Probability question. Roulette dozens bet occurring consecutively.
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Hello Mathematics Guru's,
Can I first caveat this question by saying, I'm wholly aware the house always has a mathematical edge if you play long enough in Roulette, but i am interested to know the following all the same.
I would like to know the percentage chance of the following occurring playing Roulette.
I like to bet on 2 of the dozen bets, which pays 2:1. Specifically the middle column (13-24) and high column (25-36) at the time covering approximately 64.8% of the board.
So my question is, what is the percentage chance of the low column numbers (1-12) and the zero occurring, ie the numbers i'm not betting on hitting consecutively? Specifically, 6, 7 and 8 times in a row.
Many thanks
Keir
probability gambling
asked Dec 14 '18 at 14:44
Keir DoubasKeir Doubas
11
$endgroup$
add a comment |
$begingroup$
Hello Mathematics Guru's,
Can I first caveat this question by saying, I'm wholly aware the house always has a mathematical edge if you play long enough in Roulette, but i am interested to know the following all the same.
I would like to know the percentage chance of the following occurring playing Roulette.
I like to bet on 2 of the dozen bets, which pays 2:1. Specifically the middle column (13-24) and high column (25-36) at the time covering approximately 64.8% of the board.
So my question is, what is the percentage chance of the low column numbers (1-12) and the zero occurring, ie the numbers i'm not betting on hitting consecutively? Specifically, 6, 7 and 8 times in a row.
Many thanks
Keir
probability gambling
asked Dec 14 '18 at 14:44
Keir DoubasKeir Doubas
11
$endgroup$
$begingroup$
Can you figure out the probability of [that event] happening one time?
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– The Chaz 2.0
Dec 14 '18 at 15:11
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Yes, the chance of the first dozen (1-12) or the Zero hitting is 35.1% probability. Any single no including the zero is 2.7% and any dozen is 32.4%
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– Keir Doubas
Dec 16 '18 at 19:13
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Great! Now raise that probability ($0.351$) to the power of 6, 7, or 8.
$endgroup$
– The Chaz 2.0
Dec 17 '18 at 8:04
1
$begingroup$
Many thanks, i've worked it out!
$endgroup$
– Keir Doubas
Dec 18 '18 at 10:51
add a comment |
$begingroup$
Hello Mathematics Guru's,
Can I first caveat this question by saying, I'm wholly aware the house always has a mathematical edge if you play long enough in Roulette, but i am interested to know the following all the same.
I would like to know the percentage chance of the following occurring playing Roulette.
I like to bet on 2 of the dozen bets, which pays 2:1. Specifically the middle column (13-24) and high column (25-36) at the time covering approximately 64.8% of the board.
So my question is, what is the percentage chance of the low column numbers (1-12) and the zero occurring, ie the numbers i'm not betting on hitting consecutively? Specifically, 6, 7 and 8 times in a row.
Many thanks
Keir
probability gambling
asked Dec 14 '18 at 14:44
Keir DoubasKeir Doubas
11
$endgroup$
Hello Mathematics Guru's,
Can I first caveat this question by saying, I'm wholly aware the house always has a mathematical edge if you play long enough in Roulette, but i am interested to know the following all the same.
I would like to know the percentage chance of the following occurring playing Roulette.
I like to bet on 2 of the dozen bets, which pays 2:1. Specifically the middle column (13-24) and high column (25-36) at the time covering approximately 64.8% of the board.
So my question is, what is the percentage chance of the low column numbers (1-12) and the zero occurring, ie the numbers i'm not betting on hitting consecutively? Specifically, 6, 7 and 8 times in a row.
