How to launch couple of .sh in one command?





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I have some files in a folder and want to launch them in one command. Structure looks like this:



keddad@keddad-HP:/media/$ ls
somfile.sh
otherfile.sh
onemorefile.sh


So I'm trying to do it with a command:



./*


But it starts only first file, ignoring others in the folder. How can I launch them all in one time (or make them to work one-by-one, so the second will start after terminating the first one)?










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    0















    I have some files in a folder and want to launch them in one command. Structure looks like this:



    keddad@keddad-HP:/media/$ ls
    somfile.sh
    otherfile.sh
    onemorefile.sh


    So I'm trying to do it with a command:



    ./*


    But it starts only first file, ignoring others in the folder. How can I launch them all in one time (or make them to work one-by-one, so the second will start after terminating the first one)?










    share|improve this question

























      0












      0








      0








      I have some files in a folder and want to launch them in one command. Structure looks like this:



      keddad@keddad-HP:/media/$ ls
      somfile.sh
      otherfile.sh
      onemorefile.sh


      So I'm trying to do it with a command:



      ./*


      But it starts only first file, ignoring others in the folder. How can I launch them all in one time (or make them to work one-by-one, so the second will start after terminating the first one)?










      share|improve this question














      I have some files in a folder and want to launch them in one command. Structure looks like this:



      keddad@keddad-HP:/media/$ ls
      somfile.sh
      otherfile.sh
      onemorefile.sh


      So I'm trying to do it with a command:



      ./*


      But it starts only first file, ignoring others in the folder. How can I launch them all in one time (or make them to work one-by-one, so the second will start after terminating the first one)?







      linux bash sh






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      asked Feb 2 at 7:19









      biryulin04biryulin04

      6218




      6218






















          1 Answer
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          When you tried ./* , the shell saw the single command:



          ./somfile.sh ./otherfile.sh ./onemorefile.sh


          Or, in other words, it saw one command (./somefile.sh) with two arguments (./otherfile.sh ./onemorefile.sh)



          To run them one-by-one (sequentially):



          for each in ./* ; do "${each}" ; done


          To run them all at once (simultaneously / parallel):



          for each in ./* ; do "${each}" & done





          share|improve this answer
























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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2














            When you tried ./* , the shell saw the single command:



            ./somfile.sh ./otherfile.sh ./onemorefile.sh


            Or, in other words, it saw one command (./somefile.sh) with two arguments (./otherfile.sh ./onemorefile.sh)



            To run them one-by-one (sequentially):



            for each in ./* ; do "${each}" ; done


            To run them all at once (simultaneously / parallel):



            for each in ./* ; do "${each}" & done





            share|improve this answer




























              2














              When you tried ./* , the shell saw the single command:



              ./somfile.sh ./otherfile.sh ./onemorefile.sh


              Or, in other words, it saw one command (./somefile.sh) with two arguments (./otherfile.sh ./onemorefile.sh)



              To run them one-by-one (sequentially):



              for each in ./* ; do "${each}" ; done


              To run them all at once (simultaneously / parallel):



              for each in ./* ; do "${each}" & done





              share|improve this answer


























                2












                2








                2







                When you tried ./* , the shell saw the single command:



                ./somfile.sh ./otherfile.sh ./onemorefile.sh


                Or, in other words, it saw one command (./somefile.sh) with two arguments (./otherfile.sh ./onemorefile.sh)



                To run them one-by-one (sequentially):



                for each in ./* ; do "${each}" ; done


                To run them all at once (simultaneously / parallel):



                for each in ./* ; do "${each}" & done





                share|improve this answer













                When you tried ./* , the shell saw the single command:



                ./somfile.sh ./otherfile.sh ./onemorefile.sh


                Or, in other words, it saw one command (./somefile.sh) with two arguments (./otherfile.sh ./onemorefile.sh)



                To run them one-by-one (sequentially):



                for each in ./* ; do "${each}" ; done


                To run them all at once (simultaneously / parallel):



                for each in ./* ; do "${each}" & done






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Feb 2 at 7:31









                SlartibartfastSlartibartfast

                6,46621724




                6,46621724






























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