Weak derivative












0












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I really need help with this exercise:



Let $f in L_2 (mathbb{R})$. Show the equivalence of the following statements:



(a) $f in H_1 (mathbb{R})$.



(b) The function $xi mapsto xi hat{f}(xi) in L_2 (mathbb{R})$.



(c) $lim_{h to 0} (f (x + h)-f (x)) / h$ exists in $L_2 (R)$.



I think I succeed in showing that (a) and (c) are equivalent, but I really don't know how to show that they are equivalent to (b).










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  • $begingroup$
    Hi Francesca, and welcome to the Math.SE: if you want to produce nicely formatted mathematical text for your questions, have a look at the Math Jax reference. Also, I would like to point out that, while being a customary notation, it should be pointed out that $hat{f}(xi)$ is the Fourier transform of $f(x)$
    $endgroup$
    – Daniele Tampieri
    Dec 12 '18 at 13:49
















0












$begingroup$


I really need help with this exercise:



Let $f in L_2 (mathbb{R})$. Show the equivalence of the following statements:



(a) $f in H_1 (mathbb{R})$.



(b) The function $xi mapsto xi hat{f}(xi) in L_2 (mathbb{R})$.



(c) $lim_{h to 0} (f (x + h)-f (x)) / h$ exists in $L_2 (R)$.



I think I succeed in showing that (a) and (c) are equivalent, but I really don't know how to show that they are equivalent to (b).










share|cite|improve this question











$endgroup$












  • $begingroup$
    Hi Francesca, and welcome to the Math.SE: if you want to produce nicely formatted mathematical text for your questions, have a look at the Math Jax reference. Also, I would like to point out that, while being a customary notation, it should be pointed out that $hat{f}(xi)$ is the Fourier transform of $f(x)$
    $endgroup$
    – Daniele Tampieri
    Dec 12 '18 at 13:49














0












0








0





$begingroup$


I really need help with this exercise:



Let $f in L_2 (mathbb{R})$. Show the equivalence of the following statements:



(a) $f in H_1 (mathbb{R})$.



(b) The function $xi mapsto xi hat{f}(xi) in L_2 (mathbb{R})$.



(c) $lim_{h to 0} (f (x + h)-f (x)) / h$ exists in $L_2 (R)$.



I think I succeed in showing that (a) and (c) are equivalent, but I really don't know how to show that they are equivalent to (b).










share|cite|improve this question











$endgroup$




I really need help with this exercise:



Let $f in L_2 (mathbb{R})$. Show the equivalence of the following statements:



(a) $f in H_1 (mathbb{R})$.



(b) The function $xi mapsto xi hat{f}(xi) in L_2 (mathbb{R})$.



(c) $lim_{h to 0} (f (x + h)-f (x)) / h$ exists in $L_2 (R)$.



I think I succeed in showing that (a) and (c) are equivalent, but I really don't know how to show that they are equivalent to (b).







functional-analysis fourier-transform weak-derivatives






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share|cite|improve this question













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edited Dec 12 '18 at 13:53









Daniele Tampieri

2,3272922




2,3272922










asked Dec 12 '18 at 13:35









Francesca BallatoreFrancesca Ballatore

426




426












  • $begingroup$
    Hi Francesca, and welcome to the Math.SE: if you want to produce nicely formatted mathematical text for your questions, have a look at the Math Jax reference. Also, I would like to point out that, while being a customary notation, it should be pointed out that $hat{f}(xi)$ is the Fourier transform of $f(x)$
    $endgroup$
    – Daniele Tampieri
    Dec 12 '18 at 13:49


















  • $begingroup$
    Hi Francesca, and welcome to the Math.SE: if you want to produce nicely formatted mathematical text for your questions, have a look at the Math Jax reference. Also, I would like to point out that, while being a customary notation, it should be pointed out that $hat{f}(xi)$ is the Fourier transform of $f(x)$
    $endgroup$
    – Daniele Tampieri
    Dec 12 '18 at 13:49
