Many thanks
Keir
probability gambling
probability gambling
asked Dec 14 '18 at 14:44
Keir DoubasKeir Doubas
11
asked Dec 14 '18 at 14:44
Keir DoubasKeir Doubas
11
edited Dec 16 '18 at 19:16
Keir Doubas
asked Dec 14 '18 at 14:44
Keir DoubasKeir Doubas
11
asked Dec 14 '18 at 14:44
Keir DoubasKeir Doubas
11
asked Dec 14 '18 at 14:44
Keir DoubasKeir Doubas
11
11
$begingroup$
Can you figure out the probability of [that event] happening one time?
$endgroup$
– The Chaz 2.0
Dec 14 '18 at 15:11
$begingroup$
Yes, the chance of the first dozen (1-12) or the Zero hitting is 35.1% probability. Any single no including the zero is 2.7% and any dozen is 32.4%
$endgroup$
– Keir Doubas
Dec 16 '18 at 19:13
$begingroup$
Great! Now raise that probability ($0.351$) to the power of 6, 7, or 8.
$endgroup$
– The Chaz 2.0
Dec 17 '18 at 8:04
1
$begingroup$
Many thanks, i've worked it out!
$endgroup$
– Keir Doubas
Dec 18 '18 at 10:51
add a comment |
$begingroup$
Can you figure out the probability of [that event] happening one time?
$endgroup$
– The Chaz 2.0
Dec 14 '18 at 15:11
$begingroup$
Yes, the chance of the first dozen (1-12) or the Zero hitting is 35.1% probability. Any single no including the zero is 2.7% and any dozen is 32.4%
$endgroup$
– Keir Doubas
Dec 16 '18 at 19:13
$begingroup$
Great! Now raise that probability ($0.351$) to the power of 6, 7, or 8.
$endgroup$
– The Chaz 2.0
Dec 17 '18 at 8:04
1
$begingroup$
Many thanks, i've worked it out!
$endgroup$
– Keir Doubas
Dec 18 '18 at 10:51
$begingroup$
Can you figure out the probability of [that event] happening one time?
$endgroup$
– The Chaz 2.0
Dec 14 '18 at 15:11
$begingroup$
Can you figure out the probability of [that event] happening one time?
$endgroup$
– The Chaz 2.0
Dec 14 '18 at 15:11
$begingroup$
Yes, the chance of the first dozen (1-12) or the Zero hitting is 35.1% probability. Any single no including the zero is 2.7% and any dozen is 32.4%
$endgroup$
– Keir Doubas
Dec 16 '18 at 19:13
$begingroup$
Yes, the chance of the first dozen (1-12) or the Zero hitting is 35.1% probability. Any single no including the zero is 2.7% and any dozen is 32.4%
$endgroup$
– Keir Doubas
Dec 16 '18 at 19:13
$begingroup$
Great! Now raise that probability ($0.351$) to the power of 6, 7, or 8.
$endgroup$
– The Chaz 2.0
Dec 17 '18 at 8:04
$begingroup$
Great! Now raise that probability ($0.351$) to the power of 6, 7, or 8.
$endgroup$
– The Chaz 2.0
Dec 17 '18 at 8:04
1
1
$begingroup$
Many thanks, i've worked it out!
$endgroup$
– Keir Doubas
Dec 18 '18 at 10:51
$begingroup$
Many thanks, i've worked it out!
$endgroup$
– Keir Doubas
Dec 18 '18 at 10:51
add a comment |
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$begingroup$
Can you figure out the probability of [that event] happening one time?
$endgroup$
– The Chaz 2.0
Dec 14 '18 at 15:11
$begingroup$
Yes, the chance of the first dozen (1-12) or the Zero hitting is 35.1% probability. Any single no including the zero is 2.7% and any dozen is 32.4%
$endgroup$
– Keir Doubas
Dec 16 '18 at 19:13
$begingroup$
Great! Now raise that probability ($0.351$) to the power of 6, 7, or 8.
$endgroup$
– The Chaz 2.0
Dec 17 '18 at 8:04
1
$begingroup$
Many thanks, i've worked it out!
$endgroup$
– Keir Doubas
Dec 18 '18 at 10:51