Notational question on Kunneth Formula for de Rham cohomology












1












$begingroup$


I got to learn the Kunneth Formula for de Rham cohomology as following.



$$H^n(Xtimes Y)=sum_{n=p+q} H^p(X)otimes H^q(Y). $$



And I could find same notation from https://www.encyclopediaofmath.org/index.php/K%C3%BCnneth_formula.



Actually, it is quite unfamiliar to use $sum$ for spaces. I think it should be $oplus$ instead of $sum$. It might be stupid question and maybe I am wrong and missing something. I am looking for some clarification for it!



And clear explanation for this would be appreciated! Thanks in advance.










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$endgroup$












  • $begingroup$
    You can use $sum_{iin I} W_i$ for spaces $W_i$ if they are all subspaces of a common vector space $V$. It is the subspace of $V$ consisting of all finite sums of the elements of the $W_i$. Note that the sum decomposition of an element needn’t be unique, so knowing something is a sum is less information than knowing that it is a direct sum. In case of this formula, you know that the sum is direct (and a priori the summands aren’t subspaces of a common space) so using $bigoplus$ is better.
    $endgroup$
    – Eike Schulte
    Dec 25 '18 at 11:31


















1












$begingroup$


I got to learn the Kunneth Formula for de Rham cohomology as following.



$$H^n(Xtimes Y)=sum_{n=p+q} H^p(X)otimes H^q(Y). $$



And I could find same notation from https://www.encyclopediaofmath.org/index.php/K%C3%BCnneth_formula.



Actually, it is quite unfamiliar to use $sum$ for spaces. I think it should be $oplus$ instead of $sum$. It might be stupid question and maybe I am wrong and missing something. I am looking for some clarification for it!



And clear explanation for this would be appreciated! Thanks in advance.










share|cite|improve this question









$endgroup$












  • $begingroup$
    You can use $sum_{iin I} W_i$ for spaces $W_i$ if they are all subspaces of a common vector space $V$. It is the subspace of $V$ consisting of all finite sums of the elements of the $W_i$. Note that the sum decomposition of an element needn’t be unique, so knowing something is a sum is less information than knowing that it is a direct sum. In case of this formula, you know that the sum is direct (and a priori the summands aren’t subspaces of a common space) so using $bigoplus$ is better.
    $endgroup$
    – Eike Schulte
    Dec 25 '18 at 11:31
















1












1








1





$begingroup$


I got to learn the Kunneth Formula for de Rham cohomology as following.



$$H^n(Xtimes Y)=sum_{n=p+q} H^p(X)otimes H^q(Y). $$



And I could find same notation from https://www.encyclopediaofmath.org/index.php/K%C3%BCnneth_formula.



Actually, it is quite unfamiliar to use $sum$ for spaces. I think it should be $oplus$ instead of $sum$. It might be stupid question and maybe I am wrong and missing something. I am looking for some clarification for it!



And clear explanation for this would be appreciated! Thanks in advance.










share|cite|improve this question









$endgroup$




I got to learn the Kunneth Formula for de Rham cohomology as following.



$$H^n(Xtimes Y)=sum_{n=p+q} H^p(X)otimes H^q(Y). $$



And I could find same notation from https://www.encyclopediaofmath.org/index.php/K%C3%BCnneth_formula.



Actually, it is quite unfamiliar to use $sum$ for spaces. I think it should be $oplus$ instead of $sum$. It might be stupid question and maybe I am wrong and missing something. I am looking for some clarification for it!



And clear explanation for this would be appreciated! Thanks in advance.







notation de-rham-cohomology






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asked Dec 25 '18 at 3:35









Lev BanLev Ban

1,0751317




1,0751317












  • $begingroup$
    You can use $sum_{iin I} W_i$ for spaces $W_i$ if they are all subspaces of a common vector space $V$. It is the subspace of $V$ consisting of all finite sums of the elements of the $W_i$. Note that the sum decomposition of an element needn’t be unique, so knowing something is a sum is less information than knowing that it is a direct sum. In case of this formula, you know that the sum is direct (and a priori the summands aren’t subspaces of a common space) so using $bigoplus$ is better.
    $endgroup$
    – Eike Schulte
    Dec 25 '18 at 11:31




















