Improved model of a fishery: $dot N=rN(1-frac{N}{K})-Hfrac{N}{A+N}$
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Strogatz exercise $3.7.4.a:$
An improved model of a fishery is:
$$dot N=rNleft(1-frac{N}{K}right)-Hfrac{N}{A+N}.$$
a) Give a biological interpretation of the parameter $A$; what does it measure?
Here's what I did:
I non-dimensionalized the system $(frac{dN}{dt}=N(1-N)-hfrac{N}{a+N})$ and used the 'Manipulate' function of Mathematica to gain a better understanding of what '$a$' is biologically, but still, I couldn't see it.
So here's my question: How could I approach answering such a question and gain a better insight of it?
Thank you in advance.
ordinary-differential-equations dynamical-systems mathematical-modeling biology non-linear-dynamics
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show 1 more comment
$begingroup$
Strogatz exercise $3.7.4.a:$
An improved model of a fishery is:
$$dot N=rNleft(1-frac{N}{K}right)-Hfrac{N}{A+N}.$$
a) Give a biological interpretation of the parameter $A$; what does it measure?
Here's what I did:
I non-dimensionalized the system $(frac{dN}{dt}=N(1-N)-hfrac{N}{a+N})$ and used the 'Manipulate' function of Mathematica to gain a better understanding of what '$a$' is biologically, but still, I couldn't see it.
So here's my question: How could I approach answering such a question and gain a better insight of it?
Thank you in advance.
ordinary-differential-equations dynamical-systems mathematical-modeling biology non-linear-dynamics
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$begingroup$
Have you tried Google?
$endgroup$
– John Douma
Dec 24 '18 at 19:28
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What are the parameters? Presumably $N$ is the number of fish. What are $r,H,K? What is the model you are improving? The same without $A$? The interpretation of $A$ will depend on understanding the model.
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– Ross Millikan
Dec 24 '18 at 19:33
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@JohnDouma Yes, I even tried 'Mathematical Biology' by Murray. And also this article sciencedirect.com/science/article/pii/0198971582900011.
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– Heptapod
Dec 24 '18 at 19:34
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@RossMillikan Yes, $N$ is the number of fish, $r$ is how fast the population grows, $K$ is the carrying capacity, and $H$ is the harvesting rate. In the original model, $H$ is constant which creates a simple saddle-node bifurcation and it is very easy to comprehend.
$endgroup$
– Heptapod
Dec 24 '18 at 19:37
3
$begingroup$
@Heptapod: See number $3$: math.ucdavis.edu/~hunter/m207/set3_sol.pdf
$endgroup$
– Moo
Dec 24 '18 at 19:45
|
show 1 more comment
$begingroup$
Strogatz exercise $3.7.4.a:$
An improved model of a fishery is:
$$dot N=rNleft(1-frac{N}{K}right)-Hfrac{N}{A+N}.$$
a) Give a biological interpretation of the parameter $A$; what does it measure?
Here's what I did:
I non-dimensionalized the system $(frac{dN}{dt}=N(1-N)-hfrac{N}{a+N})$ and used the 'Manipulate' function of Mathematica to gain a better understanding of what '$a$' is biologically, but still, I couldn't see it.
So here's my question: How could I approach answering such a question and gain a better insight of it?
Thank you in advance.
ordinary-differential-equations dynamical-systems mathematical-modeling biology non-linear-dynamics
$endgroup$
Strogatz exercise $3.7.4.a:$
An improved model of a fishery is:
$$dot N=rNleft(1-frac{N}{K}right)-Hfrac{N}{A+N}.$$
a) Give a biological interpretation of the parameter $A$; what does it measure?
Here's what I did:
I non-dimensionalized the system $(frac{dN}{dt}=N(1-N)-hfrac{N}{a+N})$ and used the 'Manipulate' function of Mathematica to gain a better understanding of what '$a$' is biologically, but still, I couldn't see it.
So here's my question: How could I approach answering such a question and gain a better insight of it?
Thank you in advance.
ordinary-differential-equations dynamical-systems mathematical-modeling biology non-linear-dynamics
ordinary-differential-equations dynamical-systems mathematical-modeling biology non-linear-dynamics
edited Dec 24 '18 at 19:27
Namaste
1
1
asked Dec 24 '18 at 19:09
HeptapodHeptapod
716417
716417
$begingroup$
Have you tried Google?
$endgroup$
– John Douma
Dec 24 '18 at 19:28
$begingroup$
What are the parameters? Presumably $N$ is the number of fish. What are $r,H,K? What is the model you are improving? The same without $A$? The interpretation of $A$ will depend on understanding the model.
$endgroup$
– Ross Millikan
Dec 24 '18 at 19:33
$begingroup$
@JohnDouma Yes, I even tried 'Mathematical Biology' by Murray. And also this article sciencedirect.com/science/article/pii/0198971582900011.
