How to get the available space of $HOME as a variable in shell scripting?
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I am writing a bash script
to install a program for different users.
For that I want to make sure that each user has at least 500Mb
available in their $HOME
. My $HOME
directory looks as follows
jen@ser23:~$ df -h
Filesystem Size Used Avail Use% Mounted on
/dev/sda1 2,9G 1,1G 1,7G 40% /
udev 10M 0 10M 0% /dev
tmpfs 13G 826M 12G 7% /run
/dev/sda3 15G 9,8G 4,1G 71% /usr
tmpfs 32G 0 32G 0% /dev/shm
tmpfs 5,0M 0 5,0M 0% /run/lock
tmpfs 32G 0 32G 0% /sys/fs/cgroup
/dev/mapper/local_disk_1-tmp 3,7G 21M 3,7G 1% /tmp
/dev/mapper/local_disk_1-opt 20G 2,0G 18G 10% /opt
/dev/mapper/local_disk_1-project1 401G 287G 114G 72% /project1
/dev/mapper/local_disk_1-var 3,8G 1,7G 1,7G 50% /var
/dev/mapper/local_disk_1-project2 99G 70G 29G 71% /project2
/dev/mapper/local_disk_1-usr_local 2,0G 3,4M 1,9G 1% /usr/local
nfs4.sf0.ise.fhg.de:/g/6/TSB/Archiv 632T 349T 276T 56% /net/p/600/groupdrives/TSB/Archiv
nfs4.sf0.ise.fhg.de:/home 632T 349T 276T 56% /net/home
tmpfs 6,4G 0 6,4G 0% /run/user/12419
tmpfs 6,4G 4,0K 6,4G 1% /run/user/13471
tmpfs 6,4G 4,0K 6,4G 1% /run/user/9351
tmpfs 6,4G 0 6,4G 0% /run/user/13142
My idea is to use df -h /path/to/home | awk
but I am not sure how I can get the actual available space from df -h
. Any help please? Thanks, Jen.
jen@ser23:~$ df -P /net/home/j/jen
Filesystem 1024-blocks Used Available Capacity Mounted on
nfs4.sf0.dfd.fhg.de:/home 5242880 1026048 4216832 20% /net/home
command-line bash scripts
|
show 7 more comments
I am writing a bash script
to install a program for different users.
For that I want to make sure that each user has at least 500Mb
available in their $HOME
. My $HOME
directory looks as follows
jen@ser23:~$ df -h
Filesystem Size Used Avail Use% Mounted on
/dev/sda1 2,9G 1,1G 1,7G 40% /
udev 10M 0 10M 0% /dev
tmpfs 13G 826M 12G 7% /run
/dev/sda3 15G 9,8G 4,1G 71% /usr
tmpfs 32G 0 32G 0% /dev/shm
tmpfs 5,0M 0 5,0M 0% /run/lock
tmpfs 32G 0 32G 0% /sys/fs/cgroup
/dev/mapper/local_disk_1-tmp 3,7G 21M 3,7G 1% /tmp
/dev/mapper/local_disk_1-opt 20G 2,0G 18G 10% /opt
/dev/mapper/local_disk_1-project1 401G 287G 114G 72% /project1
/dev/mapper/local_disk_1-var 3,8G 1,7G 1,7G 50% /var
/dev/mapper/local_disk_1-project2 99G 70G 29G 71% /project2
/dev/mapper/local_disk_1-usr_local 2,0G 3,4M 1,9G 1% /usr/local
nfs4.sf0.ise.fhg.de:/g/6/TSB/Archiv 632T 349T 276T 56% /net/p/600/groupdrives/TSB/Archiv
nfs4.sf0.ise.fhg.de:/home 632T 349T 276T 56% /net/home
tmpfs 6,4G 0 6,4G 0% /run/user/12419
tmpfs 6,4G 4,0K 6,4G 1% /run/user/13471
tmpfs 6,4G 4,0K 6,4G 1% /run/user/9351
tmpfs 6,4G 0 6,4G 0% /run/user/13142
My idea is to use df -h /path/to/home | awk
but I am not sure how I can get the actual available space from df -h
. Any help please? Thanks, Jen.
jen@ser23:~$ df -P /net/home/j/jen
Filesystem 1024-blocks Used Available Capacity Mounted on
nfs4.sf0.dfd.fhg.de:/home 5242880 1026048 4216832 20% /net/home
command-line bash scripts
1
@EODCraft Staff : Nop! :)
– Jenny
Apr 7 at 17:40
1
df -P /path/to/home | awk 'NR>1 {print $4}'
?
