Derivative of a function in a point $x_0 in partial A$
0
What is the definition (if exists) of partial derivative of a function $f: A subseteq mathbb{R}^n rightarrow mathbb{R}$ in a point $x_0 in partial A$ where $partial A$ is the boundary of $A$?
derivatives
asked Nov 22 at 21:26
asv
2761211
add a comment |
0
What is the definition (if exists) of partial derivative of a function $f: A subseteq mathbb{R}^n rightarrow mathbb{R}$ in a point $x_0 in partial A$ where $partial A$ is the boundary of $A$?
derivatives
asked Nov 22 at 21:26
asv
2761211
What do you mean by $Fr(A)$ ? I guess it's the "frontier" but I'm not familiar with any concept of that name.
– 0x539
Nov 22 at 21:30
Do you mean boundary? This may be translated.
– Sean Roberson
Nov 22 at 21:33
I mean boundary
– asv
Nov 22 at 21:39
For $n=1$, this is called left/right derivative (on the right/left boundary of an interval). In $Bbb R^n$, there is the notion of directional derivative. I'm not sure if this really what you are looking for though.
– Surb
Nov 22 at 23:16
add a comment |
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0
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What is the definition (if exists) of partial derivative of a function $f: A subseteq mathbb{R}^n rightarrow mathbb{R}$ in a point $x_0 in partial A$ where $partial A$ is the boundary of $A$?
derivatives
asked Nov 22 at 21:26
asv
2761211
What is the definition (if exists) of partial derivative of a function $f: A subseteq mathbb{R}^n rightarrow mathbb{R}$ in a point $x_0 in partial A$ where $partial A$ is the boundary of $A$?
derivatives
derivatives
asked Nov 22 at 21:26
asv
2761211
asked Nov 22 at 21:26
asv
2761211
edited Nov 22 at 22:05
asked Nov 22 at 21:26
asv
2761211
asked Nov 22 at 21:26
asv
2761211
asked Nov 22 at 21:26
asv
2761211
2761211
What do you mean by $Fr(A)$ ? I guess it's the "frontier" but I'm not familiar with any concept of that name.
– 0x539
Nov 22 at 21:30
Do you mean boundary? This may be translated.
– Sean Roberson
Nov 22 at 21:33
I mean boundary
– asv
Nov 22 at 21:39
For $n=1$, this is called left/right derivative (on the right/left boundary of an interval). In $Bbb R^n$, there is the notion of directional derivative. I'm not sure if this really what you are looking for though.
– Surb
Nov 22 at 23:16
add a comment |
What do you mean by $Fr(A)$ ? I guess it's the "frontier" but I'm not familiar with any concept of that name.
– 0x539
Nov 22 at 21:30
Do you mean boundary? This may be translated.
– Sean Roberson
Nov 22 at 21:33
I mean boundary
– asv
Nov 22 at 21:39
For $n=1$, this is called left/right derivative (on the right/left boundary of an interval). In $Bbb R^n$, there is the notion of directional derivative. I'm not sure if this really what you are looking for though.
– Surb
Nov 22 at 23:16
What do you mean by $Fr(A)$ ? I guess it's the "frontier" but I'm not familiar with any concept of that name.
– 0x539
Nov 22 at 21:30
What do you mean by $Fr(A)$ ? I guess it's the "frontier" but I'm not familiar with any concept of that name.
– 0x539
Nov 22 at 21:30
Do you mean boundary? This may be translated.
– Sean Roberson
Nov 22 at 21:33
Do you mean boundary? This may be translated.
– Sean Roberson
Nov 22 at 21:33
I mean boundary
– asv
Nov 22 at 21:39
I mean boundary
– asv
Nov 22 at 21:39
For $n=1$, this is called left/right derivative (on the right/left boundary of an interval). In $Bbb R^n$, there is the notion of directional derivative. I'm not sure if this really what you are looking for though.
– Surb
Nov 22 at 23:16
For $n=1$, this is called left/right derivative (on the right/left boundary of an interval). In $Bbb R^n$, there is the notion of directional derivative. I'm not sure if this really what you are looking for though.
– Surb
Nov 22 at 23:16
add a comment |
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What do you mean by $Fr(A)$ ? I guess it's the "frontier" but I'm not familiar with any concept of that name.
– 0x539
Nov 22 at 21:30
Do you mean boundary? This may be translated.
– Sean Roberson
Nov 22 at 21:33
I mean boundary
– asv
Nov 22 at 21:39
For $n=1$, this is called left/right derivative (on the right/left boundary of an interval). In $Bbb R^n$, there is the notion of directional derivative. I'm not sure if this really what you are looking for though.
– Surb
Nov 22 at 23:16