What's the easiest way to combine specific columns of two matrices?












3












$begingroup$


given matrices



A = {{3, 10, 10, 5.`}, {4, 10, 10, 6.`}, {5, 10, 10, 7.`}}

B = {{6, 10, 10, 5.`}, {7, 10, 10, 6.`}, {8, 10, 10, 7.`}}


how can i get a matrix which has the combines the first column of A with the first coulumn of B and the last column of A?
Resulting in



C = {{3,6, 5.`}, {4,7, 6.`}, {5,8, 7.`}}


Thanky you in advance for any assistance






matrix concatenation







share|improve this question









$endgroup$

















    3












    $begingroup$


    given matrices



    A = {{3, 10, 10, 5.`}, {4, 10, 10, 6.`}, {5, 10, 10, 7.`}}
    
B = {{6, 10, 10, 5.`}, {7, 10, 10, 6.`}, {8, 10, 10, 7.`}}


    how can i get a matrix which has the combines the first column of A with the first coulumn of B and the last column of A?
    Resulting in



    C = {{3,6, 5.`}, {4,7, 6.`}, {5,8, 7.`}}


    Thanky you in advance for any assistance






    matrix concatenation







    share|improve this question









    $endgroup$















      3












      3








      3





      $begingroup$


      given matrices



      A = {{3, 10, 10, 5.`}, {4, 10, 10, 6.`}, {5, 10, 10, 7.`}}
      
B = {{6, 10, 10, 5.`}, {7, 10, 10, 6.`}, {8, 10, 10, 7.`}}


      how can i get a matrix which has the combines the first column of A with the first coulumn of B and the last column of A?
      Resulting in



      C = {{3,6, 5.`}, {4,7, 6.`}, {5,8, 7.`}}


      Thanky you in advance for any assistance






      matrix concatenation







      share|improve this question









      $endgroup$




      given matrices



      A = {{3, 10, 10, 5.`}, {4, 10, 10, 6.`}, {5, 10, 10, 7.`}}
      
B = {{6, 10, 10, 5.`}, {7, 10, 10, 6.`}, {8, 10, 10, 7.`}}


      how can i get a matrix which has the combines the first column of A with the first coulumn of B and the last column of A?
      Resulting in



      C = {{3,6, 5.`}, {4,7, 6.`}, {5,8, 7.`}}


      Thanky you in advance for any assistance






      matrix concatenation




      matrix concatenation






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Apr 20 at 8:49









      AndreasAndreas

      1198




      1198






















          1 Answer
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          4












          $begingroup$

          just try 



           Transpose@{First/@A,First/@B,Last/@A}


          or 



           Transpose@{A[[All,1]],B[[All,1]],A[[All,4]]}



          {{3, 6, 5.}, {4, 7, 6.}, {5, 8, 7.}}







          share|improve this answer











          $endgroup$













          • $begingroup$
            Than you very much
            $endgroup$
            – Andreas
            Apr 20 at 9:57












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          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          4












          $begingroup$

          just try 



           Transpose@{First/@A,First/@B,Last/@A}


          or 



           Transpose@{A[[All,1]],B[[All,1]],A[[All,4]]}



          {{3, 6, 5.}, {4, 7, 6.}, {5, 8, 7.}}







          share|improve this answer











          $endgroup$













          • $begingroup$
            Than you very much
            $endgroup$
            – Andreas
            Apr 20 at 9:57
















          4












          $begingroup$

          just try 



           Transpose@{First/@A,First/@B,Last/@A}


          or 



           Transpose@{A[[All,1]],B[[All,1]],A[[All,4]]}



          {{3, 6, 5.}, {4, 7, 6.}, {5, 8, 7.}}







          share|improve this answer











          $endgroup$













          • $begingroup$
            Than you very much
            $endgroup$
            – Andreas
            Apr 20 at 9:57














          4












          4








          4





          $begingroup$

          just try 



           Transpose@{First/@A,First/@B,Last/@A}


          or 



           Transpose@{A[[All,1]],B[[All,1]],A[[All,4]]}



          {{3, 6, 5.}, {4, 7, 6.}, {5, 8, 7.}}







          share|improve this answer











          $endgroup$



          just try 



           Transpose@{First/@A,First/@B,Last/@A}


          or 



           Transpose@{A[[All,1]],B[[All,1]],A[[All,4]]}



          {{3, 6, 5.}, {4, 7, 6.}, {5, 8, 7.}}








          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Apr 20 at 9:04

























          answered Apr 20 at 8:57









          J42161217J42161217

          4,723324




          4,723324












          • $begingroup$
            Than you very much
            $endgroup$
            – Andreas
            Apr 20 at 9:57


















          • $begingroup$
            Than you very much
            $endgroup$
            – Andreas
            Apr 20 at 9:57
















          $begingroup$
          Than you very much
          $endgroup$
          – Andreas
          Apr 20 at 9:57




          $begingroup$
          Than you very much
          $endgroup$
          – Andreas
          Apr 20 at 9:57


















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