How fast are trips to the Moon for unmanned spacecraft typically?











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The period of an orbit around the Earth is given by:



$$T = 2 pi sqrt{a^3/GM}$$



For Earth GM is about 3.986E+14 m^3/s^2. Put in $a$ = ((6378+400)*1000) for the ISS in LEO (as a test) and you get 5553 seconds, or 92.6 minutes.



Put in $a$ = (384400*1000) for the Moon's orbit and you get 27.5 days, close enough. (We didn't correct for reduced mass).



A ellipse with a perigee in LEO and an apogee at the Moon ($a$ = (195589*1000)) has a period of 10.0 days and a half period of 5.0 days.



But the Apollo times from LEO to the Moon were only about 3.0 to 3.3 days, and Chang'e-4 will only be about 3.9 days Liftoff at 18:23 on 7 December UTC and lunar orbit on ~1500 hour UTC on December 11th. See also this answer.



Are most trips to the Moon actually around 3 or 4 days, and not the 5.0 days of a half-ellipse?



Or is there something about the mass of the Moon that makes the trip naturally quicker?










share|improve this question
























  • Is the formula for the orbit around the Earth applicable for a Earth-Moon transfer trajectory? The trajectory closer to the Moon is influenced by both the gravity of Earth and Moon.
    – Uwe
    2 days ago










  • @Uwe I had just added one more sentence at the bottom, seems like that occurred to both of us at the same time. Maybe you can just write a short answer?
    – uhoh
    2 days ago






  • 2




    Not a full answer but a few things to consider - the 10-day ellipse doesn't count for the Moon's gravity which is significant on approach. Also, some Apollo and other missions aimed for an apogee not at the Moon's altitude for free return
    – Jack
    2 days ago






  • 2




    @uhoh: I should be able to do an alternative calculation of the trajectory as a three body problem to write an answer. But I don't know an easy and short way to do that. May be patched conics could be used.
    – Uwe
    2 days ago






  • 2




    Lunar Orbiters 1-5 were all about 3.8-3.9 days launch-to-lunar-orbit. A quick skim of the Soviet Luna series has most of them at around 3.5 days.
    – Russell Borogove
    2 days ago















up vote
1
down vote

favorite












The period of an orbit around the Earth is given by:



$$T = 2 pi sqrt{a^3/GM}$$



For Earth GM is about 3.986E+14 m^3/s^2. Put in $a$ = ((6378+400)*1000) for the ISS in LEO (as a test) and you get 5553 seconds, or 92.6 minutes.



Put in $a$ = (384400*1000) for the Moon's orbit and you get 27.5 days, close enough. (We didn't correct for reduced mass).



A ellipse with a perigee in LEO and an apogee at the Moon ($a$ = (195589*1000)) has a period of 10.0 days and a half period of 5.0 days.



But the Apollo times from LEO to the Moon were only about 3.0 to 3.3 days, and Chang'e-4 will only be about 3.9 days Liftoff at 18:23 on 7 December UTC and lunar orbit on ~1500 hour UTC on December 11th. See also this answer.



Are most trips to the Moon actually around 3 or 4 days, and not the 5.0 days of a half-ellipse?



Or is there something about the mass of the Moon that makes the trip naturally quicker?










share|improve this question
























  • Is the formula for the orbit around the Earth applicable for a Earth-Moon transfer trajectory? The trajectory closer to the Moon is influenced by both the gravity of Earth and Moon.
    – Uwe
    2 days ago










  • @Uwe I had just added one more sentence at the bottom, seems like that occurred to both of us at the same time. Maybe you can just write a short answer?
    – uhoh
    2 days ago






  • 2




    Not a full answer but a few things to consider - the 10-day ellipse doesn't count for the Moon's gravity which is significant on approach. Also, some Apollo and other missions aimed for an apogee not at the Moon's altitude for free return
    – Jack
    2 days ago






  • 2




    @uhoh: I should be able to do an alternative calculation of the trajectory as a three body problem to write an answer. But I don't know an easy and short way to do that. May be patched conics could be used.
    – Uwe
    2 days ago






  • 2




    Lunar Orbiters 1-5 were all about 3.8-3.9 days launch-to-lunar-orbit. A quick skim of the Soviet Luna series has most of them at around 3.5 days.
    – Russell Borogove
    2 days ago













up vote
1
down vote

favorite









up vote
1
down vote

favorite











The period of an orbit around the Earth is given by:



$$T = 2 pi sqrt{a^3/GM}$$



For Earth GM is about 3.986E+14 m^3/s^2. Put in $a$ = ((6378+400)*1000) for the ISS in LEO (as a test) and you get 5553 seconds, or 92.6 minutes.



