Partial Derivatives and Physics meaning
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What is physics meaning of higher partial derivatives, for example, the physics meaning for first derivatives is velocity and the second is acceleration, but what about
$$frac{partial^2 f}{partial ypartial x} quad text{or} quad frac{partial^2 f}{partial x^2}$$
I'm looking for this question to get answer, I checked out the website but I don't get the answer.
partial-derivative mathematical-physics
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add a comment |
$begingroup$
What is physics meaning of higher partial derivatives, for example, the physics meaning for first derivatives is velocity and the second is acceleration, but what about
$$frac{partial^2 f}{partial ypartial x} quad text{or} quad frac{partial^2 f}{partial x^2}$$
I'm looking for this question to get answer, I checked out the website but I don't get the answer.
partial-derivative mathematical-physics
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$begingroup$
It depends upon the particular problem you are considering.
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– Felix Marin
Jul 22 '17 at 22:15
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math.stackexchange.com/questions/29561/…
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– Hans Lundmark
Jul 23 '17 at 6:29
add a comment |
$begingroup$
What is physics meaning of higher partial derivatives, for example, the physics meaning for first derivatives is velocity and the second is acceleration, but what about
$$frac{partial^2 f}{partial ypartial x} quad text{or} quad frac{partial^2 f}{partial x^2}$$
I'm looking for this question to get answer, I checked out the website but I don't get the answer.
partial-derivative mathematical-physics
$endgroup$
What is physics meaning of higher partial derivatives, for example, the physics meaning for first derivatives is velocity and the second is acceleration, but what about
$$frac{partial^2 f}{partial ypartial x} quad text{or} quad frac{partial^2 f}{partial x^2}$$
I'm looking for this question to get answer, I checked out the website but I don't get the answer.
partial-derivative mathematical-physics
partial-derivative mathematical-physics
edited Jul 22 '17 at 15:48
Sangchul Lee
92.8k12167269
92.8k12167269
asked Jul 22 '17 at 15:43
Ali Gh AbuSalehAli Gh AbuSaleh
61
61
$begingroup$
It depends upon the particular problem you are considering.
$endgroup$
– Felix Marin
Jul 22 '17 at 22:15
$begingroup$
math.stackexchange.com/questions/29561/…
$endgroup$
– Hans Lundmark
Jul 23 '17 at 6:29
add a comment |
$begingroup$
It depends upon the particular problem you are considering.
$endgroup$
– Felix Marin
Jul 22 '17 at 22:15
$begingroup$
math.stackexchange.com/questions/29561/…
$endgroup$
– Hans Lundmark
Jul 23 '17 at 6:29
$begingroup$
It depends upon the particular problem you are considering.
$endgroup$
– Felix Marin
Jul 22 '17 at 22:15
$begingroup$
It depends upon the particular problem you are considering.
$endgroup$
– Felix Marin
Jul 22 '17 at 22:15
$begingroup$
math.stackexchange.com/questions/29561/…
$endgroup$
– Hans Lundmark
Jul 23 '17 at 6:29
$begingroup$
math.stackexchange.com/questions/29561/…
$endgroup$
– Hans Lundmark
Jul 23 '17 at 6:29
add a comment |
1 Answer
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It really depends on both the quantity you are taking the derivative of and the variable you are taking a derivative with respect to.
When you say
the physics meaning for first derivatives is velocity and the second is acceleration
what you actually mean is that the first derivative of position with respect to time is velocity, and the second derivative of position with respect to time is acceleration. There is in fact a name in physics for a higher derivative, namely the third derivative of position with respect to time, which is called jerk. This is the rate of change of acceleration, and is not a very commonly-used quantity. This is because in physics, quantities that connect different concepts are often more useful. E.g. velocity connects the motion of a body over time (kinematics) to the energy that the body has through the kinetic energy equation, acceleration connects kinematics to the force that caused this acceleration (through Newton's 2nd law), on the other hand, there are no commonly used concepts connected with jerk as far as I am aware of.
Similarly, while you can give a name to all derivatives of all quantities with respect to all the variables they depend on, not all of these will be concepts that are useful in physics.
When you ask for
$$frac{partial^2 f}{partial x partial y}, frac{partial^2 f}{partial x^2} $$
If you are using the notation of $f$ meaning force and $x$ meaning position, the derivative of force with respect to position is not a generally useful quantity in physics, and the second derivative is also not. However, you can have the derivative of force with respect to area, which is the definition of pressure.
If you are interested in a particular $f$, $x$, and $y$, I can update my answer to try to elaborate more on specific derivatives.
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1 Answer
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1 Answer
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$begingroup$
It really depends on both the quantity you are taking the derivative of and the variable you are taking a derivative with respect to.
When you say
the physics meaning for first derivatives is velocity and the second is acceleration
what you actually mean is that the first derivative of position with respect to time is velocity, and the second derivative of position with respect to time is acceleration. There is in fact a name in physics for a higher derivative, namely the third derivative of position with respect to time, which is called jerk. This is the rate of change of acceleration, and is not a very commonly-used quantity. This is because in physics, quantities that connect different concepts are often more useful. E.g. velocity connects the motion of a body over time (kinematics) to the energy that the body has through the kinetic energy equation, acceleration connects kinematics to the force that caused this acceleration (through Newton's 2nd law), on the other hand, there are no commonly used concepts connected with jerk as far as I am aware of.
