Convert to Suzhou numerals











up vote
22
down vote

favorite
2












Suzhou numerals (蘇州碼子; also 花碼) are Chinese decimal numerals:



0 〇
1 〡 一
2 〢 二
3 〣 三
4 〤
5 〥
6 〦
7 〧
8 〨
9 〩


They pretty much work like Arabic numerals, except that when there are consecutive digits belonging to the set {1, 2, 3}, the digits alternate between vertical stroke notation {〡,〢,〣} and horizontal stroke notation {一,二,三} to avoid ambiguity. The first digit of such a consecutive group is always written with vertical stroke notation.



The task is to convert a positive integer into Suzhou numerals.



Test cases



1          〡
11 〡一
25 〢〥
50 〥〇
99 〩〩
111 〡一〡
511 〥〡一
2018 〢〇〡〨
123321 〡二〣三〢一
1234321 〡二〣〤〣二〡
9876543210 〩〨〧〦〥〤〣二〡〇


Shortest code in bytes wins.










share|improve this question
























  • I've been in Suzhou 3 times for longer period of time (quite a nice city) but didn't know about Suzhou numerals. You have my +1
    – Thomas Weller
    18 hours ago








  • 1




    @ThomasWeller For me it's the opposite: before writing this task I knew what the numerals were, but not that they were named "Suzhou numerals". In fact I've never heard them called this name (or any name at all). I've seen them in markets and on handwritten Chinese medicine prescriptions.
    – lastresort
    16 hours ago










  • Can you take input in the form of a char array?
    – Embodiment of Ignorance
    13 hours ago















up vote
22
down vote

favorite
2












Suzhou numerals (蘇州碼子; also 花碼) are Chinese decimal numerals:



0 〇
1 〡 一
2 〢 二
3 〣 三
4 〤
5 〥
6 〦
7 〧
8 〨
9 〩


They pretty much work like Arabic numerals, except that when there are consecutive digits belonging to the set {1, 2, 3}, the digits alternate between vertical stroke notation {〡,〢,〣} and horizontal stroke notation {一,二,三} to avoid ambiguity. The first digit of such a consecutive group is always written with vertical stroke notation.



The task is to convert a positive integer into Suzhou numerals.



Test cases



1          〡
11 〡一
25 〢〥
50 〥〇
99 〩〩
111 〡一〡
511 〥〡一
2018 〢〇〡〨
123321 〡二〣三〢一
1234321 〡二〣〤〣二〡
9876543210 〩〨〧〦〥〤〣二〡〇


Shortest code in bytes wins.










share|improve this question
























  • I've been in Suzhou 3 times for longer period of time (quite a nice city) but didn't know about Suzhou numerals. You have my +1
    – Thomas Weller
    18 hours ago








  • 1




    @ThomasWeller For me it's the opposite: before writing this task I knew what the numerals were, but not that they were named "Suzhou numerals". In fact I've never heard them called this name (or any name at all). I've seen them in markets and on handwritten Chinese medicine prescriptions.
    – lastresort
    16 hours ago










  • Can you take input in the form of a char array?
    – Embodiment of Ignorance
    13 hours ago













up vote
22
down vote

favorite
2









up vote
22
down vote

favorite
2






2





Suzhou numerals (蘇州碼子; also 花碼) are Chinese decimal numerals:



0 〇
1 〡 一
2 〢 二
3 〣 三
4 〤
5 〥
6 〦
7 〧
8 〨
9 〩


They pretty much work like Arabic numerals, except that when there are consecutive digits belonging to the set {1, 2, 3}, the digits alternate between vertical stroke notation {〡,〢,〣} and horizontal stroke notation {一,二,三} to avoid ambiguity. The first digit of such a consecutive group is always written with vertical stroke notation.



The task is to convert a positive integer into Suzhou numerals.



Test cases



1          〡
11 〡一
25 〢〥
50 〥〇
99 〩〩
111 〡一〡
511 〥〡一
2018 〢〇〡〨
123321 〡二〣三〢一
1234321 〡二〣〤〣二〡
9876543210 〩〨〧〦〥〤〣二〡〇


Shortest code in bytes wins.










share|improve this question















Suzhou numerals (蘇州碼子; also 花碼) are Chinese decimal numerals:



0 〇
1 〡 一
2 〢 二
3 〣 三
4 〤
5 〥
6 〦
7 〧
8 〨
9 〩


They pretty much work like Arabic numerals, except that when there are consecutive digits belonging to the set {1, 2, 3}, the digits alternate between vertical stroke notation {〡,〢,〣} and horizontal stroke notation {一,二,三} to avoid ambiguity. The first digit of such a consecutive group is always written with vertical stroke notation.



The task is to convert a positive integer into Suzhou numerals.



Test cases



1          〡
11 〡一
25 〢〥
50 〥〇
99 〩〩
111 〡一〡
511 〥〡一
2018 〢〇〡〨
123321 〡二〣三〢一
1234321 〡二〣〤〣二〡
9876543210 〩〨〧〦〥〤〣二〡〇


Shortest code in bytes wins.







code-golf number unicode






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share|improve this question




share|improve this question








edited yesterday









qwr

5,59952556




5,59952556










asked yesterday









lastresort

885313




885313












  • I've been in Suzhou 3 times for longer period of time (quite a nice city) but didn't know about Suzhou numerals. You have my +1
    – Thomas Weller
    18 hours ago








  • 1




    @ThomasWeller For me it's the opposite: before writing this task I knew what the numerals were, but not that they were named "Suzhou numerals". In fact I've never heard them called this name (or any name at all). I've seen them in markets and on handwritten Chinese medicine prescriptions.
    – lastresort
    16 hours ago










  • Can you take input in the form of a char array?
    – Embodiment of Ignorance
    13 hours ago


















  • I've been in Suzhou 3 times for longer period of time (quite a nice city) but didn't know about Suzhou numerals. You have my +1
    – Thomas Weller
    18 hours ago








  • 1




    @ThomasWeller For me it's the opposite: before writing this task I knew what the numerals were, but not that they were named "Suzhou numerals". In fact I've never heard them called this name (or any name at all). I've seen them in markets and on handwritten Chinese medicine prescriptions.
    – lastresort
    16 hours ago










  • Can you take input in the form of a char array?
    – Embodiment of Ignorance
    13 hours ago
















I've been in Suzhou 3 times for longer period of time (quite a nice city) but didn't know about Suzhou numerals. You have my +1
– Thomas Weller
18 hours ago






I've been in Suzhou 3 times for longer period of time (quite a nice city) but didn't know about Suzhou numerals. You have my +1
– Thomas Weller
18 hours ago






1




1




@ThomasWeller For me it's the opposite: before writing this task I knew what the numerals were, but not that they were named "Suzhou numerals". In fact I've never heard them called this name (or any name at all). I've seen them in markets and on handwritten Chinese medicine prescriptions.
– lastresort
16 hours ago




@ThomasWeller For me it's the opposite: before writing this task I knew what the numerals were, but not that they were named "Suzhou numerals". In fact I've never heard them called this name (or any name at all). I've seen them in markets and on handwritten Chinese medicine prescriptions.
– lastresort
16 hours ago












Can you take input in the form of a char array?
– Embodiment of Ignorance
13 hours ago




Can you take input in the form of a char array?
– Embodiment of Ignorance
13 hours ago










16 Answers
16






active

oldest

votes

















up vote
6
down vote














Retina, 46 bytes



/[1-3]{2}|./_T`d`〇〡-〩`^.
T`123`一二三


Try it online! Link includes test cases. Explanation:



/[1-3]{2}|./


Match either two digits 1-3 or any other digit.



_T`d`〇〡-〩`^.


Replace the first character of each match with its Suzhou.



T`123`一二三


Replace any remaining digits with horizontal Suzhou.