Put in $a$ = (384400*1000) for the Moon's orbit and you get 27.5 days, close enough. (We didn't correct for reduced mass).



A ellipse with a perigee in LEO and an apogee at the Moon ($a$ = (195589*1000)) has a period of 10.0 days and a half period of 5.0 days.



But the Apollo times from LEO to the Moon were only about 3.0 to 3.3 days, and Chang'e-4 will only be about 3.9 days Liftoff at 18:23 on 7 December UTC and lunar orbit on ~1500 hour UTC on December 11th. See also this answer.



Are most trips to the Moon actually around 3 or 4 days, and not the 5.0 days of a half-ellipse?



Or is there something about the mass of the Moon that makes the trip naturally quicker?










share|improve this question















The period of an orbit around the Earth is given by:



$$T = 2 pi sqrt{a^3/GM}$$



For Earth GM is about 3.986E+14 m^3/s^2. Put in $a$ = ((6378+400)*1000) for the ISS in LEO (as a test) and you get 5553 seconds, or 92.6 minutes.



Put in $a$ = (384400*1000) for the Moon's orbit and you get 27.5 days, close enough. (We didn't correct for reduced mass).



A ellipse with a perigee in LEO and an apogee at the Moon ($a$ = (195589*1000)) has a period of 10.0 days and a half period of 5.0 days.



But the Apollo times from LEO to the Moon were only about 3.0 to 3.3 days, and Chang'e-4 will only be about 3.9 days Liftoff at 18:23 on 7 December UTC and lunar orbit on ~1500 hour UTC on December 11th. See also this answer.



Are most trips to the Moon actually around 3 or 4 days, and not the 5.0 days of a half-ellipse?



Or is there something about the mass of the Moon that makes the trip naturally quicker?







orbital-mechanics planning cislunar






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago

























asked 2 days ago









uhoh

34.1k17117417




34.1k17117417












  • Is the formula for the orbit around the Earth applicable for a Earth-Moon transfer trajectory? The trajectory closer to the Moon is influenced by both the gravity of Earth and Moon.
    – Uwe
    2 days ago










  • @Uwe I had just added one more sentence at the bottom, seems like that occurred to both of us at the same time. Maybe you can just write a short answer?
    – uhoh
    2 days ago






  • 2




    Not a full answer but a few things to consider - the 10-day ellipse doesn't count for the Moon's gravity which is significant on approach. Also, some Apollo and other missions aimed for an apogee not at the Moon's altitude for free return
    – Jack
    2 days ago






  • 2




    @uhoh: I should be able to do an alternative calculation of the trajectory as a three body problem to write an answer. But I don't know an easy and short way to do that. May be patched conics could be used.
    – Uwe
    2 days ago






  • 2




    Lunar Orbiters 1-5 were all about 3.8-3.9 days launch-to-lunar-orbit. A quick skim of the Soviet Luna series has most of them at around 3.5 days.
    – Russell Borogove
    2 days ago


















  • Is the formula for the orbit around the Earth applicable for a Earth-Moon transfer trajectory? The trajectory closer to the Moon is influenced by both the gravity of Earth and Moon.
    – Uwe
    2 days ago










  • @Uwe I had just added one more sentence at the bottom, seems like that occurred to both of us at the same time. Maybe you can just write a short answer?
    – uhoh
    2 days ago






  • 2




    Not a full answer but a few things to consider - the 10-day ellipse doesn't count for the Moon's gravity which is significant on approach. Also, some Apollo and other missions aimed for an apogee not at the Moon's altitude for free return
    – Jack
    2 days ago






  • 2




    @uhoh: I should be able to do an alternative calculation of the trajectory as a three body problem to write an answer. But I don't know an easy and short way to do that. May be patched conics could be used.
    – Uwe
    2 days ago






  • 2




    Lunar Orbiters 1-5 were all about 3.8-3.9 days launch-to-lunar-orbit. A quick skim of the Soviet Luna series has most of them at around 3.5 days.
    – Russell Borogove
    2 days ago
















Is the formula for the orbit around the Earth applicable for a Earth-Moon transfer trajectory? The trajectory closer to the Moon is influenced by both the gravity of Earth and Moon.
– Uwe
2 days ago