Similarly, while you can give a name to all derivatives of all quantities with respect to all the variables they depend on, not all of these will be concepts that are useful in physics.
When you ask for
$$frac{partial^2 f}{partial x partial y}, frac{partial^2 f}{partial x^2} $$
If you are using the notation of $f$ meaning force and $x$ meaning position, the derivative of force with respect to position is not a generally useful quantity in physics, and the second derivative is also not. However, you can have the derivative of force with respect to area, which is the definition of pressure.
If you are interested in a particular $f$, $x$, and $y$, I can update my answer to try to elaborate more on specific derivatives.
$endgroup$
add a comment |
$begingroup$
It really depends on both the quantity you are taking the derivative of and the variable you are taking a derivative with respect to.
When you say
the physics meaning for first derivatives is velocity and the second is acceleration
what you actually mean is that the first derivative of position with respect to time is velocity, and the second derivative of position with respect to time is acceleration. There is in fact a name in physics for a higher derivative, namely the third derivative of position with respect to time, which is called jerk. This is the rate of change of acceleration, and is not a very commonly-used quantity. This is because in physics, quantities that connect different concepts are often more useful. E.g. velocity connects the motion of a body over time (kinematics) to the energy that the body has through the kinetic energy equation, acceleration connects kinematics to the force that caused this acceleration (through Newton's 2nd law), on the other hand, there are no commonly used concepts connected with jerk as far as I am aware of.
Similarly, while you can give a name to all derivatives of all quantities with respect to all the variables they depend on, not all of these will be concepts that are useful in physics.
When you ask for
$$frac{partial^2 f}{partial x partial y}, frac{partial^2 f}{partial x^2} $$
If you are using the notation of $f$ meaning force and $x$ meaning position, the derivative of force with respect to position is not a generally useful quantity in physics, and the second derivative is also not. However, you can have the derivative of force with respect to area, which is the definition of pressure.
If you are interested in a particular $f$, $x$, and $y$, I can update my answer to try to elaborate more on specific derivatives.
$endgroup$
add a comment |
$begingroup$
It really depends on both the quantity you are taking the derivative of and the variable you are taking a derivative with respect to.
When you say
the physics meaning for first derivatives is velocity and the second is acceleration
what you actually mean is that the first derivative of position with respect to time is velocity, and the second derivative of position with respect to time is acceleration. There is in fact a name in physics for a higher derivative, namely the third derivative of position with respect to time, which is called jerk. This is the rate of change of acceleration, and is not a very commonly-used quantity. This is because in physics, quantities that connect different concepts are often more useful. E.g. velocity connects the motion of a body over time (kinematics) to the energy that the body has through the kinetic energy equation, acceleration connects kinematics to the force that caused this acceleration (through Newton's 2nd law), on the other hand, there are no commonly used concepts connected with jerk as far as I am aware of.
Similarly, while you can give a name to all derivatives of all quantities with respect to all the variables they depend on, not all of these will be concepts that are useful in physics.
When you ask for
$$frac{partial^2 f}{partial x partial y}, frac{partial^2 f}{partial x^2} $$
If you are using the notation of $f$ meaning force and $x$ meaning position, the derivative of force with respect to position is not a generally useful quantity in physics, and the second derivative is also not. However, you can have the derivative of force with respect to area, which is the definition of pressure.
If you are interested in a particular $f$, $x$, and $y$, I can update my answer to try to elaborate more on specific derivatives.
$endgroup$
It really depends on both the quantity you are taking the derivative of and the variable you are taking a derivative with respect to.
When you say
the physics meaning for first derivatives is velocity and the second is acceleration
what you actually mean is that the first derivative of position with respect to time is velocity, and the second derivative of position with respect to time is acceleration. There is in fact a name in physics for a higher derivative, namely the third derivative of position with respect to time, which is called jerk. This is the rate of change of acceleration, and is not a very commonly-used quantity. This is because in physics, quantities that connect different concepts are often more useful. E.g. velocity connects the motion of a body over time (kinematics) to the energy that the body has through the kinetic energy equation, acceleration connects kinematics to the force that caused this acceleration (through Newton's 2nd law), on the other hand, there are no commonly used concepts connected with jerk as far as I am aware of.
Similarly, while you can give a name to all derivatives of all quantities with respect to all the variables they depend on, not all of these will be concepts that are useful in physics.
When you ask for
$$frac{partial^2 f}{partial x partial y}, frac{partial^2 f}{partial x^2} $$
If you are using the notation of $f$ meaning force and $x$ meaning position, the derivative of force with respect to position is not a generally useful quantity in physics, and the second derivative is also not. However, you can have the derivative of force with respect to area, which is the definition of pressure.
If you are interested in a particular $f$, $x$, and $y$, I can update my answer to try to elaborate more on specific derivatives.
edited Dec 3 '18 at 17:11
epimorphic
2,74031533
2,74031533
answered Dec 3 '18 at 16:37
The HagenThe Hagen
1658
1658
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$begingroup$
It depends upon the particular problem you are considering.
$endgroup$
– Felix Marin
Jul 22 '17 at 22:15
$begingroup$
math.stackexchange.com/questions/29561/…
$endgroup$
– Hans Lundmark
Jul 23 '17 at 6:29