51 bytes in Retina 0.8.2:



M!`[1-3]{2}|.
mT`d`〇〡-〩`^.
T`¶123`_一二三


Try it online! Link includes test cases. Explanation:



M!`[1-3]{2}|.


Split the input into individual digits or pairs of digits if they are both 1-3.



mT`d`〇〡-〩`^.


Replace the first character of each line with its Suzhou.



T`¶123`_一二三


Join the lines back together and replace any remaining digits with horizontal Suzhou.






share|improve this answer




























    up vote
    5
    down vote













    JavaScript, 81 bytes





    s=>s.replace(/./g,c=>(p=14>>c&!p)|c>3?eval(`"\u302${c}"`):'〇一二三'[c],p=0)


    Try it online!



    Using 14>>c saves 3 bytes. Thanks to Arnauld.






    share|improve this answer























    • p=c>0&c<4&!p can be turned into p=14>>c&!p
      – Arnauld
      16 hours ago




















    up vote
    4
    down vote













    JavaScript (ES6),  95 89  88 bytes



    Saved 6 bytes thanks to @ShieruAsakoto



    Takes input as a string.





    s=>s.replace(i=/./g,c=>'三二一〇〡〢〣〤〥〦〧〨〩'[i=112>>i&c<4?3-c:+c+3])


    Try it online!






    share|improve this answer























    • 89 bytes
      – Shieru Asakoto
      yesterday












    • @ShieruAsakoto That's much better! Thanks a lot!
      – Arnauld
      yesterday


















    up vote
    3
    down vote














    Clean, 181 165 bytes



    All octal escapes can be replaced by the equivalent single-byte characters (and are counted as one byte each), but used for readability and because otherwise it breaks TIO and SE with invalid UTF-8.



    import StdEnv
    u=mapc={'343','200',c}
    ?s=((!!)["〇":s++u['244245246247250']])o digitToInt
    $=
    $[h:t]=[?(u['241242243'])h:if(h-'1'<'03')f$t]
    f=
    f[h:t]=[?["一","二","三"]h: $t]


    Try it online!



    An encoding-unaware compiler is both a blessing and a curse.






    share|improve this answer






























      up vote
      3
      down vote














      Java (JDK), 120 bytes





      s->{for(int i=0,p=0,c;i<s.length;)s[i]+=(p>0&p<4&(c=s[i++]-48)>0&c<4)?"A䷏乚䷖".charAt(c+(p=0)):(p=c)<1?12247:12272;}


      Try it online!



      Credits




      • -3 bytes thanks to Kevin Cruijssen






      share|improve this answer



















      • 1




        c=s[i]-48;if(p>0&p<4&c>0&c<4) can be if(p>0&p<4&(c=s[i]-48)>0&c<4), and then you can also drop the brackets around the loop. Also, else{p=c;s[i]+=c<1?12247:12272;} can be else s[i]+=(p=c)<1?12247:12272;
        – Kevin Cruijssen
        20 hours ago






      • 1




        @KevinCruijssen Thank you! I was still golfing this answer, but it helped me nonetheless ^^ Now I think I'm done golfing it.
        – Olivier Grégoire
        19 hours ago




















      up vote
      3
      down vote














      Perl 5 -pl -Mutf8, 53 46 bytes



      -7 bytes thanks to Grimy



      s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c


      Try it online!



      Explanation



      # Binary AND two consecutive digits 1-3 (ASCII 0x31-0x33)
      # or any other single digit (ASCII 0x30-0x39) with string "OS"
      # (ASCII 0x4F 0x53). This converts the first digit to 0x00-0x09
      # and the second digit, if present, to 0x11-0x13.
      s/[123]{2}|./OS&$&/ge;
      # Translate empty complemented searchlist (0x00-0x13) to
      # respective Unicode characters.
      y//〇〡-〰一二三/c





      share|improve this answer























      • -3 bytes with s/[123]K[123]/$&^$;/ge;y/--</一二三〇〡-〩/ (TIO)
        – Grimy
        16 hours ago












      • 49: s/[123]{2}/$&^v0.28/ge;y/--</一二三〇〡-〩/ (TIO). 48: s/[123]{2}/$&^"34"/ge;y/--</一二三〇〡-〩/ (requires using literal control characters instead of 34, idk how to do this on TIO)
        – Grimy
        16 hours ago












      • 46: s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c (TIO)
        – Grimy
        15 hours ago


















      up vote
      2
      down vote














      Perl 6 -p, 85 61 bytes



      -13 bytes thanks to Jo King





      s:g[(1|2|3)<((1|2|3)]=chr $/+57;tr/0..</〇〡..〩一二三/


      Try it online!






      share|improve this answer






























        up vote
        2
        down vote














        Red, 198 171 bytes



        func[n][s: charset"〡〢〣"forall n[n/1: either n/1 >#"0"[to-char 12272 + n/1][#"〇"]]parse
        n[any[[s change copy t s(pick"一二三"do(to-char t)- 12320)fail]| skip]]n]


        Try it online!






        share|improve this answer






























          up vote
          2
          down vote














          R, 138 bytes



          I'll bet there's an easier way to do this. Use gsub to get the alternating numeric positions.





          function(x,r=-48+~x)Reduce(paste0,ifelse(58<~gsub("[123]{2}","0a",x),"123"["一二三",r],'0-9'["〇〡-〩",r]))
          "~"=utf8ToInt
          "["=chartr


          Try it online!






          share|improve this answer






























            up vote
            2
            down vote














            Python 3, 102 bytes





            f=0
            for i in input():f=i in'123'and 9-f;print(end='〇一二三〤〥〦〧〨〩〡〢〣'[int(i)+f])


            Try it online!



            mypetlion reminded me of a trivial golf. -4 bytes.






            share|improve this answer






























              up vote
              1
              down vote














              Ruby -p, 71 bytes





              $_=gsub(/[1-3]K[1-3]/){|x|(x.ord+9).chr}.tr"0-<","〇〡-〩一二三"


              Try it online!






              share|improve this answer




























                up vote
                1
                down vote














                K (ngn/k), 67 bytes



                {,/(0N 3#"〇一二三〤〥〦〧〨〩〡〢〣")x+9*<x&x<4}@10


                Try it online!



                10 get list of decimal digits



                { }@ apply the following function



                x&x<4 boolean (0/1) list of where the argument is less than 4 and non-zero



                < scan with less-than. this turns runs of consecutive 1s into alternating 1s and 0s



                x+9* multiply by 9 and add x



                juxtaposition is indexing, so use this as indices in...



                0N 3#"〇一二三〤〥〦〧〨〩〡〢〣" the given string, split into a list of 3-byte strings. k is not unicode aware, so it sees only bytes



                ,/ concatenate






                share|improve this answer






























                  up vote
                  0
                  down vote













                  C#, 127 bytes



                  n=>Regex.Replace(n+"",@"[4-90]|[1-3]{1,2}",x=>"〇〡〢〣〤〥〦〧〨〩"[x.Value[0]-'0']+""+(x.Value.Length>1?"一二三"[x.Value[1]-'0'-1]+"":""))


                  Try it online!






                  share|improve this answer




























                    up vote
                    0
                    down vote














                    Jelly, 38 bytes



                    9Rż“øƓ“œ%“øƈ’;-25+⁽-EỌœị@DżD<4«Ɗ‘×¥ƊƊ


                    Try it online!






                    share|improve this answer




























                      up vote
                      0
                      down vote














                      Jelly, 35 bytes



                      9Ḷ;-26ż“/Ẉ8‘+⁽ȷc¤ṃ@ɓD_2ỊŒgÄFị"+⁽-FỌ


                      Try it online!






                      share|improve this answer




























                        up vote
                        0
                        down vote














                        Wolfram Language (Mathematica), 117 bytes



                        FromCharacterCode[12320+(IntegerDigits@#/. 0->-25//.MapIndexed[{a___,c=#2[[1]],c,b___}->{a,c,#,b}&,{0,140,9}+7648])]&


                        Try it online!



