Random sampling of 100 data points from a binomial population
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This is my question I need to answer: Generate a random sample of 100 data points from a binomial population
B(40, 0.4).
I'm pretty sure that n=100 and my mean is 40 and standard deviation is .4, but I just do not know how to find the random sample?
statistics
asked Dec 12 '13 at 0:03
M ColbyM Colby
11
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add a comment |
$begingroup$
This is my question I need to answer: Generate a random sample of 100 data points from a binomial population
B(40, 0.4).
I'm pretty sure that n=100 and my mean is 40 and standard deviation is .4, but I just do not know how to find the random sample?
statistics
asked Dec 12 '13 at 0:03
M ColbyM Colby
11
$endgroup$
3
$begingroup$
Presumably you have access to a random number generator, which produces pseudo-random numbers in the interval $[0,1)$. Call something between $0$ and $0.4$ a success. Repeat $40$ times, count the number of successes. That will give you one data point. Repeat $100$ times.
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– André Nicolas
Dec 12 '13 at 0:30
add a comment |
$begingroup$
This is my question I need to answer: Generate a random sample of 100 data points from a binomial population
B(40, 0.4).
I'm pretty sure that n=100 and my mean is 40 and standard deviation is .4, but I just do not know how to find the random sample?
statistics
asked Dec 12 '13 at 0:03
M ColbyM Colby
11
$endgroup$
This is my question I need to answer: Generate a random sample of 100 data points from a binomial population
B(40, 0.4).
I'm pretty sure that n=100 and my mean is 40 and standard deviation is .4, but I just do not know how to find the random sample?
statistics
statistics
asked Dec 12 '13 at 0:03
M ColbyM Colby
11
asked Dec 12 '13 at 0:03
M ColbyM Colby
11
asked Dec 12 '13 at 0:03
M ColbyM Colby
11
asked Dec 12 '13 at 0:03
M ColbyM Colby
11
asked Dec 12 '13 at 0:03
M ColbyM Colby
11
11
3
$begingroup$
Presumably you have access to a random number generator, which produces pseudo-random numbers in the interval $[0,1)$. Call something between $0$ and $0.4$ a success. Repeat $40$ times, count the number of successes. That will give you one data point. Repeat $100$ times.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:30
add a comment |
3
$begingroup$
Presumably you have access to a random number generator, which produces pseudo-random numbers in the interval $[0,1)$. Call something between $0$ and $0.4$ a success. Repeat $40$ times, count the number of successes. That will give you one data point. Repeat $100$ times.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:30
3
3
$begingroup$
Presumably you have access to a random number generator, which produces pseudo-random numbers in the interval $[0,1)$. Call something between $0$ and $0.4$ a success. Repeat $40$ times, count the number of successes. That will give you one data point. Repeat $100$ times.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:30
$begingroup$
Presumably you have access to a random number generator, which produces pseudo-random numbers in the interval $[0,1)$. Call something between $0$ and $0.4$ a success. Repeat $40$ times, count the number of successes. That will give you one data point. Repeat $100$ times.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:30
add a comment |
2 Answers
2
active
oldest
votes
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I generated in Mathematica, here are one sample data:
13, 16, 14, 18, 13, 10, 15, 15, 22, 9, 18, 18, 13, 17, 14, 10, 18,
16, 15, 18, 12, 16, 13, 12, 12, 9, 13, 17, 14, 13, 25, 16, 20, 23,
15, 10, 23, 14, 16, 18, 19, 22, 13, 16, 20, 16, 15, 12, 12, 13, 17,
15, 18, 13, 13, 17, 15, 15, 20, 15, 13, 16, 14, 18, 15, 15, 19, 17,
16, 21, 17, 20, 19, 14, 16, 16, 17, 19, 17, 23, 14, 20, 17, 13, 15,
21, 21, 23, 17, 22, 9, 11, 21, 12, 20, 15, 22, 15, 20, 15
answered Dec 12 '13 at 0:22
LorenMtLorenMt
25818
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You said 40 is the mean..so let me redo again. 40 should be the number of trial.