$begingroup$
Hi Francesca, and welcome to the Math.SE: if you want to produce nicely formatted mathematical text for your questions, have a look at the Math Jax reference. Also, I would like to point out that, while being a customary notation, it should be pointed out that $hat{f}(xi)$ is the Fourier transform of $f(x)$
$endgroup$
– Daniele Tampieri
Dec 12 '18 at 13:49




$begingroup$
Hi Francesca, and welcome to the Math.SE: if you want to produce nicely formatted mathematical text for your questions, have a look at the Math Jax reference. Also, I would like to point out that, while being a customary notation, it should be pointed out that $hat{f}(xi)$ is the Fourier transform of $f(x)$
$endgroup$
– Daniele Tampieri
Dec 12 '18 at 13:49










1 Answer
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$begingroup$

Hint: The fourier transform of $i partial_x f(x)$ is $xi hat{f}(xi)$ (Think about why by pulling the derivative inside the Fourier integral, then try to justify that.). Since you know that the Fourier transform is a bijective and unitary map $L^2(mathbb{R}) to L^2(mathbb{R})$, you will be able to see that $partial_x f(x) in L^2$ and $xi hat{f}(xi) in L^2$ are equivalent.



Always be careful when proving things for the Fourier transform in $L^2$ because the Fourier integral $int f(x) e^{ikx}$ is only defined for some functions in a dense set in $L^2$.






share|cite|improve this answer









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    $begingroup$

    Hint: The fourier transform of $i partial_x f(x)$ is $xi hat{f}(xi)$ (Think about why by pulling the derivative inside the Fourier integral, then try to justify that.). Since you know that the Fourier transform is a bijective and unitary map $L^2(mathbb{R}) to L^2(mathbb{R})$, you will be able to see that $partial_x f(x) in L^2$ and $xi hat{f}(xi) in L^2$ are equivalent.



    Always be careful when proving things for the Fourier transform in $L^2$ because the Fourier integral $int f(x) e^{ikx}$ is only defined for some functions in a dense set in $L^2$.






    share|cite|improve this answer









    $endgroup$


















      1












      $begingroup$

      Hint: The fourier transform of $i partial_x f(x)$ is $xi hat{f}(xi)$ (Think about why by pulling the derivative inside the Fourier integral, then try to justify that.). Since you know that the Fourier transform is a bijective and unitary map $L^2(mathbb{R}) to L^2(mathbb{R})$, you will be able to see that $partial_x f(x) in L^2$ and $xi hat{f}(xi) in L^2$ are equivalent.



      Always be careful when proving things for the Fourier transform in $L^2$ because the Fourier integral $int f(x) e^{ikx}$ is only defined for some functions in a dense set in $L^2$.






      share|cite|improve this answer









      $endgroup$
















        1












        1








        1





        $begingroup$

        Hint: The fourier transform of $i partial_x f(x)$ is $xi hat{f}(xi)$ (Think about why by pulling the derivative inside the Fourier integral, then try to justify that.). Since you know that the Fourier transform is a bijective and unitary map $L^2(mathbb{R}) to L^2(mathbb{R})$, you will be able to see that $partial_x f(x) in L^2$ and $xi hat{f}(xi) in L^2$ are equivalent.



        Always be careful when proving things for the Fourier transform in $L^2$ because the Fourier integral $int f(x) e^{ikx}$ is only defined for some functions in a dense set in $L^2$.






        share|cite|improve this answer









        $endgroup$



        Hint: The fourier transform of $i partial_x f(x)$ is $xi hat{f}(xi)$ (Think about why by pulling the derivative inside the Fourier integral, then try to justify that.). Since you know that the Fourier transform is a bijective and unitary map $L^2(mathbb{R}) to L^2(mathbb{R})$, you will be able to see that $partial_x f(x) in L^2$ and $xi hat{f}(xi) in L^2$ are equivalent.



        Always be careful when proving things for the Fourier transform in $L^2$ because the Fourier integral $int f(x) e^{ikx}$ is only defined for some functions in a dense set in $L^2$.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 12 '18 at 14:05









        LukeLuke

        760216




        760216






























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