How do describe the composition of an indicator function?
I have an indicator function:
I have to describe the composition in this form:
I replaced the 'n' value with the function but I cannot simplify it, how can one describe and simplify the composition of an indicator function?
linear-algebra function-and-relation-composition
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I have an indicator function:
I have to describe the composition in this form:
I replaced the 'n' value with the function but I cannot simplify it, how can one describe and simplify the composition of an indicator function?
linear-algebra function-and-relation-composition
add a comment |
I have an indicator function:
I have to describe the composition in this form:
I replaced the 'n' value with the function but I cannot simplify it, how can one describe and simplify the composition of an indicator function?
linear-algebra function-and-relation-composition
I have an indicator function:
I have to describe the composition in this form:
I replaced the 'n' value with the function but I cannot simplify it, how can one describe and simplify the composition of an indicator function?
linear-algebra function-and-relation-composition
linear-algebra function-and-relation-composition
edited Nov 27 '18 at 21:58
user604574
asked Nov 27 '18 at 21:27
user604574user604574
166
166
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1 Answer
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Hint: Calculate $f(f(n))$ for $0le nle4$, for $n=5, 6$, and for $n>6$.
Thanks for your answer, is this the usual method? How did you choose those 'n' values?
– user604574
Nov 27 '18 at 22:27
It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
– Berci
Nov 27 '18 at 22:30
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
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active
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Hint: Calculate $f(f(n))$ for $0le nle4$, for $n=5, 6$, and for $n>6$.
Thanks for your answer, is this the usual method? How did you choose those 'n' values?
– user604574
Nov 27 '18 at 22:27
It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
– Berci
Nov 27 '18 at 22:30
add a comment |
Hint: Calculate $f(f(n))$ for $0le nle4$, for $n=5, 6$, and for $n>6$.
Thanks for your answer, is this the usual method? How did you choose those 'n' values?
– user604574
Nov 27 '18 at 22:27
It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
– Berci
Nov 27 '18 at 22:30
add a comment |
Hint: Calculate $f(f(n))$ for $0le nle4$, for $n=5, 6$, and for $n>6$.
Hint: Calculate $f(f(n))$ for $0le nle4$, for $n=5, 6$, and for $n>6$.
answered Nov 27 '18 at 22:16
BerciBerci
59.8k23672
59.8k23672
Thanks for your answer, is this the usual method? How did you choose those 'n' values?
– user604574
Nov 27 '18 at 22:27
It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
– Berci
Nov 27 '18 at 22:30
add a comment |
Thanks for your answer, is this the usual method? How did you choose those 'n' values?
– user604574
Nov 27 '18 at 22:27
It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
– Berci
Nov 27 '18 at 22:30
Thanks for your answer, is this the usual method? How did you choose those 'n' values?
– user604574
Nov 27 '18 at 22:27
Thanks for your answer, is this the usual method? How did you choose those 'n' values?
– user604574
Nov 27 '18 at 22:27
It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
– Berci
Nov 27 '18 at 22:30
It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
– Berci
Nov 27 '18 at 22:30
add a comment |
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