                        Note that on TIO this outputs the result in escaped form. In the normal Wolfram front end, it will look like this:picture of notebook interface






                        share|improve this answer





















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                          16 Answers
                          16






                          active

                          oldest

                          votes








                          16 Answers
                          16






                          active

                          oldest

                          votes









                          active

                          oldest

                          votes






                          active

                          oldest

                          votes








                          up vote
                          6
                          down vote














                          Retina, 46 bytes



                          /[1-3]{2}|./_T`d`〇〡-〩`^.
                          T`123`一二三


                          Try it online! Link includes test cases. Explanation:



                          /[1-3]{2}|./


                          Match either two digits 1-3 or any other digit.



                          _T`d`〇〡-〩`^.


                          Replace the first character of each match with its Suzhou.



                          T`123`一二三


                          Replace any remaining digits with horizontal Suzhou.



                          51 bytes in Retina 0.8.2:



                          M!`[1-3]{2}|.
                          mT`d`〇〡-〩`^.
                          T`¶123`_一二三


                          Try it online! Link includes test cases. Explanation:



                          M!`[1-3]{2}|.


                          Split the input into individual digits or pairs of digits if they are both 1-3.



                          mT`d`〇〡-〩`^.


                          Replace the first character of each line with its Suzhou.



                          T`¶123`_一二三


                          Join the lines back together and replace any remaining digits with horizontal Suzhou.






                          share|improve this answer

























                            up vote
                            6
                            down vote














                            Retina, 46 bytes



                            /[1-3]{2}|./_T`d`〇〡-〩`^.
                            T`123`一二三


                            Try it online! Link includes test cases. Explanation:



                            /[1-3]{2}|./


                            Match either two digits 1-3 or any other digit.



                            _T`d`〇〡-〩`^.


                            Replace the first character of each match with its Suzhou.



                            T`123`一二三


                            Replace any remaining digits with horizontal Suzhou.



                            51 bytes in Retina 0.8.2:



                            M!`[1-3]{2}|.
                            mT`d`〇〡-〩`^.
                            T`¶123`_一二三


                            Try it online! Link includes test cases. Explanation:



                            M!`[1-3]{2}|.


                            Split the input into individual digits or pairs of digits if they are both 1-3.



                            mT`d`〇〡-〩`^.


                            Replace the first character of each line with its Suzhou.



                            T`¶123`_一二三


                            Join the lines back together and replace any remaining digits with horizontal Suzhou.






                            share|improve this answer























                              up vote
                              6
                              down vote










                              up vote
                              6
                              down vote










                              Retina, 46 bytes



                              /[1-3]{2}|./_T`d`〇〡-〩`^.
                              T`123`一二三


                              Try it online! Link includes test cases. Explanation:



                              /[1-3]{2}|./


                              Match either two digits 1-3 or any other digit.



                              _T`d`〇〡-〩`^.


                              Replace the first character of each match with its Suzhou.



                              T`123`一二三


                              Replace any remaining digits with horizontal Suzhou.



                              51 bytes in Retina 0.8.2:



                              M!`[1-3]{2}|.
                              mT`d`〇〡-〩`^.
                              T`¶123`_一二三


                              Try it online! Link includes test cases. Explanation:



                              M!`[1-3]{2}|.


                              Split the input into individual digits or pairs of digits if they are both 1-3.



                              mT`d`〇〡-〩`^.


                              Replace the first character of each line with its Suzhou.



                              T`¶123`_一二三


                              Join the lines back together and replace any remaining digits with horizontal Suzhou.






                              share|improve this answer













                              Retina, 46 bytes



                              /[1-3]{2}|./_T`d`〇〡-〩`^.
                              T`123`一二三


                              Try it online! Link includes test cases. Explanation:



                              /[1-3]{2}|./


                              Match either two digits 1-3 or any other digit.



                              _T`d`〇〡-〩`^.


                              Replace the first character of each match with its Suzhou.



                              T`123`一二三


                              Replace any remaining digits with horizontal Suzhou.



                              51 bytes in Retina 0.8.2:



                              M!`[1-3]{2}|.
                              mT`d`〇〡-〩`^.
                              T`¶123`_一二三


                              Try it online! Link includes test cases. Explanation:



                              M!`[1-3]{2}|.


                              Split the input into individual digits or pairs of digits if they are both 1-3.



                              mT`d`〇〡-〩`^.


                              Replace the first character of each line with its Suzhou.



                              T`¶123`_一二三


                              Join the lines back together and replace any remaining digits with horizontal Suzhou.







                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered yesterday









                              Neil

                              78.8k744175




                              78.8k744175






















                                  up vote
                                  5
                                  down vote













                                  JavaScript, 81 bytes





                                  s=>s.replace(/./g,c=>(p=14>>c&!p)|c>3?eval(`"\u302${c}"`):'〇一二三'[c],p=0)


                                  Try it online!



                                  Using 14>>c saves 3 bytes. Thanks to Arnauld.






                                  share|improve this answer























                                  • p=c>0&c<4&!p can be turned into p=14>>c&!p
                                    – Arnauld
                                    16 hours ago

















                                  up vote
                                  5
                                  down vote













                                  JavaScript, 81 bytes





                                  s=>s.replace(/./g,c=>(p=14>>c&!p)|c>3?eval(`"\u302${c}"`):'〇一二三'[c],p=0)


                                  Try it online!



                                  Using 14>>c saves 3 bytes. Thanks to Arnauld.






                                  share|improve this answer























                                  • p=c>0&c<4&!p can be turned into p=14>>c&!p
                                    – Arnauld
                                    16 hours ago















                                  up vote
                                  5
                                  down vote










                                  up vote
                                  5
                                  down vote









                                  JavaScript, 81 bytes





                                  s=>s.replace(/./g,c=>(p=14>>c&!p)|c>3?eval(`"\u302${c}"`):'〇一二三'[c],p=0)


                                  Try it online!



                                  Using 14>>c saves 3 bytes. Thanks to Arnauld.






                                  share|improve this answer














                                  JavaScript, 81 bytes





                                  s=>s.replace(/./g,c=>(p=14>>c&!p)|c>3?eval(`"\u302${c}"`):'〇一二三'[c],p=0)


                                  Try it online!



                                  Using 14>>c saves 3 bytes. Thanks to Arnauld.







                                  share|improve this answer














                                  share|improve this answer



                                  share|improve this answer








                                  edited 5 hours ago

























                                  answered 21 hours ago









                                  tsh

                                  8,25511546




                                  8,25511546












                                  • p=c>0&c<4&!p can be turned into p=14>>c&!p
                                    – Arnauld
                                    16 hours ago




















                                  • p=c>0&c<4&!p can be turned into p=14>>c&!p
                                    – Arnauld
                                    16 hours ago


















                                  p=c>0&c<4&!p can be turned into p=14>>c&!p
                                  – Arnauld
                                  16 hours ago






                                  p=c>0&c<4&!p can be turned into p=14>>c&!p
                                  – Arnauld
                                  16 hours ago












                                  up vote
                                  4
                                  down vote













                                  JavaScript (ES6),  95 89  88 bytes



                                  Saved 6 bytes thanks to @ShieruAsakoto



                                  Takes input as a string.





                                  s=>s.replace(i=/./g,c=>'三二一〇〡〢〣〤〥〦〧〨〩'[i=112>>i&c<4?3-c:+c+3])


                                  Try it online!






