Elementary Linear Algebra Proof [closed]
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Having a little a trouble with this one just some review I was doing on proofs, haven't done them in a while.
linear-algebra proof-writing
edited Nov 28 '18 at 18:43
amWhy
192k28225439
asked Feb 23 '18 at 5:09
Sharath ZotisSharath Zotis
125
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closed as off-topic by amWhy, Brahadeesh, Alexander Gruber♦ Nov 30 '18 at 3:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Brahadeesh, Alexander Gruber
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
Image of question:
End image of question.
Having a little a trouble with this one just some review I was doing on proofs, haven't done them in a while.
linear-algebra proof-writing
edited Nov 28 '18 at 18:43
amWhy
192k28225439
asked Feb 23 '18 at 5:09
Sharath ZotisSharath Zotis
125
$endgroup$
closed as off-topic by amWhy, Brahadeesh, Alexander Gruber♦ Nov 30 '18 at 3:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Brahadeesh, Alexander Gruber
If this question can be reworded to fit the rules in the help center, please edit the question.
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multiply your matrix and an arbitrary matrix in both orders and solve a system of linear equations
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– qbert
Feb 23 '18 at 5:15
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hint: eigenvalues of P are 2 and 3 then what are the eigenvectors of P?
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– zimbra314
Feb 23 '18 at 6:03
add a comment |
$begingroup$
Image of question:
End image of question.
Having a little a trouble with this one just some review I was doing on proofs, haven't done them in a while.
linear-algebra proof-writing
edited Nov 28 '18 at 18:43
amWhy
192k28225439
asked Feb 23 '18 at 5:09
Sharath ZotisSharath Zotis
125
$endgroup$
Image of question:
End image of question.
Having a little a trouble with this one just some review I was doing on proofs, haven't done them in a while.
linear-algebra proof-writing
linear-algebra proof-writing
edited Nov 28 '18 at 18:43
amWhy
192k28225439
asked Feb 23 '18 at 5:09
Sharath ZotisSharath Zotis
125
edited Nov 28 '18 at 18:43
amWhy
192k28225439
asked Feb 23 '18 at 5:09
Sharath ZotisSharath Zotis
125
edited Nov 28 '18 at 18:43
amWhy
192k28225439
edited Nov 28 '18 at 18:43
amWhy
192k28225439
edited Nov 28 '18 at 18:43
amWhy
192k28225439
192k28225439
asked Feb 23 '18 at 5:09
Sharath ZotisSharath Zotis
125
asked Feb 23 '18 at 5:09
Sharath ZotisSharath Zotis
125
asked Feb 23 '18 at 5:09
Sharath ZotisSharath Zotis
125
125
closed as off-topic by amWhy, Brahadeesh, Alexander Gruber♦ Nov 30 '18 at 3:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Brahadeesh, Alexander Gruber
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by amWhy, Brahadeesh, Alexander Gruber♦ Nov 30 '18 at 3:30
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – amWhy, Brahadeesh, Alexander Gruber
If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
multiply your matrix and an arbitrary matrix in both orders and solve a system of linear equations
$endgroup$
– qbert
Feb 23 '18 at 5:15
$begingroup$
hint: eigenvalues of P are 2 and 3 then what are the eigenvectors of P?
$endgroup$
– zimbra314
Feb 23 '18 at 6:03
add a comment |
$begingroup$
multiply your matrix and an arbitrary matrix in both orders and solve a system of linear equations
$endgroup$
– qbert
Feb 23 '18 at 5:15
$begingroup$
hint: eigenvalues of P are 2 and 3 then what are the eigenvectors of P?
$endgroup$
– zimbra314
Feb 23 '18 at 6:03
$begingroup$
multiply your matrix and an arbitrary matrix in both orders and solve a system of linear equations
$endgroup$
– qbert
Feb 23 '18 at 5:15
$begingroup$
multiply your matrix and an arbitrary matrix in both orders and solve a system of linear equations
$endgroup$
– qbert
Feb 23 '18 at 5:15
$begingroup$
hint: eigenvalues of P are 2 and 3 then what are the eigenvectors of P?
$endgroup$
– zimbra314
Feb 23 '18 at 6:03
$begingroup$
hint: eigenvalues of P are 2 and 3 then what are the eigenvectors of P?
$endgroup$
– zimbra314
Feb 23 '18 at 6:03
add a comment |
1 Answer
1
active
oldest
votes
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Let $A=left[ begin{matrix} a & b \ c & d end{matrix}right]$. Then compute $AP$ and $PA$.
We get
$AP=PA iff 2a+c=2a, 2b+d=a+3b, 3c=2c$ and $3d+c=3d$.
It is now easy to see that
$AP=PA iff c=0$ and $d=a+b$.
answered Feb 23 '18 at 7:34
FredFred
44.4k1845
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add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Let $A=left[ begin{matrix} a & b \ c & d end{matrix}right]$. Then compute $AP$ and $PA$.
We get
$AP=PA iff 2a+c=2a, 2b+d=a+3b, 3c=2c$ and $3d+c=3d$.
It is now easy to see that
$AP=PA iff c=0$ and $d=a+b$.
answered Feb 23 '18 at 7:34
FredFred
44.4k1845
$endgroup$
add a comment |
$begingroup$
Let $A=left[ begin{matrix} a & b \ c & d end{matrix}right]$. Then compute $AP$ and $PA$.
We get
$AP=PA iff 2a+c=2a, 2b+d=a+3b, 3c=2c$ and $3d+c=3d$.
It is now easy to see that
$AP=PA iff c=0$ and $d=a+b$.
answered Feb 23 '18 at 7:34
FredFred
44.4k1845
$endgroup$
add a comment |
$begingroup$
Let $A=left[ begin{matrix} a & b \ c & d end{matrix}right]$. Then compute $AP$ and $PA$.
We get
$AP=PA iff 2a+c=2a, 2b+d=a+3b, 3c=2c$ and $3d+c=3d$.
It is now easy to see that
$AP=PA iff c=0$ and $d=a+b$.
answered Feb 23 '18 at 7:34
FredFred
44.4k1845
$endgroup$
Let $A=left[ begin{matrix} a & b \ c & d end{matrix}right]$. Then compute $AP$ and $PA$.
We get
$AP=PA iff 2a+c=2a, 2b+d=a+3b, 3c=2c$ and $3d+c=3d$.
It is now easy to see that
$AP=PA iff c=0$ and $d=a+b$.
answered Feb 23 '18 at 7:34
FredFred
44.4k1845
answered Feb 23 '18 at 7:34
FredFred
44.4k1845
answered Feb 23 '18 at 7:34
FredFred
44.4k1845
answered Feb 23 '18 at 7:34
FredFred
44.4k1845
44.4k1845
add a comment |
add a comment |
$begingroup$
multiply your matrix and an arbitrary matrix in both orders and solve a system of linear equations
$endgroup$
– qbert
Feb 23 '18 at 5:15
$begingroup$
hint: eigenvalues of P are 2 and 3 then what are the eigenvectors of P?
$endgroup$
– zimbra314
Feb 23 '18 at 6:03