How to use the squeeze theorem to show that $a_n→ 0$ as $n →∞ $ for the sequence $a_n :=1/n(1 +...












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Use the squeeze theorem to show that $a_n→ 0$ as $n →∞ $ for the sequence $a_n :=1/n(1 + n.cos^6(n^{2017} − 3√(5n))$.



What i did so far was i just try to use the fact that $0≤cos^6(t)≤1$ but i don't know how exactly.










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    -1














    Use the squeeze theorem to show that $a_n→ 0$ as $n →∞ $ for the sequence $a_n :=1/n(1 + n.cos^6(n^{2017} − 3√(5n))$.



    What i did so far was i just try to use the fact that $0≤cos^6(t)≤1$ but i don't know how exactly.










    share|cite|improve this question



























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      -1


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      Use the squeeze theorem to show that $a_n→ 0$ as $n →∞ $ for the sequence $a_n :=1/n(1 + n.cos^6(n^{2017} − 3√(5n))$.



      What i did so far was i just try to use the fact that $0≤cos^6(t)≤1$ but i don't know how exactly.










      share|cite|improve this question















      Use the squeeze theorem to show that $a_n→ 0$ as $n →∞ $ for the sequence $a_n :=1/n(1 + n.cos^6(n^{2017} − 3√(5n))$.



      What i did so far was i just try to use the fact that $0≤cos^6(t)≤1$ but i don't know how exactly.







      real-analysis sequences-and-series






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      edited Nov 24 at 0:53









      DonAntonio

      176k1491225




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      asked Nov 23 at 13:32









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          $$frac1{n^2+n}=frac1{n(1+n)}lefrac1{nleft(1+ncos^6left(n^{2017}-3sqrt{5n}right)right)}lefrac1{n}$$






          share|cite|improve this answer























          • @Nosrati Thanks, corrected. The basic idea remains.
            – DonAntonio
            Nov 23 at 13:49










          • The $(1+ ncos^6 dots )$ is upstairs isn't it?
            – zhw.
            Nov 23 at 21:03












          • @zhw. I'm not sure what you mean with upstairs, but int general $$1le1+ncos^6(...)le1+n$$
            – DonAntonio
            Nov 23 at 21:43












          • True, but as the problem is stated, that doesn't help.
            – zhw.
            Nov 23 at 23:39












          • @zhw. I think it does. Can you spot any mistake in what I did? If there's one I'll be glad to correct it, otherwise a straightforward use of the squeeze theorem solves the problem at once.
            – DonAntonio
            Nov 23 at 23:44











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          $$frac1{n^2+n}=frac1{n(1+n)}lefrac1{nleft(1+ncos^6left(n^{2017}-3sqrt{5n}right)right)}lefrac1{n}$$






          share|cite|improve this answer























          • @Nosrati Thanks, corrected. The basic idea remains.
            – DonAntonio
            Nov 23 at 13:49










          • The $(1+ ncos^6 dots )$ is upstairs isn't it?
            – zhw.
            Nov 23 at 21:03












          • @zhw. I'm not sure what you mean with upstairs, but int general $$1le1+ncos^6(...)le1+n$$
            – DonAntonio
            Nov 23 at 21:43












          • True, but as the problem is stated, that doesn't help.
            – zhw.
            Nov 23 at 23:39












          • @zhw. I think it does. Can you spot any mistake in what I did? If there's one I'll be glad to correct it, otherwise a straightforward use of the squeeze theorem solves the problem at once.
            – DonAntonio
            Nov 23 at 23:44
















          2














          $$frac1{n^2+n}=frac1{n(1+n)}lefrac1{nleft(1+ncos^6left(n^{2017}-3sqrt{5n}right)right)}lefrac1{n}$$






          share|cite|improve this answer























          • @Nosrati Thanks, corrected. The basic idea remains.
            – DonAntonio
            Nov 23 at 13:49










          • The $(1+ ncos^6 dots )$ is upstairs isn't it?
            – zhw.
            Nov 23 at 21:03












