Partial Derivatives and Physics meaning












1












$begingroup$


What is physics meaning of higher partial derivatives, for example, the physics meaning for first derivatives is velocity and the second is acceleration, but what about



$$frac{partial^2 f}{partial ypartial x} quad text{or} quad frac{partial^2 f}{partial x^2}$$



I'm looking for this question to get answer, I checked out the website but I don't get the answer.










share|cite|improve this question











$endgroup$












  • $begingroup$
    It depends upon the particular problem you are considering.
    $endgroup$
    – Felix Marin
    Jul 22 '17 at 22:15










  • $begingroup$
    math.stackexchange.com/questions/29561/…
    $endgroup$
    – Hans Lundmark
    Jul 23 '17 at 6:29
















1












$begingroup$


What is physics meaning of higher partial derivatives, for example, the physics meaning for first derivatives is velocity and the second is acceleration, but what about



$$frac{partial^2 f}{partial ypartial x} quad text{or} quad frac{partial^2 f}{partial x^2}$$



I'm looking for this question to get answer, I checked out the website but I don't get the answer.










share|cite|improve this question











$endgroup$












  • $begingroup$
    It depends upon the particular problem you are considering.
    $endgroup$
    – Felix Marin
    Jul 22 '17 at 22:15










  • $begingroup$
    math.stackexchange.com/questions/29561/…
    $endgroup$
    – Hans Lundmark
    Jul 23 '17 at 6:29














1












1








1





$begingroup$


What is physics meaning of higher partial derivatives, for example, the physics meaning for first derivatives is velocity and the second is acceleration, but what about



$$frac{partial^2 f}{partial ypartial x} quad text{or} quad frac{partial^2 f}{partial x^2}$$



I'm looking for this question to get answer, I checked out the website but I don't get the answer.










share|cite|improve this question











$endgroup$




What is physics meaning of higher partial derivatives, for example, the physics meaning for first derivatives is velocity and the second is acceleration, but what about



$$frac{partial^2 f}{partial ypartial x} quad text{or} quad frac{partial^2 f}{partial x^2}$$



I'm looking for this question to get answer, I checked out the website but I don't get the answer.







partial-derivative mathematical-physics






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jul 22 '17 at 15:48









Sangchul Lee

92.8k12167269




92.8k12167269










asked Jul 22 '17 at 15:43









Ali Gh AbuSalehAli Gh AbuSaleh

61




61












  • $begingroup$
    It depends upon the particular problem you are considering.
    $endgroup$
    – Felix Marin
    Jul 22 '17 at 22:15










  • $begingroup$
    math.stackexchange.com/questions/29561/…
    $endgroup$
    – Hans Lundmark
    Jul 23 '17 at 6:29


















  • $begingroup$
    It depends upon the particular problem you are considering.
    $endgroup$
    – Felix Marin
    Jul 22 '17 at 22:15










  • $begingroup$
    math.stackexchange.com/questions/29561/…
    $endgroup$
    – Hans Lundmark
    Jul 23 '17 at 6:29
















$begingroup$
It depends upon the particular problem you are considering.
$endgroup$
– Felix Marin
Jul 22 '17 at 22:15




$begingroup$
It depends upon the particular problem you are considering.
$endgroup$
– Felix Marin
Jul 22 '17 at 22:15












$begingroup$
math.stackexchange.com/questions/29561/…
$endgroup$
– Hans Lundmark
Jul 23 '17 at 6:29




$begingroup$
math.stackexchange.com/questions/29561/…
$endgroup$
– Hans Lundmark
Jul 23 '17 at 6:29










1 Answer
1






active

oldest

votes


















1












$begingroup$

It really depends on both the quantity you are taking the derivative of and the variable you are taking a derivative with respect to.



When you say




the physics meaning for first derivatives is velocity and the second is acceleration




what you actually mean is that the first derivative of position with respect to time is velocity, and the second derivative of position with respect to time is acceleration. There is in fact a name in physics for a higher derivative, namely the third derivative of position with respect to time, which is called jerk. This is the rate of change of acceleration, and is not a very commonly-used quantity. This is because in physics, quantities that connect different concepts are often more useful. E.g. velocity connects the motion of a body over time (kinematics) to the energy that the body has through the kinetic energy equation, acceleration connects kinematics to the force that caused this acceleration (through Newton's 2nd law), on the other hand, there are no commonly used concepts connected with jerk as far as I am aware of.



Similarly, while you can give a name to all derivatives of all quantities with respect to all the variables they depend on, not all of these will be concepts that are useful in physics.



When you ask for



$$frac{partial^2 f}{partial x partial y}, frac{partial^2 f}{partial x^2} $$



If you are using the notation of $f$ meaning force and $x$ meaning position, the derivative of force with respect to position is not a generally useful quantity in physics, and the second derivative is also not. However, you can have the derivative of force with respect to area, which is the definition of pressure.



If you are interested in a particular $f$, $x$, and $y$, I can update my answer to try to elaborate more on specific derivatives.






share|cite|improve this answer











$endgroup$













    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "69"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2368157%2fpartial-derivatives-and-physics-meaning%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1












    $begingroup$

    It really depends on both the quantity you are taking the derivative of and the variable you are taking a derivative with respect to.



    When you say




    the physics meaning for first derivatives is velocity and the second is acceleration




    what you actually mean is that the first derivative of position with respect to time is velocity, and the second derivative of position with respect to time is acceleration. There is in fact a name in physics for a higher derivative, namely the third derivative of position with respect to time, which is called jerk. This is the rate of change of acceleration, and is not a very commonly-used quantity. This is because in physics, quantities that connect different concepts are often more useful. E.g. velocity connects the motion of a body over time (kinematics) to the energy that the body has through the kinetic energy equation, acceleration connects kinematics to the force that caused this acceleration (through Newton's 2nd law), on the other hand, there are no commonly used concepts connected with jerk as far as I am aware of.



