Relative transmission delay to propagation delay
I was given the following problem:
Assume propagation delay is less than transmission delay on a link
connecting host A to B. If host A starts transmission at t=0, at
time equal to transmission delay, where is the first bit of the
packet?
With the solution being that the first bit has reached Host B.
However, I am having trouble understanding it. If the transmission delay has elapsed, then wouldn't the packed have just been transmitted and therefore would be on the wire still? Shouldn't the first bit reach Host B after the transmission delay + the propagation delay, regardless of how large they are in proportion to each other? In other words, how could the packet transmit AND propagate in just the time it takes to transmit?
networking
asked Jan 19 at 18:58
ParadoxParadox
194216
add a comment |
I was given the following problem:
Assume propagation delay is less than transmission delay on a link
connecting host A to B. If host A starts transmission at t=0, at
time equal to transmission delay, where is the first bit of the
packet?
With the solution being that the first bit has reached Host B.
However, I am having trouble understanding it. If the transmission delay has elapsed, then wouldn't the packed have just been transmitted and therefore would be on the wire still? Shouldn't the first bit reach Host B after the transmission delay + the propagation delay, regardless of how large they are in proportion to each other? In other words, how could the packet transmit AND propagate in just the time it takes to transmit?
networking
asked Jan 19 at 18:58
ParadoxParadox
194216
add a comment |
I was given the following problem:
Assume propagation delay is less than transmission delay on a link
connecting host A to B. If host A starts transmission at t=0, at
time equal to transmission delay, where is the first bit of the
packet?
With the solution being that the first bit has reached Host B.
However, I am having trouble understanding it. If the transmission delay has elapsed, then wouldn't the packed have just been transmitted and therefore would be on the wire still? Shouldn't the first bit reach Host B after the transmission delay + the propagation delay, regardless of how large they are in proportion to each other? In other words, how could the packet transmit AND propagate in just the time it takes to transmit?
networking
asked Jan 19 at 18:58
ParadoxParadox
194216
I was given the following problem:
Assume propagation delay is less than transmission delay on a link
connecting host A to B. If host A starts transmission at t=0, at
time equal to transmission delay, where is the first bit of the
packet?
With the solution being that the first bit has reached Host B.
However, I am having trouble understanding it. If the transmission delay has elapsed, then wouldn't the packed have just been transmitted and therefore would be on the wire still? Shouldn't the first bit reach Host B after the transmission delay + the propagation delay, regardless of how large they are in proportion to each other? In other words, how could the packet transmit AND propagate in just the time it takes to transmit?
networking
networking
asked Jan 19 at 18:58
ParadoxParadox
194216
asked Jan 19 at 18:58
ParadoxParadox
194216
asked Jan 19 at 18:58
ParadoxParadox
194216
asked Jan 19 at 18:58
ParadoxParadox
194216
asked Jan 19 at 18:58
ParadoxParadox
194216
194216
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You are right: Part of the packet might still be on the wire, but the first bit of the packet has already reached Host B.
- The transmission delay is the time interval from when Host A sends a packet to when the last bit of the packet leaves host A
- The propagation delay is the time interval from when any bit (including the first) of the packet leaves host A until the same bit arrives at host B
So since the propagation delay is less than the transmission delay the first bit has already arrived at host B.
answered Jan 19 at 19:12
Eugen RieckEugen Rieck
10.9k22429
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You are right: Part of the packet might still be on the wire, but the first bit of the packet has already reached Host B.
- The transmission delay is the time interval from when Host A sends a packet to when the last bit of the packet leaves host A
- The propagation delay is the time interval from when any bit (including the first) of the packet leaves host A until the same bit arrives at host B
So since the propagation delay is less than the transmission delay the first bit has already arrived at host B.
answered Jan 19 at 19:12
Eugen RieckEugen Rieck
10.9k22429
add a comment |
You are right: Part of the packet might still be on the wire, but the first bit of the packet has already reached Host B.
- The transmission delay is the time interval from when Host A sends a packet to when the last bit of the packet leaves host A
- The propagation delay is the time interval from when any bit (including the first) of the packet leaves host A until the same bit arrives at host B
So since the propagation delay is less than the transmission delay the first bit has already arrived at host B.
answered Jan 19 at 19:12
Eugen RieckEugen Rieck
10.9k22429
add a comment |
You are right: Part of the packet might still be on the wire, but the first bit of the packet has already reached Host B.
- The transmission delay is the time interval from when Host A sends a packet to when the last bit of the packet leaves host A
- The propagation delay is the time interval from when any bit (including the first) of the packet leaves host A until the same bit arrives at host B
So since the propagation delay is less than the transmission delay the first bit has already arrived at host B.
answered Jan 19 at 19:12
Eugen RieckEugen Rieck
10.9k22429
You are right: Part of the packet might still be on the wire, but the first bit of the packet has already reached Host B.
- The transmission delay is the time interval from when Host A sends a packet to when the last bit of the packet leaves host A
- The propagation delay is the time interval from when any bit (including the first) of the packet leaves host A until the same bit arrives at host B
So since the propagation delay is less than the transmission delay the first bit has already arrived at host B.
answered Jan 19 at 19:12
Eugen RieckEugen Rieck
10.9k22429
answered Jan 19 at 19:12
Eugen RieckEugen Rieck
10.9k22429
answered Jan 19 at 19:12
Eugen RieckEugen Rieck
10.9k22429
answered Jan 19 at 19:12
Eugen RieckEugen Rieck
10.9k22429
10.9k22429
add a comment |
add a comment |
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