Relation between parzen window estimate and histogram












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Can histogram density estimation be seen as approximation to parzen density estimation with the usual hyper cube function
$1/h^d Sigma_{1 le i le n} varphi(frac{x-x_i}{h})$ where $varphi(y)=1$ if $|y| le 1/2$ and $0$ otherwise. Parzen window raises a histogram bin at each point and determines average density at this point while histogram assumes density to uniform over fixed bins. Is my understanding correct.










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    Can histogram density estimation be seen as approximation to parzen density estimation with the usual hyper cube function
    $1/h^d Sigma_{1 le i le n} varphi(frac{x-x_i}{h})$ where $varphi(y)=1$ if $|y| le 1/2$ and $0$ otherwise. Parzen window raises a histogram bin at each point and determines average density at this point while histogram assumes density to uniform over fixed bins. Is my understanding correct.










    share|cite|improve this question









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      $begingroup$


      Can histogram density estimation be seen as approximation to parzen density estimation with the usual hyper cube function
      $1/h^d Sigma_{1 le i le n} varphi(frac{x-x_i}{h})$ where $varphi(y)=1$ if $|y| le 1/2$ and $0$ otherwise. Parzen window raises a histogram bin at each point and determines average density at this point while histogram assumes density to uniform over fixed bins. Is my understanding correct.










      share|cite|improve this question









      $endgroup$




      Can histogram density estimation be seen as approximation to parzen density estimation with the usual hyper cube function
      $1/h^d Sigma_{1 le i le n} varphi(frac{x-x_i}{h})$ where $varphi(y)=1$ if $|y| le 1/2$ and $0$ otherwise. Parzen window raises a histogram bin at each point and determines average density at this point while histogram assumes density to uniform over fixed bins. Is my understanding correct.







      estimation density-function






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      asked Dec 19 '18 at 11:14









      CuriousCurious

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