$endgroup$
– Heptapod
Dec 24 '18 at 19:34
$begingroup$
@RossMillikan Yes, $N$ is the number of fish, $r$ is how fast the population grows, $K$ is the carrying capacity, and $H$ is the harvesting rate. In the original model, $H$ is constant which creates a simple saddle-node bifurcation and it is very easy to comprehend.
$endgroup$
– Heptapod
Dec 24 '18 at 19:37
3
$begingroup$
@Heptapod: See number $3$: math.ucdavis.edu/~hunter/m207/set3_sol.pdf
$endgroup$
– Moo
Dec 24 '18 at 19:45
|
show 1 more comment
$begingroup$
Have you tried Google?
$endgroup$
– John Douma
Dec 24 '18 at 19:28
$begingroup$
What are the parameters? Presumably $N$ is the number of fish. What are $r,H,K? What is the model you are improving? The same without $A$? The interpretation of $A$ will depend on understanding the model.
$endgroup$
– Ross Millikan
Dec 24 '18 at 19:33
$begingroup$
@JohnDouma Yes, I even tried 'Mathematical Biology' by Murray. And also this article sciencedirect.com/science/article/pii/0198971582900011.
$endgroup$
– Heptapod
Dec 24 '18 at 19:34
$begingroup$
@RossMillikan Yes, $N$ is the number of fish, $r$ is how fast the population grows, $K$ is the carrying capacity, and $H$ is the harvesting rate. In the original model, $H$ is constant which creates a simple saddle-node bifurcation and it is very easy to comprehend.
$endgroup$
– Heptapod
Dec 24 '18 at 19:37
3
$begingroup$
@Heptapod: See number $3$: math.ucdavis.edu/~hunter/m207/set3_sol.pdf
$endgroup$
– Moo
Dec 24 '18 at 19:45
$begingroup$
Have you tried Google?
$endgroup$
– John Douma
Dec 24 '18 at 19:28
$begingroup$
Have you tried Google?
$endgroup$
– John Douma
Dec 24 '18 at 19:28
$begingroup$
What are the parameters? Presumably $N$ is the number of fish. What are $r,H,K? What is the model you are improving? The same without $A$? The interpretation of $A$ will depend on understanding the model.
$endgroup$
– Ross Millikan
Dec 24 '18 at 19:33
$begingroup$
What are the parameters? Presumably $N$ is the number of fish. What are $r,H,K? What is the model you are improving? The same without $A$? The interpretation of $A$ will depend on understanding the model.
$endgroup$
– Ross Millikan
Dec 24 '18 at 19:33
$begingroup$
@JohnDouma Yes, I even tried 'Mathematical Biology' by Murray. And also this article sciencedirect.com/science/article/pii/0198971582900011.
$endgroup$
– Heptapod
Dec 24 '18 at 19:34
$begingroup$
@JohnDouma Yes, I even tried 'Mathematical Biology' by Murray. And also this article sciencedirect.com/science/article/pii/0198971582900011.
$endgroup$
– Heptapod
Dec 24 '18 at 19:34
$begingroup$
@RossMillikan Yes, $N$ is the number of fish, $r$ is how fast the population grows, $K$ is the carrying capacity, and $H$ is the harvesting rate. In the original model, $H$ is constant which creates a simple saddle-node bifurcation and it is very easy to comprehend.
$endgroup$
– Heptapod
Dec 24 '18 at 19:37
$begingroup$
@RossMillikan Yes, $N$ is the number of fish, $r$ is how fast the population grows, $K$ is the carrying capacity, and $H$ is the harvesting rate. In the original model, $H$ is constant which creates a simple saddle-node bifurcation and it is very easy to comprehend.
$endgroup$
– Heptapod
Dec 24 '18 at 19:37
3
3
$begingroup$
@Heptapod: See number $3$: math.ucdavis.edu/~hunter/m207/set3_sol.pdf
$endgroup$
– Moo
Dec 24 '18 at 19:45
$begingroup$
@Heptapod: See number $3$: math.ucdavis.edu/~hunter/m207/set3_sol.pdf
$endgroup$
– Moo
Dec 24 '18 at 19:45
|
show 1 more comment
2 Answers
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$begingroup$
The term $HN/(A+N)$ is a typical saturation term (see Michaelis–Menten kinetics, or type II functional response).
For small $N$ (in comparison to $A$), the harvesting is roughly proportional to how much fish there is, since $HN/(A+N) approx (H/A)N$.
But for large $N$ (in comparison to $A$) there is saturation; no matter how much fish there is available, one can't harvest at a higher rate than $H$, since $HN/(A+N) nearrow H$ as $N to infty$.
