Declaring a method when creating an object
Why first way is correct, but second isn't?
First way:
new Object() {
public void a() {
/*code*/
}
}.a();
Second way:
Object object = new Object() {
public void a() {
/*code*/
}
};
object.a();
And where can I find more information about it?
java object methods
edited 1 hour ago
ernest_k
19.7k41942
asked 2 hours ago
Sekonoishi Kamiki
311
New contributor
Sekonoishi Kamiki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
Why first way is correct, but second isn't?
First way:
new Object() {
public void a() {
/*code*/
}
}.a();
Second way:
Object object = new Object() {
public void a() {
/*code*/
}
};
object.a();
And where can I find more information about it?
java object methods
edited 1 hour ago
ernest_k
19.7k41942
asked 2 hours ago
Sekonoishi Kamiki
311
New contributor
Sekonoishi Kamiki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
ais only in scope locally. When you try to access it in the second block, it is out of scope
– GBlodgett
2 hours ago
2
Becausea()is not a method of theObjectclass
– Federico Peralta Schaffner
1 hour ago
add a comment |
Why first way is correct, but second isn't?
First way:
new Object() {
public void a() {
/*code*/
}
}.a();
Second way:
Object object = new Object() {
public void a() {
/*code*/
}
};
object.a();
And where can I find more information about it?
java object methods
edited 1 hour ago
ernest_k
19.7k41942
asked 2 hours ago
Sekonoishi Kamiki
311
New contributor
Sekonoishi Kamiki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Why first way is correct, but second isn't?
First way:
new Object() {
public void a() {
/*code*/
}
}.a();
Second way:
Object object = new Object() {
public void a() {
/*code*/
}
};
object.a();
And where can I find more information about it?
java object methods
java object methods
edited 1 hour ago
ernest_k
19.7k41942
asked 2 hours ago
Sekonoishi Kamiki
311
New contributor
Sekonoishi Kamiki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
ernest_k
19.7k41942
asked 2 hours ago
Sekonoishi Kamiki
311
New contributor
Sekonoishi Kamiki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
ernest_k
19.7k41942
edited 1 hour ago
ernest_k
19.7k41942
edited 1 hour ago
ernest_k
19.7k41942
19.7k41942
asked 2 hours ago
Sekonoishi Kamiki
311
New contributor
Sekonoishi Kamiki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
Sekonoishi Kamiki
311
asked 2 hours ago
Sekonoishi Kamiki
311
311
New contributor
Sekonoishi Kamiki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Sekonoishi Kamiki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Sekonoishi Kamiki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
ais only in scope locally. When you try to access it in the second block, it is out of scope
– GBlodgett
2 hours ago
2
Becausea()is not a method of theObjectclass
– Federico Peralta Schaffner
1 hour ago
add a comment |
2
ais only in scope locally. When you try to access it in the second block, it is out of scope
– GBlodgett
2 hours ago
2
Becausea()is not a method of theObjectclass
– Federico Peralta Schaffner
1 hour ago
2
2
a is only in scope locally. When you try to access it in the second block, it is out of scope– GBlodgett
2 hours ago
a is only in scope locally. When you try to access it in the second block, it is out of scope– GBlodgett
2 hours ago
2
2
Because
a() is not a method of the Object class– Federico Peralta Schaffner
1 hour ago
Because
a() is not a method of the Object class– Federico Peralta Schaffner
1 hour ago
add a comment |
2 Answers
2
active
oldest
votes
In second option you assign your new object to a reference of type Object because of this only methods defined in java.lang.Object could be called on that reference.
And in first option you basically create new object of anonymous class that extends java.lang.Object. And that anonymous class has additional method a() that is why you can call it.
answered 1 hour ago
Ivan
4,7541721
add a comment |
java.lang.Object has no a methods declared (2), while the anonymous class returned by the class instance creation expression new Object() { public void a() {} } does (1).
Use local variable type inference (var) to make the second option as valid as the first one.
var object = new Object() {
public void a() {}
};
object.a();
answered 1 hour ago
Andrew Tobilko
25.6k104184
6
Interesting to know that thevarkeyword changes things here...
