Plot of a tornado-shaped surface
10
$begingroup$
What is a simple code to plot a surface shaped like a tornado?
Any help is welcome.
plotting
edited Mar 22 at 11:51
J. M. is slightly pensive♦
98.5k10308466
asked Mar 22 at 2:39
janmarqzjanmarqz
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10
$begingroup$
What is a simple code to plot a surface shaped like a tornado?
Any help is welcome.
plotting
edited Mar 22 at 11:51
J. M. is slightly pensive♦
98.5k10308466
asked Mar 22 at 2:39
janmarqzjanmarqz
1515
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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add a comment |
10
10
10
1
$begingroup$
What is a simple code to plot a surface shaped like a tornado?
Any help is welcome.
plotting
edited Mar 22 at 11:51
J. M. is slightly pensive♦
98.5k10308466
asked Mar 22 at 2:39
janmarqzjanmarqz
1515
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
What is a simple code to plot a surface shaped like a tornado?
Any help is welcome.
plotting
plotting
edited Mar 22 at 11:51
J. M. is slightly pensive♦
98.5k10308466
asked Mar 22 at 2:39
janmarqzjanmarqz
1515
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Mar 22 at 11:51
J. M. is slightly pensive♦
98.5k10308466
asked Mar 22 at 2:39
janmarqzjanmarqz
1515
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Mar 22 at 11:51
J. M. is slightly pensive♦
98.5k10308466
edited Mar 22 at 11:51
J. M. is slightly pensive♦
98.5k10308466
edited Mar 22 at 11:51
J. M. is slightly pensive♦
98.5k10308466
98.5k10308466
asked Mar 22 at 2:39
janmarqzjanmarqz
1515
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 22 at 2:39
janmarqzjanmarqz
1515
asked Mar 22 at 2:39
janmarqzjanmarqz
1515
1515
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
janmarqz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
16
$begingroup$
I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:
With[{h = 1/10, n = 24, c = 4, p = 2/3},
ParametricPlot3D[{t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p},
{t, 0, 3}, {v, 0, 2 π}, Axes -> None, Boxed -> False,
Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
PlotStyle -> Opacity[3/4, Black], ViewPoint -> {3.2, -1.6, 1.}]]
Adjust parameters as seen fit.
answered Mar 22 at 6:01
J. M. is slightly pensive♦J. M. is slightly pensive
98.5k10308466
$endgroup$
5
$begingroup$
(I should prolly do a cartoon of the "tornado" moving about in a random walk...)
$endgroup$
– J. M. is slightly pensive♦
Mar 22 at 12:38
add a comment |
15
$begingroup$
My quick go at it:
ContourPlot3D[
(x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
, {x, -1, 1}, {y, -1, 1}, {z, 0, 2}
, Mesh -> None, Axes -> False, Boxed -> False
, PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
]
answered Mar 22 at 3:32
Thies HeideckeThies Heidecke
7,2712639
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
16
$begingroup$
I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:
With[{h = 1/10, n = 24, c = 4, p = 2/3},
ParametricPlot3D[{t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p},
{t, 0, 3}, {v, 0, 2 π}, Axes -> None, Boxed -> False,
Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
PlotStyle -> Opacity[3/4, Black], ViewPoint -> {3.2, -1.6, 1.}]]
Adjust parameters as seen fit.
answered Mar 22 at 6:01
J. M. is slightly pensive♦J. M. is slightly pensive
98.5k10308466
$endgroup$
5
$begingroup$
(I should prolly do a cartoon of the "tornado" moving about in a random walk...)
$endgroup$
– J. M. is slightly pensive♦
Mar 22 at 12:38
add a comment |
16
$begingroup$
I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:
With[{h = 1/10, n = 24, c = 4, p = 2/3},
ParametricPlot3D[{t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p},
{t, 0, 3}, {v, 0, 2 π}, Axes -> None, Boxed -> False,
Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
PlotStyle -> Opacity[3/4, Black], ViewPoint -> {3.2, -1.6, 1.}]]
Adjust parameters as seen fit.
answered Mar 22 at 6:01
J. M. is slightly pensive♦J. M. is slightly pensive
98.5k10308466
$endgroup$
5
$begingroup$
(I should prolly do a cartoon of the "tornado" moving about in a random walk...)
