Odds in a “reverse” raffle
2
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If in a raffle style drawing, but where you draw until one card or number is left, are the odds any different than when the first card drawn is the winner/loser?
probability combinatorics statistics
edited Dec 21 '18 at 19:14
David G. Stork
12.2k41836
asked Dec 21 '18 at 18:03
Jonathan KimrayJonathan Kimray
111
$endgroup$
add a comment |
2
$begingroup$
If in a raffle style drawing, but where you draw until one card or number is left, are the odds any different than when the first card drawn is the winner/loser?
probability combinatorics statistics
edited Dec 21 '18 at 19:14
David G. Stork
12.2k41836
asked Dec 21 '18 at 18:03
Jonathan KimrayJonathan Kimray
111
$endgroup$
4
$begingroup$
No. By symmetry, every number has an equal chance of being the one left.
$endgroup$
– saulspatz
Dec 21 '18 at 18:09
add a comment |
2
2
2
$begingroup$
If in a raffle style drawing, but where you draw until one card or number is left, are the odds any different than when the first card drawn is the winner/loser?
probability combinatorics statistics
edited Dec 21 '18 at 19:14
David G. Stork
12.2k41836
asked Dec 21 '18 at 18:03
Jonathan KimrayJonathan Kimray
111
$endgroup$
If in a raffle style drawing, but where you draw until one card or number is left, are the odds any different than when the first card drawn is the winner/loser?
probability combinatorics statistics
probability combinatorics statistics
edited Dec 21 '18 at 19:14
David G. Stork
12.2k41836
asked Dec 21 '18 at 18:03
Jonathan KimrayJonathan Kimray
111
edited Dec 21 '18 at 19:14
David G. Stork
12.2k41836
asked Dec 21 '18 at 18:03
Jonathan KimrayJonathan Kimray
111
edited Dec 21 '18 at 19:14
David G. Stork
12.2k41836
edited Dec 21 '18 at 19:14
David G. Stork
12.2k41836
edited Dec 21 '18 at 19:14
David G. Stork
12.2k41836
12.2k41836
asked Dec 21 '18 at 18:03
Jonathan KimrayJonathan Kimray
111
asked Dec 21 '18 at 18:03
Jonathan KimrayJonathan Kimray
111
asked Dec 21 '18 at 18:03
Jonathan KimrayJonathan Kimray
111
111
4
$begingroup$
No. By symmetry, every number has an equal chance of being the one left.
$endgroup$
– saulspatz
Dec 21 '18 at 18:09
add a comment |
4
$begingroup$
No. By symmetry, every number has an equal chance of being the one left.
$endgroup$
– saulspatz
Dec 21 '18 at 18:09
4
4
$begingroup$
No. By symmetry, every number has an equal chance of being the one left.
$endgroup$
– saulspatz
Dec 21 '18 at 18:09
$begingroup$
No. By symmetry, every number has an equal chance of being the one left.
$endgroup$
– saulspatz
Dec 21 '18 at 18:09
add a comment |
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No. By symmetry, every number has an equal chance of being the one left.
$endgroup$
– saulspatz
Dec 21 '18 at 18:09