– ernest_k
1 hour ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
In second option you assign your new object to a reference of type Object because of this only methods defined in java.lang.Object could be called on that reference.
And in first option you basically create new object of anonymous class that extends java.lang.Object. And that anonymous class has additional method a() that is why you can call it.
answered 1 hour ago
Ivan
4,7541721
add a comment |
In second option you assign your new object to a reference of type Object because of this only methods defined in java.lang.Object could be called on that reference.
And in first option you basically create new object of anonymous class that extends java.lang.Object. And that anonymous class has additional method a() that is why you can call it.
answered 1 hour ago
Ivan
4,7541721
add a comment |
In second option you assign your new object to a reference of type Object because of this only methods defined in java.lang.Object could be called on that reference.
And in first option you basically create new object of anonymous class that extends java.lang.Object. And that anonymous class has additional method a() that is why you can call it.
answered 1 hour ago
Ivan
4,7541721
In second option you assign your new object to a reference of type Object because of this only methods defined in java.lang.Object could be called on that reference.
And in first option you basically create new object of anonymous class that extends java.lang.Object. And that anonymous class has additional method a() that is why you can call it.
answered 1 hour ago
Ivan
4,7541721
answered 1 hour ago
Ivan
4,7541721
answered 1 hour ago
Ivan
4,7541721
answered 1 hour ago
Ivan
4,7541721
4,7541721
add a comment |
add a comment |
java.lang.Object has no a methods declared (2), while the anonymous class returned by the class instance creation expression new Object() { public void a() {} } does (1).
Use local variable type inference (var) to make the second option as valid as the first one.
var object = new Object() {
public void a() {}
};
object.a();
answered 1 hour ago
Andrew Tobilko
25.6k104184
6
Interesting to know that thevarkeyword changes things here...
– ernest_k
1 hour ago
add a comment |
java.lang.Object has no a methods declared (2), while the anonymous class returned by the class instance creation expression new Object() { public void a() {} } does (1).
Use local variable type inference (var) to make the second option as valid as the first one.
var object = new Object() {
public void a() {}
};
object.a();
answered 1 hour ago
Andrew Tobilko
25.6k104184
6
Interesting to know that thevarkeyword changes things here...
– ernest_k
1 hour ago
add a comment |
java.lang.Object has no a methods declared (2), while the anonymous class returned by the class instance creation expression new Object() { public void a() {} } does (1).
Use local variable type inference (var) to make the second option as valid as the first one.
var object = new Object() {
public void a() {}
};
object.a();
answered 1 hour ago
Andrew Tobilko
25.6k104184
java.lang.Object has no a methods declared (2), while the anonymous class returned by the class instance creation expression new Object() { public void a() {} } does (1).
Use local variable type inference (var) to make the second option as valid as the first one.
var object = new Object() {
public void a() {}
};
object.a();
answered 1 hour ago
Andrew Tobilko
25.6k104184
edited 1 hour ago
answered 1 hour ago
Andrew Tobilko
25.6k104184
answered 1 hour ago
Andrew Tobilko
25.6k104184
answered 1 hour ago
Andrew Tobilko
25.6k104184
25.6k104184
6
Interesting to know that thevarkeyword changes things here...
– ernest_k
1 hour ago
add a comment |
6
Interesting to know that thevarkeyword changes things here...
– ernest_k
1 hour ago
6
6
Interesting to know that the
var keyword changes things here...– ernest_k
1 hour ago
Interesting to know that the
var keyword changes things here...– ernest_k
1 hour ago
add a comment |
Sekonoishi Kamiki is a new contributor. Be nice, and check out our Code of Conduct.
Sekonoishi Kamiki is a new contributor. Be nice, and check out our Code of Conduct.
Sekonoishi Kamiki is a new contributor. Be nice, and check out our Code of Conduct.
Sekonoishi Kamiki is a new contributor. Be nice, and check out our Code of Conduct.
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2
ais only in scope locally. When you try to access it in the second block, it is out of scope– GBlodgett
2 hours ago
2
Because
a()is not a method of theObjectclass– Federico Peralta Schaffner
1 hour ago