compactly support function with constant value
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I am interested in finding a function $varphicolonmathbb{R}tomathbb{R}$ with the following property:
$varphi$ has compact support, which contains $left[0,1right]$
$varphi$ is continuously differentiable on $mathbb{R}$ at every order.
$varphi$ is constant on (at least one) an intevarl of the form $left[0,1/nright]$, where $ninmathbb{N}$.
As pointed out in an exercise in the book "Functional Analysis, Sobolev Spaces, and Differential Equations" by Haim Brezis, we can construct one via mollifiers. However, it does not seem to give a closed form or explicit formula that we can easily play with.
So here is my question: Is there an example where we have a closed form that is easy to play with?
Any help/hint is highly appreciated.
real-analysis integration functional-analysis derivatives distribution-theory
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|
show 2 more comments
$begingroup$
I am interested in finding a function $varphicolonmathbb{R}tomathbb{R}$ with the following property:
$varphi$ has compact support, which contains $left[0,1right]$
$varphi$ is continuously differentiable on $mathbb{R}$ at every order.
$varphi$ is constant on (at least one) an intevarl of the form $left[0,1/nright]$, where $ninmathbb{N}$.
As pointed out in an exercise in the book "Functional Analysis, Sobolev Spaces, and Differential Equations" by Haim Brezis, we can construct one via mollifiers. However, it does not seem to give a closed form or explicit formula that we can easily play with.
So here is my question: Is there an example where we have a closed form that is easy to play with?
Any help/hint is highly appreciated.
real-analysis integration functional-analysis derivatives distribution-theory
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1
$begingroup$
This might be helpful.
$endgroup$
– MisterRiemann
Nov 30 '18 at 18:33
2
$begingroup$
You mean *mollifiers, not modifiers, presumably
$endgroup$
– qbert
Nov 30 '18 at 18:37
1
$begingroup$
I think an easier way to state your second condition is simply to say $varphi$ is $C^infty$.
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– Clayton
Nov 30 '18 at 18:38
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@MisterRiemann Yes, very helpful indeed.
$endgroup$
– weirdo
Nov 30 '18 at 18:38
2
$begingroup$
Same as MisterRiemann example : show one by one $C^infty$, compact support, constantness
$endgroup$
– reuns
Nov 30 '18 at 18:47
|
show 2 more comments
$begingroup$
I am interested in finding a function $varphicolonmathbb{R}tomathbb{R}$ with the following property:
$varphi$ has compact support, which contains $left[0,1right]$
$varphi$ is continuously differentiable on $mathbb{R}$ at every order.
$varphi$ is constant on (at least one) an intevarl of the form $left[0,1/nright]$, where $ninmathbb{N}$.
As pointed out in an exercise in the book "Functional Analysis, Sobolev Spaces, and Differential Equations" by Haim Brezis, we can construct one via mollifiers. However, it does not seem to give a closed form or explicit formula that we can easily play with.
So here is my question: Is there an example where we have a closed form that is easy to play with?
Any help/hint is highly appreciated.
real-analysis integration functional-analysis derivatives distribution-theory
$endgroup$
I am interested in finding a function $varphicolonmathbb{R}tomathbb{R}$ with the following property:
$varphi$ has compact support, which contains $left[0,1right]$
$varphi$ is continuously differentiable on $mathbb{R}$ at every order.
$varphi$ is constant on (at least one) an intevarl of the form $left[0,1/nright]$, where $ninmathbb{N}$.
As pointed out in an exercise in the book "Functional Analysis, Sobolev Spaces, and Differential Equations" by Haim Brezis, we can construct one via mollifiers. However, it does not seem to give a closed form or explicit formula that we can easily play with.
So here is my question: Is there an example where we have a closed form that is easy to play with?