                                  share|improve this answer























                                  • 89 bytes
                                    – Shieru Asakoto
                                    yesterday












                                  • @ShieruAsakoto That's much better! Thanks a lot!
                                    – Arnauld
                                    yesterday















                                  up vote
                                  4
                                  down vote













                                  JavaScript (ES6),  95 89  88 bytes



                                  Saved 6 bytes thanks to @ShieruAsakoto



                                  Takes input as a string.





                                  s=>s.replace(i=/./g,c=>'三二一〇〡〢〣〤〥〦〧〨〩'[i=112>>i&c<4?3-c:+c+3])


                                  Try it online!






                                  share|improve this answer























                                  • 89 bytes
                                    – Shieru Asakoto
                                    yesterday












                                  • @ShieruAsakoto That's much better! Thanks a lot!
                                    – Arnauld
                                    yesterday













                                  up vote
                                  4
                                  down vote










                                  up vote
                                  4
                                  down vote









                                  JavaScript (ES6),  95 89  88 bytes



                                  Saved 6 bytes thanks to @ShieruAsakoto



                                  Takes input as a string.





                                  s=>s.replace(i=/./g,c=>'三二一〇〡〢〣〤〥〦〧〨〩'[i=112>>i&c<4?3-c:+c+3])


                                  Try it online!






                                  share|improve this answer














                                  JavaScript (ES6),  95 89  88 bytes



                                  Saved 6 bytes thanks to @ShieruAsakoto



                                  Takes input as a string.





                                  s=>s.replace(i=/./g,c=>'三二一〇〡〢〣〤〥〦〧〨〩'[i=112>>i&c<4?3-c:+c+3])


                                  Try it online!







                                  share|improve this answer














                                  share|improve this answer



                                  share|improve this answer








                                  edited 16 hours ago

























                                  answered yesterday









                                  Arnauld

                                  71.5k688299




                                  71.5k688299












                                  • 89 bytes
                                    – Shieru Asakoto
                                    yesterday












                                  • @ShieruAsakoto That's much better! Thanks a lot!
                                    – Arnauld
                                    yesterday


















                                  • 89 bytes
                                    – Shieru Asakoto
                                    yesterday












                                  • @ShieruAsakoto That's much better! Thanks a lot!
                                    – Arnauld
                                    yesterday
















                                  89 bytes
                                  – Shieru Asakoto
                                  yesterday






                                  89 bytes
                                  – Shieru Asakoto
                                  yesterday














                                  @ShieruAsakoto That's much better! Thanks a lot!
                                  – Arnauld
                                  yesterday




                                  @ShieruAsakoto That's much better! Thanks a lot!
                                  – Arnauld
                                  yesterday










                                  up vote
                                  3
                                  down vote














                                  Clean, 181 165 bytes



                                  All octal escapes can be replaced by the equivalent single-byte characters (and are counted as one byte each), but used for readability and because otherwise it breaks TIO and SE with invalid UTF-8.



                                  import StdEnv
                                  u=mapc={'343','200',c}
                                  ?s=((!!)["〇":s++u['244245246247250']])o digitToInt
                                  $=
                                  $[h:t]=[?(u['241242243'])h:if(h-'1'<'03')f$t]
                                  f=
                                  f[h:t]=[?["一","二","三"]h: $t]


                                  Try it online!



                                  An encoding-unaware compiler is both a blessing and a curse.






                                  share|improve this answer



























                                    up vote
                                    3
                                    down vote














                                    Clean, 181 165 bytes



                                    All octal escapes can be replaced by the equivalent single-byte characters (and are counted as one byte each), but used for readability and because otherwise it breaks TIO and SE with invalid UTF-8.



                                    import StdEnv
                                    u=mapc={'343','200',c}
                                    ?s=((!!)["〇":s++u['244245246247250']])o digitToInt
                                    $=
                                    $[h:t]=[?(u['241242243'])h:if(h-'1'<'03')f$t]
                                    f=
                                    f[h:t]=[?["一","二","三"]h: $t]


                                    Try it online!



                                    An encoding-unaware compiler is both a blessing and a curse.






                                    share|improve this answer

























                                      up vote
                                      3
                                      down vote










                                      up vote
                                      3
                                      down vote










                                      Clean, 181 165 bytes



                                      All octal escapes can be replaced by the equivalent single-byte characters (and are counted as one byte each), but used for readability and because otherwise it breaks TIO and SE with invalid UTF-8.



                                      import StdEnv
                                      u=mapc={'343','200',c}
                                      ?s=((!!)["〇":s++u['244245246247250']])o digitToInt
                                      $=
                                      $[h:t]=[?(u['241242243'])h:if(h-'1'<'03')f$t]
                                      f=
                                      f[h:t]=[?["一","二","三"]h: $t]


                                      Try it online!



                                      An encoding-unaware compiler is both a blessing and a curse.






                                      share|improve this answer















                                      Clean, 181 165 bytes



                                      All octal escapes can be replaced by the equivalent single-byte characters (and are counted as one byte each), but used for readability and because otherwise it breaks TIO and SE with invalid UTF-8.



                                      import StdEnv
                                      u=mapc={'343','200',c}
                                      ?s=((!!)["〇":s++u['244245246247250']])o digitToInt
                                      $=
                                      $[h:t]=[?(u['241242243'])h:if(h-'1'<'03')f$t]
                                      f=
                                      f[h:t]=[?["一","二","三"]h: $t]


                                      Try it online!



                                      An encoding-unaware compiler is both a blessing and a curse.







                                      share|improve this answer














                                      share|improve this answer



                                      share|improve this answer








                                      edited yesterday

























                                      answered yesterday









                                      Οurous

                                      6,26811032




                                      6,26811032






















                                          up vote
                                          3
                                          down vote














                                          Java (JDK), 120 bytes





                                          s->{for(int i=0,p=0,c;i<s.length;)s[i]+=(p>0&p<4&(c=s[i++]-48)>0&c<4)?"A䷏乚䷖".charAt(c+(p=0)):(p=c)<1?12247:12272;}


                                          Try it online!



                                          Credits




                                          • -3 bytes thanks to Kevin Cruijssen






                                          share|improve this answer



















                                          • 1




                                            c=s[i]-48;if(p>0&p<4&c>0&c<4) can be if(p>0&p<4&(c=s[i]-48)>0&c<4), and then you can also drop the brackets around the loop. Also, else{p=c;s[i]+=c<1?12247:12272;} can be else s[i]+=(p=c)<1?12247:12272;
                                            – Kevin Cruijssen
                                            20 hours ago






                                          • 1




                                            @KevinCruijssen Thank you! I was still golfing this answer, but it helped me nonetheless ^^ Now I think I'm done golfing it.
                                            – Olivier Grégoire
                                            19 hours ago

















                                          up vote
                                          3
                                          down vote














                                          Java (JDK), 120 bytes





                                          s->{for(int i=0,p=0,c;i<s.length;)s[i]+=(p>0&p<4&(c=s[i++]-48)>0&c<4)?"A䷏乚䷖".charAt(c+(p=0)):(p=c)<1?12247:12272;}


                                          Try it online!



                                          Credits




                                          • -3 bytes thanks to Kevin Cruijssen






                                          share|improve this answer



















                                          • 1




                                            c=s[i]-48;if(p>0&p<4&c>0&c<4) can be if(p>0&p<4&(c=s[i]-48)>0&c<4), and then you can also drop the brackets around the loop. Also, else{p=c;s[i]+=c<1?12247:12272;} can be else s[i]+=(p=c)<1?12247:12272;
                                            – Kevin Cruijssen
                                            20 hours ago






                                          • 1




                                            @KevinCruijssen Thank you! I was still golfing this answer, but it helped me nonetheless ^^ Now I think I'm done golfing it.
                                            – Olivier Grégoire
                                            19 hours ago















                                          up vote
                                          3
                                          down vote










                                          up vote
                                          3
                                          down vote










                                          Java (JDK), 120 bytes





                                          s->{for(int i=0,p=0,c;i<s.length;)s[i]+=(p>0&p<4&(c=s[i++]-48)>0&c<4)?"A䷏乚䷖".charAt(c+(p=0)):(p=c)<1?12247:12272;}


                                          Try it online!



