print the first line of those files in current directory which are having last line with a pattern
I have multiple log files in a directory and want to print first line of those files which are having pattern vanished on last line.
Could it be done with awk for *.logs having also printed name of the logfile before the first line is printed out?
text-processing awk files
edited Dec 22 '18 at 17:35
don_crissti
50.3k15134162
asked Dec 22 '18 at 14:44
ChrisChris
146112
add a comment |
I have multiple log files in a directory and want to print first line of those files which are having pattern vanished on last line.
Could it be done with awk for *.logs having also printed name of the logfile before the first line is printed out?
text-processing awk files
edited Dec 22 '18 at 17:35
don_crissti
50.3k15134162
asked Dec 22 '18 at 14:44
ChrisChris
146112
add a comment |
I have multiple log files in a directory and want to print first line of those files which are having pattern vanished on last line.
Could it be done with awk for *.logs having also printed name of the logfile before the first line is printed out?
text-processing awk files
edited Dec 22 '18 at 17:35
don_crissti
50.3k15134162
asked Dec 22 '18 at 14:44
ChrisChris
146112
I have multiple log files in a directory and want to print first line of those files which are having pattern vanished on last line.
Could it be done with awk for *.logs having also printed name of the logfile before the first line is printed out?
text-processing awk files
text-processing awk files
edited Dec 22 '18 at 17:35
don_crissti
50.3k15134162
asked Dec 22 '18 at 14:44
ChrisChris
146112
edited Dec 22 '18 at 17:35
don_crissti
50.3k15134162
asked Dec 22 '18 at 14:44
ChrisChris
146112
edited Dec 22 '18 at 17:35
don_crissti
50.3k15134162
edited Dec 22 '18 at 17:35
don_crissti
50.3k15134162
edited Dec 22 '18 at 17:35
don_crissti
50.3k15134162
50.3k15134162
asked Dec 22 '18 at 14:44
ChrisChris
146112
asked Dec 22 '18 at 14:44
ChrisChris
146112
asked Dec 22 '18 at 14:44
ChrisChris
146112
146112
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
something like this?
for f in *.logs; do tail -n 1 -- "$f" | grep -q vanished && { printf '%s: ' "$f"; head -n 1 -- "$f"; }; done
You can also do it with awk but it will be less efficient if the files are big, because you will have to read the whole file, not just the beginning and the end.
edited Dec 22 '18 at 18:00
Stéphane Chazelas
301k55565917
answered Dec 22 '18 at 15:04
Uncle BillyUncle Billy
4185
add a comment |
If you want to do this with awk only this could probably get you in the right direction:
for f in *.log; do awk 'NR==1{ first_line=$0 } END { last_line=$0; print( last_line ~ /varnished/) ? "File: " FILENAME "n" first_line : "" }' "$f"; done
The for loop is probably not necessarily but this is the most efficient way I could find doing it with awk
And thanks to the comments below, now we can let gawk do its work as follows:
gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print substr(FILENAME,3) ":", first}' ./*.log
On recent linux systems, awk is a symlink to gawk. For example, on recent Fedora releases this is the case:
# ls -l /bin/awk
lrwxrwxrwx. 1 root root 4 Jul 13 07:55 /bin/awk -> gawk
answered Dec 22 '18 at 16:17
Valentin BajramiValentin Bajrami
5,96111627
2
With a reasonably recent GNU awk you probably could avoid the loop e.g.gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print FILENAME ":", first}' *.log
– steeldriver
Dec 22 '18 at 17:31
2
That wouldn't work with files namesfoo=bar.logfor instance. You can work around it by using./*.logand replaceFILENAMEwithsubstr(FILENAME, 3).
