Generalisation of a term (bSc)
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Someone tell me how that 
underlined term is generalised.
I mean
I know how solve such questions but i didn't get that underlined.
I got my ans. About generalization but still i'm confused about the -1
How is it generalised?
calculus
asked Nov 15 at 1:25
Akash
586
|
show 3 more comments
up vote
0
down vote
favorite
Someone tell me how that underlined term is generalised.
I mean
I know how solve such questions but i didn't get that underlined.
I got my ans. About generalization but still i'm confused about the -1
How is it generalised?
calculus
asked Nov 15 at 1:25
Akash
586
1
Just try to predict $y_8(0) $, $y_{10}(0)$ as the book have done you will get the answer.
– Sujit Bhattacharyya
Nov 15 at 1:29
Yeah it is making a pattern like
– Akash
Nov 15 at 1:38
Product of square of n +ve even numbers
– Akash
Nov 15 at 1:39
1
Correct! now try to generalize the pattern and try to verify it for $y_{12}(0)$ and calculate $y_{12}(0)$ manually.
– Sujit Bhattacharyya
Nov 15 at 1:40
But what about the -ve 1
– Akash
Nov 15 at 1:40
|
show 3 more comments
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Someone tell me how that underlined term is generalised.
I mean
I know how solve such questions but i didn't get that underlined.
I got my ans. About generalization but still i'm confused about the -1
How is it generalised?
calculus
asked Nov 15 at 1:25
Akash
586
Someone tell me how that underlined term is generalised.
I mean
I know how solve such questions but i didn't get that underlined.
I got my ans. About generalization but still i'm confused about the -1
How is it generalised?
calculus
calculus
asked Nov 15 at 1:25
Akash
586
asked Nov 15 at 1:25
Akash
586
edited Nov 15 at 1:45
asked Nov 15 at 1:25
Akash
586
asked Nov 15 at 1:25
Akash
586
asked Nov 15 at 1:25
Akash
586
586
1
Just try to predict $y_8(0) $, $y_{10}(0)$ as the book have done you will get the answer.
– Sujit Bhattacharyya
Nov 15 at 1:29
Yeah it is making a pattern like
– Akash
Nov 15 at 1:38
Product of square of n +ve even numbers
– Akash
Nov 15 at 1:39
1
Correct! now try to generalize the pattern and try to verify it for $y_{12}(0)$ and calculate $y_{12}(0)$ manually.
– Sujit Bhattacharyya
Nov 15 at 1:40
But what about the -ve 1
– Akash
Nov 15 at 1:40
|
show 3 more comments
1
Just try to predict $y_8(0) $, $y_{10}(0)$ as the book have done you will get the answer.
– Sujit Bhattacharyya
Nov 15 at 1:29
Yeah it is making a pattern like
– Akash
Nov 15 at 1:38
Product of square of n +ve even numbers
– Akash
Nov 15 at 1:39
1
Correct! now try to generalize the pattern and try to verify it for $y_{12}(0)$ and calculate $y_{12}(0)$ manually.
– Sujit Bhattacharyya
Nov 15 at 1:40
But what about the -ve 1
– Akash
Nov 15 at 1:40
1
1
Just try to predict $y_8(0) $, $y_{10}(0)$ as the book have done you will get the answer.
– Sujit Bhattacharyya
Nov 15 at 1:29
Just try to predict $y_8(0) $, $y_{10}(0)$ as the book have done you will get the answer.
– Sujit Bhattacharyya
Nov 15 at 1:29
Yeah it is making a pattern like
– Akash
Nov 15 at 1:38
Yeah it is making a pattern like
– Akash
Nov 15 at 1:38
Product of square of n +ve even numbers
– Akash
Nov 15 at 1:39
Product of square of n +ve even numbers
– Akash
Nov 15 at 1:39
1
1
Correct! now try to generalize the pattern and try to verify it for $y_{12}(0)$ and calculate $y_{12}(0)$ manually.
– Sujit Bhattacharyya
Nov 15 at 1:40
Correct! now try to generalize the pattern and try to verify it for $y_{12}(0)$ and calculate $y_{12}(0)$ manually.
– Sujit Bhattacharyya
Nov 15 at 1:40
But what about the -ve 1
– Akash
Nov 15 at 1:40
But what about the -ve 1
– Akash
Nov 15 at 1:40
|
show 3 more comments
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Just try to predict $y_8(0) $, $y_{10}(0)$ as the book have done you will get the answer.
– Sujit Bhattacharyya
Nov 15 at 1:29
Yeah it is making a pattern like
– Akash
Nov 15 at 1:38
Product of square of n +ve even numbers
– Akash
Nov 15 at 1:39
1
Correct! now try to generalize the pattern and try to verify it for $y_{12}(0)$ and calculate $y_{12}(0)$ manually.
– Sujit Bhattacharyya
Nov 15 at 1:40
But what about the -ve 1
– Akash
Nov 15 at 1:40