Determine a solution of an ODE by “inspection”












5














I'm checking Zill's A First Course in Differential Equations with Modeling Applications, and there's an exercise that says:




From the following problems determine by inspection at least two solutions of the given IVP.




  • $y'=3y^{2/3},,y(0)=0$

  • $xy'=2y,,y(0)=0$




I don't quite understand what in means by "by inspection", what's the difference between just finding the solutions and determine by inspection?










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  • 1




    The difference is doing it in your head. You can ignore that stipulation if you want.
    – arctic tern
    Aug 12 '16 at 18:04
















5














I'm checking Zill's A First Course in Differential Equations with Modeling Applications, and there's an exercise that says:




From the following problems determine by inspection at least two solutions of the given IVP.




  • $y'=3y^{2/3},,y(0)=0$

  • $xy'=2y,,y(0)=0$




I don't quite understand what in means by "by inspection", what's the difference between just finding the solutions and determine by inspection?










share|cite|improve this question


















  • 1




    The difference is doing it in your head. You can ignore that stipulation if you want.
    – arctic tern
    Aug 12 '16 at 18:04














5












5








5







I'm checking Zill's A First Course in Differential Equations with Modeling Applications, and there's an exercise that says:




From the following problems determine by inspection at least two solutions of the given IVP.




  • $y'=3y^{2/3},,y(0)=0$

  • $xy'=2y,,y(0)=0$




I don't quite understand what in means by "by inspection", what's the difference between just finding the solutions and determine by inspection?










share|cite|improve this question













I'm checking Zill's A First Course in Differential Equations with Modeling Applications, and there's an exercise that says:




From the following problems determine by inspection at least two solutions of the given IVP.




  • $y'=3y^{2/3},,y(0)=0$

  • $xy'=2y,,y(0)=0$




I don't quite understand what in means by "by inspection", what's the difference between just finding the solutions and determine by inspection?







differential-equations






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asked Aug 12 '16 at 18:00









Ana Galois

1,2401233




1,2401233








  • 1




    The difference is doing it in your head. You can ignore that stipulation if you want.
    – arctic tern
    Aug 12 '16 at 18:04














  • 1




    The difference is doing it in your head. You can ignore that stipulation if you want.
    – arctic tern
    Aug 12 '16 at 18:04








1




1




The difference is doing it in your head. You can ignore that stipulation if you want.
– arctic tern
Aug 12 '16 at 18:04




The difference is doing it in your head. You can ignore that stipulation if you want.
– arctic tern
Aug 12 '16 at 18:04










3 Answers
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2














In general, the phrase "by inspection" means "by reasonable guessing". For instance, suppose we are to prove that there are integers $x,y,z$ such that $x^{2}+y^{2}=z^{2}$. Without manipulating the given condition, we have a candidate solution to the equation in mind, i.e. the triple $(3,4,5)$ of integers, which happens to be a solution to the equation; hence the proposition is proved. Well, we just proved the proposition by inspection.



Yes, it is just the same thing to say "just find some solutions" instead of "find some solutions by inspection".






share|cite|improve this answer





























    1














    To find a solution ''by inspection'' usually means that the solution can be found (almost) immediately, using some result that is expected to be well known.



    In your case, as an example, from the fact that the derivative of $y=x^2$ is $y'=2x$ we can say ''by inspection'' that the solution of $xy'=2y$ can be a function of the form $y=x^2$, that satisfies the initial condition.



    Analogously, using the fact that $y=x^3 rightarrow y'=3x^2$ you can solve ''by inspection'' the other IVP.






    share|cite|improve this answer































      0














      I already see that the trivial solution $y=0$ satisfies both systems. We can slso try $y=x^3$ for the first and $y=x^2$ for the second.






      share|cite|improve this answer























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        3 Answers
        3






        active

        oldest

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        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2














        In general, the phrase "by inspection" means "by reasonable guessing". For instance, suppose we are to prove that there are integers $x,y,z$ such that $x^{2}+y^{2}=z^{2}$. Without manipulating the given condition, we have a candidate solution to the equation in mind, i.e. the triple $(3,4,5)$ of integers, which happens to be a solution to the equation; hence the proposition is proved. Well, we just proved the proposition by inspection.



        Yes, it is just the same thing to say "just find some solutions" instead of "find some solutions by inspection".






        share|cite|improve this answer


























          2














          In general, the phrase "by inspection" means "by reasonable guessing". For instance, suppose we are to prove that there are integers $x,y,z$ such that $x^{2}+y^{2}=z^{2}$. Without manipulating the given condition, we have a candidate solution to the equation in mind, i.e. the triple $(3,4,5)$ of integers, which happens to be a solution to the equation; hence the proposition is proved. Well, we just proved the proposition by inspection.



