Is it possible to solve this or too many unknowns?
$begingroup$
Here are what I know.
- Length of $AB$ is known (and is variable)
- Lines with arrows are parallel
$ A$ and $B$ are right angle to each other (not sure if this is the correct term)- Angle $A$ is known (and is variable)
$AC$ is the bisector of angle $ A$
What I need to find is $AC$
Is it possible to find a formula to get length of $AC$?
geometry
$endgroup$
add a comment |
$begingroup$
Here are what I know.
- Length of $AB$ is known (and is variable)
- Lines with arrows are parallel
$ A$ and $B$ are right angle to each other (not sure if this is the correct term)- Angle $A$ is known (and is variable)
$AC$ is the bisector of angle $ A$
What I need to find is $AC$
Is it possible to find a formula to get length of $AC$?
geometry
$endgroup$
add a comment |
$begingroup$
Here are what I know.
- Length of $AB$ is known (and is variable)
- Lines with arrows are parallel
$ A$ and $B$ are right angle to each other (not sure if this is the correct term)- Angle $A$ is known (and is variable)
$AC$ is the bisector of angle $ A$
What I need to find is $AC$
Is it possible to find a formula to get length of $AC$?
geometry
$endgroup$
Here are what I know.
- Length of $AB$ is known (and is variable)
- Lines with arrows are parallel
$ A$ and $B$ are right angle to each other (not sure if this is the correct term)- Angle $A$ is known (and is variable)
$AC$ is the bisector of angle $ A$
What I need to find is $AC$
Is it possible to find a formula to get length of $AC$?
geometry
geometry
edited Dec 20 '18 at 14:48
Ergec
asked Dec 19 '18 at 6:48
ErgecErgec
1156
1156
add a comment |
add a comment |
1 Answer
1
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oldest
votes
$begingroup$
$textbf{Hint:}$ Vertical angles are equal and Alternate interior angles are equal. $$sinleft(dfrac{A}{2}right)=dfrac{AB}{AC}$$
$endgroup$
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
$textbf{Hint:}$ Vertical angles are equal and Alternate interior angles are equal. $$sinleft(dfrac{A}{2}right)=dfrac{AB}{AC}$$
$endgroup$
add a comment |
$begingroup$
$textbf{Hint:}$ Vertical angles are equal and Alternate interior angles are equal. $$sinleft(dfrac{A}{2}right)=dfrac{AB}{AC}$$
$endgroup$
add a comment |
$begingroup$
$textbf{Hint:}$ Vertical angles are equal and Alternate interior angles are equal. $$sinleft(dfrac{A}{2}right)=dfrac{AB}{AC}$$
$endgroup$
$textbf{Hint:}$ Vertical angles are equal and Alternate interior angles are equal. $$sinleft(dfrac{A}{2}right)=dfrac{AB}{AC}$$
edited Dec 19 '18 at 7:01
answered Dec 19 '18 at 6:54
Yadati KiranYadati Kiran
2,1161622
2,1161622
add a comment |
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