  • $begingroup$
    You can use $sum_{iin I} W_i$ for spaces $W_i$ if they are all subspaces of a common vector space $V$. It is the subspace of $V$ consisting of all finite sums of the elements of the $W_i$. Note that the sum decomposition of an element needn’t be unique, so knowing something is a sum is less information than knowing that it is a direct sum. In case of this formula, you know that the sum is direct (and a priori the summands aren’t subspaces of a common space) so using $bigoplus$ is better.
    $endgroup$
    – Eike Schulte
    Dec 25 '18 at 11:31


















$begingroup$
You can use $sum_{iin I} W_i$ for spaces $W_i$ if they are all subspaces of a common vector space $V$. It is the subspace of $V$ consisting of all finite sums of the elements of the $W_i$. Note that the sum decomposition of an element needn’t be unique, so knowing something is a sum is less information than knowing that it is a direct sum. In case of this formula, you know that the sum is direct (and a priori the summands aren’t subspaces of a common space) so using $bigoplus$ is better.
$endgroup$
– Eike Schulte
Dec 25 '18 at 11:31






$begingroup$
You can use $sum_{iin I} W_i$ for spaces $W_i$ if they are all subspaces of a common vector space $V$. It is the subspace of $V$ consisting of all finite sums of the elements of the $W_i$. Note that the sum decomposition of an element needn’t be unique, so knowing something is a sum is less information than knowing that it is a direct sum. In case of this formula, you know that the sum is direct (and a priori the summands aren’t subspaces of a common space) so using $bigoplus$ is better.
$endgroup$
– Eike Schulte
Dec 25 '18 at 11:31












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$begingroup$

Yes, you're right. Indeed we are talking about the direct sum over these spaces. Some people use $sum$ rather than $bigoplus$ in this situation. My advisor actually does the same thing. I suspect that it's a more old-fashioned means of writing the expression. But, anyway, the expression should be read as:
$$ H^n(Xtimes Y)=bigoplus_{p+q=n} H^p(X)otimes H^q(Y)$$
as you propose.






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    1 Answer
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    $begingroup$

    Yes, you're right. Indeed we are talking about the direct sum over these spaces. Some people use $sum$ rather than $bigoplus$ in this situation. My advisor actually does the same thing. I suspect that it's a more old-fashioned means of writing the expression. But, anyway, the expression should be read as:
    $$ H^n(Xtimes Y)=bigoplus_{p+q=n} H^p(X)otimes H^q(Y)$$
    as you propose.






    share|cite|improve this answer









    $endgroup$


















      1












      $begingroup$

      Yes, you're right. Indeed we are talking about the direct sum over these spaces. Some people use $sum$ rather than $bigoplus$ in this situation. My advisor actually does the same thing. I suspect that it's a more old-fashioned means of writing the expression. But, anyway, the expression should be read as:
      $$ H^n(Xtimes Y)=bigoplus_{p+q=n} H^p(X)otimes H^q(Y)$$
      as you propose.






      share|cite|improve this answer









      $endgroup$
















        1












        1








        1





        $begingroup$

        Yes, you're right. Indeed we are talking about the direct sum over these spaces. Some people use $sum$ rather than $bigoplus$ in this situation. My advisor actually does the same thing. I suspect that it's a more old-fashioned means of writing the expression. But, anyway, the expression should be read as:
        $$ H^n(Xtimes Y)=bigoplus_{p+q=n} H^p(X)otimes H^q(Y)$$
        as you propose.






        share|cite|improve this answer









        $endgroup$



        Yes, you're right. Indeed we are talking about the direct sum over these spaces. Some people use $sum$ rather than $bigoplus$ in this situation. My advisor actually does the same thing. I suspect that it's a more old-fashioned means of writing the expression. But, anyway, the expression should be read as:
        $$ H^n(Xtimes Y)=bigoplus_{p+q=n} H^p(X)otimes H^q(Y)$$
        as you propose.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 25 '18 at 3:38









        Antonios-Alexandros RobotisAntonios-Alexandros Robotis

        10.6k41741




        10.6k41741






























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