Interesting and hard question for me. [closed]











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I showed that an interesting question. I don't know answers.





The borders of our world
in any part of a country
the bell is ringing.



When the bell rings the number of unknown airports airplane take off.



Every plane
to the nearest airport.



An airport
maximum how many planes can land?



$textbf{Solution:}$
Same as six planes
airport
airport layout, easily
as seen
(see hexagon on the side) easily
is available. No more airplanes can land at the same airport,
up to six planes. Why is that?



https://imgur.com/a/PqmIMks










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closed as off-topic by ancientmathematician, Lord Shark the Unknown, Jens, amWhy, Phil H Nov 14 at 20:56


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is not about mathematics, within the scope defined in the help center." – ancientmathematician, Lord Shark the Unknown, amWhy

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Assume start from any airport and any of its neighbor, there is at most one airplane fight between them. the answer will be six. Even though an airport can has infinitely many nearest neighbors, it can be the nearest neighbor for at most 6 airports (or 5 if the airports are placed in general position).
    – achille hui
    Nov 14 at 9:30










  • @achillehui Yes, Answer will be six. I have looked. But, I can't understand well. Why was the negative vote given :)?
    – 1ENİGMA1
    Nov 14 at 9:38












  • The negative vote isn't from me. Let's say we have an airport located at $p$. Let $q_1, q_2$ be the location of two other airports which have the first airport as nearest neighbor. WOLOG, assume $|pq_1| ge |pq_2|$. Since $p$ is a nearest neighbor of $q_1$, we have $|q_1q_2| ge |pq_1|$. These two inequalities together implies $angle q_1pq_2 ge 60^circ$. As a result, $p$ can be the nearest neighbor for at most $6$ airports.
    – achille hui
    Nov 14 at 10:56










  • I vote to close the question.
    – Dog_69
    Nov 14 at 14:11












  • I click on "Leave Open."
    – Narasimham
    Nov 14 at 15:15















up vote
-3
down vote

favorite












I showed that an interesting question. I don't know answers.





The borders of our world
in any part of a country
the bell is ringing.



When the bell rings the number of unknown airports airplane take off.



Every plane
to the nearest airport.



An airport
maximum how many planes can land?



$textbf{Solution:}$
Same as six planes
airport
airport layout, easily
as seen
(see hexagon on the side) easily
is available. No more airplanes can land at the same airport,
up to six planes. Why is that?



https://imgur.com/a/PqmIMks










share|cite|improve this question















closed as off-topic by ancientmathematician, Lord Shark the Unknown, Jens, amWhy, Phil H Nov 14 at 20:56


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is not about mathematics, within the scope defined in the help center." – ancientmathematician, Lord Shark the Unknown, amWhy

If this question can be reworded to fit the rules in the help center, please edit the question.













  • Assume start from any airport and any of its neighbor, there is at most one airplane fight between them. the answer will be six. Even though an airport can has infinitely many nearest neighbors, it can be the nearest neighbor for at most 6 airports (or 5 if the airports are placed in general position).
    – achille hui
    Nov 14 at 9:30










  • @achillehui Yes, Answer will be six. I have looked. But, I can't understand well. Why was the negative vote given :)?
    – 1ENİGMA1
    Nov 14 at 9:38












  • The negative vote isn't from me. Let's say we have an airport located at $p$. Let $q_1, q_2$ be the location of two other airports which have the first airport as nearest neighbor. WOLOG, assume $|pq_1| ge |pq_2|$. Since $p$ is a nearest neighbor of $q_1$, we have $|q_1q_2| ge |pq_1|$. These two inequalities together implies $angle q_1pq_2 ge 60^circ$. As a result, $p$ can be the nearest neighbor for at most $6$ airports.
    – achille hui
    Nov 14 at 10:56










  • I vote to close the question.
    – Dog_69
    Nov 14 at 14:11












  • I click on "Leave Open."
    – Narasimham
    Nov 14 at 15:15













up vote
-3
down vote

favorite









up vote
-3
down vote

favorite











I showed that an interesting question. I don't know answers.





The borders of our world
in any part of a country
the bell is ringing.



When the bell rings the number of unknown airports airplane take off.



Every plane
to the nearest airport.



An airport
maximum how many planes can land?



$textbf{Solution:}$
Same as six planes
airport
airport layout, easily
as seen
(see hexagon on the side) easily
is available. No more airplanes can land at the same airport,
up to six planes. Why is that?



https://imgur.com/a/PqmIMks










share|cite|improve this question















I showed that an interesting question. I don't know answers.





The borders of our world
in any part of a country
the bell is ringing.



When the bell rings the number of unknown airports airplane take off.



Every plane
to the nearest airport.



An airport
maximum how many planes can land?



