Is it possible to search for a directory/file combination?
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I need to find an image, say ABC.jpg, that I know will have been programmatically placed into a directory named ABC_MPSC. I've tried:
cd /
find . -name "ABC_MPSC/ABC.jpg"
But that doesn't return anything (I actually know where the particular one I'm searching for is, so I know it exists). Is there a find command that could have helped me not have to search manually?
find
New contributor
add a comment |
I need to find an image, say ABC.jpg, that I know will have been programmatically placed into a directory named ABC_MPSC. I've tried:
cd /
find . -name "ABC_MPSC/ABC.jpg"
But that doesn't return anything (I actually know where the particular one I'm searching for is, so I know it exists). Is there a find command that could have helped me not have to search manually?
find
New contributor
Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
Mar 29 at 18:31
2
You can also find it usinglocate
, which should be significantly faster, but only works if the file already existed whenupdatedb
was last run.
– Simon Richter
Mar 29 at 20:01
add a comment |
I need to find an image, say ABC.jpg, that I know will have been programmatically placed into a directory named ABC_MPSC. I've tried:
cd /
find . -name "ABC_MPSC/ABC.jpg"
But that doesn't return anything (I actually know where the particular one I'm searching for is, so I know it exists). Is there a find command that could have helped me not have to search manually?
find
New contributor
I need to find an image, say ABC.jpg, that I know will have been programmatically placed into a directory named ABC_MPSC. I've tried:
cd /
find . -name "ABC_MPSC/ABC.jpg"
But that doesn't return anything (I actually know where the particular one I'm searching for is, so I know it exists). Is there a find command that could have helped me not have to search manually?
find
find
New contributor
New contributor
New contributor
asked Mar 29 at 18:27
PascLeRascPascLeRasc
1534
1534
New contributor
New contributor
Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
Mar 29 at 18:31
2
You can also find it usinglocate
, which should be significantly faster, but only works if the file already existed whenupdatedb
was last run.
– Simon Richter
Mar 29 at 20:01
add a comment |
Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
Mar 29 at 18:31
2
You can also find it usinglocate
, which should be significantly faster, but only works if the file already existed whenupdatedb
was last run.
– Simon Richter
Mar 29 at 20:01
Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
Mar 29 at 18:31
Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
Mar 29 at 18:31
2
2
You can also find it using
locate
, which should be significantly faster, but only works if the file already existed when updatedb
was last run.– Simon Richter
Mar 29 at 20:01
You can also find it using
locate
, which should be significantly faster, but only works if the file already existed when updatedb
was last run.– Simon Richter
Mar 29 at 20:01
add a comment |
2 Answers
2
active
oldest
votes
There's a -path
predicate that's useful here:
find . -path '*/ABC_MPSC/ABC.jpg'
The POSIX description for that predicate is:
The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.
The reason that your -name "ABC_MPSC/ABC.jpg"
failed is because the -name
predicate:
shall evaluate as true if the basename of the current pathname matches pattern
In other words, -name
never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).
add a comment |
Two ways (apart from using -path
):
Look for the directory, then detect the file:
find / -type d -name 'ABC_MPSC' -exec test -f {}/ABC.jpg ; -print
This relies on the
find
implementation to expand{}
to the current pathname of the found directory, even though it's concatenated with/ABC.jpg
(it's not required to do that). It could also be written as
find / -type d -name 'ABC_MPSC'
-exec sh -c 'test -f "$1"/ABC.jpg' sh {} ; -print
Look for the file, then check it's parent directory name:
find / -type f -name 'ABC.jpg' -exec sh -c '
case $(dirname "$1") in
*/ABC_MPSC) exit 0 ;;
*) exit 1
esac' sh {} ; -print
Both of these alternatives would be slower than using -path
in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
There's a -path
predicate that's useful here:
find . -path '*/ABC_MPSC/ABC.jpg'
The POSIX description for that predicate is:
The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.
The reason that your -name "ABC_MPSC/ABC.jpg"
failed is because the -name
predicate:
shall evaluate as true if the basename of the current pathname matches pattern
In other words, -name
never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).
add a comment |
There's a -path
predicate that's useful here:
find . -path '*/ABC_MPSC/ABC.jpg'
The POSIX description for that predicate is:
The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.
The reason that your -name "ABC_MPSC/ABC.jpg"
failed is because the -name
predicate:
shall evaluate as true if the basename of the current pathname matches pattern
In other words, -name
never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).
add a comment |
There's a -path
predicate that's useful here:
find . -path '*/ABC_MPSC/ABC.jpg'
The POSIX description for that predicate is:
The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.