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– LorenMt
Dec 12 '13 at 0:37
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OP had indeed said $40$ is the mean, but that is not true.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:39
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I have changed the data.
$endgroup$
– LorenMt
Dec 12 '13 at 0:41
add a comment |
$begingroup$
You need a random number generator. If you have excel, you can simply use the following formula: BINOM.INV(40,0.4,RAND()) and copy it into 100 cells. Each time you pres F9, you will get a new set of observations.
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add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
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active
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active
oldest
votes
$begingroup$
I generated in Mathematica, here are one sample data:
13, 16, 14, 18, 13, 10, 15, 15, 22, 9, 18, 18, 13, 17, 14, 10, 18,
16, 15, 18, 12, 16, 13, 12, 12, 9, 13, 17, 14, 13, 25, 16, 20, 23,
15, 10, 23, 14, 16, 18, 19, 22, 13, 16, 20, 16, 15, 12, 12, 13, 17,
15, 18, 13, 13, 17, 15, 15, 20, 15, 13, 16, 14, 18, 15, 15, 19, 17,
16, 21, 17, 20, 19, 14, 16, 16, 17, 19, 17, 23, 14, 20, 17, 13, 15,
21, 21, 23, 17, 22, 9, 11, 21, 12, 20, 15, 22, 15, 20, 15
answered Dec 12 '13 at 0:22
LorenMtLorenMt
25818
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$begingroup$
You said 40 is the mean..so let me redo again. 40 should be the number of trial.
$endgroup$
– LorenMt
Dec 12 '13 at 0:37
$begingroup$
OP had indeed said $40$ is the mean, but that is not true.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:39
$begingroup$
I have changed the data.
$endgroup$
– LorenMt
Dec 12 '13 at 0:41
add a comment |
$begingroup$
I generated in Mathematica, here are one sample data:
13, 16, 14, 18, 13, 10, 15, 15, 22, 9, 18, 18, 13, 17, 14, 10, 18,
16, 15, 18, 12, 16, 13, 12, 12, 9, 13, 17, 14, 13, 25, 16, 20, 23,
15, 10, 23, 14, 16, 18, 19, 22, 13, 16, 20, 16, 15, 12, 12, 13, 17,
15, 18, 13, 13, 17, 15, 15, 20, 15, 13, 16, 14, 18, 15, 15, 19, 17,
16, 21, 17, 20, 19, 14, 16, 16, 17, 19, 17, 23, 14, 20, 17, 13, 15,
21, 21, 23, 17, 22, 9, 11, 21, 12, 20, 15, 22, 15, 20, 15
answered Dec 12 '13 at 0:22
LorenMtLorenMt
25818
$endgroup$
$begingroup$
You said 40 is the mean..so let me redo again. 40 should be the number of trial.
$endgroup$
– LorenMt
Dec 12 '13 at 0:37
$begingroup$
OP had indeed said $40$ is the mean, but that is not true.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:39
$begingroup$
I have changed the data.