$endgroup$
– J. M. is slightly pensive♦
Mar 22 at 12:38
add a comment |
16
16
16
$begingroup$
I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:
With[{h = 1/10, n = 24, c = 4, p = 2/3},
ParametricPlot3D[{t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p},
{t, 0, 3}, {v, 0, 2 π}, Axes -> None, Boxed -> False,
Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
PlotStyle -> Opacity[3/4, Black], ViewPoint -> {3.2, -1.6, 1.}]]
Adjust parameters as seen fit.
answered Mar 22 at 6:01
J. M. is slightly pensive♦J. M. is slightly pensive
98.5k10308466
$endgroup$
I like "surface synthesis" questions. Here's a simple-minded model that combines an Archimedean spiral with a power law curve:
With[{h = 1/10, n = 24, c = 4, p = 2/3},
ParametricPlot3D[{t (h Cos[n t] + Cos[v]), t (h Sin[n t] + Sin[v]), (c t)^p},
{t, 0, 3}, {v, 0, 2 π}, Axes -> None, Boxed -> False,
Lighting -> "Neutral", Mesh -> False, PlotPoints -> 85,
PlotStyle -> Opacity[3/4, Black], ViewPoint -> {3.2, -1.6, 1.}]]
Adjust parameters as seen fit.
answered Mar 22 at 6:01
J. M. is slightly pensive♦J. M. is slightly pensive
98.5k10308466
answered Mar 22 at 6:01
J. M. is slightly pensive♦J. M. is slightly pensive
98.5k10308466
answered Mar 22 at 6:01
J. M. is slightly pensive♦J. M. is slightly pensive
98.5k10308466
answered Mar 22 at 6:01
J. M. is slightly pensive♦J. M. is slightly pensive
98.5k10308466
98.5k10308466
5
$begingroup$
(I should prolly do a cartoon of the "tornado" moving about in a random walk...)
$endgroup$
– J. M. is slightly pensive♦
Mar 22 at 12:38
add a comment |
5
$begingroup$
(I should prolly do a cartoon of the "tornado" moving about in a random walk...)
$endgroup$
– J. M. is slightly pensive♦
Mar 22 at 12:38
5
5
$begingroup$
(I should prolly do a cartoon of the "tornado" moving about in a random walk...)
$endgroup$
– J. M. is slightly pensive♦
Mar 22 at 12:38
$begingroup$
(I should prolly do a cartoon of the "tornado" moving about in a random walk...)
$endgroup$
– J. M. is slightly pensive♦
Mar 22 at 12:38
add a comment |
15
$begingroup$
My quick go at it:
ContourPlot3D[
(x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
, {x, -1, 1}, {y, -1, 1}, {z, 0, 2}
, Mesh -> None, Axes -> False, Boxed -> False
, PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
]
answered Mar 22 at 3:32
Thies HeideckeThies Heidecke
7,2712639
$endgroup$
add a comment |
15
$begingroup$
My quick go at it:
ContourPlot3D[
(x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
, {x, -1, 1}, {y, -1, 1}, {z, 0, 2}
, Mesh -> None, Axes -> False, Boxed -> False
, PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
]
answered Mar 22 at 3:32
Thies HeideckeThies Heidecke
7,2712639
$endgroup$
add a comment |
15
15
15
$begingroup$
My quick go at it:
ContourPlot3D[
(x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
, {x, -1, 1}, {y, -1, 1}, {z, 0, 2}
, Mesh -> None, Axes -> False, Boxed -> False
, PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
]
answered Mar 22 at 3:32
Thies HeideckeThies Heidecke
7,2712639
$endgroup$
My quick go at it:
ContourPlot3D[
(x - z/5 Cos[[Pi] z])^2 + (y - z/5 Sin[[Pi] z])^2 == (z/4)^2
, {x, -1, 1}, {y, -1, 1}, {z, 0, 2}
, Mesh -> None, Axes -> False, Boxed -> False
, PlotTheme -> "ThickSurface", ContourStyle -> RGBColor[0.41, 0.5, 0.63]
]
answered Mar 22 at 3:32
Thies HeideckeThies Heidecke
7,2712639
answered Mar 22 at 3:32
Thies HeideckeThies Heidecke
7,2712639
answered Mar 22 at 3:32
Thies HeideckeThies Heidecke
7,2712639
answered Mar 22 at 3:32
Thies HeideckeThies Heidecke
7,2712639
7,2712639
add a comment |
add a comment |
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janmarqz is a new contributor. Be nice, and check out our Code of Conduct.
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