Function notation when $f^n=g^n$ at some $n$?












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What is the proper terminology / symbol to use for a function that reaches some point/value or a variable? Not necessarily converge to it, but passes it somehow?



Example



For $xinmathbb{N}$. Set initially $x_0=2$.



Iterating the function $f(x) = 2x$ will at some point reach the value $64$ for example: ${4,8,16,32,underline{64},128,256,..}$. For this case, $f(x)$ passes $x_0^6$ ? (i.e. $x_0$ raised to $6$).



Or do you say, for some $n$ the function $f^n(x)$ will reach or pass the value $64$ or $x_0^6$?



If we use two functions, is it possible to say the function $f^n$ passes through function $g^n$ at some $n$? or $f^n = g^n$ at some $n$ ?










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    0












    $begingroup$


    What is the proper terminology / symbol to use for a function that reaches some point/value or a variable? Not necessarily converge to it, but passes it somehow?



    Example



    For $xinmathbb{N}$. Set initially $x_0=2$.



    Iterating the function $f(x) = 2x$ will at some point reach the value $64$ for example: ${4,8,16,32,underline{64},128,256,..}$. For this case, $f(x)$ passes $x_0^6$ ? (i.e. $x_0$ raised to $6$).



    Or do you say, for some $n$ the function $f^n(x)$ will reach or pass the value $64$ or $x_0^6$?



    If we use two functions, is it possible to say the function $f^n$ passes through function $g^n$ at some $n$? or $f^n = g^n$ at some $n$ ?










    share|cite|improve this question









    $endgroup$















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      0



      $begingroup$


      What is the proper terminology / symbol to use for a function that reaches some point/value or a variable? Not necessarily converge to it, but passes it somehow?



      Example



      For $xinmathbb{N}$. Set initially $x_0=2$.



      Iterating the function $f(x) = 2x$ will at some point reach the value $64$ for example: ${4,8,16,32,underline{64},128,256,..}$. For this case, $f(x)$ passes $x_0^6$ ? (i.e. $x_0$ raised to $6$).



      Or do you say, for some $n$ the function $f^n(x)$ will reach or pass the value $64$ or $x_0^6$?



      If we use two functions, is it possible to say the function $f^n$ passes through function $g^n$ at some $n$? or $f^n = g^n$ at some $n$ ?










      share|cite|improve this question









      $endgroup$




      What is the proper terminology / symbol to use for a function that reaches some point/value or a variable? Not necessarily converge to it, but passes it somehow?



      Example



      For $xinmathbb{N}$. Set initially $x_0=2$.



      Iterating the function $f(x) = 2x$ will at some point reach the value $64$ for example: ${4,8,16,32,underline{64},128,256,..}$. For this case, $f(x)$ passes $x_0^6$ ? (i.e. $x_0$ raised to $6$).



      Or do you say, for some $n$ the function $f^n(x)$ will reach or pass the value $64$ or $x_0^6$?



      If we use two functions, is it possible to say the function $f^n$ passes through function $g^n$ at some $n$? or $f^n = g^n$ at some $n$ ?







      functions notation terminology






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      asked Dec 14 '18 at 16:13









      Natural Number GuyNatural Number Guy

      500518




      500518






















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          $begingroup$

          To answer the question in the body, we say that "$64$ is in the orbit of $2$ under $f$".



          More generally, if $f^n(x_0)=y$, then say that "$y$ is in the orbit of $x_0$ under $f$".






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            1 Answer
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            active

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            votes









            0












            $begingroup$

            To answer the question in the body, we say that "$64$ is in the orbit of $2$ under $f$".



            More generally, if $f^n(x_0)=y$, then say that "$y$ is in the orbit of $x_0$ under $f$".






            share|cite|improve this answer









            $endgroup$


















              0












              $begingroup$

              To answer the question in the body, we say that "$64$ is in the orbit of $2$ under $f$".



              More generally, if $f^n(x_0)=y$, then say that "$y$ is in the orbit of $x_0$ under $f$".






              share|cite|improve this answer









              $endgroup$
















                0












                0








                0





                $begingroup$

                To answer the question in the body, we say that "$64$ is in the orbit of $2$ under $f$".



                More generally, if $f^n(x_0)=y$, then say that "$y$ is in the orbit of $x_0$ under $f$".






                share|cite|improve this answer









                $endgroup$



                To answer the question in the body, we say that "$64$ is in the orbit of $2$ under $f$".



                More generally, if $f^n(x_0)=y$, then say that "$y$ is in the orbit of $x_0$ under $f$".







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 14 '18 at 16:44









                lhflhf

                166k10171396




                166k10171396






























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