          Yes, it is just the same thing to say "just find some solutions" instead of "find some solutions by inspection".






          share|cite|improve this answer
























            2












            2








            2






            In general, the phrase "by inspection" means "by reasonable guessing". For instance, suppose we are to prove that there are integers $x,y,z$ such that $x^{2}+y^{2}=z^{2}$. Without manipulating the given condition, we have a candidate solution to the equation in mind, i.e. the triple $(3,4,5)$ of integers, which happens to be a solution to the equation; hence the proposition is proved. Well, we just proved the proposition by inspection.



            Yes, it is just the same thing to say "just find some solutions" instead of "find some solutions by inspection".






            share|cite|improve this answer












            In general, the phrase "by inspection" means "by reasonable guessing". For instance, suppose we are to prove that there are integers $x,y,z$ such that $x^{2}+y^{2}=z^{2}$. Without manipulating the given condition, we have a candidate solution to the equation in mind, i.e. the triple $(3,4,5)$ of integers, which happens to be a solution to the equation; hence the proposition is proved. Well, we just proved the proposition by inspection.



            Yes, it is just the same thing to say "just find some solutions" instead of "find some solutions by inspection".







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered Aug 12 '16 at 18:36









            Gary Moore

            17.2k21545




            17.2k21545























                1














                To find a solution ''by inspection'' usually means that the solution can be found (almost) immediately, using some result that is expected to be well known.



                In your case, as an example, from the fact that the derivative of $y=x^2$ is $y'=2x$ we can say ''by inspection'' that the solution of $xy'=2y$ can be a function of the form $y=x^2$, that satisfies the initial condition.



                Analogously, using the fact that $y=x^3 rightarrow y'=3x^2$ you can solve ''by inspection'' the other IVP.






                share|cite|improve this answer




























                  1














                  To find a solution ''by inspection'' usually means that the solution can be found (almost) immediately, using some result that is expected to be well known.



                  In your case, as an example, from the fact that the derivative of $y=x^2$ is $y'=2x$ we can say ''by inspection'' that the solution of $xy'=2y$ can be a function of the form $y=x^2$, that satisfies the initial condition.



                  Analogously, using the fact that $y=x^3 rightarrow y'=3x^2$ you can solve ''by inspection'' the other IVP.






                  share|cite|improve this answer


























                    1












                    1








                    1






                    To find a solution ''by inspection'' usually means that the solution can be found (almost) immediately, using some result that is expected to be well known.



                    In your case, as an example, from the fact that the derivative of $y=x^2$ is $y'=2x$ we can say ''by inspection'' that the solution of $xy'=2y$ can be a function of the form $y=x^2$, that satisfies the initial condition.



                    Analogously, using the fact that $y=x^3 rightarrow y'=3x^2$ you can solve ''by inspection'' the other IVP.






                    share|cite|improve this answer














                    To find a solution ''by inspection'' usually means that the solution can be found (almost) immediately, using some result that is expected to be well known.



                    In your case, as an example, from the fact that the derivative of $y=x^2$ is $y'=2x$ we can say ''by inspection'' that the solution of $xy'=2y$ can be a function of the form $y=x^2$, that satisfies the initial condition.



                    Analogously, using the fact that $y=x^3 rightarrow y'=3x^2$ you can solve ''by inspection'' the other IVP.







                    share|cite|improve this answer














                    share|cite|improve this answer



                    share|cite|improve this answer








                    edited Aug 12 '16 at 20:13

























                    answered Aug 12 '16 at 19:52









                    Emilio Novati

                    51.4k43472




                    51.4k43472























                        0














                        I already see that the trivial solution $y=0$ satisfies both systems. We can slso try $y=x^3$ for the first and $y=x^2$ for the second.






                        share|cite|improve this answer




























                          0














                          I already see that the trivial solution $y=0$ satisfies both systems. We can slso try $y=x^3$ for the first and $y=x^2$ for the second.






                          share|cite|improve this answer


























                            0












                            0








                            0






                            I already see that the trivial solution $y=0$ satisfies both systems. We can slso try $y=x^3$ for the first and $y=x^2$ for the second.






                            share|cite|improve this answer














                            I already see that the trivial solution $y=0$ satisfies both systems. We can slso try $y=x^3$ for the first and $y=x^2$ for the second.







                            share|cite|improve this answer














                            share|cite|improve this answer



                            share|cite|improve this answer








                            edited Nov 23 at 14:33

























                            answered Nov 23 at 14:23









                            Wesley Strik

                            1,486422




                            1,486422






























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