find what:
@w+
- Replace with:
@replaced
- check Wrap around
- check Regular expression
- Replace all
Explanation:
@ # literally
w+ # 1 or more word character (i.e. [a-zA-Z0-9_])
You may use S+ if you want to match any character that is not a space
Result for given example:
@replaced TEST TEST TEST
@replaced EXAMPLE EXAMPLE
@replaced JK JK JK
answered Dec 6 at 14:04
Toto
3,47091226
edited Dec 6 at 15:06
answered Dec 6 at 14:04
Toto
3,47091226
answered Dec 6 at 14:04
Toto
3,47091226
answered Dec 6 at 14:04
Toto
3,47091226
3,47091226
Thanks for your answer, although it didn't worked 100% for me... I'm using: Find what: @S+ Replace with: @replacedL$0 And I get: @replaced@john TEST TEST TEST
– pedroribeiro98
Dec 6 at 14:27
@pedroribeiro98: Could you show some cases that don't work?
– Toto
Dec 6 at 14:28
I just edit my comment above @Toto. Thanks for the help
– pedroribeiro98
Dec 6 at 14:29
@pedroribeiro98: Please, edit your question and add some test cases with expected result.
– Toto
Dec 6 at 14:39
I think it's clear, I want to replace the word that starts with @, so instead of getting [@john] , I get [@replaced] , but with your solution, I'm getting [@replaced@john]
– pedroribeiro98
Dec 6 at 14:43
|
show 2 more comments
Thanks for your answer, although it didn't worked 100% for me... I'm using: Find what: @S+ Replace with: @replacedL$0 And I get: @replaced@john TEST TEST TEST
– pedroribeiro98
Dec 6 at 14:27
@pedroribeiro98: Could you show some cases that don't work?
– Toto
Dec 6 at 14:28
I just edit my comment above @Toto. Thanks for the help
– pedroribeiro98
Dec 6 at 14:29
@pedroribeiro98: Please, edit your question and add some test cases with expected result.
– Toto
Dec 6 at 14:39
I think it's clear, I want to replace the word that starts with @, so instead of getting [@john] , I get [@replaced] , but with your solution, I'm getting [@replaced@john]
– pedroribeiro98
Dec 6 at 14:43
Thanks for your answer, although it didn't worked 100% for me... I'm using: Find what: @S+ Replace with: @replacedL$0 And I get: @replaced@john TEST TEST TEST
– pedroribeiro98
Dec 6 at 14:27
Thanks for your answer, although it didn't worked 100% for me... I'm using: Find what: @S+ Replace with: @replacedL$0 And I get: @replaced@john TEST TEST TEST
– pedroribeiro98
Dec 6 at 14:27
@pedroribeiro98: Could you show some cases that don't work?
– Toto
Dec 6 at 14:28
@pedroribeiro98: Could you show some cases that don't work?
– Toto
Dec 6 at 14:28
I just edit my comment above @Toto. Thanks for the help
– pedroribeiro98
Dec 6 at 14:29
I just edit my comment above @Toto. Thanks for the help
– pedroribeiro98
Dec 6 at 14:29
@pedroribeiro98: Please, edit your question and add some test cases with expected result.
– Toto
Dec 6 at 14:39
@pedroribeiro98: Please, edit your question and add some test cases with expected result.
– Toto
Dec 6 at 14:39
I think it's clear, I want to replace the word that starts with @, so instead of getting [@john] , I get [@replaced] , but with your solution, I'm getting [@replaced@john]
– pedroribeiro98
Dec 6 at 14:43
I think it's clear, I want to replace the word that starts with @, so instead of getting [@john] , I get [@replaced] , but with your solution, I'm getting [@replaced@john]
– pedroribeiro98
Dec 6 at 14:43
|
show 2 more comments
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