The reason that your -name "ABC_MPSC/ABC.jpg"
failed is because the -name
predicate:
shall evaluate as true if the basename of the current pathname matches pattern
In other words, -name
never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).
There's a -path
predicate that's useful here:
find . -path '*/ABC_MPSC/ABC.jpg'
The POSIX description for that predicate is:
The primary shall evaluate as true if the current pathname matches pattern using the pattern matching notation described in Pattern Matching Notation. The additional rules in Patterns Used for Filename Expansion do not apply as this is a matching operation, not an expansion.
The reason that your -name "ABC_MPSC/ABC.jpg"
failed is because the -name
predicate:
shall evaluate as true if the basename of the current pathname matches pattern
In other words, -name
never sees the directory of the current filename, only the base filename itself (ABC.jpg, for example).
edited Mar 29 at 18:40
answered Mar 29 at 18:30
Jeff Schaller♦Jeff Schaller
44.6k1162145
44.6k1162145
add a comment |
add a comment |
Two ways (apart from using -path
):
Look for the directory, then detect the file:
find / -type d -name 'ABC_MPSC' -exec test -f {}/ABC.jpg ; -print
This relies on the
find
implementation to expand{}
to the current pathname of the found directory, even though it's concatenated with/ABC.jpg
(it's not required to do that). It could also be written as
find / -type d -name 'ABC_MPSC'
-exec sh -c 'test -f "$1"/ABC.jpg' sh {} ; -print
Look for the file, then check it's parent directory name:
find / -type f -name 'ABC.jpg' -exec sh -c '
case $(dirname "$1") in
*/ABC_MPSC) exit 0 ;;
*) exit 1
esac' sh {} ; -print
Both of these alternatives would be slower than using -path
in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.
add a comment |
Two ways (apart from using -path
):
Look for the directory, then detect the file:
find / -type d -name 'ABC_MPSC' -exec test -f {}/ABC.jpg ; -print
This relies on the
find
implementation to expand{}
to the current pathname of the found directory, even though it's concatenated with/ABC.jpg
(it's not required to do that). It could also be written as
find / -type d -name 'ABC_MPSC'
-exec sh -c 'test -f "$1"/ABC.jpg' sh {} ; -print
Look for the file, then check it's parent directory name:
find / -type f -name 'ABC.jpg' -exec sh -c '
case $(dirname "$1") in
*/ABC_MPSC) exit 0 ;;
*) exit 1
esac' sh {} ; -print
Both of these alternatives would be slower than using -path
in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.
add a comment |
Two ways (apart from using -path
):
Look for the directory, then detect the file:
find / -type d -name 'ABC_MPSC' -exec test -f {}/ABC.jpg ; -print
This relies on the
find
implementation to expand{}
to the current pathname of the found directory, even though it's concatenated with/ABC.jpg
(it's not required to do that). It could also be written as
find / -type d -name 'ABC_MPSC'
-exec sh -c 'test -f "$1"/ABC.jpg' sh {} ; -print
Look for the file, then check it's parent directory name:
find / -type f -name 'ABC.jpg' -exec sh -c '
case $(dirname "$1") in
*/ABC_MPSC) exit 0 ;;
*) exit 1
esac' sh {} ; -print
Both of these alternatives would be slower than using -path
in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.
Two ways (apart from using -path
):
Look for the directory, then detect the file:
find / -type d -name 'ABC_MPSC' -exec test -f {}/ABC.jpg ; -print
This relies on the
find
implementation to expand{}
to the current pathname of the found directory, even though it's concatenated with/ABC.jpg
(it's not required to do that). It could also be written as
find / -type d -name 'ABC_MPSC'
-exec sh -c 'test -f "$1"/ABC.jpg' sh {} ; -print
Look for the file, then check it's parent directory name:
find / -type f -name 'ABC.jpg' -exec sh -c '
case $(dirname "$1") in
*/ABC_MPSC) exit 0 ;;
*) exit 1
esac' sh {} ; -print
Both of these alternatives would be slower than using -path
in the way as Jeff shows. I'm leaving them here as examples none the less, as they could possibly be adapted for other things.
edited Mar 29 at 23:34
answered Mar 29 at 18:37
Kusalananda♦Kusalananda
139k17261433
139k17261433
add a comment |
add a comment |
PascLeRasc is a new contributor. Be nice, and check out our Code of Conduct.
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Very similar: unix.stackexchange.com/q/342392/117549; also: unix.stackexchange.com/q/352844/117549
– Jeff Schaller♦
Mar 29 at 18:31
2
You can also find it using
locate
, which should be significantly faster, but only works if the file already existed whenupdatedb
was last run.– Simon Richter
Mar 29 at 20:01