$endgroup$
add a comment |
$begingroup$
I don't think you are expected to do any manipulation, you are just supposed to explain what $A$ does in the model. I would answer along the lines of
It reflects that harvesting gets less when fish get scarce. If $N=A$ the harvesting drops in half compared to when $N$ is very large compared with $A$.
$endgroup$
add a comment |
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2 Answers
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active
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2 Answers
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$begingroup$
The term $HN/(A+N)$ is a typical saturation term (see Michaelis–Menten kinetics, or type II functional response).
For small $N$ (in comparison to $A$), the harvesting is roughly proportional to how much fish there is, since $HN/(A+N) approx (H/A)N$.
But for large $N$ (in comparison to $A$) there is saturation; no matter how much fish there is available, one can't harvest at a higher rate than $H$, since $HN/(A+N) nearrow H$ as $N to infty$.
$endgroup$
add a comment |
$begingroup$
The term $HN/(A+N)$ is a typical saturation term (see Michaelis–Menten kinetics, or type II functional response).
For small $N$ (in comparison to $A$), the harvesting is roughly proportional to how much fish there is, since $HN/(A+N) approx (H/A)N$.
But for large $N$ (in comparison to $A$) there is saturation; no matter how much fish there is available, one can't harvest at a higher rate than $H$, since $HN/(A+N) nearrow H$ as $N to infty$.
$endgroup$
add a comment |
$begingroup$
The term $HN/(A+N)$ is a typical saturation term (see Michaelis–Menten kinetics, or type II functional response).
For small $N$ (in comparison to $A$), the harvesting is roughly proportional to how much fish there is, since $HN/(A+N) approx (H/A)N$.
But for large $N$ (in comparison to $A$) there is saturation; no matter how much fish there is available, one can't harvest at a higher rate than $H$, since $HN/(A+N) nearrow H$ as $N to infty$.
$endgroup$
The term $HN/(A+N)$ is a typical saturation term (see Michaelis–Menten kinetics, or type II functional response).
For small $N$ (in comparison to $A$), the harvesting is roughly proportional to how much fish there is, since $HN/(A+N) approx (H/A)N$.
But for large $N$ (in comparison to $A$) there is saturation; no matter how much fish there is available, one can't harvest at a higher rate than $H$, since $HN/(A+N) nearrow H$ as $N to infty$.
answered Dec 24 '18 at 20:36
Hans LundmarkHans Lundmark
36.3k564116
36.3k564116
add a comment |
add a comment |
$begingroup$
I don't think you are expected to do any manipulation, you are just supposed to explain what $A$ does in the model. I would answer along the lines of
It reflects that harvesting gets less when fish get scarce. If $N=A$ the harvesting drops in half compared to when $N$ is very large compared with $A$.
$endgroup$
add a comment |
$begingroup$
I don't think you are expected to do any manipulation, you are just supposed to explain what $A$ does in the model. I would answer along the lines of
It reflects that harvesting gets less when fish get scarce. If $N=A$ the harvesting drops in half compared to when $N$ is very large compared with $A$.
$endgroup$
add a comment |
$begingroup$
I don't think you are expected to do any manipulation, you are just supposed to explain what $A$ does in the model. I would answer along the lines of
It reflects that harvesting gets less when fish get scarce. If $N=A$ the harvesting drops in half compared to when $N$ is very large compared with $A$.
$endgroup$
I don't think you are expected to do any manipulation, you are just supposed to explain what $A$ does in the model. I would answer along the lines of
It reflects that harvesting gets less when fish get scarce. If $N=A$ the harvesting drops in half compared to when $N$ is very large compared with $A$.
answered Dec 24 '18 at 19:44
Ross MillikanRoss Millikan
302k24201375
302k24201375
add a comment |
add a comment |
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$begingroup$
Have you tried Google?
$endgroup$
– John Douma
Dec 24 '18 at 19:28
$begingroup$
What are the parameters? Presumably $N$ is the number of fish. What are $r,H,K? What is the model you are improving? The same without $A$? The interpretation of $A$ will depend on understanding the model.
$endgroup$
– Ross Millikan
Dec 24 '18 at 19:33
$begingroup$
@JohnDouma Yes, I even tried 'Mathematical Biology' by Murray. And also this article sciencedirect.com/science/article/pii/0198971582900011.
$endgroup$
– Heptapod
Dec 24 '18 at 19:34
$begingroup$
@RossMillikan Yes, $N$ is the number of fish, $r$ is how fast the population grows, $K$ is the carrying capacity, and $H$ is the harvesting rate. In the original model, $H$ is constant which creates a simple saddle-node bifurcation and it is very easy to comprehend.
$endgroup$
– Heptapod
Dec 24 '18 at 19:37
3
$begingroup$
@Heptapod: See number $3$: math.ucdavis.edu/~hunter/m207/set3_sol.pdf
$endgroup$
– Moo
Dec 24 '18 at 19:45