Any help/hint is highly appreciated.
real-analysis integration functional-analysis derivatives distribution-theory
real-analysis integration functional-analysis derivatives distribution-theory
edited Nov 30 '18 at 18:38
weirdo
asked Nov 30 '18 at 18:31
weirdoweirdo
420210
420210
1
$begingroup$
This might be helpful.
$endgroup$
– MisterRiemann
Nov 30 '18 at 18:33
2
$begingroup$
You mean *mollifiers, not modifiers, presumably
$endgroup$
– qbert
Nov 30 '18 at 18:37
1
$begingroup$
I think an easier way to state your second condition is simply to say $varphi$ is $C^infty$.
$endgroup$
– Clayton
Nov 30 '18 at 18:38
$begingroup$
@MisterRiemann Yes, very helpful indeed.
$endgroup$
– weirdo
Nov 30 '18 at 18:38
2
$begingroup$
Same as MisterRiemann example : show one by one $C^infty$, compact support, constantness
$endgroup$
– reuns
Nov 30 '18 at 18:47
|
show 2 more comments
1
$begingroup$
This might be helpful.
$endgroup$
– MisterRiemann
Nov 30 '18 at 18:33
2
$begingroup$
You mean *mollifiers, not modifiers, presumably
$endgroup$
– qbert
Nov 30 '18 at 18:37
1
$begingroup$
I think an easier way to state your second condition is simply to say $varphi$ is $C^infty$.
$endgroup$
– Clayton
Nov 30 '18 at 18:38
$begingroup$
@MisterRiemann Yes, very helpful indeed.
$endgroup$
– weirdo
Nov 30 '18 at 18:38
2
$begingroup$
Same as MisterRiemann example : show one by one $C^infty$, compact support, constantness
$endgroup$
– reuns
Nov 30 '18 at 18:47
1
1
$begingroup$
This might be helpful.
$endgroup$
– MisterRiemann
Nov 30 '18 at 18:33
$begingroup$
This might be helpful.
$endgroup$
– MisterRiemann
Nov 30 '18 at 18:33
2
2
$begingroup$
You mean *mollifiers, not modifiers, presumably
$endgroup$
– qbert
Nov 30 '18 at 18:37
$begingroup$
You mean *mollifiers, not modifiers, presumably
$endgroup$
– qbert
Nov 30 '18 at 18:37
1
1
$begingroup$
I think an easier way to state your second condition is simply to say $varphi$ is $C^infty$.
$endgroup$
– Clayton
Nov 30 '18 at 18:38
$begingroup$
I think an easier way to state your second condition is simply to say $varphi$ is $C^infty$.
$endgroup$
– Clayton
Nov 30 '18 at 18:38
$begingroup$
@MisterRiemann Yes, very helpful indeed.
$endgroup$
– weirdo
Nov 30 '18 at 18:38
$begingroup$
@MisterRiemann Yes, very helpful indeed.
$endgroup$
– weirdo
Nov 30 '18 at 18:38
2
2
$begingroup$
Same as MisterRiemann example : show one by one $C^infty$, compact support, constantness
$endgroup$
– reuns
Nov 30 '18 at 18:47
$begingroup$
Same as MisterRiemann example : show one by one $C^infty$, compact support, constantness
$endgroup$
– reuns
Nov 30 '18 at 18:47
|
show 2 more comments
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1
$begingroup$
This might be helpful.
$endgroup$
– MisterRiemann
Nov 30 '18 at 18:33
2
$begingroup$
You mean *mollifiers, not modifiers, presumably
$endgroup$
– qbert
Nov 30 '18 at 18:37
1
$begingroup$
I think an easier way to state your second condition is simply to say $varphi$ is $C^infty$.
$endgroup$
– Clayton
Nov 30 '18 at 18:38
$begingroup$
@MisterRiemann Yes, very helpful indeed.
$endgroup$
– weirdo
Nov 30 '18 at 18:38
2
$begingroup$
Same as MisterRiemann example : show one by one $C^infty$, compact support, constantness
$endgroup$
– reuns
Nov 30 '18 at 18:47