How does the Pauli exclusion work on fermions but not on bosons?
How does fractional spin effect the symmetry of combined wavefunctions?
Why is Planck constant the universal anchor for determining if a particle is a Boson or a Fermion?
quantum-mechanics quantum-spin pauli-exclusion-principle
edited Nov 24 at 8:41
Blazar
13211
asked Nov 24 at 8:27
Naama-sela
195
add a comment |
How does fractional spin effect the symmetry of combined wavefunctions?
Why is Planck constant the universal anchor for determining if a particle is a Boson or a Fermion?
quantum-mechanics quantum-spin pauli-exclusion-principle
edited Nov 24 at 8:41
Blazar
13211
asked Nov 24 at 8:27
Naama-sela
195
add a comment |
How does fractional spin effect the symmetry of combined wavefunctions?
Why is Planck constant the universal anchor for determining if a particle is a Boson or a Fermion?
quantum-mechanics quantum-spin pauli-exclusion-principle
edited Nov 24 at 8:41
Blazar
13211
asked Nov 24 at 8:27
Naama-sela
195
How does fractional spin effect the symmetry of combined wavefunctions?
Why is Planck constant the universal anchor for determining if a particle is a Boson or a Fermion?
quantum-mechanics quantum-spin pauli-exclusion-principle
quantum-mechanics quantum-spin pauli-exclusion-principle
edited Nov 24 at 8:41
Blazar
13211
asked Nov 24 at 8:27
Naama-sela
195
edited Nov 24 at 8:41
Blazar
13211
asked Nov 24 at 8:27
Naama-sela
195
edited Nov 24 at 8:41
Blazar
13211
edited Nov 24 at 8:41
Blazar
13211
edited Nov 24 at 8:41
Blazar
13211
13211
asked Nov 24 at 8:27
Naama-sela
195
asked Nov 24 at 8:27
Naama-sela
195
asked Nov 24 at 8:27
Naama-sela
195
195
add a comment |
add a comment |
1 Answer
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The relation between spin and the exclusion principle is called the spin statistics theorem, but I don't think there is an elementary explanation for it (other than doing the math).
Plancks constant does not determine if a particle is a boson or a fermion
answered Nov 24 at 9:03
yankyl
836
1
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
– Pieter
Nov 24 at 12:14
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The relation between spin and the exclusion principle is called the spin statistics theorem, but I don't think there is an elementary explanation for it (other than doing the math).
Plancks constant does not determine if a particle is a boson or a fermion
answered Nov 24 at 9:03
yankyl
836
1
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
– Pieter
Nov 24 at 12:14
add a comment |
The relation between spin and the exclusion principle is called the spin statistics theorem, but I don't think there is an elementary explanation for it (other than doing the math).
Plancks constant does not determine if a particle is a boson or a fermion
answered Nov 24 at 9:03
yankyl
836
1
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
– Pieter
Nov 24 at 12:14
add a comment |
The relation between spin and the exclusion principle is called the spin statistics theorem, but I don't think there is an elementary explanation for it (other than doing the math).
Plancks constant does not determine if a particle is a boson or a fermion
answered Nov 24 at 9:03
yankyl
836
The relation between spin and the exclusion principle is called the spin statistics theorem, but I don't think there is an elementary explanation for it (other than doing the math).
Plancks constant does not determine if a particle is a boson or a fermion
answered Nov 24 at 9:03
yankyl
836
answered Nov 24 at 9:03
yankyl
836
answered Nov 24 at 9:03
yankyl
836
answered Nov 24 at 9:03
yankyl
836
836
1
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
– Pieter
Nov 24 at 12:14
add a comment |
1
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
– Pieter
Nov 24 at 12:14
1
1
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
– Pieter
Nov 24 at 12:14
There is the elementary handwaving that exchanging two particles is half a rotation. At least in 3D, a full rotation gives the state that one started with, but in 2D one can have anyons (fractional quantum Hall effect).
– Pieter
Nov 24 at 12:14
add a comment |
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