A problem with functions defined on positive integers.
0
$begingroup$
Where [x] denotes the greatest integer number, which does not exceed x.
I need some help please. The proof should also be at high school level. Please don’t use hard or complex things.
functions functional-equations
asked Dec 13 '18 at 18:02
furfurfurfur
855
$endgroup$
|
show 2 more comments
0
$begingroup$
Where [x] denotes the greatest integer number, which does not exceed x.
I need some help please. The proof should also be at high school level. Please don’t use hard or complex things.
functions functional-equations
asked Dec 13 '18 at 18:02
furfurfurfur
855
$endgroup$
$begingroup$
What does that little mark on the start of the last line mean?
$endgroup$
– fleablood
Dec 13 '18 at 18:09
$begingroup$
I guess "prove that"
$endgroup$
– Federico
Dec 13 '18 at 18:09
$begingroup$
Experimenting, it seems that $f(2^k+k-2)=2^{k-1}$
$endgroup$
– Federico
Dec 13 '18 at 18:10
$begingroup$
Yeah. It means prove that
$endgroup$
– furfur
Dec 13 '18 at 18:15
$begingroup$
The answer says that f(2^k + k - 2)=(2^(k -1))^2
$endgroup$
– furfur
Dec 13 '18 at 18:17
|
show 2 more comments
0
0
0
$begingroup$
Where [x] denotes the greatest integer number, which does not exceed x.
I need some help please. The proof should also be at high school level. Please don’t use hard or complex things.
functions functional-equations
asked Dec 13 '18 at 18:02
furfurfurfur
855
$endgroup$
Where [x] denotes the greatest integer number, which does not exceed x.
I need some help please. The proof should also be at high school level. Please don’t use hard or complex things.
functions functional-equations
functions functional-equations
asked Dec 13 '18 at 18:02
furfurfurfur
855
asked Dec 13 '18 at 18:02
furfurfurfur
855
asked Dec 13 '18 at 18:02
furfurfurfur
855
asked Dec 13 '18 at 18:02
furfurfurfur
855
asked Dec 13 '18 at 18:02
furfurfurfur
855
855
$begingroup$
What does that little mark on the start of the last line mean?
$endgroup$
– fleablood
Dec 13 '18 at 18:09
$begingroup$
I guess "prove that"
$endgroup$
– Federico
Dec 13 '18 at 18:09
$begingroup$
Experimenting, it seems that $f(2^k+k-2)=2^{k-1}$
$endgroup$
– Federico
Dec 13 '18 at 18:10
$begingroup$
Yeah. It means prove that
$endgroup$
– furfur
Dec 13 '18 at 18:15
$begingroup$
The answer says that f(2^k + k - 2)=(2^(k -1))^2
$endgroup$
– furfur
Dec 13 '18 at 18:17
|
show 2 more comments
$begingroup$
What does that little mark on the start of the last line mean?
$endgroup$
– fleablood
Dec 13 '18 at 18:09
$begingroup$
I guess "prove that"
$endgroup$
– Federico
Dec 13 '18 at 18:09
$begingroup$
Experimenting, it seems that $f(2^k+k-2)=2^{k-1}$
$endgroup$
– Federico
Dec 13 '18 at 18:10
$begingroup$
Yeah. It means prove that
$endgroup$
– furfur
Dec 13 '18 at 18:15
$begingroup$
The answer says that f(2^k + k - 2)=(2^(k -1))^2
$endgroup$
– furfur
Dec 13 '18 at 18:17
$begingroup$
What does that little mark on the start of the last line mean?
$endgroup$
– fleablood
Dec 13 '18 at 18:09
$begingroup$
What does that little mark on the start of the last line mean?
$endgroup$
– fleablood
Dec 13 '18 at 18:09
$begingroup$
I guess "prove that"
$endgroup$
– Federico
Dec 13 '18 at 18:09
$begingroup$
I guess "prove that"
$endgroup$
– Federico
Dec 13 '18 at 18:09
$begingroup$
Experimenting, it seems that $f(2^k+k-2)=2^{k-1}$
$endgroup$
– Federico
Dec 13 '18 at 18:10
$begingroup$
Experimenting, it seems that $f(2^k+k-2)=2^{k-1}$
$endgroup$
– Federico
Dec 13 '18 at 18:10
$begingroup$
Yeah. It means prove that
$endgroup$
– furfur
Dec 13 '18 at 18:15
$begingroup$
Yeah. It means prove that
$endgroup$
– furfur
Dec 13 '18 at 18:15
$begingroup$
The answer says that f(2^k + k - 2)=(2^(k -1))^2
$endgroup$
– furfur
Dec 13 '18 at 18:17
$begingroup$
The answer says that f(2^k + k - 2)=(2^(k -1))^2
$endgroup$
– furfur
Dec 13 '18 at 18:17
|
show 2 more comments
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$begingroup$
What does that little mark on the start of the last line mean?
$endgroup$
– fleablood
Dec 13 '18 at 18:09
$begingroup$
I guess "prove that"
$endgroup$
– Federico
Dec 13 '18 at 18:09
$begingroup$
Experimenting, it seems that $f(2^k+k-2)=2^{k-1}$
$endgroup$
– Federico
Dec 13 '18 at 18:10
$begingroup$
Yeah. It means prove that
$endgroup$
– furfur
Dec 13 '18 at 18:15
$begingroup$
The answer says that f(2^k + k - 2)=(2^(k -1))^2
$endgroup$
– furfur
Dec 13 '18 at 18:17