Is the formula for the orbit around the Earth applicable for a Earth-Moon transfer trajectory? The trajectory closer to the Moon is influenced by both the gravity of Earth and Moon.
– Uwe
2 days ago












@Uwe I had just added one more sentence at the bottom, seems like that occurred to both of us at the same time. Maybe you can just write a short answer?
– uhoh
2 days ago




@Uwe I had just added one more sentence at the bottom, seems like that occurred to both of us at the same time. Maybe you can just write a short answer?
– uhoh
2 days ago




2




2




Not a full answer but a few things to consider - the 10-day ellipse doesn't count for the Moon's gravity which is significant on approach. Also, some Apollo and other missions aimed for an apogee not at the Moon's altitude for free return
– Jack
2 days ago




Not a full answer but a few things to consider - the 10-day ellipse doesn't count for the Moon's gravity which is significant on approach. Also, some Apollo and other missions aimed for an apogee not at the Moon's altitude for free return
– Jack
2 days ago




2




2




@uhoh: I should be able to do an alternative calculation of the trajectory as a three body problem to write an answer. But I don't know an easy and short way to do that. May be patched conics could be used.
– Uwe
2 days ago




@uhoh: I should be able to do an alternative calculation of the trajectory as a three body problem to write an answer. But I don't know an easy and short way to do that. May be patched conics could be used.
– Uwe
2 days ago




2




2




Lunar Orbiters 1-5 were all about 3.8-3.9 days launch-to-lunar-orbit. A quick skim of the Soviet Luna series has most of them at around 3.5 days.
– Russell Borogove
2 days ago




Lunar Orbiters 1-5 were all about 3.8-3.9 days launch-to-lunar-orbit. A quick skim of the Soviet Luna series has most of them at around 3.5 days.
– Russell Borogove
2 days ago










1 Answer
1






active

oldest

votes

















up vote
4
down vote














Are most trips to the Moon actually around 3 or 4 days, and not the 5.0 days of a half-ellipse?




The 5 spacecraft of the US Lunar Orbiter program took 3.8-3.9 days to reach lunar orbit.



The Ranger and Surveyor missions were on faster trajectories -- around 2.7 days from launch to lunar impact or landing.



The early Soviet Luna series missions that I've looked at took 3.3-3.6 days to reach the moon -- some were orbiters, some were (intentional or unintentional) direct impactors, some were direct soft-landers. The later sample-return missions/attempts (e.g. Luna 20) took 4.5 day flights.



I'm not sure what motivated these different trajectories. Ranger and Surveyor both had solar panels, so shouldn't have been "racing the clock" to complete their missions before batteries ran down. There may have been some drive to make the flights short simply because these early complex spacecraft were not very reliable; you'd want to get to the moon before things broke down.



I don't know if the early lunar projects started from a desired flight time, factored with the available launcher, to determine the maximum spacecraft mass; or if the final design of the spacecraft factored with the launcher to determine the minimum flight time, or some iterated back-and-forth combination thereof.



The Apollo landing flights generally took about 3.3 days from launch to lunar orbit. Apollo 8 was faster, not being burdened with a 15-ton LM, and reached lunar orbit in about 2.9 days.



Some more recent missions have taken much more leisurely approaches, possibly because progressive orbit-raising can be done with a smaller, lighter motor and the hardware is reliable enough to allow the longer flight time.



ISRO's Chandrayaan-1 took two weeks plus another week to reach its final orbit -- obviously not a Hohmann-esque single translunar insertion burn!



Likewise, JAXA's SELENE/Kaguya took more than two weeks to reach lunar orbit.




Or is there something about the mass of the Moon that makes the trip naturally quicker?




At some point in a translunar trajectory, the Moon's gravity does start accelerating the spacecraft toward the destination; for the Apollo missions it would be about 2.5 days into the flight when the moon's gravity began to dominate over the Earth's. So it's not surprising that the flight times would be significantly less than 5 days, but the exact math for the "Hohmann to massive destination" calculation is beyond me.






share|improve this answer























  • wow, somebody's been busy. Thanks!
    – uhoh
    2 days ago











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up vote
4
down vote














Are most trips to the Moon actually around 3 or 4 days, and not the 5.0 days of a half-ellipse?




The 5 spacecraft of the US Lunar Orbiter program took 3.8-3.9 days to reach lunar orbit.



The Ranger and Surveyor missions were on faster trajectories -- around 2.7 days from launch to lunar impact or landing.