                                          Credits




                                          • -3 bytes thanks to Kevin Cruijssen






                                          share|improve this answer















                                          Java (JDK), 120 bytes





                                          s->{for(int i=0,p=0,c;i<s.length;)s[i]+=(p>0&p<4&(c=s[i++]-48)>0&c<4)?"A䷏乚䷖".charAt(c+(p=0)):(p=c)<1?12247:12272;}


                                          Try it online!



                                          Credits




                                          • -3 bytes thanks to Kevin Cruijssen







                                          share|improve this answer














                                          share|improve this answer



                                          share|improve this answer








                                          edited 19 hours ago

























                                          answered 20 hours ago









                                          Olivier Grégoire

                                          8,68711843




                                          8,68711843








                                          • 1




                                            c=s[i]-48;if(p>0&p<4&c>0&c<4) can be if(p>0&p<4&(c=s[i]-48)>0&c<4), and then you can also drop the brackets around the loop. Also, else{p=c;s[i]+=c<1?12247:12272;} can be else s[i]+=(p=c)<1?12247:12272;
                                            – Kevin Cruijssen
                                            20 hours ago






                                          • 1




                                            @KevinCruijssen Thank you! I was still golfing this answer, but it helped me nonetheless ^^ Now I think I'm done golfing it.
                                            – Olivier Grégoire
                                            19 hours ago
















                                          • 1




                                            c=s[i]-48;if(p>0&p<4&c>0&c<4) can be if(p>0&p<4&(c=s[i]-48)>0&c<4), and then you can also drop the brackets around the loop. Also, else{p=c;s[i]+=c<1?12247:12272;} can be else s[i]+=(p=c)<1?12247:12272;
                                            – Kevin Cruijssen
                                            20 hours ago






                                          • 1




                                            @KevinCruijssen Thank you! I was still golfing this answer, but it helped me nonetheless ^^ Now I think I'm done golfing it.
                                            – Olivier Grégoire
                                            19 hours ago










                                          1




                                          1




                                          c=s[i]-48;if(p>0&p<4&c>0&c<4) can be if(p>0&p<4&(c=s[i]-48)>0&c<4), and then you can also drop the brackets around the loop. Also, else{p=c;s[i]+=c<1?12247:12272;} can be else s[i]+=(p=c)<1?12247:12272;
                                          – Kevin Cruijssen
                                          20 hours ago




                                          c=s[i]-48;if(p>0&p<4&c>0&c<4) can be if(p>0&p<4&(c=s[i]-48)>0&c<4), and then you can also drop the brackets around the loop. Also, else{p=c;s[i]+=c<1?12247:12272;} can be else s[i]+=(p=c)<1?12247:12272;
                                          – Kevin Cruijssen
                                          20 hours ago




                                          1




                                          1




                                          @KevinCruijssen Thank you! I was still golfing this answer, but it helped me nonetheless ^^ Now I think I'm done golfing it.
                                          – Olivier Grégoire
                                          19 hours ago






                                          @KevinCruijssen Thank you! I was still golfing this answer, but it helped me nonetheless ^^ Now I think I'm done golfing it.
                                          – Olivier Grégoire
                                          19 hours ago












                                          up vote
                                          3
                                          down vote














                                          Perl 5 -pl -Mutf8, 53 46 bytes



                                          -7 bytes thanks to Grimy



                                          s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c


                                          Try it online!



                                          Explanation



                                          # Binary AND two consecutive digits 1-3 (ASCII 0x31-0x33)
                                          # or any other single digit (ASCII 0x30-0x39) with string "OS"
                                          # (ASCII 0x4F 0x53). This converts the first digit to 0x00-0x09
                                          # and the second digit, if present, to 0x11-0x13.
                                          s/[123]{2}|./OS&$&/ge;
                                          # Translate empty complemented searchlist (0x00-0x13) to
                                          # respective Unicode characters.
                                          y//〇〡-〰一二三/c





                                          share|improve this answer























                                          • -3 bytes with s/[123]K[123]/$&^$;/ge;y/--</一二三〇〡-〩/ (TIO)
                                            – Grimy
                                            16 hours ago












                                          • 49: s/[123]{2}/$&^v0.28/ge;y/--</一二三〇〡-〩/ (TIO). 48: s/[123]{2}/$&^"34"/ge;y/--</一二三〇〡-〩/ (requires using literal control characters instead of 34, idk how to do this on TIO)
                                            – Grimy
                                            16 hours ago












                                          • 46: s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c (TIO)
                                            – Grimy
                                            15 hours ago















                                          up vote
                                          3
                                          down vote














                                          Perl 5 -pl -Mutf8, 53 46 bytes



                                          -7 bytes thanks to Grimy



                                          s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c


                                          Try it online!



                                          Explanation



                                          # Binary AND two consecutive digits 1-3 (ASCII 0x31-0x33)
                                          # or any other single digit (ASCII 0x30-0x39) with string "OS"
                                          # (ASCII 0x4F 0x53). This converts the first digit to 0x00-0x09
                                          # and the second digit, if present, to 0x11-0x13.
                                          s/[123]{2}|./OS&$&/ge;
                                          # Translate empty complemented searchlist (0x00-0x13) to
                                          # respective Unicode characters.
                                          y//〇〡-〰一二三/c





                                          share|improve this answer























                                          • -3 bytes with s/[123]K[123]/$&^$;/ge;y/--</一二三〇〡-〩/ (TIO)
                                            – Grimy
                                            16 hours ago












                                          • 49: s/[123]{2}/$&^v0.28/ge;y/--</一二三〇〡-〩/ (TIO). 48: s/[123]{2}/$&^"34"/ge;y/--</一二三〇〡-〩/ (requires using literal control characters instead of 34, idk how to do this on TIO)
                                            – Grimy
                                            16 hours ago












                                          • 46: s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c (TIO)
                                            – Grimy
                                            15 hours ago













                                          up vote
                                          3
                                          down vote










                                          up vote
                                          3
                                          down vote










                                          Perl 5 -pl -Mutf8, 53 46 bytes



                                          -7 bytes thanks to Grimy



                                          s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c


                                          Try it online!



                                          Explanation



                                          # Binary AND two consecutive digits 1-3 (ASCII 0x31-0x33)
                                          # or any other single digit (ASCII 0x30-0x39) with string "OS"
                                          # (ASCII 0x4F 0x53). This converts the first digit to 0x00-0x09
                                          # and the second digit, if present, to 0x11-0x13.
                                          s/[123]{2}|./OS&$&/ge;
                                          # Translate empty complemented searchlist (0x00-0x13) to
                                          # respective Unicode characters.
                                          y//〇〡-〰一二三/c





                                          share|improve this answer















                                          Perl 5 -pl -Mutf8, 53 46 bytes



                                          -7 bytes thanks to Grimy



                                          s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c


                                          Try it online!



