Whats the final result of this equation: -z * d/dz(1/(1-a*z^(-1)))
$begingroup$
Okay so im really confused about this because in the book the solution is the equation and book solution
Now the book is using the quotient rule for this differentiation, Now I hate that rule so I thought why not try composition rule instead and the end result was different for me so I tried using online calculators and they gave the same solution I got which is The solution from an online calculator
Okay so now im just confuse which one is right and i dont know if this helps but the topic is z-transform for Digital Signal Processing course.
Thank you
calculus derivatives
$endgroup$
add a comment |
$begingroup$
Okay so im really confused about this because in the book the solution is the equation and book solution
Now the book is using the quotient rule for this differentiation, Now I hate that rule so I thought why not try composition rule instead and the end result was different for me so I tried using online calculators and they gave the same solution I got which is The solution from an online calculator
Okay so now im just confuse which one is right and i dont know if this helps but the topic is z-transform for Digital Signal Processing course.
Thank you
calculus derivatives
$endgroup$
add a comment |
$begingroup$
Okay so im really confused about this because in the book the solution is the equation and book solution
Now the book is using the quotient rule for this differentiation, Now I hate that rule so I thought why not try composition rule instead and the end result was different for me so I tried using online calculators and they gave the same solution I got which is The solution from an online calculator
Okay so now im just confuse which one is right and i dont know if this helps but the topic is z-transform for Digital Signal Processing course.
Thank you
calculus derivatives
$endgroup$
Okay so im really confused about this because in the book the solution is the equation and book solution
Now the book is using the quotient rule for this differentiation, Now I hate that rule so I thought why not try composition rule instead and the end result was different for me so I tried using online calculators and they gave the same solution I got which is The solution from an online calculator
Okay so now im just confuse which one is right and i dont know if this helps but the topic is z-transform for Digital Signal Processing course.
Thank you
calculus derivatives
calculus derivatives
asked Dec 2 '18 at 21:41
cyotmhndcyotmhnd
11
11
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3023246%2fwhats-the-final-result-of-this-equation-z-d-dz1-1-az-1%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3023246%2fwhats-the-final-result-of-this-equation-z-d-dz1-1-az-1%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown