Is every right coset a subgroup of the group? [closed]












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Is every right coset a subgroup of the group?










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closed as off-topic by Shaun, KReiser, José Carlos Santos, amWhy, Shailesh Nov 29 '18 at 0:27


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shaun, KReiser, José Carlos Santos, amWhy, Shailesh

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    No. In fact, only one of the cosets contains the identity element.
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    – Darío G
    Mar 18 '16 at 10:11
















0












$begingroup$


Is every right coset a subgroup of the group?










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closed as off-topic by Shaun, KReiser, José Carlos Santos, amWhy, Shailesh Nov 29 '18 at 0:27


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shaun, KReiser, José Carlos Santos, amWhy, Shailesh

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 5




    $begingroup$
    No. In fact, only one of the cosets contains the identity element.
    $endgroup$
    – Darío G
    Mar 18 '16 at 10:11














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0





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Is every right coset a subgroup of the group?










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Is every right coset a subgroup of the group?







group-theory






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edited Nov 28 '18 at 23:17









Shaun

8,832113681




8,832113681










asked Mar 18 '16 at 10:10









Kiran PatelKiran Patel

41




41




closed as off-topic by Shaun, KReiser, José Carlos Santos, amWhy, Shailesh Nov 29 '18 at 0:27


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shaun, KReiser, José Carlos Santos, amWhy, Shailesh

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Shaun, KReiser, José Carlos Santos, amWhy, Shailesh Nov 29 '18 at 0:27


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shaun, KReiser, José Carlos Santos, amWhy, Shailesh

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 5




    $begingroup$
    No. In fact, only one of the cosets contains the identity element.
    $endgroup$
    – Darío G
    Mar 18 '16 at 10:11














  • 5




    $begingroup$
    No. In fact, only one of the cosets contains the identity element.
    $endgroup$
    – Darío G
    Mar 18 '16 at 10:11








5




5




$begingroup$
No. In fact, only one of the cosets contains the identity element.
$endgroup$
– Darío G
Mar 18 '16 at 10:11




$begingroup$
No. In fact, only one of the cosets contains the identity element.
$endgroup$
– Darío G
Mar 18 '16 at 10:11










3 Answers
3






active

oldest

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2












$begingroup$

To expand on the other answers with an example: Wikipedia has this neat diagram about cosets.



coset diagram



It portrays




  • the group $G = mathbb Z_8$ under addition,

  • its subgroup $H = {0, 4}$,

  • all cosets of $H$ in $G$.


Clearly, only $H$ contains the identity element $0$, so only $H$ is a group. The cosets $1+H$ and $2+H$ and $3+H$ don’t contain $0$, so they fail to satisfy this important group property.






share|cite|improve this answer









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    1












    $begingroup$

    No, Let $(G,circ ,e)$ be our group, Note that for every $gin G$ and $Hle G$ s.t $gneq e$, We get that $enotin gH$ And therefor cannot be a subgroup of $H$ nor $G$ (the same goes for left cosets)






    share|cite|improve this answer









    $endgroup$





















      1












      $begingroup$

      If $H leq G$ then $aHbH=abH quad forall a,bin G$ if and only if $H$ is a normal subgroup of $G$ i.e $aHa^{-1}=H quad forall ain G$ .

      For a counter example $ langle (1,2)rangle leq S_3 $.






      share|cite|improve this answer











      $endgroup$













      • $begingroup$
        I thought that he,she had asked that when cosets make a group :)
        $endgroup$
        – user217174
        Mar 18 '16 at 14:20




















      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      2












      $begingroup$

      To expand on the other answers with an example: Wikipedia has this neat diagram about cosets.



      coset diagram



      It portrays




      • the group $G = mathbb Z_8$ under addition,

      • its subgroup $H = {0, 4}$,

      • all cosets of $H$ in $G$.


      Clearly, only $H$ contains the identity element $0$, so only $H$ is a group. The cosets $1+H$ and $2+H$ and $3+H$ don’t contain $0$, so they fail to satisfy this important group property.






      share|cite|improve this answer









      $endgroup$


















        2












        $begingroup$

        To expand on the other answers with an example: Wikipedia has this neat diagram about cosets.



        coset diagram



        It portrays




        • the group $G = mathbb Z_8$ under addition,

        • its subgroup $H = {0, 4}$,

        • all cosets of $H$ in $G$.


        Clearly, only $H$ contains the identity element $0$, so only $H$ is a group. The cosets $1+H$ and $2+H$ and $3+H$ don’t contain $0$, so they fail to satisfy this important group property.






        share|cite|improve this answer









        $endgroup$
















          2












          2








          2





          $begingroup$

          To expand on the other answers with an example: Wikipedia has this neat diagram about cosets.



          coset diagram



          It portrays




          • the group $G = mathbb Z_8$ under addition,

          • its subgroup $H = {0, 4}$,

          • all cosets of $H$ in $G$.