                                          Explanation



                                          # Binary AND two consecutive digits 1-3 (ASCII 0x31-0x33)
                                          # or any other single digit (ASCII 0x30-0x39) with string "OS"
                                          # (ASCII 0x4F 0x53). This converts the first digit to 0x00-0x09
                                          # and the second digit, if present, to 0x11-0x13.
                                          s/[123]{2}|./OS&$&/ge;
                                          # Translate empty complemented searchlist (0x00-0x13) to
                                          # respective Unicode characters.
                                          y//〇〡-〰一二三/c






                                          share|improve this answer














                                          share|improve this answer



                                          share|improve this answer








                                          edited 15 hours ago

























                                          answered yesterday









                                          nwellnhof

                                          6,4431125




                                          6,4431125












                                          • -3 bytes with s/[123]K[123]/$&^$;/ge;y/--</一二三〇〡-〩/ (TIO)
                                            – Grimy
                                            16 hours ago












                                          • 49: s/[123]{2}/$&^v0.28/ge;y/--</一二三〇〡-〩/ (TIO). 48: s/[123]{2}/$&^"34"/ge;y/--</一二三〇〡-〩/ (requires using literal control characters instead of 34, idk how to do this on TIO)
                                            – Grimy
                                            16 hours ago












                                          • 46: s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c (TIO)
                                            – Grimy
                                            15 hours ago


















                                          • -3 bytes with s/[123]K[123]/$&^$;/ge;y/--</一二三〇〡-〩/ (TIO)
                                            – Grimy
                                            16 hours ago












                                          • 49: s/[123]{2}/$&^v0.28/ge;y/--</一二三〇〡-〩/ (TIO). 48: s/[123]{2}/$&^"34"/ge;y/--</一二三〇〡-〩/ (requires using literal control characters instead of 34, idk how to do this on TIO)
                                            – Grimy
                                            16 hours ago












                                          • 46: s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c (TIO)
                                            – Grimy
                                            15 hours ago
















                                          -3 bytes with s/[123]K[123]/$&^$;/ge;y/--</一二三〇〡-〩/ (TIO)
                                          – Grimy
                                          16 hours ago






                                          -3 bytes with s/[123]K[123]/$&^$;/ge;y/--</一二三〇〡-〩/ (TIO)
                                          – Grimy
                                          16 hours ago














                                          49: s/[123]{2}/$&^v0.28/ge;y/--</一二三〇〡-〩/ (TIO). 48: s/[123]{2}/$&^"34"/ge;y/--</一二三〇〡-〩/ (requires using literal control characters instead of 34, idk how to do this on TIO)
                                          – Grimy
                                          16 hours ago






                                          49: s/[123]{2}/$&^v0.28/ge;y/--</一二三〇〡-〩/ (TIO). 48: s/[123]{2}/$&^"34"/ge;y/--</一二三〇〡-〩/ (requires using literal control characters instead of 34, idk how to do this on TIO)
                                          – Grimy
                                          16 hours ago














                                          46: s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c (TIO)
                                          – Grimy
                                          15 hours ago




                                          46: s/[123]{2}|./OS&$&/ge;y//〇〡-〰一二三/c (TIO)
                                          – Grimy
                                          15 hours ago










                                          up vote
                                          2
                                          down vote














                                          Perl 6 -p, 85 61 bytes



                                          -13 bytes thanks to Jo King





                                          s:g[(1|2|3)<((1|2|3)]=chr $/+57;tr/0..</〇〡..〩一二三/


                                          Try it online!






                                          share|improve this answer



























                                            up vote
                                            2
                                            down vote














                                            Perl 6 -p, 85 61 bytes



                                            -13 bytes thanks to Jo King





                                            s:g[(1|2|3)<((1|2|3)]=chr $/+57;tr/0..</〇〡..〩一二三/


                                            Try it online!






                                            share|improve this answer

























                                              up vote
                                              2
                                              down vote










                                              up vote
                                              2
                                              down vote










                                              Perl 6 -p, 85 61 bytes



                                              -13 bytes thanks to Jo King





                                              s:g[(1|2|3)<((1|2|3)]=chr $/+57;tr/0..</〇〡..〩一二三/


                                              Try it online!






                                              share|improve this answer















                                              Perl 6 -p, 85 61 bytes



                                              -13 bytes thanks to Jo King





                                              s:g[(1|2|3)<((1|2|3)]=chr $/+57;tr/0..</〇〡..〩一二三/


                                              Try it online!







                                              share|improve this answer














                                              share|improve this answer



                                              share|improve this answer








                                              edited yesterday

























                                              answered yesterday









                                              nwellnhof

                                              6,4431125




                                              6,4431125






















                                                  up vote
                                                  2
                                                  down vote














                                                  Red, 198 171 bytes



                                                  func[n][s: charset"〡〢〣"forall n[n/1: either n/1 >#"0"[to-char 12272 + n/1][#"〇"]]parse
                                                  n[any[[s change copy t s(pick"一二三"do(to-char t)- 12320)fail]| skip]]n]


                                                  Try it online!






                                                  share|improve this answer



























                                                    up vote
                                                    2
                                                    down vote














                                                    Red, 198 171 bytes



                                                    func[n][s: charset"〡〢〣"forall n[n/1: either n/1 >#"0"[to-char 12272 + n/1][#"〇"]]parse
                                                    n[any[[s change copy t s(pick"一二三"do(to-char t)- 12320)fail]| skip]]n]


                                                    Try it online!






                                                    share|improve this answer

























                                                      up vote
                                                      2
                                                      down vote










                                                      up vote
                                                      2
                                                      down vote










                                                      Red, 198 171 bytes



                                                      func[n][s: charset"〡〢〣"forall n[n/1: either n/1 >#"0"[to-char 12272 + n/1][#"〇"]]parse
                                                      n[any[[s change copy t s(pick"一二三"do(to-char t)- 12320)fail]| skip]]n]


                                                      Try it online!






                                                      share|improve this answer















                                                      Red, 198 171 bytes



                                                      func[n][s: charset"〡〢〣"forall n[n/1: either n/1 >#"0"[to-char 12272 + n/1][#"〇"]]parse
                                                      n[any[[s change copy t s(pick"一二三"do(to-char t)- 12320)fail]| skip]]n]


                                                      Try it online!







                                                      share|improve this answer














                                                      share|improve this answer



                                                      share|improve this answer








                                                      edited 19 hours ago

























                                                      answered 20 hours ago









                                                      Galen Ivanov

                                                      6,15211032




                                                      6,15211032






















                                                          up vote
                                                          2
                                                          down vote














                                                          R, 138 bytes



                                                          I'll bet there's an easier way to do this. Use gsub to get the alternating numeric positions.





                                                          function(x,r=-48+~x)Reduce(paste0,ifelse(58<~gsub("[123]{2}","0a",x),"123"["一二三",r],'0-9'["〇〡-〩",r]))
                                                          "~"=utf8ToInt
                                                          "["=chartr


                                                          Try it online!






                                                          share|improve this answer



























                                                            up vote
                                                            2
                                                            down vote














                                                            R, 138 bytes



                                                            I'll bet there's an easier way to do this. Use gsub to get the alternating numeric positions.





                                                            function(x,r=-48+~x)Reduce(paste0,ifelse(58<~gsub("[123]{2}","0a",x),"123"["一二三",r],'0-9'["〇〡-〩",r]))
                                                            "~"=utf8ToInt
                                                            "["=chartr


                                                            Try it online!






                                                            share|improve this answer

























                                                              up vote
                                                              2
                                                              down vote










                                                              up vote
                                                              2
                                                              down vote










                                                              R, 138 bytes



                                                              I'll bet there's an easier way to do this. Use gsub to get the alternating numeric positions.





                                                              function(x,r=-48+~x)Reduce(paste0,ifelse(58<~gsub("[123]{2}","0a",x),"123"["一二三",r],'0-9'["〇〡-〩",r]))
                                                              "~"=utf8ToInt
                                                              "["=chartr


                                                              Try it online!






                                                              share|improve this answer















                                                              R, 138 bytes



                                                              I'll bet there's an easier way to do this. Use gsub to get the alternating numeric positions.





                                                              function(x,r=-48+~x)Reduce(paste0,ifelse(58<~gsub("[123]{2}","0a",x),"123"["一二三",r],'0-9'["〇〡-〩",r]))
                                                              "~"=utf8ToInt
                                                              "["=chartr


                                                              Try it online!