The early Soviet Luna series missions that I've looked at took 3.3-3.6 days to reach the moon -- some were orbiters, some were (intentional or unintentional) direct impactors, some were direct soft-landers. The later sample-return missions/attempts (e.g. Luna 20) took 4.5 day flights.



I'm not sure what motivated these different trajectories. Ranger and Surveyor both had solar panels, so shouldn't have been "racing the clock" to complete their missions before batteries ran down. There may have been some drive to make the flights short simply because these early complex spacecraft were not very reliable; you'd want to get to the moon before things broke down.



I don't know if the early lunar projects started from a desired flight time, factored with the available launcher, to determine the maximum spacecraft mass; or if the final design of the spacecraft factored with the launcher to determine the minimum flight time, or some iterated back-and-forth combination thereof.



The Apollo landing flights generally took about 3.3 days from launch to lunar orbit. Apollo 8 was faster, not being burdened with a 15-ton LM, and reached lunar orbit in about 2.9 days.



Some more recent missions have taken much more leisurely approaches, possibly because progressive orbit-raising can be done with a smaller, lighter motor and the hardware is reliable enough to allow the longer flight time.



ISRO's Chandrayaan-1 took two weeks plus another week to reach its final orbit -- obviously not a Hohmann-esque single translunar insertion burn!



Likewise, JAXA's SELENE/Kaguya took more than two weeks to reach lunar orbit.




Or is there something about the mass of the Moon that makes the trip naturally quicker?




At some point in a translunar trajectory, the Moon's gravity does start accelerating the spacecraft toward the destination; for the Apollo missions it would be about 2.5 days into the flight when the moon's gravity began to dominate over the Earth's. So it's not surprising that the flight times would be significantly less than 5 days, but the exact math for the "Hohmann to massive destination" calculation is beyond me.






share|improve this answer























  • wow, somebody's been busy. Thanks!
    – uhoh
    2 days ago















up vote
4
down vote














Are most trips to the Moon actually around 3 or 4 days, and not the 5.0 days of a half-ellipse?




The 5 spacecraft of the US Lunar Orbiter program took 3.8-3.9 days to reach lunar orbit.



The Ranger and Surveyor missions were on faster trajectories -- around 2.7 days from launch to lunar impact or landing.



The early Soviet Luna series missions that I've looked at took 3.3-3.6 days to reach the moon -- some were orbiters, some were (intentional or unintentional) direct impactors, some were direct soft-landers. The later sample-return missions/attempts (e.g. Luna 20) took 4.5 day flights.



I'm not sure what motivated these different trajectories. Ranger and Surveyor both had solar panels, so shouldn't have been "racing the clock" to complete their missions before batteries ran down. There may have been some drive to make the flights short simply because these early complex spacecraft were not very reliable; you'd want to get to the moon before things broke down.



I don't know if the early lunar projects started from a desired flight time, factored with the available launcher, to determine the maximum spacecraft mass; or if the final design of the spacecraft factored with the launcher to determine the minimum flight time, or some iterated back-and-forth combination thereof.



The Apollo landing flights generally took about 3.3 days from launch to lunar orbit. Apollo 8 was faster, not being burdened with a 15-ton LM, and reached lunar orbit in about 2.9 days.



Some more recent missions have taken much more leisurely approaches, possibly because progressive orbit-raising can be done with a smaller, lighter motor and the hardware is reliable enough to allow the longer flight time.



ISRO's Chandrayaan-1 took two weeks plus another week to reach its final orbit -- obviously not a Hohmann-esque single translunar insertion burn!



Likewise, JAXA's SELENE/Kaguya took more than two weeks to reach lunar orbit.




Or is there something about the mass of the Moon that makes the trip naturally quicker?




At some point in a translunar trajectory, the Moon's gravity does start accelerating the spacecraft toward the destination; for the Apollo missions it would be about 2.5 days into the flight when the moon's gravity began to dominate over the Earth's. So it's not surprising that the flight times would be significantly less than 5 days, but the exact math for the "Hohmann to massive destination" calculation is beyond me.






share|improve this answer























  • wow, somebody's been busy. Thanks!
    – uhoh
    2 days ago













up vote
4
down vote










up vote
4
down vote










Are most trips to the Moon actually around 3 or 4 days, and not the 5.0 days of a half-ellipse?




The 5 spacecraft of the US Lunar Orbiter program took 3.8-3.9 days to reach lunar orbit.



The Ranger and Surveyor missions were on faster trajectories -- around 2.7 days from launch to lunar impact or landing.



