Schur product decomposition of Doubly stochastic matrix












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It is true that for any unitary matrix $U$ a Schur product of the following form
$$A=U^*circ U$$
,where $U^*$ is the complex conjugate of $U$, is a doubly stochastic matrix. However, is the converse of this fact true? In other words, for arbitrary doubly stochastic matrix $A$, does there exist a unitary matrix such that $A=U^*circ U$ holds?










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    It is true that for any unitary matrix $U$ a Schur product of the following form
    $$A=U^*circ U$$
    ,where $U^*$ is the complex conjugate of $U$, is a doubly stochastic matrix. However, is the converse of this fact true? In other words, for arbitrary doubly stochastic matrix $A$, does there exist a unitary matrix such that $A=U^*circ U$ holds?










    share|cite|improve this question



























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      It is true that for any unitary matrix $U$ a Schur product of the following form
      $$A=U^*circ U$$
      ,where $U^*$ is the complex conjugate of $U$, is a doubly stochastic matrix. However, is the converse of this fact true? In other words, for arbitrary doubly stochastic matrix $A$, does there exist a unitary matrix such that $A=U^*circ U$ holds?










      share|cite|improve this question















      It is true that for any unitary matrix $U$ a Schur product of the following form
      $$A=U^*circ U$$
      ,where $U^*$ is the complex conjugate of $U$, is a doubly stochastic matrix. However, is the converse of this fact true? In other words, for arbitrary doubly stochastic matrix $A$, does there exist a unitary matrix such that $A=U^*circ U$ holds?







      matrix-decomposition






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      share|cite|improve this question













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      edited Nov 28 '18 at 5:46







      generic properties

















      asked Nov 28 '18 at 5:27









      generic propertiesgeneric properties

      447217




      447217






















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