Set of nowhere differentiable function in C[(0,1]) is dense












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How can we prove with Baire's Theorem that in C[(0,1]), the set of nowhere differentiable function is dense.










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  • I have sketched the proof below but if you show some work, you will get a lot more feedback here. Otherwise, prepare to be flooded with downvotes.
    – Matematleta
    Nov 25 at 4:04
















0














How can we prove with Baire's Theorem that in C[(0,1]), the set of nowhere differentiable function is dense.










share|cite|improve this question






















  • I have sketched the proof below but if you show some work, you will get a lot more feedback here. Otherwise, prepare to be flooded with downvotes.
    – Matematleta
    Nov 25 at 4:04














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How can we prove with Baire's Theorem that in C[(0,1]), the set of nowhere differentiable function is dense.










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How can we prove with Baire's Theorem that in C[(0,1]), the set of nowhere differentiable function is dense.







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asked Nov 25 at 3:25









mimi

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175












  • I have sketched the proof below but if you show some work, you will get a lot more feedback here. Otherwise, prepare to be flooded with downvotes.
    – Matematleta
    Nov 25 at 4:04


















  • I have sketched the proof below but if you show some work, you will get a lot more feedback here. Otherwise, prepare to be flooded with downvotes.
    – Matematleta
    Nov 25 at 4:04
















I have sketched the proof below but if you show some work, you will get a lot more feedback here. Otherwise, prepare to be flooded with downvotes.
– Matematleta
Nov 25 at 4:04




I have sketched the proof below but if you show some work, you will get a lot more feedback here. Otherwise, prepare to be flooded with downvotes.
– Matematleta
Nov 25 at 4:04










1 Answer
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Here is a sketch:



$1).$ Show that $C([0,1])$ is not the countable union of nowhere dense sets.



$2).$ Set



$D={fin C([0,1]): f text{ is differentiable at some $x$ }}$



and



$A_{n,m}=left { fin C([0,1]): frac{f(t)-f(x)}{t-x})<n text{if} 0<|x-t|<frac{1}{m}right }$.



$3). Dsubseteq A_{n,m}$ and $A_{n,m}$ is closed.



$4). A_{n,m}$ are nowhere dense. (This is the only really hard part).



$5).$ Conclude.






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    1 Answer
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    1 Answer
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    active

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    active

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    0














    Here is a sketch:



    $1).$ Show that $C([0,1])$ is not the countable union of nowhere dense sets.



    $2).$ Set



    $D={fin C([0,1]): f text{ is differentiable at some $x$ }}$



    and



    $A_{n,m}=left { fin C([0,1]): frac{f(t)-f(x)}{t-x})<n text{if} 0<|x-t|<frac{1}{m}right }$.



    $3). Dsubseteq A_{n,m}$ and $A_{n,m}$ is closed.



    $4). A_{n,m}$ are nowhere dense. (This is the only really hard part).



    $5).$ Conclude.






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      0














      Here is a sketch:



      $1).$ Show that $C([0,1])$ is not the countable union of nowhere dense sets.



      $2).$ Set



      $D={fin C([0,1]): f text{ is differentiable at some $x$ }}$



      and



      $A_{n,m}=left { fin C([0,1]): frac{f(t)-f(x)}{t-x})<n text{if} 0<|x-t|<frac{1}{m}right }$.



      $3). Dsubseteq A_{n,m}$ and $A_{n,m}$ is closed.



      $4). A_{n,m}$ are nowhere dense. (This is the only really hard part).



      $5).$ Conclude.






      share|cite|improve this answer
























        0












        0








        0






        Here is a sketch:



        $1).$ Show that $C([0,1])$ is not the countable union of nowhere dense sets.



        $2).$ Set



        $D={fin C([0,1]): f text{ is differentiable at some $x$ }}$



        and



        $A_{n,m}=left { fin C([0,1]): frac{f(t)-f(x)}{t-x})<n text{if} 0<|x-t|<frac{1}{m}right }$.



        $3). Dsubseteq A_{n,m}$ and $A_{n,m}$ is closed.



        $4). A_{n,m}$ are nowhere dense. (This is the only really hard part).



        $5).$ Conclude.






        share|cite|improve this answer












        Here is a sketch:



        $1).$ Show that $C([0,1])$ is not the countable union of nowhere dense sets.



        $2).$ Set



        $D={fin C([0,1]): f text{ is differentiable at some $x$ }}$



        and



        $A_{n,m}=left { fin C([0,1]): frac{f(t)-f(x)}{t-x})<n text{if} 0<|x-t|<frac{1}{m}right }$.



        $3). Dsubseteq A_{n,m}$ and $A_{n,m}$ is closed.



        $4). A_{n,m}$ are nowhere dense. (This is the only really hard part).



        $5).$ Conclude.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 25 at 4:01









        Matematleta

        9,9522918




        9,9522918






























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