– Cyrus
Apr 7 at 17:41
1
There's no 1,7G. There's at the moment 4216832.
– Cyrus
Apr 7 at 17:53
1
Ah! I thought I should actually get the space in the partition/dev/sda1 2,9G 1,1G 1,7G 40% /
– Jenny
Apr 7 at 17:57
1
If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used thediskquota
command to check the available space. You may want to check if an equivalent system exists at your institution.
– nneonneo
Apr 7 at 21:12
|
show 7 more comments
I am writing a bash script
to install a program for different users.
For that I want to make sure that each user has at least 500Mb
available in their $HOME
. My $HOME
directory looks as follows
jen@ser23:~$ df -h
Filesystem Size Used Avail Use% Mounted on
/dev/sda1 2,9G 1,1G 1,7G 40% /
udev 10M 0 10M 0% /dev
tmpfs 13G 826M 12G 7% /run
/dev/sda3 15G 9,8G 4,1G 71% /usr
tmpfs 32G 0 32G 0% /dev/shm
tmpfs 5,0M 0 5,0M 0% /run/lock
tmpfs 32G 0 32G 0% /sys/fs/cgroup
/dev/mapper/local_disk_1-tmp 3,7G 21M 3,7G 1% /tmp
/dev/mapper/local_disk_1-opt 20G 2,0G 18G 10% /opt
/dev/mapper/local_disk_1-project1 401G 287G 114G 72% /project1
/dev/mapper/local_disk_1-var 3,8G 1,7G 1,7G 50% /var
/dev/mapper/local_disk_1-project2 99G 70G 29G 71% /project2
/dev/mapper/local_disk_1-usr_local 2,0G 3,4M 1,9G 1% /usr/local
nfs4.sf0.ise.fhg.de:/g/6/TSB/Archiv 632T 349T 276T 56% /net/p/600/groupdrives/TSB/Archiv
nfs4.sf0.ise.fhg.de:/home 632T 349T 276T 56% /net/home
tmpfs 6,4G 0 6,4G 0% /run/user/12419
tmpfs 6,4G 4,0K 6,4G 1% /run/user/13471
tmpfs 6,4G 4,0K 6,4G 1% /run/user/9351
tmpfs 6,4G 0 6,4G 0% /run/user/13142
My idea is to use df -h /path/to/home | awk
but I am not sure how I can get the actual available space from df -h
. Any help please? Thanks, Jen.
jen@ser23:~$ df -P /net/home/j/jen
Filesystem 1024-blocks Used Available Capacity Mounted on
nfs4.sf0.dfd.fhg.de:/home 5242880 1026048 4216832 20% /net/home
command-line bash scripts
I am writing a bash script
to install a program for different users.
For that I want to make sure that each user has at least 500Mb
available in their $HOME
. My $HOME
directory looks as follows
jen@ser23:~$ df -h
Filesystem Size Used Avail Use% Mounted on
/dev/sda1 2,9G 1,1G 1,7G 40% /
udev 10M 0 10M 0% /dev
tmpfs 13G 826M 12G 7% /run
/dev/sda3 15G 9,8G 4,1G 71% /usr
tmpfs 32G 0 32G 0% /dev/shm
tmpfs 5,0M 0 5,0M 0% /run/lock
tmpfs 32G 0 32G 0% /sys/fs/cgroup
/dev/mapper/local_disk_1-tmp 3,7G 21M 3,7G 1% /tmp
/dev/mapper/local_disk_1-opt 20G 2,0G 18G 10% /opt
/dev/mapper/local_disk_1-project1 401G 287G 114G 72% /project1
/dev/mapper/local_disk_1-var 3,8G 1,7G 1,7G 50% /var
/dev/mapper/local_disk_1-project2 99G 70G 29G 71% /project2
/dev/mapper/local_disk_1-usr_local 2,0G 3,4M 1,9G 1% /usr/local
nfs4.sf0.ise.fhg.de:/g/6/TSB/Archiv 632T 349T 276T 56% /net/p/600/groupdrives/TSB/Archiv
nfs4.sf0.ise.fhg.de:/home 632T 349T 276T 56% /net/home
tmpfs 6,4G 0 6,4G 0% /run/user/12419
tmpfs 6,4G 4,0K 6,4G 1% /run/user/13471
tmpfs 6,4G 4,0K 6,4G 1% /run/user/9351
tmpfs 6,4G 0 6,4G 0% /run/user/13142
My idea is to use df -h /path/to/home | awk
but I am not sure how I can get the actual available space from df -h
. Any help please? Thanks, Jen.
