Sequence of functions having a convergent subsequence












0












$begingroup$


let $V=$ space of all continuous functions on R with compact support endowed with $d(f,g)=(int_{-infty}^{infty}|f(t)-g(t)|^2dt)^{frac{1}{2}}$



Define $fin V$ .define $f_n=f(x-n)$ Then show that $f_n$ has no convergent subsequence.



I don't know how to start it.There is a similar version of this question.I am not getting it.Can anyone show an easier version of this










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    What's your problem with the previous version
    $endgroup$
    – Learnmore
    Jan 9 '15 at 5:48










  • $begingroup$
    I cant understand that.Please help me
    $endgroup$
    – Learnmore
    Jan 9 '15 at 5:49
















0












$begingroup$


let $V=$ space of all continuous functions on R with compact support endowed with $d(f,g)=(int_{-infty}^{infty}|f(t)-g(t)|^2dt)^{frac{1}{2}}$



Define $fin V$ .define $f_n=f(x-n)$ Then show that $f_n$ has no convergent subsequence.



I don't know how to start it.There is a similar version of this question.I am not getting it.Can anyone show an easier version of this










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    What's your problem with the previous version
    $endgroup$
    – Learnmore
    Jan 9 '15 at 5:48










  • $begingroup$
    I cant understand that.Please help me
    $endgroup$
    – Learnmore
    Jan 9 '15 at 5:49














0












0








0


1



$begingroup$


let $V=$ space of all continuous functions on R with compact support endowed with $d(f,g)=(int_{-infty}^{infty}|f(t)-g(t)|^2dt)^{frac{1}{2}}$



Define $fin V$ .define $f_n=f(x-n)$ Then show that $f_n$ has no convergent subsequence.



I don't know how to start it.There is a similar version of this question.I am not getting it.Can anyone show an easier version of this










share|cite|improve this question











$endgroup$




let $V=$ space of all continuous functions on R with compact support endowed with $d(f,g)=(int_{-infty}^{infty}|f(t)-g(t)|^2dt)^{frac{1}{2}}$



Define $fin V$ .define $f_n=f(x-n)$ Then show that $f_n$ has no convergent subsequence.



I don't know how to start it.There is a similar version of this question.I am not getting it.Can anyone show an easier version of this







real-analysis






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 9 '15 at 7:01









Mhenni Benghorbal

43.3k63775




43.3k63775










asked Jan 9 '15 at 5:47









LearnmoreLearnmore

17.9k325106




17.9k325106








  • 1




    $begingroup$
    What's your problem with the previous version
    $endgroup$
    – Learnmore
    Jan 9 '15 at 5:48










  • $begingroup$
    I cant understand that.Please help me
    $endgroup$
    – Learnmore
    Jan 9 '15 at 5:49














  • 1




    $begingroup$
    What's your problem with the previous version
    $endgroup$
    – Learnmore
    Jan 9 '15 at 5:48










  • $begingroup$
    I cant understand that.Please help me
    $endgroup$
    – Learnmore
    Jan 9 '15 at 5:49








1




1




$begingroup$
What's your problem with the previous version
$endgroup$
– Learnmore
Jan 9 '15 at 5:48




$begingroup$
What's your problem with the previous version
$endgroup$
– Learnmore
Jan 9 '15 at 5:48












$begingroup$
I cant understand that.Please help me
$endgroup$
– Learnmore
Jan 9 '15 at 5:49




$begingroup$
I cant understand that.Please help me
$endgroup$
– Learnmore
Jan 9 '15 at 5:49










1 Answer
1






active

oldest

votes


















1












$begingroup$

It seems the following.



Let $fin V$ be an arbitrary non-zero function. Since the function $f$ is continuous, $d(f,0)>0$. Since the support $text{supp } f$ of the function $f$ is compact, there exists a number $M$ such that $text{supp } fsubset[-M,M].$ Suppose that the sequence ${f_n}$ has a convergent subsequence ${f_{n_k}}$. Then the sequence ${f_{n_k}}$ is fundamental, that is for each $varepsilon>0$ there exists a number $K=K(varepsilon)>0$ such that $d(f_{n_k}, f_{n_k’})<varepsilon$ provided $k,k’>K$. Let $k>K(sqrt{2}d(f,0))$ be an arbitrary number and $k’$ be such a number that $n_k’>n_k+2M$. Since $text{supp } f_{n_k}cap text{supp } f_{n_k’}=varnothing$,



$$d(f_{n_k}, f_{n’_k})=left(int_{-infty}^{infty}| f_{n_k}(t)-f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$
$$left(int_{text{supp } f_{n_k}}| f_{n_k}(t)-f_{n’_k}(t)|^2dt+int_{text{supp } f_{n’_k}}| f_{n_k}(t)-f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$ $$
left(int_{text{supp } f_{n_k}}| f_{n_k}(t)|^2dt+int_{text{supp } f_{n’_k}}|f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$
$$
left(2int_{text{supp } f}| f (t)|^2dtright)^{frac{1}{2}}=sqrt{2}d(f,0),$$



a contradiction.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    @ Alex im not getting how u directly write $d(f_{n_k}, f_{n_k’})=2d(f,0),$ ??
    $endgroup$
    – jasmine
    Sep 14 '18 at 16:04








