Proving a set is not a embedded submaifold.











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So I am asked to find out which level sets of the function $f:mathbb{R}^2 to mathbb{R}$ given by $f(x,y)=x^3+xy+y^3+1$ are embedded submanifolds of $mathbb{R}^2$.



You can see that the points in the set $X=mathbb{R}-{1,frac{28}{27}}$ are regular values ($(0,0)$ and $(-frac{1}{3},-frac{1}{3})$ are not regular points).



So $f^{-1}(q)$ is a embedded submanifold for every $q$ in $X$.



My question is, how can I find out if $f^{-1}(1)$ is/is not an embedded submanifold? Likewise with $frac{28}{27}$.



Thanks in advanced.










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  • $f$ is defined on $mathbb{R}^2$.
    – Paul Frost
    Nov 16 at 16:14










  • My bad... its a typo though. My mind was someplace else when I was writting, evidently. Thanks
    – Bajo Fondo
    Nov 16 at 17:49















up vote
0
down vote

favorite












So I am asked to find out which level sets of the function $f:mathbb{R}^2 to mathbb{R}$ given by $f(x,y)=x^3+xy+y^3+1$ are embedded submanifolds of $mathbb{R}^2$.



You can see that the points in the set $X=mathbb{R}-{1,frac{28}{27}}$ are regular values ($(0,0)$ and $(-frac{1}{3},-frac{1}{3})$ are not regular points).



So $f^{-1}(q)$ is a embedded submanifold for every $q$ in $X$.



My question is, how can I find out if $f^{-1}(1)$ is/is not an embedded submanifold? Likewise with $frac{28}{27}$.



Thanks in advanced.










share|cite|improve this question
























  • $f$ is defined on $mathbb{R}^2$.
    – Paul Frost
    Nov 16 at 16:14










  • My bad... its a typo though. My mind was someplace else when I was writting, evidently. Thanks
    – Bajo Fondo
    Nov 16 at 17:49













up vote
0
down vote

favorite









up vote
0
down vote

favorite











So I am asked to find out which level sets of the function $f:mathbb{R}^2 to mathbb{R}$ given by $f(x,y)=x^3+xy+y^3+1$ are embedded submanifolds of $mathbb{R}^2$.



You can see that the points in the set $X=mathbb{R}-{1,frac{28}{27}}$ are regular values ($(0,0)$ and $(-frac{1}{3},-frac{1}{3})$ are not regular points).



So $f^{-1}(q)$ is a embedded submanifold for every $q$ in $X$.



My question is, how can I find out if $f^{-1}(1)$ is/is not an embedded submanifold? Likewise with $frac{28}{27}$.



Thanks in advanced.










share|cite|improve this question















So I am asked to find out which level sets of the function $f:mathbb{R}^2 to mathbb{R}$ given by $f(x,y)=x^3+xy+y^3+1$ are embedded submanifolds of $mathbb{R}^2$.



You can see that the points in the set $X=mathbb{R}-{1,frac{28}{27}}$ are regular values ($(0,0)$ and $(-frac{1}{3},-frac{1}{3})$ are not regular points).



So $f^{-1}(q)$ is a embedded submanifold for every $q$ in $X$.



My question is, how can I find out if $f^{-1}(1)$ is/is not an embedded submanifold? Likewise with $frac{28}{27}$.



Thanks in advanced.







differential-topology






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 16 at 17:49

























asked Nov 16 at 14:50









Bajo Fondo

421213




421213












  • $f$ is defined on $mathbb{R}^2$.
    – Paul Frost
    Nov 16 at 16:14










  • My bad... its a typo though. My mind was someplace else when I was writting, evidently. Thanks
    – Bajo Fondo
    Nov 16 at 17:49


















  • $f$ is defined on $mathbb{R}^2$.
    – Paul Frost
    Nov 16 at 16:14










  • My bad... its a typo though. My mind was someplace else when I was writting, evidently. Thanks
    – Bajo Fondo
    Nov 16 at 17:49
















$f$ is defined on $mathbb{R}^2$.
– Paul Frost
Nov 16 at 16:14




$f$ is defined on $mathbb{R}^2$.
– Paul Frost
Nov 16 at 16:14












My bad... its a typo though. My mind was someplace else when I was writting, evidently. Thanks
– Bajo Fondo
Nov 16 at 17:49




My bad... its a typo though. My mind was someplace else when I was writting, evidently. Thanks
– Bajo Fondo
Nov 16 at 17:49















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