jen@ser23:~$ df -P /net/home/j/jen
Filesystem 1024-blocks Used Available Capacity Mounted on
nfs4.sf0.dfd.fhg.de:/home 5242880 1026048 4216832 20% /net/home
command-line bash scripts
command-line bash scripts
edited Apr 7 at 17:52
Jenny
asked Apr 7 at 17:31
JennyJenny
1018
1018
1
@EODCraft Staff : Nop! :)
– Jenny
Apr 7 at 17:40
1
df -P /path/to/home | awk 'NR>1 {print $4}'
?
– Cyrus
Apr 7 at 17:41
1
There's no 1,7G. There's at the moment 4216832.
– Cyrus
Apr 7 at 17:53
1
Ah! I thought I should actually get the space in the partition/dev/sda1 2,9G 1,1G 1,7G 40% /
– Jenny
Apr 7 at 17:57
1
If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used thediskquota
command to check the available space. You may want to check if an equivalent system exists at your institution.
– nneonneo
Apr 7 at 21:12
|
show 7 more comments
1
@EODCraft Staff : Nop! :)
– Jenny
Apr 7 at 17:40
1
df -P /path/to/home | awk 'NR>1 {print $4}'
?
– Cyrus
Apr 7 at 17:41
1
There's no 1,7G. There's at the moment 4216832.
– Cyrus
Apr 7 at 17:53
1
Ah! I thought I should actually get the space in the partition/dev/sda1 2,9G 1,1G 1,7G 40% /
– Jenny
Apr 7 at 17:57
1
If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used thediskquota
command to check the available space. You may want to check if an equivalent system exists at your institution.
– nneonneo
Apr 7 at 21:12
1
1
@EODCraft Staff : Nop! :)
– Jenny
Apr 7 at 17:40
@EODCraft Staff : Nop! :)
– Jenny
Apr 7 at 17:40
1
1
df -P /path/to/home | awk 'NR>1 {print $4}'
?– Cyrus
Apr 7 at 17:41
df -P /path/to/home | awk 'NR>1 {print $4}'
?– Cyrus
Apr 7 at 17:41
1
1
There's no 1,7G. There's at the moment 4216832.
– Cyrus
Apr 7 at 17:53
There's no 1,7G. There's at the moment 4216832.
– Cyrus
Apr 7 at 17:53
1
1
Ah! I thought I should actually get the space in the partition
/dev/sda1 2,9G 1,1G 1,7G 40% /
– Jenny
Apr 7 at 17:57
Ah! I thought I should actually get the space in the partition
/dev/sda1 2,9G 1,1G 1,7G 40% /
– Jenny
Apr 7 at 17:57
1
1
If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used the
diskquota
command to check the available space. You may want to check if an equivalent system exists at your institution.– nneonneo
Apr 7 at 21:12
If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used the
diskquota
command to check the available space. You may want to check if an equivalent system exists at your institution.– nneonneo
Apr 7 at 21:12
|
show 7 more comments
3 Answers
3
active
oldest
votes
The important point to remember is that df
operates on filesystems, which may be attached to particular folders, and if you specify a path or file, it will resolve to usage of the filesystem on which file/folder resides. So df -P /net/home/j/jen
operates on the filesystem mounted at /net/home
, which is nfs4.sf0.ise.fhg.de
network attached storage apparently.
The usage of a directory and all the files requires a recursive solution that will traverse files and directories within particular directory. The tool that you seek then, is du
and in particular du -shx /net/home/user
.
Keypoints (for more read man du):
du
is recursive by default
-s
provides summary instead of listing filesizes individually
-h
provides human readable output. If you require further processing on data,-b
might be more preferable.
-x
is to keepdu
descending into another. For instance, you could have another network server attached to/net/home/user/anotherplace
, so processing that directory is undesirable as it will give incorrect filesystem usage results.