  • 1




    $begingroup$
    @jasmine Thanks for your remark. I corrected and extended my answer.
    $endgroup$
    – Alex Ravsky
    Dec 21 '18 at 7:35












Your Answer








StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1097339%2fsequence-of-functions-having-a-convergent-subsequence%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1












$begingroup$

It seems the following.



Let $fin V$ be an arbitrary non-zero function. Since the function $f$ is continuous, $d(f,0)>0$. Since the support $text{supp } f$ of the function $f$ is compact, there exists a number $M$ such that $text{supp } fsubset[-M,M].$ Suppose that the sequence ${f_n}$ has a convergent subsequence ${f_{n_k}}$. Then the sequence ${f_{n_k}}$ is fundamental, that is for each $varepsilon>0$ there exists a number $K=K(varepsilon)>0$ such that $d(f_{n_k}, f_{n_k’})<varepsilon$ provided $k,k’>K$. Let $k>K(sqrt{2}d(f,0))$ be an arbitrary number and $k’$ be such a number that $n_k’>n_k+2M$. Since $text{supp } f_{n_k}cap text{supp } f_{n_k’}=varnothing$,



$$d(f_{n_k}, f_{n’_k})=left(int_{-infty}^{infty}| f_{n_k}(t)-f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$
$$left(int_{text{supp } f_{n_k}}| f_{n_k}(t)-f_{n’_k}(t)|^2dt+int_{text{supp } f_{n’_k}}| f_{n_k}(t)-f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$ $$
left(int_{text{supp } f_{n_k}}| f_{n_k}(t)|^2dt+int_{text{supp } f_{n’_k}}|f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$
$$
left(2int_{text{supp } f}| f (t)|^2dtright)^{frac{1}{2}}=sqrt{2}d(f,0),$$



a contradiction.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    @ Alex im not getting how u directly write $d(f_{n_k}, f_{n_k’})=2d(f,0),$ ??
    $endgroup$
    – jasmine
    Sep 14 '18 at 16:04








  • 1




    $begingroup$
    @jasmine Thanks for your remark. I corrected and extended my answer.
    $endgroup$
    – Alex Ravsky
    Dec 21 '18 at 7:35
















1












$begingroup$

It seems the following.



Let $fin V$ be an arbitrary non-zero function. Since the function $f$ is continuous, $d(f,0)>0$. Since the support $text{supp } f$ of the function $f$ is compact, there exists a number $M$ such that $text{supp } fsubset[-M,M].$ Suppose that the sequence ${f_n}$ has a convergent subsequence ${f_{n_k}}$. Then the sequence ${f_{n_k}}$ is fundamental, that is for each $varepsilon>0$ there exists a number $K=K(varepsilon)>0$ such that $d(f_{n_k}, f_{n_k’})<varepsilon$ provided $k,k’>K$. Let $k>K(sqrt{2}d(f,0))$ be an arbitrary number and $k’$ be such a number that $n_k’>n_k+2M$. Since $text{supp } f_{n_k}cap text{supp } f_{n_k’}=varnothing$,



$$d(f_{n_k}, f_{n’_k})=left(int_{-infty}^{infty}| f_{n_k}(t)-f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$
$$left(int_{text{supp } f_{n_k}}| f_{n_k}(t)-f_{n’_k}(t)|^2dt+int_{text{supp } f_{n’_k}}| f_{n_k}(t)-f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$ $$
left(int_{text{supp } f_{n_k}}| f_{n_k}(t)|^2dt+int_{text{supp } f_{n’_k}}|f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$
$$
left(2int_{text{supp } f}| f (t)|^2dtright)^{frac{1}{2}}=sqrt{2}d(f,0),$$



a contradiction.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    @ Alex im not getting how u directly write $d(f_{n_k}, f_{n_k’})=2d(f,0),$ ??
    $endgroup$
    – jasmine
    Sep 14 '18 at 16:04








  • 1




    $begingroup$
    @jasmine Thanks for your remark. I corrected and extended my answer.
    $endgroup$
    – Alex Ravsky
    Dec 21 '18 at 7:35














1












1








1





$begingroup$

It seems the following.



