What could be the equation of this curve?
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Does anyone have an idea what (parametric) equation might give a plot like this?

This is in the XY plane. I want to render it nicely on Mathematica, hence why I need the equation.
So far I came up with ${t*sin[t/2], cos[t/2]}$ which seems to be on the right track but doesn't quite do what I want...
functions graphing-functions
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add a comment |
$begingroup$
Does anyone have an idea what (parametric) equation might give a plot like this?

This is in the XY plane. I want to render it nicely on Mathematica, hence why I need the equation.
So far I came up with ${t*sin[t/2], cos[t/2]}$ which seems to be on the right track but doesn't quite do what I want...
functions graphing-functions
$endgroup$
add a comment |
$begingroup$
Does anyone have an idea what (parametric) equation might give a plot like this?

This is in the XY plane. I want to render it nicely on Mathematica, hence why I need the equation.
So far I came up with ${t*sin[t/2], cos[t/2]}$ which seems to be on the right track but doesn't quite do what I want...
functions graphing-functions
$endgroup$
Does anyone have an idea what (parametric) equation might give a plot like this?

This is in the XY plane. I want to render it nicely on Mathematica, hence why I need the equation.
So far I came up with ${t*sin[t/2], cos[t/2]}$ which seems to be on the right track but doesn't quite do what I want...
functions graphing-functions
functions graphing-functions
asked Dec 18 '18 at 16:51
SuperCiociaSuperCiocia
285213
285213
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2 Answers
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ParametricPlot[(1 + .1 Sin[θ/2 - π/4]) {Cos[θ], Sin[θ]}, {θ, 0, 4 π}]

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If you don't need perfect circles, maybe:


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2 Answers
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2 Answers
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$begingroup$
ParametricPlot[(1 + .1 Sin[θ/2 - π/4]) {Cos[θ], Sin[θ]}, {θ, 0, 4 π}]

$endgroup$
add a comment |
$begingroup$
ParametricPlot[(1 + .1 Sin[θ/2 - π/4]) {Cos[θ], Sin[θ]}, {θ, 0, 4 π}]

$endgroup$
add a comment |
$begingroup$
ParametricPlot[(1 + .1 Sin[θ/2 - π/4]) {Cos[θ], Sin[θ]}, {θ, 0, 4 π}]

$endgroup$
ParametricPlot[(1 + .1 Sin[θ/2 - π/4]) {Cos[θ], Sin[θ]}, {θ, 0, 4 π}]

answered Dec 18 '18 at 17:04
David G. StorkDavid G. Stork
11.5k41533
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$begingroup$
If you don't need perfect circles, maybe:


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add a comment |
$begingroup$
If you don't need perfect circles, maybe:


$endgroup$
add a comment |
$begingroup$
If you don't need perfect circles, maybe:


$endgroup$
If you don't need perfect circles, maybe:


answered Dec 18 '18 at 17:23
Shubham JohriShubham Johri
5,462818
5,462818
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