Considering that this is an assignment, further processing and manipulations on output of du
are left to the reader to implement
add a comment |
It looks like you're heading towards a workable solution already in the comments, but I'm going to throw this in:
DFHOME=$( df $HOME | awk {'print $4;'} | tail -n 1 )
if [ $DFHOME -lt 500000 ]; then
echo "You don't got enough space!";
fi
I'd recommend not using -h because if the size is small enough, the G will turn to an M and your solution might break.
add a comment |
No need to parse df
output with awk
, you can use --output
switch:
df --output=avail "$HOME" | tail -n1
--output[=FIELD_LIST]
use the output format defined by FIELD_LIST, or print all fields if FIELD_LIST is omitted.
FIELD_LIST is a comma-separated list of columns to be included. Valid field names are: 'source', 'fstype', 'itotal', 'iused', 'iavail', 'ipcent', 'size', 'used', 'avail', 'pcent', 'file' and 'tar‐
get'
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
The important point to remember is that df
operates on filesystems, which may be attached to particular folders, and if you specify a path or file, it will resolve to usage of the filesystem on which file/folder resides. So df -P /net/home/j/jen
operates on the filesystem mounted at /net/home
, which is nfs4.sf0.ise.fhg.de
network attached storage apparently.
The usage of a directory and all the files requires a recursive solution that will traverse files and directories within particular directory. The tool that you seek then, is du
and in particular du -shx /net/home/user
.
Keypoints (for more read man du):
du
is recursive by default
-s
provides summary instead of listing filesizes individually
-h
provides human readable output. If you require further processing on data,-b
might be more preferable.
-x
is to keepdu
descending into another. For instance, you could have another network server attached to/net/home/user/anotherplace
, so processing that directory is undesirable as it will give incorrect filesystem usage results.
Considering that this is an assignment, further processing and manipulations on output of du
are left to the reader to implement
add a comment |
The important point to remember is that df
operates on filesystems, which may be attached to particular folders, and if you specify a path or file, it will resolve to usage of the filesystem on which file/folder resides. So df -P /net/home/j/jen
operates on the filesystem mounted at /net/home
, which is nfs4.sf0.ise.fhg.de
network attached storage apparently.
The usage of a directory and all the files requires a recursive solution that will traverse files and directories within particular directory. The tool that you seek then, is du
and in particular du -shx /net/home/user
.
Keypoints (for more read man du):
du
is recursive by default
-s
provides summary instead of listing filesizes individually
-h
provides human readable output. If you require further processing on data,-b
might be more preferable.
-x
is to keepdu
descending into another. For instance, you could have another network server attached to/net/home/user/anotherplace
, so processing that directory is undesirable as it will give incorrect filesystem usage results.
Considering that this is an assignment, further processing and manipulations on output of du
are left to the reader to implement
add a comment |
The important point to remember is that df
operates on filesystems, which may be attached to particular folders, and if you specify a path or file, it will resolve to usage of the filesystem on which file/folder resides. So df -P /net/home/j/jen
operates on the filesystem mounted at /net/home
, which is nfs4.sf0.ise.fhg.de
network attached storage apparently.
The usage of a directory and all the files requires a recursive solution that will traverse files and directories within particular directory. The tool that you seek then, is du
and in particular du -shx /net/home/user
.
Keypoints (for more read man du):
du
is recursive by default
-s
provides summary instead of listing filesizes individually
-h
provides human readable output. If you require further processing on data,-b
might be more preferable.
-x
is to keepdu
descending into another. For instance, you could have another network server attached to/net/home/user/anotherplace
, so processing that directory is undesirable as it will give incorrect filesystem usage results.
Considering that this is an assignment, further processing and manipulations on output of du
are left to the reader to implement
The important point to remember is that df
operates on filesystems, which may be attached to particular folders, and if you specify a path or file, it will resolve to usage of the filesystem on which file/folder resides. So df -P /net/home/j/jen
operates on the filesystem mounted at /net/home
, which is nfs4.sf0.ise.fhg.de
network attached storage apparently.
The usage of a directory and all the files requires a recursive solution that will traverse files and directories within particular directory. The tool that you seek then, is du
and in particular du -shx /net/home/user
.
Keypoints (for more read man du):
du
is recursive by default
-s
provides summary instead of listing filesizes individually
-h
provides human readable output. If you require further processing on data,-b
might be more preferable.
-x
is to keepdu
descending into another. For instance, you could have another network server attached to/net/home/user/anotherplace
, so processing that directory is undesirable as it will give incorrect filesystem usage results.