– Stéphane Chazelas
Dec 22 '18 at 18:02
add a comment |
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2 Answers
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2 Answers
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something like this?
for f in *.logs; do tail -n 1 -- "$f" | grep -q vanished && { printf '%s: ' "$f"; head -n 1 -- "$f"; }; done
You can also do it with awk but it will be less efficient if the files are big, because you will have to read the whole file, not just the beginning and the end.
edited Dec 22 '18 at 18:00
Stéphane Chazelas
301k55565917
answered Dec 22 '18 at 15:04
Uncle BillyUncle Billy
4185
add a comment |
something like this?
for f in *.logs; do tail -n 1 -- "$f" | grep -q vanished && { printf '%s: ' "$f"; head -n 1 -- "$f"; }; done
You can also do it with awk but it will be less efficient if the files are big, because you will have to read the whole file, not just the beginning and the end.
edited Dec 22 '18 at 18:00
Stéphane Chazelas
301k55565917
answered Dec 22 '18 at 15:04
Uncle BillyUncle Billy
4185
add a comment |
something like this?
for f in *.logs; do tail -n 1 -- "$f" | grep -q vanished && { printf '%s: ' "$f"; head -n 1 -- "$f"; }; done
You can also do it with awk but it will be less efficient if the files are big, because you will have to read the whole file, not just the beginning and the end.
edited Dec 22 '18 at 18:00
Stéphane Chazelas
301k55565917
answered Dec 22 '18 at 15:04
Uncle BillyUncle Billy
4185
something like this?
for f in *.logs; do tail -n 1 -- "$f" | grep -q vanished && { printf '%s: ' "$f"; head -n 1 -- "$f"; }; done
You can also do it with awk but it will be less efficient if the files are big, because you will have to read the whole file, not just the beginning and the end.
edited Dec 22 '18 at 18:00
Stéphane Chazelas
301k55565917
answered Dec 22 '18 at 15:04
Uncle BillyUncle Billy
4185
edited Dec 22 '18 at 18:00
Stéphane Chazelas
301k55565917
edited Dec 22 '18 at 18:00
Stéphane Chazelas
301k55565917
edited Dec 22 '18 at 18:00
Stéphane Chazelas
301k55565917
301k55565917
answered Dec 22 '18 at 15:04
Uncle BillyUncle Billy
4185
answered Dec 22 '18 at 15:04
Uncle BillyUncle Billy
4185
answered Dec 22 '18 at 15:04
Uncle BillyUncle Billy
4185
4185
add a comment |
add a comment |
If you want to do this with awk only this could probably get you in the right direction:
for f in *.log; do awk 'NR==1{ first_line=$0 } END { last_line=$0; print( last_line ~ /varnished/) ? "File: " FILENAME "n" first_line : "" }' "$f"; done
The for loop is probably not necessarily but this is the most efficient way I could find doing it with awk
And thanks to the comments below, now we can let gawk do its work as follows:
gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print substr(FILENAME,3) ":", first}' ./*.log
On recent linux systems, awk is a symlink to gawk. For example, on recent Fedora releases this is the case:
# ls -l /bin/awk
lrwxrwxrwx. 1 root root 4 Jul 13 07:55 /bin/awk -> gawk
answered Dec 22 '18 at 16:17
Valentin BajramiValentin Bajrami
5,96111627
2
With a reasonably recent GNU awk you probably could avoid the loop e.g.gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print FILENAME ":", first}' *.log
– steeldriver
Dec 22 '18 at 17:31
2
That wouldn't work with files namesfoo=bar.logfor instance. You can work around it by using./*.logand replaceFILENAMEwithsubstr(FILENAME, 3).
– Stéphane Chazelas
Dec 22 '18 at 18:02
add a comment |
If you want to do this with awk only this could probably get you in the right direction:
for f in *.log; do awk 'NR==1{ first_line=$0 } END { last_line=$0; print( last_line ~ /varnished/) ? "File: " FILENAME "n" first_line : "" }' "$f"; done
The for loop is probably not necessarily but this is the most efficient way I could find doing it with awk
And thanks to the comments below, now we can let gawk do its work as follows:
gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print substr(FILENAME,3) ":", first}' ./*.log
On recent linux systems, awk is a symlink to gawk. For example, on recent Fedora releases this is the case:
# ls -l /bin/awk
lrwxrwxrwx. 1 root root 4 Jul 13 07:55 /bin/awk -> gawk
answered Dec 22 '18 at 16:17
Valentin BajramiValentin Bajrami
5,96111627
2
With a reasonably recent GNU awk you probably could avoid the loop e.g.gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print FILENAME ":", first}' *.log
– steeldriver
Dec 22 '18 at 17:31
2
That wouldn't work with files namesfoo=bar.logfor instance. You can work around it by using./*.logand replaceFILENAMEwithsubstr(FILENAME, 3).