                                                              share|improve this answer














                                                              share|improve this answer



                                                              share|improve this answer








                                                              edited 15 hours ago

























                                                              answered 15 hours ago









                                                              J.Doe

                                                              2,149112




                                                              2,149112






















                                                                  up vote
                                                                  2
                                                                  down vote














                                                                  Python 3, 102 bytes





                                                                  f=0
                                                                  for i in input():f=i in'123'and 9-f;print(end='〇一二三〤〥〦〧〨〩〡〢〣'[int(i)+f])


                                                                  Try it online!



                                                                  mypetlion reminded me of a trivial golf. -4 bytes.






                                                                  share|improve this answer



























                                                                    up vote
                                                                    2
                                                                    down vote














                                                                    Python 3, 102 bytes





                                                                    f=0
                                                                    for i in input():f=i in'123'and 9-f;print(end='〇一二三〤〥〦〧〨〩〡〢〣'[int(i)+f])


                                                                    Try it online!



                                                                    mypetlion reminded me of a trivial golf. -4 bytes.






                                                                    share|improve this answer

























                                                                      up vote
                                                                      2
                                                                      down vote










                                                                      up vote
                                                                      2
                                                                      down vote










                                                                      Python 3, 102 bytes





                                                                      f=0
                                                                      for i in input():f=i in'123'and 9-f;print(end='〇一二三〤〥〦〧〨〩〡〢〣'[int(i)+f])


                                                                      Try it online!



                                                                      mypetlion reminded me of a trivial golf. -4 bytes.






                                                                      share|improve this answer















                                                                      Python 3, 102 bytes





                                                                      f=0
                                                                      for i in input():f=i in'123'and 9-f;print(end='〇一二三〤〥〦〧〨〩〡〢〣'[int(i)+f])


                                                                      Try it online!



                                                                      mypetlion reminded me of a trivial golf. -4 bytes.







                                                                      share|improve this answer














                                                                      share|improve this answer



                                                                      share|improve this answer








                                                                      edited 10 hours ago

























                                                                      answered 12 hours ago









                                                                      Erik the Outgolfer

                                                                      31.1k429102




                                                                      31.1k429102






















                                                                          up vote
                                                                          1
                                                                          down vote














                                                                          Ruby -p, 71 bytes





                                                                          $_=gsub(/[1-3]K[1-3]/){|x|(x.ord+9).chr}.tr"0-<","〇〡-〩一二三"


                                                                          Try it online!






                                                                          share|improve this answer

























                                                                            up vote
                                                                            1
                                                                            down vote














                                                                            Ruby -p, 71 bytes





                                                                            $_=gsub(/[1-3]K[1-3]/){|x|(x.ord+9).chr}.tr"0-<","〇〡-〩一二三"


                                                                            Try it online!






                                                                            share|improve this answer























                                                                              up vote
                                                                              1
                                                                              down vote










                                                                              up vote
                                                                              1
                                                                              down vote










                                                                              Ruby -p, 71 bytes





                                                                              $_=gsub(/[1-3]K[1-3]/){|x|(x.ord+9).chr}.tr"0-<","〇〡-〩一二三"


                                                                              Try it online!






                                                                              share|improve this answer













                                                                              Ruby -p, 71 bytes





                                                                              $_=gsub(/[1-3]K[1-3]/){|x|(x.ord+9).chr}.tr"0-<","〇〡-〩一二三"


                                                                              Try it online!







                                                                              share|improve this answer












                                                                              share|improve this answer



                                                                              share|improve this answer










                                                                              answered 20 hours ago









                                                                              Kirill L.

                                                                              3,5051218




                                                                              3,5051218






















                                                                                  up vote
                                                                                  1
                                                                                  down vote














                                                                                  K (ngn/k), 67 bytes



                                                                                  {,/(0N 3#"〇一二三〤〥〦〧〨〩〡〢〣")x+9*<x&x<4}@10


                                                                                  Try it online!



                                                                                  10 get list of decimal digits



                                                                                  { }@ apply the following function



                                                                                  x&x<4 boolean (0/1) list of where the argument is less than 4 and non-zero



                                                                                  < scan with less-than. this turns runs of consecutive 1s into alternating 1s and 0s



                                                                                  x+9* multiply by 9 and add x



                                                                                  juxtaposition is indexing, so use this as indices in...



                                                                                  0N 3#"〇一二三〤〥〦〧〨〩〡〢〣" the given string, split into a list of 3-byte strings. k is not unicode aware, so it sees only bytes



                                                                                  ,/ concatenate






                                                                                  share|improve this answer



























                                                                                    up vote
                                                                                    1
                                                                                    down vote














                                                                                    K (ngn/k), 67 bytes



                                                                                    {,/(0N 3#"〇一二三〤〥〦〧〨〩〡〢〣")x+9*<x&x<4}@10


                                                                                    Try it online!



                                                                                    10 get list of decimal digits



                                                                                    { }@ apply the following function



                                                                                    x&x<4 boolean (0/1) list of where the argument is less than 4 and non-zero



                                                                                    < scan with less-than. this turns runs of consecutive 1s into alternating 1s and 0s



                                                                                    x+9* multiply by 9 and add x



                                                                                    juxtaposition is indexing, so use this as indices in...



                                                                                    0N 3#"〇一二三〤〥〦〧〨〩〡〢〣" the given string, split into a list of 3-byte strings. k is not unicode aware, so it sees only bytes



                                                                                    ,/ concatenate






                                                                                    share|improve this answer

























                                                                                      up vote
                                                                                      1
                                                                                      down vote










                                                                                      up vote
                                                                                      1
                                                                                      down vote










                                                                                      K (ngn/k), 67 bytes



                                                                                      {,/(0N 3#"〇一二三〤〥〦〧〨〩〡〢〣")x+9*<x&x<4}@10


                                                                                      Try it online!



                                                                                      10 get list of decimal digits



                                                                                      { }@ apply the following function



                                                                                      x&x<4 boolean (0/1) list of where the argument is less than 4 and non-zero



                                                                                      < scan with less-than. this turns runs of consecutive 1s into alternating 1s and 0s



                                                                                      x+9* multiply by 9 and add x



                                                                                      juxtaposition is indexing, so use this as indices in...



                                                                                      0N 3#"〇一二三〤〥〦〧〨〩〡〢〣" the given string, split into a list of 3-byte strings. k is not unicode aware, so it sees only bytes



                                                                                      ,/ concatenate






                                                                                      share|improve this answer















                                                                                      K (ngn/k), 67 bytes



                                                                                      {,/(0N 3#"〇一二三〤〥〦〧〨〩〡〢〣")x+9*<x&x<4}@10


                                                                                      Try it online!



                                                                                      10 get list of decimal digits



                                                                                      { }@ apply the following function



                                                                                      x&x<4 boolean (0/1) list of where the argument is less than 4 and non-zero



                                                                                      < scan with less-than. this turns runs of consecutive 1s into alternating 1s and 0s



                                                                                      x+9* multiply by 9 and add x



                                                                                      juxtaposition is indexing, so use this as indices in...



                                                                                      0N 3#"〇一二三〤〥〦〧〨〩〡〢〣" the given string, split into a list of 3-byte strings. k is not unicode aware, so it sees only bytes



                                                                                      ,/ concatenate







                                                                                      share|improve this answer














                                                                                      share|improve this answer



                                                                                      share|improve this answer








                                                                                      edited 20 hours ago

























                                                                                      answered 20 hours ago









                                                                                      ngn

                                                                                      6,67312459




                                                                                      6,67312459






















                                                                                          up vote
                                                                                          0
                                                                                          down vote













                                                                                          C#, 127 bytes



                                                                                          n=>Regex.Replace(n+"",@"[4-90]|[1-3]{1,2}",x=>"〇〡〢〣〤〥〦〧〨〩"[x.Value[0]-'0']+""+(x.Value.Length>1?"一二三"[x.Value[1]-'0'-1]+"":""))


                                                                                          Try it online!






