Loop in macOS not working





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I need to execute the following shell script in my macOS terminal.
The loop never executes more than its first iteration.



function execute_function() {
# Launch job
number_of_jobs=$1
echo "Launching ${number_of_jobs} jobs"
for i in {1..$1}; do
job_id=`head /dev/urandom | tr -dc A-Z0-9 | head -c 6 ; echo ''`
echo "Launching Job: $job_id"
echo $i
done
}


When I run it, I always get:



execute_function 10

Launching 10 jobs
Launching Job: XX9BWC
{1..10}


The same happens if I replace: $1 with $number_of_jobs or "${number_of_jobs}"










share|improve this question









New contributor




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    6















    I need to execute the following shell script in my macOS terminal.
    The loop never executes more than its first iteration.



    function execute_function() {
    # Launch job
    number_of_jobs=$1
    echo "Launching ${number_of_jobs} jobs"
    for i in {1..$1}; do
    job_id=`head /dev/urandom | tr -dc A-Z0-9 | head -c 6 ; echo ''`
    echo "Launching Job: $job_id"
    echo $i
    done
    }


    When I run it, I always get:



    execute_function 10

    Launching 10 jobs
    Launching Job: XX9BWC
    {1..10}


    The same happens if I replace: $1 with $number_of_jobs or "${number_of_jobs}"










    share|improve this question









    New contributor




    spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      6












      6








      6








      I need to execute the following shell script in my macOS terminal.
      The loop never executes more than its first iteration.



      function execute_function() {
      # Launch job
      number_of_jobs=$1
      echo "Launching ${number_of_jobs} jobs"
      for i in {1..$1}; do
      job_id=`head /dev/urandom | tr -dc A-Z0-9 | head -c 6 ; echo ''`
      echo "Launching Job: $job_id"
      echo $i
      done
      }


      When I run it, I always get:



      execute_function 10

      Launching 10 jobs
      Launching Job: XX9BWC
      {1..10}


      The same happens if I replace: $1 with $number_of_jobs or "${number_of_jobs}"










      share|improve this question









      New contributor




      spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I need to execute the following shell script in my macOS terminal.
      The loop never executes more than its first iteration.



      function execute_function() {
      # Launch job
      number_of_jobs=$1
      echo "Launching ${number_of_jobs} jobs"
      for i in {1..$1}; do
      job_id=`head /dev/urandom | tr -dc A-Z0-9 | head -c 6 ; echo ''`
      echo "Launching Job: $job_id"
      echo $i
      done
      }


      When I run it, I always get:



      execute_function 10

      Launching 10 jobs
      Launching Job: XX9BWC
      {1..10}


      The same happens if I replace: $1 with $number_of_jobs or "${number_of_jobs}"







      shell-script shell osx brace-expansion






      share|improve this question









      New contributor




      spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited Apr 2 at 8:02









      Kusalananda

      140k17261435




      140k17261435






      New contributor




      spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      asked Apr 2 at 4:55









      spicyramenspicyramen

      1334




      1334




      New contributor




      spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      spicyramen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















          2 Answers
          2






          active

          oldest

          votes


















          6














          The problem here is variable in braces expansion.



          Try rewriting it to



          for ((i=1;i<=$1;i++))
          do
          #your code here
          done





          share|improve this answer


























          • That worked perfectly

            – spicyramen
            Apr 2 at 5:22



















          7














          Your script is written for zsh but you are executing it with bash.



          bash does not support using variables as ranges in brace-expansions.



          To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.



          See also:




          • Listing numbered files using wildcard sequence with predefined range

          • How can I use $variable in a shell brace expansion of a sequence?

          • Does the shebang determine the shell which runs the script?






          share|improve this answer





















          • 1





            include #!/bin/zsh as first line. (you may need to check the path.

            – ctrl-alt-delor
            Apr 2 at 7:57











          • what about #!/usr/bin/env zsh?

            – Jakub Jindra
            Apr 2 at 8:46











          • @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.

            – Kusalananda
            Apr 2 at 8:50














          Your Answer








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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          6














          The problem here is variable in braces expansion.



          Try rewriting it to



          for ((i=1;i<=$1;i++))
          do
          #your code here
          done





          share|improve this answer


























          • That worked perfectly

            – spicyramen
            Apr 2 at 5:22
















          6














          The problem here is variable in braces expansion.



          Try rewriting it to



          for ((i=1;i<=$1;i++))
          do
          #your code here
          done





          share|improve this answer


























          • That worked perfectly

            – spicyramen
            Apr 2 at 5:22














          6












          6








          6







          The problem here is variable in braces expansion.