$textbf{Solution:}$
Same as six planes
airport
airport layout, easily
as seen
(see hexagon on the side) easily
is available. No more airplanes can land at the same airport,
up to six planes. Why is that?



https://imgur.com/a/PqmIMks







puzzle






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 15 at 15:47

























asked Nov 14 at 8:41









1ENİGMA1

936316




936316




closed as off-topic by ancientmathematician, Lord Shark the Unknown, Jens, amWhy, Phil H Nov 14 at 20:56


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is not about mathematics, within the scope defined in the help center." – ancientmathematician, Lord Shark the Unknown, amWhy

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by ancientmathematician, Lord Shark the Unknown, Jens, amWhy, Phil H Nov 14 at 20:56


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is not about mathematics, within the scope defined in the help center." – ancientmathematician, Lord Shark the Unknown, amWhy

If this question can be reworded to fit the rules in the help center, please edit the question.












  • Assume start from any airport and any of its neighbor, there is at most one airplane fight between them. the answer will be six. Even though an airport can has infinitely many nearest neighbors, it can be the nearest neighbor for at most 6 airports (or 5 if the airports are placed in general position).
    – achille hui
    Nov 14 at 9:30










  • @achillehui Yes, Answer will be six. I have looked. But, I can't understand well. Why was the negative vote given :)?
    – 1ENİGMA1
    Nov 14 at 9:38












  • The negative vote isn't from me. Let's say we have an airport located at $p$. Let $q_1, q_2$ be the location of two other airports which have the first airport as nearest neighbor. WOLOG, assume $|pq_1| ge |pq_2|$. Since $p$ is a nearest neighbor of $q_1$, we have $|q_1q_2| ge |pq_1|$. These two inequalities together implies $angle q_1pq_2 ge 60^circ$. As a result, $p$ can be the nearest neighbor for at most $6$ airports.
    – achille hui
    Nov 14 at 10:56










  • I vote to close the question.
    – Dog_69
    Nov 14 at 14:11












  • I click on "Leave Open."
    – Narasimham
    Nov 14 at 15:15


















  • Assume start from any airport and any of its neighbor, there is at most one airplane fight between them. the answer will be six. Even though an airport can has infinitely many nearest neighbors, it can be the nearest neighbor for at most 6 airports (or 5 if the airports are placed in general position).
    – achille hui
    Nov 14 at 9:30










  • @achillehui Yes, Answer will be six. I have looked. But, I can't understand well. Why was the negative vote given :)?
    – 1ENİGMA1
    Nov 14 at 9:38












  • The negative vote isn't from me. Let's say we have an airport located at $p$. Let $q_1, q_2$ be the location of two other airports which have the first airport as nearest neighbor. WOLOG, assume $|pq_1| ge |pq_2|$. Since $p$ is a nearest neighbor of $q_1$, we have $|q_1q_2| ge |pq_1|$. These two inequalities together implies $angle q_1pq_2 ge 60^circ$. As a result, $p$ can be the nearest neighbor for at most $6$ airports.
    – achille hui
    Nov 14 at 10:56










  • I vote to close the question.
    – Dog_69
    Nov 14 at 14:11












  • I click on "Leave Open."
    – Narasimham
    Nov 14 at 15:15
















Assume start from any airport and any of its neighbor, there is at most one airplane fight between them. the answer will be six. Even though an airport can has infinitely many nearest neighbors, it can be the nearest neighbor for at most 6 airports (or 5 if the airports are placed in general position).
– achille hui
Nov 14 at 9:30




Assume start from any airport and any of its neighbor, there is at most one airplane fight between them. the answer will be six. Even though an airport can has infinitely many nearest neighbors, it can be the nearest neighbor for at most 6 airports (or 5 if the airports are placed in general position).
– achille hui
Nov 14 at 9:30












@achillehui Yes, Answer will be six. I have looked. But, I can't understand well. Why was the negative vote given :)?
– 1ENİGMA1
Nov 14 at 9:38






@achillehui Yes, Answer will be six. I have looked. But, I can't understand well. Why was the negative vote given :)?
– 1ENİGMA1
Nov 14 at 9:38














The negative vote isn't from me. Let's say we have an airport located at $p$. Let $q_1, q_2$ be the location of two other airports which have the first airport as nearest neighbor. WOLOG, assume $|pq_1| ge |pq_2|$. Since $p$ is a nearest neighbor of $q_1$, we have $|q_1q_2| ge |pq_1|$. These two inequalities together implies $angle q_1pq_2 ge 60^circ$. As a result, $p$ can be the nearest neighbor for at most $6$ airports.
– achille hui
Nov 14 at 10:56




The negative vote isn't from me. Let's say we have an airport located at $p$. Let $q_1, q_2$ be the location of two other airports which have the first airport as nearest neighbor. WOLOG, assume $|pq_1| ge |pq_2|$. Since $p$ is a nearest neighbor of $q_1$, we have $|q_1q_2| ge |pq_1|$. These two inequalities together implies $angle q_1pq_2 ge 60^circ$. As a result, $p$ can be the nearest neighbor for at most $6$ airports.
– achille hui
Nov 14 at 10:56












I vote to close the question.
– Dog_69
Nov 14 at 14:11






I vote to close the question.
– Dog_69
Nov 14 at 14:11














I click on "Leave Open."
– Narasimham
Nov 14 at 15:15




I click on "Leave Open."
– Narasimham
Nov 14 at 15:15















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