Embedding of two normed vector spaces
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Let $V,U$ be two normed vector spaces such that $V subset U$.
If people say $i$ is an embedding of $V to U$, do they mean that $i$ is the identity map which is well-defined since $V subset U$?
functional-analysis
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up vote
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Let $V,U$ be two normed vector spaces such that $V subset U$.
If people say $i$ is an embedding of $V to U$, do they mean that $i$ is the identity map which is well-defined since $V subset U$?
functional-analysis
Is the restriction of the identity map to $V$. In general, en embedding is an injective morphism, so that you may identify its domain with its image
– Alonso Delfín
Nov 14 at 21:44
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Let $V,U$ be two normed vector spaces such that $V subset U$.
If people say $i$ is an embedding of $V to U$, do they mean that $i$ is the identity map which is well-defined since $V subset U$?
functional-analysis
Let $V,U$ be two normed vector spaces such that $V subset U$.
If people say $i$ is an embedding of $V to U$, do they mean that $i$ is the identity map which is well-defined since $V subset U$?
functional-analysis
functional-analysis
asked Nov 14 at 20:36
mmnn
323
323
Is the restriction of the identity map to $V$. In general, en embedding is an injective morphism, so that you may identify its domain with its image
– Alonso Delfín
Nov 14 at 21:44
add a comment |
Is the restriction of the identity map to $V$. In general, en embedding is an injective morphism, so that you may identify its domain with its image
– Alonso Delfín
Nov 14 at 21:44
Is the restriction of the identity map to $V$. In general, en embedding is an injective morphism, so that you may identify its domain with its image
– Alonso Delfín
Nov 14 at 21:44
Is the restriction of the identity map to $V$. In general, en embedding is an injective morphism, so that you may identify its domain with its image
– Alonso Delfín
Nov 14 at 21:44
add a comment |
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Is the restriction of the identity map to $V$. In general, en embedding is an injective morphism, so that you may identify its domain with its image
– Alonso Delfín
Nov 14 at 21:44