          Try rewriting it to



          for ((i=1;i<=$1;i++))
          do
          #your code here
          done





          share|improve this answer















          The problem here is variable in braces expansion.



          Try rewriting it to



          for ((i=1;i<=$1;i++))
          do
          #your code here
          done






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Apr 2 at 6:59

























          answered Apr 2 at 5:08









          Jakub JindraJakub Jindra

          608514




          608514













          • That worked perfectly

            – spicyramen
            Apr 2 at 5:22



















          • That worked perfectly

            – spicyramen
            Apr 2 at 5:22

















          That worked perfectly

          – spicyramen
          Apr 2 at 5:22





          That worked perfectly

          – spicyramen
          Apr 2 at 5:22













          7














          Your script is written for zsh but you are executing it with bash.



          bash does not support using variables as ranges in brace-expansions.



          To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.



          See also:




          • Listing numbered files using wildcard sequence with predefined range

          • How can I use $variable in a shell brace expansion of a sequence?

          • Does the shebang determine the shell which runs the script?






          share|improve this answer





















          • 1





            include #!/bin/zsh as first line. (you may need to check the path.

            – ctrl-alt-delor
            Apr 2 at 7:57











          • what about #!/usr/bin/env zsh?

            – Jakub Jindra
            Apr 2 at 8:46











          • @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.

            – Kusalananda
            Apr 2 at 8:50


















          7














          Your script is written for zsh but you are executing it with bash.



          bash does not support using variables as ranges in brace-expansions.



          To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.



          See also:




          • Listing numbered files using wildcard sequence with predefined range

          • How can I use $variable in a shell brace expansion of a sequence?

          • Does the shebang determine the shell which runs the script?






          share|improve this answer





















          • 1





            include #!/bin/zsh as first line. (you may need to check the path.

            – ctrl-alt-delor
            Apr 2 at 7:57











          • what about #!/usr/bin/env zsh?

            – Jakub Jindra
            Apr 2 at 8:46











          • @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.

            – Kusalananda
            Apr 2 at 8:50
















          7












          7








          7







          Your script is written for zsh but you are executing it with bash.



          bash does not support using variables as ranges in brace-expansions.



          To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.



          See also:




          • Listing numbered files using wildcard sequence with predefined range

          • How can I use $variable in a shell brace expansion of a sequence?

          • Does the shebang determine the shell which runs the script?






          share|improve this answer















          Your script is written for zsh but you are executing it with bash.



          bash does not support using variables as ranges in brace-expansions.



          To resolve this, simply arrange for the script or function be executed in a zsh shell (especially if the script is longer than what you are showing and is using other zsh features). This shell is installed by default on macOS as /bin/zsh. You may add #!/bin/zsh as the first line in the script to have it execute with zsh by default.



          See also:




          • Listing numbered files using wildcard sequence with predefined range

          • How can I use $variable in a shell brace expansion of a sequence?

          • Does the shebang determine the shell which runs the script?







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Apr 2 at 7:59

























          answered Apr 2 at 5:28









          KusalanandaKusalananda

          140k17261435




          140k17261435








          • 1





            include #!/bin/zsh as first line. (you may need to check the path.

            – ctrl-alt-delor
            Apr 2 at 7:57











          • what about #!/usr/bin/env zsh?

            – Jakub Jindra
            Apr 2 at 8:46











          • @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.

            – Kusalananda
            Apr 2 at 8:50
















          • 1





            include #!/bin/zsh as first line. (you may need to check the path.

            – ctrl-alt-delor
            Apr 2 at 7:57











          • what about #!/usr/bin/env zsh?

            – Jakub Jindra
            Apr 2 at 8:46











          • @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.

            – Kusalananda
            Apr 2 at 8:50










          1




          1





          include #!/bin/zsh as first line. (you may need to check the path.

          – ctrl-alt-delor
          Apr 2 at 7:57





          include #!/bin/zsh as first line. (you may need to check the path.

          – ctrl-alt-delor
          Apr 2 at 7:57













          what about #!/usr/bin/env zsh?

          – Jakub Jindra
          Apr 2 at 8:46





          what about #!/usr/bin/env zsh?

          – Jakub Jindra
          Apr 2 at 8:46













          @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.

          – Kusalananda
          Apr 2 at 8:50







          @JakubJindra That would work to, but the default location of zsh is /bin/zsh on macOS. Obviously, you may want to use env if you need to use a 3rd-party installation of zsh. However, this is not the essence of this particular question.

          – Kusalananda
          Apr 2 at 8:50












          spicyramen is a new contributor. Be nice, and check out our Code of Conduct.










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