plotting phase portrait for a system [closed]












-1












$begingroup$


I want to plot phase portrait for below system
begin{cases}
dphi/dzeta=Z \
dZ/dzeta=aphi+bphi^2+cphi^3
end{cases}

a=-0.13
b=-0.07
c=-2.83
Can any body help me?
Thanks










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$endgroup$



closed as off-topic by Did, Saad, Brahadeesh, Dando18, Potato Dec 8 '18 at 20:48


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, Saad, Brahadeesh, Dando18, Potato

If this question can be reworded to fit the rules in the help center, please edit the question.












  • 2




    $begingroup$
    You can't really, if $a, b$ and $c$ are unknown.
    $endgroup$
    – Rebellos
    Dec 7 '18 at 9:37










  • $begingroup$
    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    $endgroup$
    – José Carlos Santos
    Dec 7 '18 at 9:37
















-1












$begingroup$


I want to plot phase portrait for below system
begin{cases}
dphi/dzeta=Z \
dZ/dzeta=aphi+bphi^2+cphi^3
end{cases}

a=-0.13
b=-0.07
c=-2.83
Can any body help me?
Thanks










share|cite|improve this question











$endgroup$



closed as off-topic by Did, Saad, Brahadeesh, Dando18, Potato Dec 8 '18 at 20:48


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, Saad, Brahadeesh, Dando18, Potato

If this question can be reworded to fit the rules in the help center, please edit the question.












  • 2




    $begingroup$
    You can't really, if $a, b$ and $c$ are unknown.
    $endgroup$
    – Rebellos
    Dec 7 '18 at 9:37










  • $begingroup$
    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    $endgroup$
    – José Carlos Santos
    Dec 7 '18 at 9:37














-1












-1








-1


1



$begingroup$


I want to plot phase portrait for below system
begin{cases}
dphi/dzeta=Z \
dZ/dzeta=aphi+bphi^2+cphi^3
end{cases}

a=-0.13
b=-0.07
c=-2.83
Can any body help me?
Thanks










share|cite|improve this question











$endgroup$




I want to plot phase portrait for below system
begin{cases}
dphi/dzeta=Z \
dZ/dzeta=aphi+bphi^2+cphi^3
end{cases}

a=-0.13
b=-0.07
c=-2.83
Can any body help me?
Thanks







graphing-functions






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edited Dec 7 '18 at 10:58







sepide shirazi

















asked Dec 7 '18 at 9:33









sepide shirazisepide shirazi

43




43




closed as off-topic by Did, Saad, Brahadeesh, Dando18, Potato Dec 8 '18 at 20:48


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, Saad, Brahadeesh, Dando18, Potato

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by Did, Saad, Brahadeesh, Dando18, Potato Dec 8 '18 at 20:48


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, Saad, Brahadeesh, Dando18, Potato

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    $begingroup$
    You can't really, if $a, b$ and $c$ are unknown.
    $endgroup$
    – Rebellos
    Dec 7 '18 at 9:37










  • $begingroup$
    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    $endgroup$
    – José Carlos Santos
    Dec 7 '18 at 9:37














  • 2




    $begingroup$
    You can't really, if $a, b$ and $c$ are unknown.
    $endgroup$
    – Rebellos
    Dec 7 '18 at 9:37










  • $begingroup$
    Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
    $endgroup$
    – José Carlos Santos
    Dec 7 '18 at 9:37








2




2




$begingroup$
You can't really, if $a, b$ and $c$ are unknown.
$endgroup$
– Rebellos
Dec 7 '18 at 9:37




$begingroup$
You can't really, if $a, b$ and $c$ are unknown.
$endgroup$
– Rebellos
Dec 7 '18 at 9:37












$begingroup$
Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
$endgroup$
– José Carlos Santos
Dec 7 '18 at 9:37




$begingroup$
Welcome to MSE. Your question is phrased as an isolated problem, without any further information or context. This does not match many users' quality standards, so it may attract downvotes, or be put on hold. To prevent that, please edit the question. This will help you recognise and resolve the issues. Concretely: please provide context, and include your work and thoughts on the problem. These changes can help in formulating more appropriate answers.
$endgroup$
– José Carlos Santos
Dec 7 '18 at 9:37