    Similarly, while you can give a name to all derivatives of all quantities with respect to all the variables they depend on, not all of these will be concepts that are useful in physics.



    When you ask for



    $$frac{partial^2 f}{partial x partial y}, frac{partial^2 f}{partial x^2} $$



    If you are using the notation of $f$ meaning force and $x$ meaning position, the derivative of force with respect to position is not a generally useful quantity in physics, and the second derivative is also not. However, you can have the derivative of force with respect to area, which is the definition of pressure.



    If you are interested in a particular $f$, $x$, and $y$, I can update my answer to try to elaborate more on specific derivatives.






    share|cite|improve this answer











    $endgroup$


















      1












      $begingroup$

      It really depends on both the quantity you are taking the derivative of and the variable you are taking a derivative with respect to.



      When you say




      the physics meaning for first derivatives is velocity and the second is acceleration




      what you actually mean is that the first derivative of position with respect to time is velocity, and the second derivative of position with respect to time is acceleration. There is in fact a name in physics for a higher derivative, namely the third derivative of position with respect to time, which is called jerk. This is the rate of change of acceleration, and is not a very commonly-used quantity. This is because in physics, quantities that connect different concepts are often more useful. E.g. velocity connects the motion of a body over time (kinematics) to the energy that the body has through the kinetic energy equation, acceleration connects kinematics to the force that caused this acceleration (through Newton's 2nd law), on the other hand, there are no commonly used concepts connected with jerk as far as I am aware of.



      Similarly, while you can give a name to all derivatives of all quantities with respect to all the variables they depend on, not all of these will be concepts that are useful in physics.



      When you ask for



      $$frac{partial^2 f}{partial x partial y}, frac{partial^2 f}{partial x^2} $$



      If you are using the notation of $f$ meaning force and $x$ meaning position, the derivative of force with respect to position is not a generally useful quantity in physics, and the second derivative is also not. However, you can have the derivative of force with respect to area, which is the definition of pressure.



      If you are interested in a particular $f$, $x$, and $y$, I can update my answer to try to elaborate more on specific derivatives.






      share|cite|improve this answer











      $endgroup$
















        1












        1








        1





        $begingroup$

        It really depends on both the quantity you are taking the derivative of and the variable you are taking a derivative with respect to.



        When you say




        the physics meaning for first derivatives is velocity and the second is acceleration




        what you actually mean is that the first derivative of position with respect to time is velocity, and the second derivative of position with respect to time is acceleration. There is in fact a name in physics for a higher derivative, namely the third derivative of position with respect to time, which is called jerk. This is the rate of change of acceleration, and is not a very commonly-used quantity. This is because in physics, quantities that connect different concepts are often more useful. E.g. velocity connects the motion of a body over time (kinematics) to the energy that the body has through the kinetic energy equation, acceleration connects kinematics to the force that caused this acceleration (through Newton's 2nd law), on the other hand, there are no commonly used concepts connected with jerk as far as I am aware of.



        Similarly, while you can give a name to all derivatives of all quantities with respect to all the variables they depend on, not all of these will be concepts that are useful in physics.



        When you ask for



        $$frac{partial^2 f}{partial x partial y}, frac{partial^2 f}{partial x^2} $$



        If you are using the notation of $f$ meaning force and $x$ meaning position, the derivative of force with respect to position is not a generally useful quantity in physics, and the second derivative is also not. However, you can have the derivative of force with respect to area, which is the definition of pressure.



        If you are interested in a particular $f$, $x$, and $y$, I can update my answer to try to elaborate more on specific derivatives.






        share|cite|improve this answer











        $endgroup$



        It really depends on both the quantity you are taking the derivative of and the variable you are taking a derivative with respect to.



        When you say




        the physics meaning for first derivatives is velocity and the second is acceleration




        what you actually mean is that the first derivative of position with respect to time is velocity, and the second derivative of position with respect to time is acceleration. There is in fact a name in physics for a higher derivative, namely the third derivative of position with respect to time, which is called jerk. This is the rate of change of acceleration, and is not a very commonly-used quantity. This is because in physics, quantities that connect different concepts are often more useful. E.g. velocity connects the motion of a body over time (kinematics) to the energy that the body has through the kinetic energy equation, acceleration connects kinematics to the force that caused this acceleration (through Newton's 2nd law), on the other hand, there are no commonly used concepts connected with jerk as far as I am aware of.



        Similarly, while you can give a name to all derivatives of all quantities with respect to all the variables they depend on, not all of these will be concepts that are useful in physics.



        When you ask for



        $$frac{partial^2 f}{partial x partial y}, frac{partial^2 f}{partial x^2} $$



        If you are using the notation of $f$ meaning force and $x$ meaning position, the derivative of force with respect to position is not a generally useful quantity in physics, and the second derivative is also not. However, you can have the derivative of force with respect to area, which is the definition of pressure.



        If you are interested in a particular $f$, $x$, and $y$, I can update my answer to try to elaborate more on specific derivatives.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Dec 3 '18 at 17:11









        epimorphic

        2,74031533




        2,74031533










        answered Dec 3 '18 at 16:37









        The HagenThe Hagen

        1658




        1658






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Mathematics Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2368157%2fpartial-derivatives-and-physics-meaning%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Plaza Victoria

            Puebla de Zaragoza

            Musa