Let $fin V$ be an arbitrary non-zero function. Since the function $f$ is continuous, $d(f,0)>0$. Since the support $text{supp } f$ of the function $f$ is compact, there exists a number $M$ such that $text{supp } fsubset[-M,M].$ Suppose that the sequence ${f_n}$ has a convergent subsequence ${f_{n_k}}$. Then the sequence ${f_{n_k}}$ is fundamental, that is for each $varepsilon>0$ there exists a number $K=K(varepsilon)>0$ such that $d(f_{n_k}, f_{n_k’})<varepsilon$ provided $k,k’>K$. Let $k>K(sqrt{2}d(f,0))$ be an arbitrary number and $k’$ be such a number that $n_k’>n_k+2M$. Since $text{supp } f_{n_k}cap text{supp } f_{n_k’}=varnothing$,



$$d(f_{n_k}, f_{n’_k})=left(int_{-infty}^{infty}| f_{n_k}(t)-f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$
$$left(int_{text{supp } f_{n_k}}| f_{n_k}(t)-f_{n’_k}(t)|^2dt+int_{text{supp } f_{n’_k}}| f_{n_k}(t)-f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$ $$
left(int_{text{supp } f_{n_k}}| f_{n_k}(t)|^2dt+int_{text{supp } f_{n’_k}}|f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$
$$
left(2int_{text{supp } f}| f (t)|^2dtright)^{frac{1}{2}}=sqrt{2}d(f,0),$$



a contradiction.






share|cite|improve this answer











$endgroup$



It seems the following.



Let $fin V$ be an arbitrary non-zero function. Since the function $f$ is continuous, $d(f,0)>0$. Since the support $text{supp } f$ of the function $f$ is compact, there exists a number $M$ such that $text{supp } fsubset[-M,M].$ Suppose that the sequence ${f_n}$ has a convergent subsequence ${f_{n_k}}$. Then the sequence ${f_{n_k}}$ is fundamental, that is for each $varepsilon>0$ there exists a number $K=K(varepsilon)>0$ such that $d(f_{n_k}, f_{n_k’})<varepsilon$ provided $k,k’>K$. Let $k>K(sqrt{2}d(f,0))$ be an arbitrary number and $k’$ be such a number that $n_k’>n_k+2M$. Since $text{supp } f_{n_k}cap text{supp } f_{n_k’}=varnothing$,



$$d(f_{n_k}, f_{n’_k})=left(int_{-infty}^{infty}| f_{n_k}(t)-f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$
$$left(int_{text{supp } f_{n_k}}| f_{n_k}(t)-f_{n’_k}(t)|^2dt+int_{text{supp } f_{n’_k}}| f_{n_k}(t)-f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$ $$
left(int_{text{supp } f_{n_k}}| f_{n_k}(t)|^2dt+int_{text{supp } f_{n’_k}}|f_{n’_k}(t)|^2dtright)^{frac{1}{2}}=$$
$$
left(2int_{text{supp } f}| f (t)|^2dtright)^{frac{1}{2}}=sqrt{2}d(f,0),$$



a contradiction.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Dec 21 '18 at 7:34

























answered Jan 22 '15 at 20:20









Alex RavskyAlex Ravsky

43.1k32583




43.1k32583












  • $begingroup$
    @ Alex im not getting how u directly write $d(f_{n_k}, f_{n_k’})=2d(f,0),$ ??
    $endgroup$
    – jasmine
    Sep 14 '18 at 16:04








  • 1




    $begingroup$
    @jasmine Thanks for your remark. I corrected and extended my answer.
    $endgroup$
    – Alex Ravsky
    Dec 21 '18 at 7:35


















  • $begingroup$
    @ Alex im not getting how u directly write $d(f_{n_k}, f_{n_k’})=2d(f,0),$ ??
    $endgroup$
    – jasmine
    Sep 14 '18 at 16:04








  • 1




    $begingroup$
    @jasmine Thanks for your remark. I corrected and extended my answer.
    $endgroup$
    – Alex Ravsky
    Dec 21 '18 at 7:35
















$begingroup$
@ Alex im not getting how u directly write $d(f_{n_k}, f_{n_k’})=2d(f,0),$ ??
$endgroup$
– jasmine
Sep 14 '18 at 16:04






$begingroup$
@ Alex im not getting how u directly write $d(f_{n_k}, f_{n_k’})=2d(f,0),$ ??
$endgroup$
– jasmine
Sep 14 '18 at 16:04






1




1




$begingroup$
@jasmine Thanks for your remark. I corrected and extended my answer.
$endgroup$
– Alex Ravsky
Dec 21 '18 at 7:35




$begingroup$
@jasmine Thanks for your remark. I corrected and extended my answer.
$endgroup$
– Alex Ravsky
Dec 21 '18 at 7:35


















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1097339%2fsequence-of-functions-having-a-convergent-subsequence%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Plaza Victoria

Puebla de Zaragoza

Musa