1 Answer
1






active

oldest

votes


















0












$begingroup$

With the MATHEMATICA script




tmax = 10;
gr1 = StreamPlot[{-0.13 phi - 0.07 phi^2 - 2.83 phi^3, z}, {z, -1, 1}, {phi, -1, 1}];
sol = NDSolve[
{phi'[t] == z[t],
z'[t] == -0.13 phi[t] - 0.07 phi[t]^2 - 2.83 phi[t]^3,
z[0] == 0.6, phi[0] == 0.6}, {z, phi}, {t, 0, tmax}][[1]];
gr2 = ParametricPlot[Evaluate[{z[t], phi[t]} /. sol], {t, 0, tmax}, PlotStyle -> Red];
Show[gr1, gr2]



we get the stream flow in blue and a typical orbit in red.



enter image description here






share|cite|improve this answer









$endgroup$




















    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0












    $begingroup$

    With the MATHEMATICA script




    tmax = 10;
    gr1 = StreamPlot[{-0.13 phi - 0.07 phi^2 - 2.83 phi^3, z}, {z, -1, 1}, {phi, -1, 1}];
    sol = NDSolve[
    {phi'[t] == z[t],
    z'[t] == -0.13 phi[t] - 0.07 phi[t]^2 - 2.83 phi[t]^3,
    z[0] == 0.6, phi[0] == 0.6}, {z, phi}, {t, 0, tmax}][[1]];
    gr2 = ParametricPlot[Evaluate[{z[t], phi[t]} /. sol], {t, 0, tmax}, PlotStyle -> Red];
    Show[gr1, gr2]



    we get the stream flow in blue and a typical orbit in red.



    enter image description here






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      With the MATHEMATICA script




      tmax = 10;
      gr1 = StreamPlot[{-0.13 phi - 0.07 phi^2 - 2.83 phi^3, z}, {z, -1, 1}, {phi, -1, 1}];
      sol = NDSolve[
      {phi'[t] == z[t],
      z'[t] == -0.13 phi[t] - 0.07 phi[t]^2 - 2.83 phi[t]^3,
      z[0] == 0.6, phi[0] == 0.6}, {z, phi}, {t, 0, tmax}][[1]];
      gr2 = ParametricPlot[Evaluate[{z[t], phi[t]} /. sol], {t, 0, tmax}, PlotStyle -> Red];
      Show[gr1, gr2]



      we get the stream flow in blue and a typical orbit in red.



      enter image description here






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        With the MATHEMATICA script




        tmax = 10;
        gr1 = StreamPlot[{-0.13 phi - 0.07 phi^2 - 2.83 phi^3, z}, {z, -1, 1}, {phi, -1, 1}];
        sol = NDSolve[
        {phi'[t] == z[t],
        z'[t] == -0.13 phi[t] - 0.07 phi[t]^2 - 2.83 phi[t]^3,
        z[0] == 0.6, phi[0] == 0.6}, {z, phi}, {t, 0, tmax}][[1]];
        gr2 = ParametricPlot[Evaluate[{z[t], phi[t]} /. sol], {t, 0, tmax}, PlotStyle -> Red];
        Show[gr1, gr2]



        we get the stream flow in blue and a typical orbit in red.



        enter image description here






        share|cite|improve this answer









        $endgroup$



        With the MATHEMATICA script




        tmax = 10;
        gr1 = StreamPlot[{-0.13 phi - 0.07 phi^2 - 2.83 phi^3, z}, {z, -1, 1}, {phi, -1, 1}];
        sol = NDSolve[
        {phi'[t] == z[t],
        z'[t] == -0.13 phi[t] - 0.07 phi[t]^2 - 2.83 phi[t]^3,
        z[0] == 0.6, phi[0] == 0.6}, {z, phi}, {t, 0, tmax}][[1]];
        gr2 = ParametricPlot[Evaluate[{z[t], phi[t]} /. sol], {t, 0, tmax}, PlotStyle -> Red];
        Show[gr1, gr2]



        we get the stream flow in blue and a typical orbit in red.



        enter image description here







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 7 '18 at 12:53









        CesareoCesareo

        8,7693516




        8,7693516















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