          Clearly, only $H$ contains the identity element $0$, so only $H$ is a group. The cosets $1+H$ and $2+H$ and $3+H$ don’t contain $0$, so they fail to satisfy this important group property.






          share|cite|improve this answer









          $endgroup$



          To expand on the other answers with an example: Wikipedia has this neat diagram about cosets.



          coset diagram



          It portrays




          • the group $G = mathbb Z_8$ under addition,

          • its subgroup $H = {0, 4}$,

          • all cosets of $H$ in $G$.


          Clearly, only $H$ contains the identity element $0$, so only $H$ is a group. The cosets $1+H$ and $2+H$ and $3+H$ don’t contain $0$, so they fail to satisfy this important group property.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Mar 18 '16 at 10:27









          LynnLynn

          2,5851526




          2,5851526























              1












              $begingroup$

              No, Let $(G,circ ,e)$ be our group, Note that for every $gin G$ and $Hle G$ s.t $gneq e$, We get that $enotin gH$ And therefor cannot be a subgroup of $H$ nor $G$ (the same goes for left cosets)






              share|cite|improve this answer









              $endgroup$


















                1












                $begingroup$

                No, Let $(G,circ ,e)$ be our group, Note that for every $gin G$ and $Hle G$ s.t $gneq e$, We get that $enotin gH$ And therefor cannot be a subgroup of $H$ nor $G$ (the same goes for left cosets)






                share|cite|improve this answer









                $endgroup$
















                  1












                  1








                  1





                  $begingroup$

                  No, Let $(G,circ ,e)$ be our group, Note that for every $gin G$ and $Hle G$ s.t $gneq e$, We get that $enotin gH$ And therefor cannot be a subgroup of $H$ nor $G$ (the same goes for left cosets)






                  share|cite|improve this answer









                  $endgroup$



                  No, Let $(G,circ ,e)$ be our group, Note that for every $gin G$ and $Hle G$ s.t $gneq e$, We get that $enotin gH$ And therefor cannot be a subgroup of $H$ nor $G$ (the same goes for left cosets)







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Mar 18 '16 at 10:16









                  shasha

                  987615




                  987615























                      1












                      $begingroup$

                      If $H leq G$ then $aHbH=abH quad forall a,bin G$ if and only if $H$ is a normal subgroup of $G$ i.e $aHa^{-1}=H quad forall ain G$ .

                      For a counter example $ langle (1,2)rangle leq S_3 $.






                      share|cite|improve this answer











                      $endgroup$













                      • $begingroup$
                        I thought that he,she had asked that when cosets make a group :)
                        $endgroup$
                        – user217174
                        Mar 18 '16 at 14:20


















                      1












                      $begingroup$

                      If $H leq G$ then $aHbH=abH quad forall a,bin G$ if and only if $H$ is a normal subgroup of $G$ i.e $aHa^{-1}=H quad forall ain G$ .

                      For a counter example $ langle (1,2)rangle leq S_3 $.






                      share|cite|improve this answer











                      $endgroup$













                      • $begingroup$
                        I thought that he,she had asked that when cosets make a group :)
                        $endgroup$
                        – user217174
                        Mar 18 '16 at 14:20
















                      1












                      1








                      1





                      $begingroup$

                      If $H leq G$ then $aHbH=abH quad forall a,bin G$ if and only if $H$ is a normal subgroup of $G$ i.e $aHa^{-1}=H quad forall ain G$ .

                      For a counter example $ langle (1,2)rangle leq S_3 $.






                      share|cite|improve this answer











                      $endgroup$



                      If $H leq G$ then $aHbH=abH quad forall a,bin G$ if and only if $H$ is a normal subgroup of $G$ i.e $aHa^{-1}=H quad forall ain G$ .

                      For a counter example $ langle (1,2)rangle leq S_3 $.







                      share|cite|improve this answer














                      share|cite|improve this answer



                      share|cite|improve this answer








                      edited Mar 18 '16 at 10:20

























                      answered Mar 18 '16 at 10:14







                      user217174



















                      • $begingroup$
                        I thought that he,she had asked that when cosets make a group :)
                        $endgroup$
                        – user217174
                        Mar 18 '16 at 14:20




















                      • $begingroup$
                        I thought that he,she had asked that when cosets make a group :)
                        $endgroup$
                        – user217174
                        Mar 18 '16 at 14:20


















                      $begingroup$
                      I thought that he,she had asked that when cosets make a group :)
                      $endgroup$
                      – user217174
                      Mar 18 '16 at 14:20






                      $begingroup$
                      I thought that he,she had asked that when cosets make a group :)
                      $endgroup$
                      – user217174
                      Mar 18 '16 at 14:20





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