          • @zhw. I'm not sure what you mean with upstairs, but int general $$1le1+ncos^6(...)le1+n$$
            – DonAntonio
            Nov 23 at 21:43












          • True, but as the problem is stated, that doesn't help.
            – zhw.
            Nov 23 at 23:39












          • @zhw. I think it does. Can you spot any mistake in what I did? If there's one I'll be glad to correct it, otherwise a straightforward use of the squeeze theorem solves the problem at once.
            – DonAntonio
            Nov 23 at 23:44














          2












          2








          2






          $$frac1{n^2+n}=frac1{n(1+n)}lefrac1{nleft(1+ncos^6left(n^{2017}-3sqrt{5n}right)right)}lefrac1{n}$$






          share|cite|improve this answer














          $$frac1{n^2+n}=frac1{n(1+n)}lefrac1{nleft(1+ncos^6left(n^{2017}-3sqrt{5n}right)right)}lefrac1{n}$$







          share|cite|improve this answer














          share|cite|improve this answer



          share|cite|improve this answer








          edited Nov 23 at 13:49

























          answered Nov 23 at 13:38









          DonAntonio

          176k1491225




          176k1491225












          • @Nosrati Thanks, corrected. The basic idea remains.
            – DonAntonio
            Nov 23 at 13:49










          • The $(1+ ncos^6 dots )$ is upstairs isn't it?
            – zhw.
            Nov 23 at 21:03












          • @zhw. I'm not sure what you mean with upstairs, but int general $$1le1+ncos^6(...)le1+n$$
            – DonAntonio
            Nov 23 at 21:43












          • True, but as the problem is stated, that doesn't help.
            – zhw.
            Nov 23 at 23:39












          • @zhw. I think it does. Can you spot any mistake in what I did? If there's one I'll be glad to correct it, otherwise a straightforward use of the squeeze theorem solves the problem at once.
            – DonAntonio
            Nov 23 at 23:44


















          • @Nosrati Thanks, corrected. The basic idea remains.
            – DonAntonio
            Nov 23 at 13:49










          • The $(1+ ncos^6 dots )$ is upstairs isn't it?
            – zhw.
            Nov 23 at 21:03












          • @zhw. I'm not sure what you mean with upstairs, but int general $$1le1+ncos^6(...)le1+n$$
            – DonAntonio
            Nov 23 at 21:43












          • True, but as the problem is stated, that doesn't help.
            – zhw.
            Nov 23 at 23:39












          • @zhw. I think it does. Can you spot any mistake in what I did? If there's one I'll be glad to correct it, otherwise a straightforward use of the squeeze theorem solves the problem at once.
            – DonAntonio
            Nov 23 at 23:44
















          @Nosrati Thanks, corrected. The basic idea remains.
          – DonAntonio
          Nov 23 at 13:49




          @Nosrati Thanks, corrected. The basic idea remains.
          – DonAntonio
          Nov 23 at 13:49












          The $(1+ ncos^6 dots )$ is upstairs isn't it?
          – zhw.
          Nov 23 at 21:03






          The $(1+ ncos^6 dots )$ is upstairs isn't it?
          – zhw.
          Nov 23 at 21:03














          @zhw. I'm not sure what you mean with upstairs, but int general $$1le1+ncos^6(...)le1+n$$
          – DonAntonio
          Nov 23 at 21:43






          @zhw. I'm not sure what you mean with upstairs, but int general $$1le1+ncos^6(...)le1+n$$
          – DonAntonio
          Nov 23 at 21:43














          True, but as the problem is stated, that doesn't help.
          – zhw.
          Nov 23 at 23:39






          True, but as the problem is stated, that doesn't help.
          – zhw.
          Nov 23 at 23:39














          @zhw. I think it does. Can you spot any mistake in what I did? If there's one I'll be glad to correct it, otherwise a straightforward use of the squeeze theorem solves the problem at once.
          – DonAntonio
          Nov 23 at 23:44




          @zhw. I think it does. Can you spot any mistake in what I did? If there's one I'll be glad to correct it, otherwise a straightforward use of the squeeze theorem solves the problem at once.
          – DonAntonio
          Nov 23 at 23:44


















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