Calculating the order of two function in some group












0












$begingroup$


While studying a subject about the group operator I came across with the following question:




Consider the following function: $h_1,h_2,:,mathbb{R}tomathbb{R}$
where $h_1=-x$ and $h_2=-x+1$. Lets define a new group $X=langle h_1,
h_2rangle$
which follows $Xcurvearrowrightmathbb{R}$ by $h_1cdot x
= h_1(x)$
.



Calculate $o(h_1)$ and $o(h_2)$.




Unfortunately, the books does not have final answer or solutions. I started from using the following definition of order: Let $G$ be a group, the order of $gin G$, meaning $o(g)$ is the minimal $nin mathbb{N}$ so $g^n=e$.



By using this definition, I understand that I need to find the minimal $n,minmathbb{N}$ so $h_1^n=e$ and $h_2^m=e$. But I'm not sure how to use the that $Xcurvearrowright mathbb{R}$.










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  • $begingroup$
    What books are you using?
    $endgroup$
    – Shaun
    Dec 22 '18 at 15:52
















0












$begingroup$


While studying a subject about the group operator I came across with the following question:




Consider the following function: $h_1,h_2,:,mathbb{R}tomathbb{R}$
where $h_1=-x$ and $h_2=-x+1$. Lets define a new group $X=langle h_1,
h_2rangle$
which follows $Xcurvearrowrightmathbb{R}$ by $h_1cdot x
= h_1(x)$
.



Calculate $o(h_1)$ and $o(h_2)$.




Unfortunately, the books does not have final answer or solutions. I started from using the following definition of order: Let $G$ be a group, the order of $gin G$, meaning $o(g)$ is the minimal $nin mathbb{N}$ so $g^n=e$.



By using this definition, I understand that I need to find the minimal $n,minmathbb{N}$ so $h_1^n=e$ and $h_2^m=e$. But I'm not sure how to use the that $Xcurvearrowright mathbb{R}$.










share|cite|improve this question









$endgroup$












  • $begingroup$
    What books are you using?
    $endgroup$
    – Shaun
    Dec 22 '18 at 15:52














0












0








0





$begingroup$


While studying a subject about the group operator I came across with the following question:




Consider the following function: $h_1,h_2,:,mathbb{R}tomathbb{R}$
where $h_1=-x$ and $h_2=-x+1$. Lets define a new group $X=langle h_1,
h_2rangle$
which follows $Xcurvearrowrightmathbb{R}$ by $h_1cdot x
= h_1(x)$
.



Calculate $o(h_1)$ and $o(h_2)$.




Unfortunately, the books does not have final answer or solutions. I started from using the following definition of order: Let $G$ be a group, the order of $gin G$, meaning $o(g)$ is the minimal $nin mathbb{N}$ so $g^n=e$.



By using this definition, I understand that I need to find the minimal $n,minmathbb{N}$ so $h_1^n=e$ and $h_2^m=e$. But I'm not sure how to use the that $Xcurvearrowright mathbb{R}$.










share|cite|improve this question









$endgroup$




While studying a subject about the group operator I came across with the following question:




Consider the following function: $h_1,h_2,:,mathbb{R}tomathbb{R}$
where $h_1=-x$ and $h_2=-x+1$. Lets define a new group $X=langle h_1,
h_2rangle$
which follows $Xcurvearrowrightmathbb{R}$ by $h_1cdot x
= h_1(x)$
.



Calculate $o(h_1)$ and $o(h_2)$.




Unfortunately, the books does not have final answer or solutions. I started from using the following definition of order: Let $G$ be a group, the order of $gin G$, meaning $o(g)$ is the minimal $nin mathbb{N}$ so $g^n=e$.



By using this definition, I understand that I need to find the minimal $n,minmathbb{N}$ so $h_1^n=e$ and $h_2^m=e$. But I'm not sure how to use the that $Xcurvearrowright mathbb{R}$.







group-theory






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asked Dec 22 '18 at 15:42









vesiivesii

3978




3978












  • $begingroup$
    What books are you using?
    $endgroup$
    – Shaun
    Dec 22 '18 at 15:52


















  • $begingroup$
    What books are you using?
    $endgroup$
    – Shaun
    Dec 22 '18 at 15:52
















$begingroup$
What books are you using?
$endgroup$
– Shaun
Dec 22 '18 at 15:52




$begingroup$
What books are you using?
$endgroup$
– Shaun
Dec 22 '18 at 15:52










1 Answer
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oldest

votes


















0












$begingroup$

Hint/Explanation:



You should use the group action axioms, in particular this one:



If $g,hin G$ elements and $G$ acts on $X$ then $$g.(h.x) = (gh).x$$



Using this you should calculate $h_1^2.x$ and $h_2^2.x$






share|cite|improve this answer









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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

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    active

    oldest

    votes









    0












    $begingroup$

    Hint/Explanation:



    You should use the group action axioms, in particular this one:



    If $g,hin G$ elements and $G$ acts on $X$ then $$g.(h.x) = (gh).x$$



    Using this you should calculate $h_1^2.x$ and $h_2^2.x$






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      Hint/Explanation:



      You should use the group action axioms, in particular this one:



      If $g,hin G$ elements and $G$ acts on $X$ then $$g.(h.x) = (gh).x$$



      Using this you should calculate $h_1^2.x$ and $h_2^2.x$






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        Hint/Explanation:



        You should use the group action axioms, in particular this one:



        If $g,hin G$ elements and $G$ acts on $X$ then $$g.(h.x) = (gh).x$$



        Using this you should calculate $h_1^2.x$ and $h_2^2.x$






        share|cite|improve this answer









        $endgroup$



        Hint/Explanation:



        You should use the group action axioms, in particular this one:



        If $g,hin G$ elements and $G$ acts on $X$ then $$g.(h.x) = (gh).x$$



        Using this you should calculate $h_1^2.x$ and $h_2^2.x$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 22 '18 at 15:55









        YankoYanko

        8,4692830




        8,4692830






























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