Solving for a function in Maxima (software)












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I'm using the Maxima software to solve an equation (involving derivatives) and I basically have an equation of the following form (although more complicated because there are more terms in my equation):



Eq: $Af(r) = Bdisplaystylefrac{d g(r)}{dr}$.



Now, I would like to solve this for $f$ and I tried using commands like "funcsolve(Eq, f(r))", which when applied to the above equation gives the output:



Outp: $f(r) = displaystylefrac{B}{A} frac{d g(r)}{dr}$.



But this is juste an output and the function $f$ is not yet defined, so I do:



define(f(r), rhs(Outp));



and it defines the function $f$ as:



$f(r) = displaystylefrac{B}{A} frac{d g(r)}{dr}$.



The problem is that when I evaluate $f$ in a point $a$, it gives the following:



$f(a) = displaystylefrac{B}{A} frac{d g(a)}{da}$,



whereas I would obviously like to have:



$f(a) = displaystylefrac{B}{A} frac{d g(a)}{dr}$.



Does anyone know how to resolve this problem?



Thanks in advance for any help










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    0












    $begingroup$


    I'm using the Maxima software to solve an equation (involving derivatives) and I basically have an equation of the following form (although more complicated because there are more terms in my equation):



    Eq: $Af(r) = Bdisplaystylefrac{d g(r)}{dr}$.



    Now, I would like to solve this for $f$ and I tried using commands like "funcsolve(Eq, f(r))", which when applied to the above equation gives the output:



    Outp: $f(r) = displaystylefrac{B}{A} frac{d g(r)}{dr}$.



    But this is juste an output and the function $f$ is not yet defined, so I do:



    define(f(r), rhs(Outp));



    and it defines the function $f$ as:



    $f(r) = displaystylefrac{B}{A} frac{d g(r)}{dr}$.



    The problem is that when I evaluate $f$ in a point $a$, it gives the following:



    $f(a) = displaystylefrac{B}{A} frac{d g(a)}{da}$,



    whereas I would obviously like to have:



    $f(a) = displaystylefrac{B}{A} frac{d g(a)}{dr}$.



    Does anyone know how to resolve this problem?



    Thanks in advance for any help










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      I'm using the Maxima software to solve an equation (involving derivatives) and I basically have an equation of the following form (although more complicated because there are more terms in my equation):



      Eq: $Af(r) = Bdisplaystylefrac{d g(r)}{dr}$.



      Now, I would like to solve this for $f$ and I tried using commands like "funcsolve(Eq, f(r))", which when applied to the above equation gives the output:



      Outp: $f(r) = displaystylefrac{B}{A} frac{d g(r)}{dr}$.



      But this is juste an output and the function $f$ is not yet defined, so I do:



      define(f(r), rhs(Outp));



      and it defines the function $f$ as:



      $f(r) = displaystylefrac{B}{A} frac{d g(r)}{dr}$.



      The problem is that when I evaluate $f$ in a point $a$, it gives the following:



      $f(a) = displaystylefrac{B}{A} frac{d g(a)}{da}$,



      whereas I would obviously like to have:



      $f(a) = displaystylefrac{B}{A} frac{d g(a)}{dr}$.



      Does anyone know how to resolve this problem?



      Thanks in advance for any help










      share|cite|improve this question









      $endgroup$




      I'm using the Maxima software to solve an equation (involving derivatives) and I basically have an equation of the following form (although more complicated because there are more terms in my equation):



      Eq: $Af(r) = Bdisplaystylefrac{d g(r)}{dr}$.



      Now, I would like to solve this for $f$ and I tried using commands like "funcsolve(Eq, f(r))", which when applied to the above equation gives the output:



      Outp: $f(r) = displaystylefrac{B}{A} frac{d g(r)}{dr}$.



      But this is juste an output and the function $f$ is not yet defined, so I do:



      define(f(r), rhs(Outp));



      and it defines the function $f$ as:



      $f(r) = displaystylefrac{B}{A} frac{d g(r)}{dr}$.



      The problem is that when I evaluate $f$ in a point $a$, it gives the following:



      $f(a) = displaystylefrac{B}{A} frac{d g(a)}{da}$,



      whereas I would obviously like to have:



      $f(a) = displaystylefrac{B}{A} frac{d g(a)}{dr}$.



      Does anyone know how to resolve this problem?



      Thanks in advance for any help







      maxima-software






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      share|cite|improve this question











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      share|cite|improve this question










      asked Dec 20 '18 at 16:14









      MichaëlMichaël

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