The early Soviet Luna series missions that I've looked at took 3.3-3.6 days to reach the moon -- some were orbiters, some were (intentional or unintentional) direct impactors, some were direct soft-landers. The later sample-return missions/attempts (e.g. Luna 20) took 4.5 day flights.



I'm not sure what motivated these different trajectories. Ranger and Surveyor both had solar panels, so shouldn't have been "racing the clock" to complete their missions before batteries ran down. There may have been some drive to make the flights short simply because these early complex spacecraft were not very reliable; you'd want to get to the moon before things broke down.



I don't know if the early lunar projects started from a desired flight time, factored with the available launcher, to determine the maximum spacecraft mass; or if the final design of the spacecraft factored with the launcher to determine the minimum flight time, or some iterated back-and-forth combination thereof.



The Apollo landing flights generally took about 3.3 days from launch to lunar orbit. Apollo 8 was faster, not being burdened with a 15-ton LM, and reached lunar orbit in about 2.9 days.



Some more recent missions have taken much more leisurely approaches, possibly because progressive orbit-raising can be done with a smaller, lighter motor and the hardware is reliable enough to allow the longer flight time.



ISRO's Chandrayaan-1 took two weeks plus another week to reach its final orbit -- obviously not a Hohmann-esque single translunar insertion burn!



Likewise, JAXA's SELENE/Kaguya took more than two weeks to reach lunar orbit.




Or is there something about the mass of the Moon that makes the trip naturally quicker?




At some point in a translunar trajectory, the Moon's gravity does start accelerating the spacecraft toward the destination; for the Apollo missions it would be about 2.5 days into the flight when the moon's gravity began to dominate over the Earth's. So it's not surprising that the flight times would be significantly less than 5 days, but the exact math for the "Hohmann to massive destination" calculation is beyond me.






share|improve this answer















Are most trips to the Moon actually around 3 or 4 days, and not the 5.0 days of a half-ellipse?




The 5 spacecraft of the US Lunar Orbiter program took 3.8-3.9 days to reach lunar orbit.



The Ranger and Surveyor missions were on faster trajectories -- around 2.7 days from launch to lunar impact or landing.



The early Soviet Luna series missions that I've looked at took 3.3-3.6 days to reach the moon -- some were orbiters, some were (intentional or unintentional) direct impactors, some were direct soft-landers. The later sample-return missions/attempts (e.g. Luna 20) took 4.5 day flights.



I'm not sure what motivated these different trajectories. Ranger and Surveyor both had solar panels, so shouldn't have been "racing the clock" to complete their missions before batteries ran down. There may have been some drive to make the flights short simply because these early complex spacecraft were not very reliable; you'd want to get to the moon before things broke down.



I don't know if the early lunar projects started from a desired flight time, factored with the available launcher, to determine the maximum spacecraft mass; or if the final design of the spacecraft factored with the launcher to determine the minimum flight time, or some iterated back-and-forth combination thereof.



The Apollo landing flights generally took about 3.3 days from launch to lunar orbit. Apollo 8 was faster, not being burdened with a 15-ton LM, and reached lunar orbit in about 2.9 days.



Some more recent missions have taken much more leisurely approaches, possibly because progressive orbit-raising can be done with a smaller, lighter motor and the hardware is reliable enough to allow the longer flight time.



ISRO's Chandrayaan-1 took two weeks plus another week to reach its final orbit -- obviously not a Hohmann-esque single translunar insertion burn!



Likewise, JAXA's SELENE/Kaguya took more than two weeks to reach lunar orbit.




Or is there something about the mass of the Moon that makes the trip naturally quicker?




At some point in a translunar trajectory, the Moon's gravity does start accelerating the spacecraft toward the destination; for the Apollo missions it would be about 2.5 days into the flight when the moon's gravity began to dominate over the Earth's. So it's not surprising that the flight times would be significantly less than 5 days, but the exact math for the "Hohmann to massive destination" calculation is beyond me.







share|improve this answer














share|improve this answer



share|improve this answer








edited 2 days ago

























answered 2 days ago









Russell Borogove

79.3k2261347




79.3k2261347












  • wow, somebody's been busy. Thanks!
    – uhoh
    2 days ago


















  • wow, somebody's been busy. Thanks!
    – uhoh
    2 days ago
















wow, somebody's been busy. Thanks!
– uhoh
2 days ago




wow, somebody's been busy. Thanks!
– uhoh
2 days ago


















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