$endgroup$
– LorenMt
Dec 12 '13 at 0:41
add a comment |
$begingroup$
I generated in Mathematica, here are one sample data:
13, 16, 14, 18, 13, 10, 15, 15, 22, 9, 18, 18, 13, 17, 14, 10, 18,
16, 15, 18, 12, 16, 13, 12, 12, 9, 13, 17, 14, 13, 25, 16, 20, 23,
15, 10, 23, 14, 16, 18, 19, 22, 13, 16, 20, 16, 15, 12, 12, 13, 17,
15, 18, 13, 13, 17, 15, 15, 20, 15, 13, 16, 14, 18, 15, 15, 19, 17,
16, 21, 17, 20, 19, 14, 16, 16, 17, 19, 17, 23, 14, 20, 17, 13, 15,
21, 21, 23, 17, 22, 9, 11, 21, 12, 20, 15, 22, 15, 20, 15
answered Dec 12 '13 at 0:22
LorenMtLorenMt
25818
$endgroup$
I generated in Mathematica, here are one sample data:
13, 16, 14, 18, 13, 10, 15, 15, 22, 9, 18, 18, 13, 17, 14, 10, 18,
16, 15, 18, 12, 16, 13, 12, 12, 9, 13, 17, 14, 13, 25, 16, 20, 23,
15, 10, 23, 14, 16, 18, 19, 22, 13, 16, 20, 16, 15, 12, 12, 13, 17,
15, 18, 13, 13, 17, 15, 15, 20, 15, 13, 16, 14, 18, 15, 15, 19, 17,
16, 21, 17, 20, 19, 14, 16, 16, 17, 19, 17, 23, 14, 20, 17, 13, 15,
21, 21, 23, 17, 22, 9, 11, 21, 12, 20, 15, 22, 15, 20, 15
answered Dec 12 '13 at 0:22
LorenMtLorenMt
25818
edited Dec 12 '13 at 0:38
answered Dec 12 '13 at 0:22
LorenMtLorenMt
25818
answered Dec 12 '13 at 0:22
LorenMtLorenMt
25818
answered Dec 12 '13 at 0:22
LorenMtLorenMt
25818
25818
$begingroup$
You said 40 is the mean..so let me redo again. 40 should be the number of trial.
$endgroup$
– LorenMt
Dec 12 '13 at 0:37
$begingroup$
OP had indeed said $40$ is the mean, but that is not true.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:39
$begingroup$
I have changed the data.
$endgroup$
– LorenMt
Dec 12 '13 at 0:41
add a comment |
$begingroup$
You said 40 is the mean..so let me redo again. 40 should be the number of trial.
$endgroup$
– LorenMt
Dec 12 '13 at 0:37
$begingroup$
OP had indeed said $40$ is the mean, but that is not true.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:39
$begingroup$
I have changed the data.
$endgroup$
– LorenMt
Dec 12 '13 at 0:41
$begingroup$
You said 40 is the mean..so let me redo again. 40 should be the number of trial.
$endgroup$
– LorenMt
Dec 12 '13 at 0:37
$begingroup$
You said 40 is the mean..so let me redo again. 40 should be the number of trial.
$endgroup$
– LorenMt
Dec 12 '13 at 0:37
$begingroup$
OP had indeed said $40$ is the mean, but that is not true.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:39
$begingroup$
OP had indeed said $40$ is the mean, but that is not true.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:39
$begingroup$
I have changed the data.
$endgroup$
– LorenMt
Dec 12 '13 at 0:41
$begingroup$
I have changed the data.
$endgroup$
– LorenMt
Dec 12 '13 at 0:41
add a comment |
$begingroup$
You need a random number generator. If you have excel, you can simply use the following formula: BINOM.INV(40,0.4,RAND()) and copy it into 100 cells. Each time you pres F9, you will get a new set of observations.
$endgroup$
add a comment |
$begingroup$
You need a random number generator. If you have excel, you can simply use the following formula: BINOM.INV(40,0.4,RAND()) and copy it into 100 cells. Each time you pres F9, you will get a new set of observations.
$endgroup$
add a comment |
$begingroup$
You need a random number generator. If you have excel, you can simply use the following formula: BINOM.INV(40,0.4,RAND()) and copy it into 100 cells. Each time you pres F9, you will get a new set of observations.
$endgroup$
You need a random number generator. If you have excel, you can simply use the following formula: BINOM.INV(40,0.4,RAND()) and copy it into 100 cells. Each time you pres F9, you will get a new set of observations.
answered Dec 12 '13 at 3:52
user76844
add a comment |
add a comment |
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$begingroup$
Presumably you have access to a random number generator, which produces pseudo-random numbers in the interval $[0,1)$. Call something between $0$ and $0.4$ a success. Repeat $40$ times, count the number of successes. That will give you one data point. Repeat $100$ times.
$endgroup$
– André Nicolas
Dec 12 '13 at 0:30