– Stéphane Chazelas
Dec 22 '18 at 18:02
add a comment |
If you want to do this with awk only this could probably get you in the right direction:
for f in *.log; do awk 'NR==1{ first_line=$0 } END { last_line=$0; print( last_line ~ /varnished/) ? "File: " FILENAME "n" first_line : "" }' "$f"; done
The for loop is probably not necessarily but this is the most efficient way I could find doing it with awk
And thanks to the comments below, now we can let gawk do its work as follows:
gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print substr(FILENAME,3) ":", first}' ./*.log
On recent linux systems, awk is a symlink to gawk. For example, on recent Fedora releases this is the case:
# ls -l /bin/awk
lrwxrwxrwx. 1 root root 4 Jul 13 07:55 /bin/awk -> gawk
answered Dec 22 '18 at 16:17
Valentin BajramiValentin Bajrami
5,96111627
If you want to do this with awk only this could probably get you in the right direction:
for f in *.log; do awk 'NR==1{ first_line=$0 } END { last_line=$0; print( last_line ~ /varnished/) ? "File: " FILENAME "n" first_line : "" }' "$f"; done
The for loop is probably not necessarily but this is the most efficient way I could find doing it with awk
And thanks to the comments below, now we can let gawk do its work as follows:
gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print substr(FILENAME,3) ":", first}' ./*.log
On recent linux systems, awk is a symlink to gawk. For example, on recent Fedora releases this is the case:
# ls -l /bin/awk
lrwxrwxrwx. 1 root root 4 Jul 13 07:55 /bin/awk -> gawk
answered Dec 22 '18 at 16:17
Valentin BajramiValentin Bajrami
5,96111627
edited Dec 23 '18 at 13:59
answered Dec 22 '18 at 16:17
Valentin BajramiValentin Bajrami
5,96111627
answered Dec 22 '18 at 16:17
Valentin BajramiValentin Bajrami
5,96111627
answered Dec 22 '18 at 16:17
Valentin BajramiValentin Bajrami
5,96111627
5,96111627
2
With a reasonably recent GNU awk you probably could avoid the loop e.g.gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print FILENAME ":", first}' *.log
– steeldriver
Dec 22 '18 at 17:31
2
That wouldn't work with files namesfoo=bar.logfor instance. You can work around it by using./*.logand replaceFILENAMEwithsubstr(FILENAME, 3).
– Stéphane Chazelas
Dec 22 '18 at 18:02
add a comment |
2
With a reasonably recent GNU awk you probably could avoid the loop e.g.gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print FILENAME ":", first}' *.log
– steeldriver
Dec 22 '18 at 17:31
2
That wouldn't work with files namesfoo=bar.logfor instance. You can work around it by using./*.logand replaceFILENAMEwithsubstr(FILENAME, 3).
– Stéphane Chazelas
Dec 22 '18 at 18:02
2
2
With a reasonably recent GNU awk you probably could avoid the loop e.g.
gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print FILENAME ":", first}' *.log– steeldriver
Dec 22 '18 at 17:31
With a reasonably recent GNU awk you probably could avoid the loop e.g.
gawk 'FNR==1 {first = $0} ENDFILE {if($0 ~ /varnished/) print FILENAME ":", first}' *.log– steeldriver
Dec 22 '18 at 17:31
2
2
That wouldn't work with files names
foo=bar.log for instance. You can work around it by using ./*.log and replace FILENAME with substr(FILENAME, 3).– Stéphane Chazelas
Dec 22 '18 at 18:02
That wouldn't work with files names
foo=bar.log for instance. You can work around it by using ./*.log and replace FILENAME with substr(FILENAME, 3).– Stéphane Chazelas
Dec 22 '18 at 18:02
add a comment |
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