                                                                                          share|improve this answer

























                                                                                            up vote
                                                                                            0
                                                                                            down vote













                                                                                            C#, 127 bytes



                                                                                            n=>Regex.Replace(n+"",@"[4-90]|[1-3]{1,2}",x=>"〇〡〢〣〤〥〦〧〨〩"[x.Value[0]-'0']+""+(x.Value.Length>1?"一二三"[x.Value[1]-'0'-1]+"":""))


                                                                                            Try it online!






                                                                                            share|improve this answer























                                                                                              up vote
                                                                                              0
                                                                                              down vote










                                                                                              up vote
                                                                                              0
                                                                                              down vote









                                                                                              C#, 127 bytes



                                                                                              n=>Regex.Replace(n+"",@"[4-90]|[1-3]{1,2}",x=>"〇〡〢〣〤〥〦〧〨〩"[x.Value[0]-'0']+""+(x.Value.Length>1?"一二三"[x.Value[1]-'0'-1]+"":""))


                                                                                              Try it online!






                                                                                              share|improve this answer












                                                                                              C#, 127 bytes



                                                                                              n=>Regex.Replace(n+"",@"[4-90]|[1-3]{1,2}",x=>"〇〡〢〣〤〥〦〧〨〩"[x.Value[0]-'0']+""+(x.Value.Length>1?"一二三"[x.Value[1]-'0'-1]+"":""))


                                                                                              Try it online!







                                                                                              share|improve this answer












                                                                                              share|improve this answer



                                                                                              share|improve this answer










                                                                                              answered 14 hours ago









                                                                                              zruF

                                                                                              495




                                                                                              495






















                                                                                                  up vote
                                                                                                  0
                                                                                                  down vote














                                                                                                  Jelly, 38 bytes



                                                                                                  9Rż“øƓ“œ%“øƈ’;-25+⁽-EỌœị@DżD<4«Ɗ‘×¥ƊƊ


                                                                                                  Try it online!






                                                                                                  share|improve this answer

























                                                                                                    up vote
                                                                                                    0
                                                                                                    down vote














                                                                                                    Jelly, 38 bytes



                                                                                                    9Rż“øƓ“œ%“øƈ’;-25+⁽-EỌœị@DżD<4«Ɗ‘×¥ƊƊ


                                                                                                    Try it online!






                                                                                                    share|improve this answer























                                                                                                      up vote
                                                                                                      0
                                                                                                      down vote










                                                                                                      up vote
                                                                                                      0
                                                                                                      down vote










                                                                                                      Jelly, 38 bytes



                                                                                                      9Rż“øƓ“œ%“øƈ’;-25+⁽-EỌœị@DżD<4«Ɗ‘×¥ƊƊ


                                                                                                      Try it online!






                                                                                                      share|improve this answer













                                                                                                      Jelly, 38 bytes



                                                                                                      9Rż“øƓ“œ%“øƈ’;-25+⁽-EỌœị@DżD<4«Ɗ‘×¥ƊƊ


                                                                                                      Try it online!







                                                                                                      share|improve this answer












                                                                                                      share|improve this answer



                                                                                                      share|improve this answer










                                                                                                      answered 12 hours ago









                                                                                                      Erik the Outgolfer

                                                                                                      31.1k429102




                                                                                                      31.1k429102






















                                                                                                          up vote
                                                                                                          0
                                                                                                          down vote














                                                                                                          Jelly, 35 bytes



                                                                                                          9Ḷ;-26ż“/Ẉ8‘+⁽ȷc¤ṃ@ɓD_2ỊŒgÄFị"+⁽-FỌ


                                                                                                          Try it online!






                                                                                                          share|improve this answer

























                                                                                                            up vote
                                                                                                            0
                                                                                                            down vote














                                                                                                            Jelly, 35 bytes



                                                                                                            9Ḷ;-26ż“/Ẉ8‘+⁽ȷc¤ṃ@ɓD_2ỊŒgÄFị"+⁽-FỌ


                                                                                                            Try it online!






                                                                                                            share|improve this answer























                                                                                                              up vote
                                                                                                              0
                                                                                                              down vote










                                                                                                              up vote
                                                                                                              0
                                                                                                              down vote










                                                                                                              Jelly, 35 bytes



                                                                                                              9Ḷ;-26ż“/Ẉ8‘+⁽ȷc¤ṃ@ɓD_2ỊŒgÄFị"+⁽-FỌ


                                                                                                              Try it online!






                                                                                                              share|improve this answer













                                                                                                              Jelly, 35 bytes



                                                                                                              9Ḷ;-26ż“/Ẉ8‘+⁽ȷc¤ṃ@ɓD_2ỊŒgÄFị"+⁽-FỌ


                                                                                                              Try it online!







                                                                                                              share|improve this answer












                                                                                                              share|improve this answer



                                                                                                              share|improve this answer










                                                                                                              answered 9 hours ago









                                                                                                              Dennis

                                                                                                              185k32295734




                                                                                                              185k32295734






















                                                                                                                  up vote
                                                                                                                  0
                                                                                                                  down vote














                                                                                                                  Wolfram Language (Mathematica), 117 bytes



                                                                                                                  FromCharacterCode[12320+(IntegerDigits@#/. 0->-25//.MapIndexed[{a___,c=#2[[1]],c,b___}->{a,c,#,b}&,{0,140,9}+7648])]&


                                                                                                                  Try it online!



                                                                                                                  Note that on TIO this outputs the result in escaped form. In the normal Wolfram front end, it will look like this:picture of notebook interface






                                                                                                                  share|improve this answer

























                                                                                                                    up vote
                                                                                                                    0
                                                                                                                    down vote














                                                                                                                    Wolfram Language (Mathematica), 117 bytes



                                                                                                                    FromCharacterCode[12320+(IntegerDigits@#/. 0->-25//.MapIndexed[{a___,c=#2[[1]],c,b___}->{a,c,#,b}&,{0,140,9}+7648])]&


                                                                                                                    Try it online!



                                                                                                                    Note that on TIO this outputs the result in escaped form. In the normal Wolfram front end, it will look like this:picture of notebook interface






                                                                                                                    share|improve this answer























                                                                                                                      up vote
                                                                                                                      0
                                                                                                                      down vote










                                                                                                                      up vote
                                                                                                                      0
                                                                                                                      down vote










                                                                                                                      Wolfram Language (Mathematica), 117 bytes



                                                                                                                      FromCharacterCode[12320+(IntegerDigits@#/. 0->-25//.MapIndexed[{a___,c=#2[[1]],c,b___}->{a,c,#,b}&,{0,140,9}+7648])]&


                                                                                                                      Try it online!



                                                                                                                      Note that on TIO this outputs the result in escaped form. In the normal Wolfram front end, it will look like this:picture of notebook interface






                                                                                                                      share|improve this answer













                                                                                                                      Wolfram Language (Mathematica), 117 bytes



                                                                                                                      FromCharacterCode[12320+(IntegerDigits@#/. 0->-25//.MapIndexed[{a___,c=#2[[1]],c,b___}->{a,c,#,b}&,{0,140,9}+7648])]&


                                                                                                                      Try it online!



                                                                                                                      Note that on TIO this outputs the result in escaped form. In the normal Wolfram front end, it will look like this:picture of notebook interface







                                                                                                                      share|improve this answer












                                                                                                                      share|improve this answer



                                                                                                                      share|improve this answer










                                                                                                                      answered 4 hours ago









                                                                                                                      Kelly Lowder

                                                                                                                      2,988416




                                                                                                                      2,988416






























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