A question on operators of subsets of integer numbers












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If $A={x^2-m|xin Z, -3<x<m}$ ($m$ is a constant number and $Z$ is symbol integer numbers) and $B={x|dfrac{x}{3}in Z, -4<xleq 12}$ and $n(Acap B)=3$, then prove that the least value for $n(A-B)$ is 2.



My work: I guess that if $m=4$, then $A={0,-3,-4,5,12}$ and so $n(A-B)=2$.










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    $begingroup$


    If $A={x^2-m|xin Z, -3<x<m}$ ($m$ is a constant number and $Z$ is symbol integer numbers) and $B={x|dfrac{x}{3}in Z, -4<xleq 12}$ and $n(Acap B)=3$, then prove that the least value for $n(A-B)$ is 2.



    My work: I guess that if $m=4$, then $A={0,-3,-4,5,12}$ and so $n(A-B)=2$.










    share|cite|improve this question











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      0





      $begingroup$


      If $A={x^2-m|xin Z, -3<x<m}$ ($m$ is a constant number and $Z$ is symbol integer numbers) and $B={x|dfrac{x}{3}in Z, -4<xleq 12}$ and $n(Acap B)=3$, then prove that the least value for $n(A-B)$ is 2.



      My work: I guess that if $m=4$, then $A={0,-3,-4,5,12}$ and so $n(A-B)=2$.










      share|cite|improve this question











      $endgroup$




      If $A={x^2-m|xin Z, -3<x<m}$ ($m$ is a constant number and $Z$ is symbol integer numbers) and $B={x|dfrac{x}{3}in Z, -4<xleq 12}$ and $n(Acap B)=3$, then prove that the least value for $n(A-B)$ is 2.



      My work: I guess that if $m=4$, then $A={0,-3,-4,5,12}$ and so $n(A-B)=2$.







      elementary-number-theory arithmetic






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      share|cite|improve this question













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      edited Dec 14 '18 at 17:16







      A.G

















      asked Dec 14 '18 at 16:07









      A.GA.G

      401310




      401310






















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