probability that 4 people will get their numbers











up vote
0
down vote

favorite












4 women gave their coats to cloakroom. By the accident ruber mixed their number. He didn't say anything to women and gave them numbers. What probability is that women got they coats?



I thought that $P=1/4^4= 1/256$ but I am not sure










share|cite|improve this question







New contributor




Atstovas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
























    up vote
    0
    down vote

    favorite












    4 women gave their coats to cloakroom. By the accident ruber mixed their number. He didn't say anything to women and gave them numbers. What probability is that women got they coats?



    I thought that $P=1/4^4= 1/256$ but I am not sure










    share|cite|improve this question







    New contributor




    Atstovas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      4 women gave their coats to cloakroom. By the accident ruber mixed their number. He didn't say anything to women and gave them numbers. What probability is that women got they coats?



      I thought that $P=1/4^4= 1/256$ but I am not sure










      share|cite|improve this question







      New contributor




      Atstovas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      4 women gave their coats to cloakroom. By the accident ruber mixed their number. He didn't say anything to women and gave them numbers. What probability is that women got they coats?



      I thought that $P=1/4^4= 1/256$ but I am not sure







      probability probability-theory






      share|cite|improve this question







      New contributor




      Atstovas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|cite|improve this question







      New contributor




      Atstovas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|cite|improve this question




      share|cite|improve this question






      New contributor




      Atstovas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 14 hours ago









      Atstovas

      292




      292




      New contributor




      Atstovas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Atstovas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Atstovas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















          1 Answer
          1






          active

          oldest

          votes

















          up vote
          0
          down vote













          Not quite!



          There are 4•3•2•1 ways to give a number to each woman.



          Only one of those assignments give each woman the correct coat.



          Therefore, the probability is $displaystyle frac{1}{24}$






          share|cite|improve this answer





















          • what about the probability that only one women will get her coat? is it 11/24? or 1/6?
            – Atstovas
            13 hours ago













          Your Answer





          StackExchange.ifUsing("editor", function () {
          return StackExchange.using("mathjaxEditing", function () {
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          });
          });
          }, "mathjax-editing");

          StackExchange.ready(function() {
          var channelOptions = {
          tags: "".split(" "),
          id: "69"
          };
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function() {
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled) {
          StackExchange.using("snippets", function() {
          createEditor();
          });
          }
          else {
          createEditor();
          }
          });

          function createEditor() {
          StackExchange.prepareEditor({
          heartbeatType: 'answer',
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader: {
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          },
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          });


          }
          });






          Atstovas is a new contributor. Be nice, and check out our Code of Conduct.










           

          draft saved


          draft discarded


















          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2997900%2fprobability-that-4-people-will-get-their-numbers%23new-answer', 'question_page');
          }
          );

          Post as a guest
































          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote













          Not quite!



          There are 4•3•2•1 ways to give a number to each woman.



          Only one of those assignments give each woman the correct coat.



          Therefore, the probability is $displaystyle frac{1}{24}$






          share|cite|improve this answer





















          • what about the probability that only one women will get her coat? is it 11/24? or 1/6?
            – Atstovas
            13 hours ago

















          up vote
          0
          down vote













          Not quite!



          There are 4•3•2•1 ways to give a number to each woman.



          Only one of those assignments give each woman the correct coat.



          Therefore, the probability is $displaystyle frac{1}{24}$






          share|cite|improve this answer





















          • what about the probability that only one women will get her coat? is it 11/24? or 1/6?
            – Atstovas
            13 hours ago















          up vote
          0
          down vote










          up vote
          0
          down vote









          Not quite!



          There are 4•3•2•1 ways to give a number to each woman.



          Only one of those assignments give each woman the correct coat.



          Therefore, the probability is $displaystyle frac{1}{24}$






          share|cite|improve this answer












          Not quite!



          There are 4•3•2•1 ways to give a number to each woman.



          Only one of those assignments give each woman the correct coat.



          Therefore, the probability is $displaystyle frac{1}{24}$







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered 14 hours ago









          Saketh Malyala

          7,3111534




          7,3111534












          • what about the probability that only one women will get her coat? is it 11/24? or 1/6?
            – Atstovas
            13 hours ago




















          • what about the probability that only one women will get her coat? is it 11/24? or 1/6?
            – Atstovas
            13 hours ago


















          what about the probability that only one women will get her coat? is it 11/24? or 1/6?
          – Atstovas
          13 hours ago






          what about the probability that only one women will get her coat? is it 11/24? or 1/6?
          – Atstovas
          13 hours ago












          Atstovas is a new contributor. Be nice, and check out our Code of Conduct.










           

          draft saved


          draft discarded


















          Atstovas is a new contributor. Be nice, and check out our Code of Conduct.













          Atstovas is a new contributor. Be nice, and check out our Code of Conduct.












          Atstovas is a new contributor. Be nice, and check out our Code of Conduct.















           


          draft saved


          draft discarded














          StackExchange.ready(
          function () {
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2997900%2fprobability-that-4-people-will-get-their-numbers%23new-answer', 'question_page');
          }
          );

          Post as a guest




















































































          Popular posts from this blog

          Plaza Victoria

          Puebla de Zaragoza

          Musa