Considering that this is an assignment, further processing and manipulations on output of du
are left to the reader to implement
edited Apr 8 at 6:19
answered Apr 7 at 18:26
Sergiy KolodyazhnyySergiy Kolodyazhnyy
75.4k9155328
75.4k9155328
add a comment |
add a comment |
It looks like you're heading towards a workable solution already in the comments, but I'm going to throw this in:
DFHOME=$( df $HOME | awk {'print $4;'} | tail -n 1 )
if [ $DFHOME -lt 500000 ]; then
echo "You don't got enough space!";
fi
I'd recommend not using -h because if the size is small enough, the G will turn to an M and your solution might break.
add a comment |
It looks like you're heading towards a workable solution already in the comments, but I'm going to throw this in:
DFHOME=$( df $HOME | awk {'print $4;'} | tail -n 1 )
if [ $DFHOME -lt 500000 ]; then
echo "You don't got enough space!";
fi
I'd recommend not using -h because if the size is small enough, the G will turn to an M and your solution might break.
add a comment |
It looks like you're heading towards a workable solution already in the comments, but I'm going to throw this in:
DFHOME=$( df $HOME | awk {'print $4;'} | tail -n 1 )
if [ $DFHOME -lt 500000 ]; then
echo "You don't got enough space!";
fi
I'd recommend not using -h because if the size is small enough, the G will turn to an M and your solution might break.
It looks like you're heading towards a workable solution already in the comments, but I'm going to throw this in:
DFHOME=$( df $HOME | awk {'print $4;'} | tail -n 1 )
if [ $DFHOME -lt 500000 ]; then
echo "You don't got enough space!";
fi
I'd recommend not using -h because if the size is small enough, the G will turn to an M and your solution might break.
edited Apr 7 at 18:11
answered Apr 7 at 17:56
KarlKarl
215
215
add a comment |
add a comment |
No need to parse df
output with awk
, you can use --output
switch:
df --output=avail "$HOME" | tail -n1
--output[=FIELD_LIST]
use the output format defined by FIELD_LIST, or print all fields if FIELD_LIST is omitted.
FIELD_LIST is a comma-separated list of columns to be included. Valid field names are: 'source', 'fstype', 'itotal', 'iused', 'iavail', 'ipcent', 'size', 'used', 'avail', 'pcent', 'file' and 'tar‐
get'
add a comment |
No need to parse df
output with awk
, you can use --output
switch:
df --output=avail "$HOME" | tail -n1
--output[=FIELD_LIST]
use the output format defined by FIELD_LIST, or print all fields if FIELD_LIST is omitted.
FIELD_LIST is a comma-separated list of columns to be included. Valid field names are: 'source', 'fstype', 'itotal', 'iused', 'iavail', 'ipcent', 'size', 'used', 'avail', 'pcent', 'file' and 'tar‐
get'
add a comment |
No need to parse df
output with awk
, you can use --output
switch:
df --output=avail "$HOME" | tail -n1
--output[=FIELD_LIST]
use the output format defined by FIELD_LIST, or print all fields if FIELD_LIST is omitted.
FIELD_LIST is a comma-separated list of columns to be included. Valid field names are: 'source', 'fstype', 'itotal', 'iused', 'iavail', 'ipcent', 'size', 'used', 'avail', 'pcent', 'file' and 'tar‐
get'
No need to parse df
output with awk
, you can use --output
switch:
df --output=avail "$HOME" | tail -n1
--output[=FIELD_LIST]
use the output format defined by FIELD_LIST, or print all fields if FIELD_LIST is omitted.
FIELD_LIST is a comma-separated list of columns to be included. Valid field names are: 'source', 'fstype', 'itotal', 'iused', 'iavail', 'ipcent', 'size', 'used', 'avail', 'pcent', 'file' and 'tar‐
get'
answered Apr 8 at 7:47
RoVoRoVo
8,2591943
8,2591943
add a comment |
add a comment |
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1
@EODCraft Staff : Nop! :)
– Jenny
Apr 7 at 17:40
1
df -P /path/to/home | awk 'NR>1 {print $4}'
?– Cyrus
Apr 7 at 17:41
1
There's no 1,7G. There's at the moment 4216832.
– Cyrus
Apr 7 at 17:53
1
Ah! I thought I should actually get the space in the partition
/dev/sda1 2,9G 1,1G 1,7G 40% /
– Jenny
Apr 7 at 17:57
1
If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used the
diskquota
command to check the available space. You may want to check if an equivalent system exists at your institution.– nneonneo
Apr 7 at 21:12